Try Out I Fisika Online Ujian Nasional Sma/Ma
Try Out Ujian Nasional SUOA adalah wajib diikuti oleh siswa MA Baitul Arqom Balung - Jember, kelas XII (Dua Belas), Program IPA, tetapi kami di sini juga memberikan peluang kepada siswa Indonesia yang lainnya secara khusus siswa yang akan menghadapi Ujian Nasioanal pada tahun 2014 ini dan secara umum anak - anak bangsa yang peduli terhadap prestasinya, anak didik kami kelas X (Sepuluh) dan kelas XI (Sebelas) untuk mengikuti program try out ini, FREE, tidak dipunggut biaya. Try Out merupakan sarana bagi siswa dalam mengasa kemampuannya sebelum menghadapi Ujian Nasional sesungguhnya dan sekaligus parameter semantara terhadap materi yang sudah Read morediajarkan dapat diterima dengan baik atau masih perlu bimbingan yang lebih inten lagi. Ingat, tidak ada orang sukses tanpa belajar. Don't be lazy if you want to pass the exam. Kami ucapkan selamat belajar, Good Luck.
Salam Sukses,
Questions and Answers
- 1.
Gambar di bawah ini merupakan hasil bacaan pengukuran tebal suatu balok kayu dengan jangka sorong dan pengukuran diameter silinder logam dengan mikrometer sekrup: Hasil pengukuran tebal balok kayu dan diameter silinder logam dapat dituliskan dalam bentuk laporan adalah .....
- A.
0,85 ± 0,05) cm dan (2,77 ± 0,005) mm
- B.
(0,850 ± 0,005) cm dan (2,770 ± 0,005) mm
- C.
(0,850 ± 0,005) cm dan (5,270 ± 0,005) mm
- D.
(0,95 ± 0,05) cm dan (5,270 ± 0,05) mm
- E.
(0,950 ± 0,005) cm dan (5,270 ± 0,005) mm
Correct Answer
B. (0,850 ± 0,005) cm dan (2,770 ± 0,005) mmExplanation
The correct answer is (0,850 ± 0,005) cm dan (2,770 ± 0,005) mm. This is because the measurements are given with their respective uncertainties. The value 0.850 cm represents the thickness of the wooden block with an uncertainty of ±0.005 cm. Similarly, the value 2.770 mm represents the diameter of the metal cylinder with an uncertainty of ±0.005 mm. The other options either have incorrect values or incorrect uncertainties, making them incorrect choices.Rate this question:
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- 2.
Tiga buah vektor gaya masing – masing F1 = 30 N, F2 = 70 N, dan F3 = 30 N, disusun seperti pada gambar. Besar resultan ketiga vektor tersebut adalah .....
- A.
0 N
- B.
70 N
- C.
85 N
- D.
85 Â N
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- E.
100 N
Correct Answer
E. 100 NExplanation
The question asks for the magnitude of the resultant of three force vectors arranged as shown in the diagram. The magnitudes of the three vectors are given as F1 = 30 N, F2 = 70 N, and F3 = 30 N. To find the resultant, we need to add the vectors together. When we add F1, F2, and F3, we get a total of 130 N. Therefore, the magnitude of the resultant is 130 N.Rate this question:
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- 3.
Perhatikan gambar di bawah ini! Jika massa balok 4 kg, dan antara balok dan lantai tidak ada gesekan, maka balok tersebut dalam keadaan .….
- A.
Diam (tidak bergerak)
- B.
Gerak lurus berubah beraturan arah ke kanan
- C.
Bergerak lurus berubah beraturan arah ke kiri
- D.
Bergerak lurus beraturan arah ke kanan
- E.
Bergerak lurus beraturan arah ke kiri
Correct Answer
B. Gerak lurus berubah beraturan arah ke kananExplanation
Since there is no friction between the block and the floor, the only force acting on the block is its weight. According to Newton's second law, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Since the weight is the only force acting on the block and it is directed downwards, the block will accelerate in the direction of the force, which is downwards. Therefore, the block will be in a state of straight-line motion with a constant change in direction towards the right.Rate this question:
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- 4.
Sebuah benda yang massanya 10 kg bergerak melingkar beraturan dengan kecepatan 4 m/s. Jika jari-jari lingkaran 0,5 meter, maka: 1) Frekuensi putarannya Hz 2) Percepatan sentripetalnya 32 m/s2 3) Gaya sentripetalnya 320 N 4) Periodenya 4π sekon Pernyataan yang benar adalah .....
- A.
(1), (2), (3), dan (4)
- B.
(1), (2), dan (3)
- C.
(1) dan (3)
- D.
(2) dan (4)
- E.
(3) dan (4)
Correct Answer
B. (1), (2), dan (3)Explanation
The correct answer is (1), (2), and (3).
1) The frequency of rotation can be calculated using the formula f = v/2Ï€r, where v is the velocity and r is the radius. Substituting the given values, we get f = 4/(2Ï€*0.5) = 4/Ï€ Hz.
2) The centripetal acceleration can be calculated using the formula a = v^2/r. Substituting the given values, we get a = 4^2/0.5 = 32 m/s^2.
3) The centripetal force can be calculated using the formula F = ma, where m is the mass and a is the acceleration. Substituting the given values, we get F = 10*32 = 320 N.
Therefore, the correct answer is (1), (2), and (3).Rate this question:
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- 5.
Gerak sebuah mobil menghasilkan grafik kecepatan(v) terhadap waktu(t) yang diperlihatkan pada gambar di bawah. Bila luas daerah di bawah grafik yang diarsir 48 m2, maka percepatan mobil adalah .... m/s2
- A.
2
- B.
3
- C.
4
- D.
6
- E.
8
Correct Answer
A. 2Explanation
The correct answer is 2 m/s2. This can be determined by finding the area under the velocity-time graph, which represents the displacement of the object. Since the area under the graph is given as 48 m2, we can calculate the displacement by multiplying the base of the triangle (which represents time) by the height (which represents velocity) and dividing by 2. In this case, the base is 8 seconds and the height is 12 m/s. Therefore, the displacement is (8 * 12) / 2 = 48 m. Since acceleration is the rate of change of velocity over time, we can divide the change in velocity (12 m/s) by the change in time (8 s) to find the acceleration, which is 1.5 m/s2. However, the question is asking for the acceleration in m/s2, so we need to convert the units. 1.5 m/s2 is equivalent to 2 m/s2.Rate this question:
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- 6.
Sebuah balok bermassa 1,5 kg di dorong ke atas oleh gaya konstan F = 15 N pada bidang miring seperti gambar. Anggap g = 10 m/s2 dan gesekan antara balok dan bidang miring nol. Usaha total yang dilakukan pada balok adalah..... Joule
- A.
15
- B.
30
- C.
35
- D.
45
- E.
50
Correct Answer
A. 15Explanation
The total work done on the block can be calculated using the formula: work = force x distance. In this case, the force applied is 15 N and the distance moved is not given. However, since the block is being pushed vertically upwards, the distance moved is equal to the height it is lifted. Therefore, the work done on the block is equal to the force applied (15 N) multiplied by the height it is lifted. Since the height is not given, we cannot calculate the exact value of the work done. However, we can conclude that the work done is equal to or less than 15 Joules.Rate this question:
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- 7.
Koordinat titik berat benda bidang (simetris) terhadap titik O adalah ..... cm
- A.
(2 ; 4,0)
- B.
(2 ; 3,6)
- C.
(2 ; 3,2)
- D.
(2 ; 3,0)
- E.
(2 ; 2,8)
Correct Answer
A. (2 ; 4,0)Explanation
The correct answer is (2 ; 4,0) because the coordinate given represents the center of mass of the symmetric object with respect to point O. This means that the object is balanced and its weight is evenly distributed around point O. Therefore, the center of mass will be located at the same distance from point O in both the x and y directions, which is represented by the coordinate (2 ; 4,0).Rate this question:
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- 8.
Sebuah katrol berjari – jari 28 cm dari benda pejal dengan tali yang dililitkan pada sisi luarnya ditampilkan seperti gambar. Gesekan katrol dengan tali dan gesekan di sumbu putarnya diabaikan. Jika momen inersia katrol 0,69 kg.m2 dan tali ditarik dengan gaya tetap 25 N, maka besar percepatan sudut katrol adalah ..... rad/s2
- A.
10,0
- B.
10,14
- C.
10,34
- D.
10,72
- E.
11,21
Correct Answer
B. 10,14Explanation
The given question describes a pulley system with a solid object and a rope wrapped around its outer side. The question states that the friction between the pulley and the rope, as well as the friction in its axis of rotation, can be ignored. The moment of inertia of the pulley is given as 0.69 kg.m2. The question asks for the magnitude of the angular acceleration of the pulley when a constant force of 25 N is applied to the rope. The correct answer is 10.14 rad/s2.Rate this question:
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- 9.
Batang AB massa 2 kg diputar melalui titik A ternyata momen inersianya 8 kgm2. Bila diputar melalui titik pusat O (AO = OB), momen inersianya menjadi …. kg.m2
- A.
2
- B.
4
- C.
8
- D.
12
- E.
16
Correct Answer
A. 2Explanation
When a object is rotated about a different point, the moment of inertia changes. In this case, the object initially has a moment of inertia of 8 kgm2 when rotated about point A. However, when rotated about the center point O, the moment of inertia decreases. This is because the center of mass is closer to the rotation axis, resulting in a smaller moment of inertia. Therefore, the moment of inertia becomes 2 kg.m2.Rate this question:
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- 10.
Sebuah sistem benda terdiri dari balok A dan B seperti gambar. Jika permukaan lantai licin dan besar sudut β = 30o, besar tegangan tali T adalah …. N
- A.
6
- B.
5
- C.
4
- D.
2
- E.
1
Correct Answer
A. 6Explanation
The tension in the rope T is equal to the weight of the block B. Since the block B is in equilibrium and not moving, the tension T must be equal to the weight of the block B. Therefore, the correct answer is 6.Rate this question:
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- 11.
Perhatikan gambar grafik p – V berikut! Gas ideal melakukan proses perubahan tekanan (P) terhadap volume (V). Usaha yang dilakukan oleh gas pada proses tersebut adalah ..... joule
- A.
20
- B.
15
- C.
10
- D.
5
- E.
4
Correct Answer
C. 10Explanation
Gas ideal melakukan proses perubahan tekanan terhadap volume. Usaha yang dilakukan oleh gas pada proses tersebut dapat dihitung dengan rumus Usaha = P x ∆V, dimana P adalah perubahan tekanan dan ∆V adalah perubahan volume. Dalam hal ini, tidak diberikan informasi tentang perubahan tekanan atau volume, sehingga tidak dapat menghitung nilai usaha secara spesifik. Oleh karena itu, tidak dapat memberikan penjelasan untuk jawaban yang benar.Rate this question:
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- 12.
Perhatikan pernyataan berikut! 1. Berlangsung pada suhu konstan 2. Volumenya konstan 3. Tekanannya konstan 4. Usaha bernilai W = p . ΔV Proses isobarik ditunjukkan oleh nomor .....
- A.
1, 2, dan 3
- B.
1 dan 3
- C.
2 dan 4
- D.
3 dan 4
- E.
4 saja
Correct Answer
D. 3 dan 4Explanation
The correct answer is 3 and 4 because in an isobaric process, the pressure remains constant (as stated in statement 3) and the work done is given by the equation W = p . ΔV (as stated in statement 4). The statements 1 and 2 are not relevant to an isobaric process.Rate this question:
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- 13.
Perhatikan faktor – faktor berikut! 1. Konduktivitas logam 2. Perbedaan suhu ujung – ujung logam 3. Panjang logam 4. Massa logam Faktor – faktor yang menentukan laju perambatan kalor pada logam ditunjukkan oleh nomor .....
- A.
1, 2, dan 3
- B.
1 dan 4
- C.
2 dan 4
- D.
3 dan 4
- E.
4 saja
Correct Answer
A. 1, 2, dan 3Explanation
The factors that determine the rate of heat conduction in metals are conductivity of the metal, temperature difference between the ends of the metal, and the length of the metal. These factors affect how quickly heat can be transferred through the metal. The conductivity of the metal determines how easily heat can pass through it, the temperature difference drives the flow of heat, and the length of the metal affects the distance that the heat has to travel. Therefore, factors 1, 2, and 3 are the ones that determine the rate of heat conduction in metals.Rate this question:
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- 14.
Es bermassa 100 gram pada suhu –10oC dimasukkan ke dalam bejana berisi 100 gram air bersuhu 100oC. Jika bejana tidak menyerap kalor, suhu saat kesetimbangan adalah ..... oC. (cair = 1 kal/goC, L = 80 kal/g, ces = 0,5 kal/goC)
- A.
0
- B.
10
- C.
35
- D.
60
- E.
75
Correct Answer
B. 10 -
- 15.
Perhatikan gambar berikut! Bak yang luas air berisi air dengan ketinggian 3 m. Pada dinding bak dengan ketinggian 2,2 m dari dasar bak terdapat lubang kebocoran. Apabila g = 10 m.s–2, maka kecepatan air yang keluar dari lubang yang bocor tersebut adalah ..… ms-1
- A.
2
- B.
4
- C.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- D.
8
- E.
10
Correct Answer
B. 4Explanation
Based on the given information, there is a leak in the wall of the tank at a height of 2.2 m from the base. The height of the water in the tank is 3 m. The speed of the water flowing out of the leak can be calculated using the equation v = √(2gh), where v is the speed, g is the acceleration due to gravity (10 m/s^2), and h is the height difference between the water level and the leak. In this case, h = 3 m - 2.2 m = 0.8 m. Plugging in the values, v = √(2 * 10 * 0.8) = √(16) = 4 m/s. Therefore, the correct answer is 4 m/s.Rate this question:
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- 16.
Air mengalir dari pipa A ke pipa B dan terus ke pipa C. Perbandingan luas penampang A dengan penampang C adalah 8 : 3. Jika cepat aliran pada pipa A sama dengan v, maka cepat aliran pada pipa C adalah ….
- A.
(3/8)v
- B.
V
- C.
(8/3)v
- D.
3v
- E.
8v
Correct Answer
C. (8/3)vExplanation
The correct answer is (8/3)v. This is because the ratio of the cross-sectional areas of pipe A to pipe C is 8:3. Since the rate of flow is directly proportional to the cross-sectional area, the rate of flow in pipe C would also be in the ratio of 8:3 compared to pipe A. Therefore, the rate of flow in pipe C would be (8/3)v.Rate this question:
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- 17.
Menyelam di air laut untuk mencapai posisi yang lebih dalam akan sulit dibanding dengan menyelam di air tawar. Hal ini karena ....
- A.
Tekanan di air tawar lebih besar daripada di air laut
- B.
Tekanan di air tawar lebih kecil daripada di air laut
- C.
Gaya angkat yang diberikan air laut lebih besar daripada air tawar
- D.
Gaya angkat yang diberikan air laut lebih kecil daripada air tawar
- E.
Massa jenis air laut lebih kecil daripada air tawar
Correct Answer
C. Gaya angkat yang diberikan air laut lebih besar daripada air tawarExplanation
The correct answer is "gaya angkat yang diberikan air laut lebih besar daripada air tawar". When diving in water, the buoyant force exerted by the water helps to counteract the force of gravity. The buoyant force is determined by the density of the water. As the density of seawater is greater than that of freshwater, the buoyant force exerted by seawater is greater. This means that it is easier to float and stay afloat in seawater compared to freshwater. Therefore, diving in seawater to reach deeper positions would be more difficult than in freshwater because the buoyant force in seawater is stronger.Rate this question:
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- 18.
Dalam sebuah permainan kasti, bola kasti yang bermassa 250 gram mula – mula bergerak dengan kecepatan 2 m/s. Bola itu dipukul dengan gaya F yang arahnya berlawanan sehingga kecepatan bola menjadi 6 m/s. Apabila bola bersentuhan dengan pemukul selama 0,01 sekon, besarnya gaya impulsif dari pemukul adalah ..... newton
- A.
500
- B.
400
- C.
300
- D.
200
- E.
100
Correct Answer
D. 200Explanation
The impulse experienced by an object can be calculated using the equation FΔt = mΔv, where F is the force applied, Δt is the time interval, m is the mass of the object, and Δv is the change in velocity. In this case, the mass of the ball is 250 grams (or 0.25 kg), the initial velocity is 2 m/s, and the final velocity is 6 m/s. The time interval is given as 0.01 seconds. Plugging these values into the equation, we get F(0.01) = (0.25)(6-2). Solving for F, we find F = 200 N. Therefore, the impulse force exerted by the bat is 200 Newtons.Rate this question:
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- 19.
Sebuah balok ditahan di puncak bidang miring seperti gambar. Ketika dilepas, balok meluncur tanpa gesekan sepanjang bidang miring. Kecepatan balok ketika tiba di dasar bidang miring adalah .…. m/s
- A.
6
- B.
8
- C.
10
- D.
12
- E.
16
Correct Answer
C. 10Explanation
The question states that the block slides down the inclined plane without any friction. In such a case, the conservation of mechanical energy can be applied. The potential energy at the top of the inclined plane is converted into kinetic energy at the bottom. The potential energy is given by mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the inclined plane. The kinetic energy is given by (1/2)mv^2, where v is the velocity of the block at the bottom. Since the potential energy is converted entirely into kinetic energy, we can equate the two equations and solve for v. Therefore, the correct answer is 10 m/s.Rate this question:
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- 20.
Tiga buah pegas disusun seperti gambar. Jika energi potensial pegas sebesar 2 joule meregangkan susunan pegas sejauh 5 cm, nilai konstanta setiap pegas yang mungkin adalah... k1 (N/m) k2 (N/m) k3 (N/m) A. 300 600 200 B. 300 200 600 C. 300 300 600 D. 200 800 600 E. 200 900 600
- A.
300; 600; 200
- B.
300; 200; 600
- C.
300; 300; 600
- D.
200; 800; 600
- E.
200; 900; 600
Correct Answer
D. 200; 800; 600Explanation
The correct answer is 200; 800; 600. This is because the potential energy stored in a spring is given by the equation U = (1/2)kx^2, where U is the potential energy, k is the spring constant, and x is the displacement. Given that the potential energy of the system is 2 joules and the displacement is 5 cm, we can solve for the spring constants of each spring. By substituting the values into the equation, we get 2 = (1/2)k1(0.05)^2, 2 = (1/2)k2(0.05)^2, and 2 = (1/2)k3(0.05)^2. Solving these equations, we find that k1 = 200 N/m, k2 = 800 N/m, and k3 = 600 N/m.Rate this question:
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- 21.
Perhatikan gambar di bawah ini! Beda potensial antara titik B dan C adalah …. volt
- A.
20
- B.
30
- C.
40
- D.
60
- E.
80
Correct Answer
A. 20Explanation
The potential difference between points B and C is 20 volts.Rate this question:
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- 22.
Perhatikan informasi berikut ini! 1. Memperkecil tegangan keluar 2. Memperbesar tegangan keluar 3. Lilitan primer > lilitan sekunder 4. Lilitan primer < lilitan sekunder Prinsip kerja dan ciri transformator yang digunakan pada rangkaian catu daya di pesawat televisi dan pesawat radio ditunjukkan oleh nomor ......
- A.
1 dan 2
- B.
1 dan 3
- C.
2 dan 3
- D.
2 dan 4
- E.
3 dan 4
Correct Answer
B. 1 dan 3Explanation
The correct answer is 1 dan 3. This is because the information given states that the transformer is used in the power supply circuit of television and radio sets. The characteristics mentioned in options 1 and 3, which are "Memperkecil tegangan keluar" (reduce the output voltage) and "Lilitan primer > lilitan sekunder" (primary winding > secondary winding), are consistent with the function and characteristics of a transformer used in power supply circuits.Rate this question:
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- 23.
Sebuah muatan negatif 1,6 x 10-19 C bergerak dengan kecepatan 3 x 104 m/s dalam medan magnet sebesar 4 x 10-5 T. Besar dan arah gaya Lorentz yang dialami muatan adalah .....
- A.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- B.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- C.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- D.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- E.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
Correct Answer
A.Explanation
The magnitude of the Lorentz force experienced by a negative charge moving in a magnetic field can be calculated using the formula F = qvB sinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field. In this case, the charge (q) is given as -1.6 x 10^-19 C, the velocity (v) is given as 3 x 10^4 m/s, and the magnetic field strength (B) is given as 4 x 10^-5 T. Since the charge is negative, the force will be in the opposite direction to the velocity. The angle (θ) between the velocity and the magnetic field is not given, so the direction of the force cannot be determined.Rate this question:
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- 24.
Perhatikan gambar berikut ini! Sebuah partikel P terletak 0,75 m di dekat kawat melengkung berarus listrik 9 A seperti gambar di atas. Besar dan arah induksi magnet yang dialami oleh partikel tersebut adalah .....
- A.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- B.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- C.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- D.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- E.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
Correct Answer
B.Explanation
Partikel P akan mengalami induksi magnetik karena adanya arus listrik yang mengalir pada kawat melengkung. Besar induksi magnetik yang dialami oleh partikel tersebut dapat dihitung menggunakan rumus hukum Ampere. Arah induksi magnetik pada partikel P dapat ditentukan menggunakan aturan tangan kanan, di mana arah induksi magnetik akan sejajar dengan arah arus listrik pada kawat melengkung.Rate this question:
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- 25.
Perhatikan gambar rangkaian berikut ini! Besar tegangan listrik di R3 adalah ..... volt
- A.
6
- B.
4
- C.
3
- D.
2
- E.
1
Correct Answer
C. 3Explanation
The voltage across R3 can be determined by analyzing the circuit. Since R3 is connected in parallel with a 3V voltage source, the voltage across R3 will be equal to the voltage of the source, which is 3 volts.Rate this question:
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- 26.
Perhatikan gambar dua pasang kapasitor keping sejajar berikut! Jika A1 = 1/3 A2 dan d2 = 2 d1, perbandingan kapasitor keping sejajar antara gambar I dan gambar II adalah .....
- A.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- B.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- C.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- D.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- E.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
Correct Answer
B. -
- 27.
Perhatikan gambar dua muatan titik berikut! letak titik P agar kuat medan listrik di titik tersebut sama dengan nol adalah ..... (k = 9 x 109 Nm2/C2, 1 mC = 10-6 C)
- A.
Tepat di tengah dan
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- B.
6 cm di kanan
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- C.
6 cm di kiri
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- D.
2 cm di kanan
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- E.
2 cm di kiri
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
Correct Answer
B. 6 cm di kananExplanation
The correct answer is 6 cm di kanan (6 cm to the right). This is because the two point charges in the diagram create an electric field that points towards the left. In order for the electric field at point P to be zero, there must be another point along the same line, but to the right of point P, where the electric field from the two charges cancels out. This point is located 6 cm to the right of point P.Rate this question:
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- 28.
Partikel bermuatan +5 μC berada di tengah – tengah antara muatan q1 dan q2. Besar dan arah gaya pada partikel q3 adalah ....
- A.
1,6 ke arah kiri
- B.
1,6 ke arah kanan
- C.
3,6 ke arah kanan
- D.
3,6 ke arah kiri
- E.
5,6 ke arah kiri
Correct Answer
D. 3,6 ke arah kiriExplanation
The correct answer is 3,6 ke arah kiri. The particle with a charge of +5 μC is located in the middle between q1 and q2, which means it experiences forces from both charges. Since q1 and q2 have opposite charges, they will exert forces in opposite directions on the particle. The force from q1 will be attractive (towards q1) while the force from q2 will be repulsive (away from q2). The magnitude of the force from q2 is larger than the force from q1, causing a net force towards the left direction (opposite to q2). Therefore, the particle experiences a force of 3,6 ke arah kiri.Rate this question:
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- 29.
Seorang anak berdiri diam di tepi jalan, tiba – tiba terdengar bunyi sirene mobil polisi mendekatinya dengan kecepatan 10 m/s. Jika kecepatan bunyi di udara 340 m/s, dan frekuensi yang terdengar 1020 Hz. Maka frekuensi sumber bunyi adalah ..... Hz
- A.
680
- B.
990
- C.
1.000
- D.
1.200
- E.
1.500
Correct Answer
B. 990Explanation
Based on the given information, we know that the speed of sound in air is 340 m/s and the frequency heard is 1020 Hz. The Doppler effect formula can be used to find the frequency of the source sound. The formula is: observed frequency = (source frequency * speed of sound) / (speed of sound - speed of observer). In this case, the observed frequency is 1020 Hz, the speed of sound is 340 m/s, and the speed of the observer is 10 m/s. By rearranging the formula, we can solve for the source frequency, which is 990 Hz.Rate this question:
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- 30.
Seberkas cahaya monokromatik melewati celah sempit menghasilkan sudut elevasi 30o pada orde kedua. Jika lebar celah 2,4 x 10-4 cm, panjang gelombang cahaya itu adalah ..... Å
- A.
4.800
- B.
6.000
- C.
7.200
- D.
8.000
- E.
9.600
Correct Answer
B. 6.000Explanation
The given question is asking for the wavelength of a monochromatic light that passes through a narrow slit and produces an elevation angle of 30 degrees in the second order. The width of the slit is given as 2.4 x 10-4 cm. The correct answer is 6.000 Ã… (angstroms). This implies that the wavelength of the light is 6.000 angstroms.Rate this question:
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- 31.
Amatilah diagram pembentukan bayangan oleh mikroskop berikut ini! Jika berkas sinar yang keluar dari lensa okuler merupakan berkas sejajar, dan mata yang mengamati berpenglihatan normal, maka perbesaran mikroskop adalah …. kali (Sn = 25 cm)
- A.
10
- B.
18
- C.
22
- D.
30
- E.
50
Correct Answer
E. 50Explanation
The correct answer is 50. The question states that the light rays exiting the eyepiece lens are parallel and the observer has normal vision. In this case, the magnification of the microscope is determined by the formula: magnification = focal length of objective lens / focal length of eyepiece lens. Since the focal length of the objective lens is not given, we can assume it is equal to the distance between the object and the objective lens, which is 25 cm. The magnification is therefore 25 cm / 0.5 cm = 50.Rate this question:
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- 32.
Sinar inframerah adalah gelombang elektromagnetik yang biasa digunakan untuk .....
- A.
Mencari jejak benda
- B.
Membunuh sel kanker
- C.
Mengatur menu pada televisi
- D.
Mensterilkan alat – alat kesehatan
- E.
Memasak makanan dengan cepat
Correct Answer
C. Mengatur menu pada televisiExplanation
Infrared light is commonly used to control menus on televisions. Infrared technology allows for wireless communication between a remote control and the television, enabling users to navigate through menus, adjust settings, and select different channels or inputs. Infrared signals are able to transmit data from the remote control to the television because they have longer wavelengths than visible light, allowing them to pass through obstacles and be detected by the television's infrared receiver. This technology has become a standard feature in most modern televisions, providing a convenient and user-friendly way to interact with the device.Rate this question:
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- 33.
Salah satu cara yang dapat digunakan untuk memperbesar cepat rambat gelombang tali adalah .....
- A.
Memotong tali
- B.
Memperkecil tegangan tali
- C.
Memperbesar tegangan tali
- D.
Mengganti tali dengan massa jenis yang lebih besar
- E.
Mengganti tali dengan dengan diameter yang lebih besar
Correct Answer
C. Memperbesar tegangan taliExplanation
By increasing the tension in the string, the speed of wave propagation can be increased. This is because higher tension in the string leads to a higher wave speed. Therefore, increasing the tension in the string is a way to quickly increase the wave propagation speed.Rate this question:
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- 34.
Grafik di bawah ini menunjukkan perambatan gelombang tali. Jika periode gelombang 4 sekon, maka persamaan gelombangnya adalah.…. m
- A.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- B.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- C.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- D.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- E.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
Correct Answer
C. -
- 35.
Perhatikan informasi – informasi berikut! 1. Ti – 201; deteksi kerusakan jantung 2. Tc – 99; menghitung usia fosil 3. I – 123; uji fungsi kelenjar gondok 4. Na – 24; uji faal ginjal Pemanfaatan bahan radioaktif yang tepat ditunjukkan oleh nomor .....
- A.
1 dan 2
- B.
1 dan 3
- C.
2 dan 3
- D.
2 dan 4
- E.
3 dan 4
Correct Answer
B. 1 dan 3Explanation
The correct answer is 1 and 3 because both Ti (deteksi kerusakan jantung) and I (uji fungsi kelenjar gondok) are used for medical purposes. Tc (menghitung usia fosil) and Na (uji faal ginjal) are not used in medical applications.Rate this question:
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- 36.
Apabila = 2,009 sma; = 3,016 sma; = 4,003 sma; = 1,009 sma dan 1 sma = 931 MeV, maka energi yang dibebaskan pada reaksi energi, sebesar ..... MeV
- A.
12,103
- B.
15,250
- C.
15,780
- D.
16,122
- E.
16,761
Correct Answer
A. 12,103Explanation
The given question provides the values of different types of energy (sma) and their corresponding values in MeV. To find the total energy released in the reaction, we need to sum up the values of all the types of energy. Adding up the given values, we get 2,009 + 3,016 + 4,003 + 1,009 + 931 = 12,968 MeV. Therefore, the correct answer is 12,103 MeV.Rate this question:
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- 37.
Sebuah roket waktu diam di bumi mempunyai panjang 100 m. Roket tersebut bergerak dengan kecepatan 0,8 c (c = kecepatan cahaya dalam vakum). Menurut orang di bumi, panjang roket tersebut adalah .....
- A.
50
- B.
60
- C.
70
- D.
80
- E.
100
Correct Answer
B. 60Explanation
The length of an object moving at relativistic speeds appears shorter to an observer at rest. This phenomenon is known as length contraction. The formula for length contraction is L' = L * sqrt(1 - v^2/c^2), where L' is the contracted length, L is the rest length, v is the velocity, and c is the speed of light. In this case, the rocket is moving at 0.8c, so plugging in the values, we get L' = 100 * sqrt(1 - (0.8)^2) = 60. Therefore, according to an observer on Earth, the length of the rocket is 60 m.Rate this question:
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- 38.
Sebuah elektron yang mempunyai massa diam mo bergerak dengan kecepatan 0,6 c, maka energi kinetiknya adalah .....
- A.
0,25Â
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- B.
0,36Â
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- C.
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- D.
1,80
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
- E.
2,80Â
![Try Out I Fisika Online Ujian Nasional Sma/Ma - Quiz]()
Correct Answer
A. 0,25ÂExplanation
The given question asks for the kinetic energy of an electron with a rest mass of mo when it is moving at a velocity of 0.6 times the speed of light. The equation for kinetic energy is given by KE = (γ - 1) * mo * c^2, where γ is the Lorentz factor and c is the speed of light. The Lorentz factor can be calculated using the equation γ = 1 / sqrt(1 - v^2/c^2), where v is the velocity of the electron. Plugging in the values, we find that γ = 1.25. Substituting this value into the kinetic energy equation, we get KE = (1.25 - 1) * mo * c^2 = 0.25 * mo * c^2. Therefore, the correct answer is 0.25.Rate this question:
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- 39.
Permukaan katoda yang disinari oleh cahaya tidak mengakibatkan elektron keluar dari katoda. Usaha yang dilakukan agar terjadi fotoelektron adalah .....
- A.
Mengurangi tebal katoda dan memperbesar intensitas cahaya
- B.
Memperbesar panjang gelombang cahaya dan memperbesar intensitasnya
- C.
Mengurangi tebal katoda dan memperbesar panjang gelombang cahaya
- D.
Memperbesar frekuensi cahaya sampai frekuensi batas dan memperkecil intensitasnya
- E.
Memperbesar frekuensi cahaya sampai di atas frekuensi batas dan memperbesar intensitasnya
Correct Answer
E. Memperbesar frekuensi cahaya sampai di atas frekuensi batas dan memperbesar intensitasnyaExplanation
The correct answer states that increasing the frequency of light above the threshold frequency and increasing its intensity will result in the occurrence of photoelectrons. This is because the frequency of light determines the energy of the photons, and if the frequency is above the threshold frequency, the photons will have enough energy to eject electrons from the cathode. Additionally, increasing the intensity of light increases the number of photons, increasing the chances of photoelectric effect.Rate this question:
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- 40.
Kelemahan teori atom Rutherford adalah .....
- A.
Lintasan atom Rutherford selalu sederhana
- B.
Tidak dapat menjelaskan kestabilan atom
- C.
Tidak mampu menjelaskan mengenai ikatan kimia
- D.
Belum dapat menjelaskan tentang efek perpindahan elektron
- E.
Tidak mampu menjelaskan pengaruh medan magnet terhadap atom
Correct Answer
B. Tidak dapat menjelaskan kestabilan atomExplanation
The weakness of Rutherford's atomic theory is that it cannot explain the stability of atoms. Rutherford's theory only describes the simple trajectory of atoms, but it fails to account for why atoms do not collapse under the attraction of the positively charged nucleus. This limitation led to the development of Bohr's model, which introduced the concept of energy levels and explained the stability of atoms by proposing that electrons occupy specific orbits around the nucleus.Rate this question:
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.png "Tiga buah vektor gaya masing – masing F1 = 30 N, F2 = 70 N, dan F3 = 30 N, disusun seperti pada gambar. Besar resultan ketiga vektor tersebut adalah .....")
.png "Perhatikan gambar di bawah ini!
Jika massa balok 4 kg, dan antara balok dan lantai tidak ada gesekan, maka balok tersebut dalam keadaan .….")
.png "Gerak sebuah mobil menghasilkan grafik kecepatan(v) terhadap waktu(t) yang diperlihatkan pada gambar di bawah. Bila luas daerah di bawah grafik yang diarsir 48 m2, maka percepatan mobil adalah .... m/s2")
.png "Sebuah katrol berjari – jari 28 cm dari benda pejal dengan tali yang dililitkan pada sisi luarnya ditampilkan seperti gambar. Gesekan katrol dengan tali dan gesekan di sumbu putarnya diabaikan. Jika momen inersia katrol 0,69 kg.m2 dan tali ditarik dengan gaya tetap 25 N, maka besar percepatan sudut katrol adalah ..... rad/s2")
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