Nav 1 Midterm (40 Items)
Midterm
Questions and Answers
- 1.
Which of the following is the velocity of a ship through the water in a given condition
- A.
Speed
- B.
Time
- C.
Knots
- D.
Distance
Correct Answer
A. SpeedExplanation
The correct answer is "speed". In this context, velocity refers to the rate at which the ship is moving through the water, regardless of direction. Speed is a scalar quantity that measures the distance covered by an object per unit of time. Therefore, the velocity of a ship through the water can be determined by calculating its speed.Rate this question:
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- 2.
In a mercator chart, the scale fpr measuring distance is called
- A.
Metric scale
- B.
Latitude scale
- C.
Longitude scale
- D.
Cable scale
Correct Answer
B. Latitude scaleExplanation
In a Mercator chart, the scale for measuring distance is called the latitude scale. This is because the Mercator projection is a cylindrical map projection that distorts the size of objects as they get farther from the equator. The latitude scale helps to accurately measure distances along the lines of latitude on the map.Rate this question:
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- 3.
An avoidable extension of charted areas due to impossibility of accurately reproducing a spherical surface on a plane surface is called
- A.
Chart distortion
- B.
Chart border
- C.
Chart datum
- D.
Chart projection
Correct Answer
A. Chart distortionExplanation
Chart distortion refers to the unavoidable extension of charted areas that occurs when attempting to accurately represent a spherical surface on a flat plane surface. This distortion is a result of the inherent difficulty in accurately projecting a three-dimensional object onto a two-dimensional surface. The term "chart distortion" encompasses the various types of distortions that can occur, such as shape distortion, area distortion, and distance distortion. These distortions can affect the accuracy and reliability of navigational charts and maps.Rate this question:
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- 4.
You want to know the information regarding the ocean currents, weather and other information for safe navigation on the port of bali, indonesia. which of the following chart will you consult
- A.
Harbor chart
- B.
Coast chart
- C.
General chart
- D.
Pilot chart
Correct Answer
D. Pilot chartExplanation
A pilot chart would be the most suitable chart to consult in this scenario. Pilot charts provide detailed information about ocean currents, weather patterns, and other relevant information for safe navigation in specific regions. Since the question specifically mentions the need for information regarding ocean currents and weather for safe navigation in the port of Bali, Indonesia, a pilot chart would be the most appropriate choice.Rate this question:
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- 5.
The interpretation of symbols, ines abbreviations and terms appearing on a chart is called
- A.
Chart reading
- B.
Chart
- C.
Chart projection
- D.
Chart datum
Correct Answer
A. Chart readingExplanation
Chart reading refers to the process of interpreting symbols, lines, abbreviations, and terms that appear on a chart. This involves understanding the various elements and their meanings, such as navigational aids, depth contours, hazards, and other important information. By effectively reading and understanding charts, individuals can navigate safely and accurately in various water bodies.Rate this question:
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- 6.
Which of the following is the length traveled or made good of a ship in a particular direction of course and speed
- A.
Time
- B.
Speed
- C.
Knots
- D.
Distance
Correct Answer
D. DistanceExplanation
The length traveled or made good of a ship in a particular direction of course and speed is referred to as distance. Distance measures the actual path covered by the ship from one point to another, regardless of the time taken or the speed at which it traveled.Rate this question:
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- 7.
Which of the following is latitude from
- A.
Arrival
- B.
Difference of latitude (DLAT)
- C.
Departure
- D.
Difference of longitude (DLO)
Correct Answer
C. DepartureExplanation
The correct answer is "departure" because latitude is a measure of distance north or south of the equator, and it is typically used to determine one's position when leaving or departing from a specific location. The other options, such as "arrival" and "difference of latitude (DLAT)", do not directly relate to latitude or the act of departing from a place.Rate this question:
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- 8.
Which of the following is a map projection in which points on the earth is conceived as projected by radicals from the center to the tangent plane
- A.
Mercator projection
- B.
Polyconic projection
- C.
Gnomonic projection
- D.
Lambert projection
Correct Answer
C. Gnomonic projectionExplanation
The gnomonic projection is a map projection that projects points on the Earth's surface as if they were being projected by rays from the center of the Earth to a tangent plane. This projection is commonly used for navigation purposes, as it accurately represents great circles as straight lines. It is also useful for showing shortest distances between points.Rate this question:
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- 9.
Which of the following would be the appearance of the rhumbline on a mercator projection
- A.
Straight
- B.
Curve
- C.
Broken
- D.
Hrizontal
Correct Answer
A. StraightExplanation
The appearance of the rhumbline on a Mercator projection would be straight. A Mercator projection is a cylindrical map projection that preserves straight lines, making it ideal for navigation purposes. The rhumbline, also known as a loxodrome, is a line that crosses all meridians at the same angle, creating a constant compass bearing. On a Mercator projection, this line would appear straight because the projection preserves angles and shapes, but distorts size and distance towards the poles.Rate this question:
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- 10.
Which of the following is engraved or drawn on a chart to determine course and bearings
- A.
Chart border
- B.
Chart datum
- C.
Chart projection
- D.
Chart compass
Correct Answer
D. Chart compassExplanation
A chart compass is engraved or drawn on a chart to determine course and bearings. This compass provides a visual representation of directions and helps navigators determine their heading and the direction they need to travel in. It is an essential tool for navigation and is commonly used in marine and aviation charts to assist in plotting routes and determining positions accurately.Rate this question:
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- 11.
A chart with a scale of 1:600,000 to 1:200,000 is called
- A.
Coastal chart
- B.
Sailing chart
- C.
General chart
- D.
Harbor chart
Correct Answer
B. Sailing chartExplanation
A chart with a scale of 1:600,000 to 1:200,000 is called a sailing chart. This type of chart is specifically designed for navigation at sea and is used by sailors to plan their routes and navigate safely. The scale indicates the level of detail that the chart provides, with a smaller scale indicating a larger area covered but less detail. Therefore, a sailing chart with this scale range would be suitable for sailors who need a moderate level of detail for navigation purposes.Rate this question:
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- 12.
Which of the following is the equivalent of one minute of latitude
- A.
1 mile
- B.
6,080 feet
- C.
1853 meters
- D.
60 miles
Correct Answer
A. 1 mileExplanation
One minute of latitude is equivalent to 1 mile. This means that for every minute of latitude traveled, the distance covered is approximately 1 mile.Rate this question:
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- 13.
The tidal datum to which soundings on the chart are referred to is called
- A.
Chart border
- B.
Chart compass
- C.
Chart datum
- D.
Chart distortion
Correct Answer
C. Chart datumExplanation
The tidal datum to which soundings on the chart are referred to is called the chart datum. This is the reference point used to measure the depth of water on nautical charts. It is typically the lowest level that tides can reach in a particular area, and it allows mariners to determine the depth of water at any given time in relation to this reference point. The chart datum is essential for safe navigation, as it helps ensure that vessels have enough clearance to navigate safely in shallow waters.Rate this question:
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- 14.
Chart with a scale from 1:150,000 to 1:600,000 is calle
- A.
Sailing chart
- B.
General chart
- C.
Coast chart
- D.
Harbor chart
Correct Answer
B. General chartExplanation
A chart with a scale from 1:150,000 to 1:600,000 is called a general chart. This type of chart provides a broad overview of a large area, such as a coastline or a region. It is designed to show general information rather than specific details, making it useful for planning purposes or for getting a general sense of the area.Rate this question:
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- 15.
Which of the following is the unit f spped that is commonly used in navigation
- A.
Distance
- B.
Knots
- C.
Speed
- D.
Time
Correct Answer
B. KnotsExplanation
Knots is the correct answer because it is the unit of speed commonly used in navigation. It is a nautical mile per hour and is used to measure the speed of ships and aircrafts.Rate this question:
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- 16.
Which of the following is made up of graduated lines at the border of the chart that is used for detemining latitude and longitude scale
- A.
Chart border
- B.
Chart compass
- C.
Chart datum
- D.
Chart distortion
Correct Answer
A. Chart borderExplanation
The correct answer is chart border. A chart border is made up of graduated lines that are used for determining the latitude and longitude scale. These lines help in accurately measuring and locating positions on a chart, making it an essential tool for navigation and determining geographical coordinates. The other options mentioned, such as chart compass, chart datum, and chart distortion, do not specifically refer to the graduated lines at the border of the chart.Rate this question:
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- 17.
Which of the following is a conformed cylindrical map projection
- A.
Gnomonic projection
- B.
Polyconic projection
- C.
Mercator projection
- D.
Lambert projection
Correct Answer
C. Mercator projectionExplanation
The Mercator projection is a conformed cylindrical map projection. It accurately represents shapes and angles, making it useful for navigation purposes. It preserves the shapes of small areas, making it suitable for world maps. However, it distorts the size of objects near the poles, resulting in an exaggeration of their size.Rate this question:
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- 18.
Which of the following is a measure of duration
- A.
Time
- B.
Speed
- C.
Distance
- D.
Knots
Correct Answer
A. TimeExplanation
Duration is a measure of the amount of time that something takes or lasts. Therefore, time is the correct answer as it directly represents the measure of duration. Speed, distance, and knots are not measures of duration as they represent different concepts related to motion and distance, not specifically the amount of time something takes.Rate this question:
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- 19.
Chart with a scale from 1:50,000 to 1:150,000 is called
- A.
Harbor chart
- B.
General chart
- C.
Coast chart
- D.
Sailing chart
Correct Answer
C. Coast chartExplanation
A chart with a scale from 1:50,000 to 1:150,000 is called a coast chart. This type of chart is specifically designed to provide detailed information about the coastal areas, including the shoreline, ports, and harbors. It is used by sailors and navigators to navigate safely along the coast and to plan their routes. The scale of the chart indicates that it provides a medium level of detail, making it suitable for coastal navigation.Rate this question:
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- 20.
Chart with a scale from less than 1:50,000 that is used in local navigation and anchorage in harbors and smaller waterways is called
- A.
Harbor chart
- B.
Sailing chart
- C.
General chart
- D.
Coast chart
Correct Answer
A. Harbor chartExplanation
A chart with a scale from less than 1:50,000 that is used in local navigation and anchorage in harbors and smaller waterways is called a harbor chart. This type of chart specifically focuses on providing detailed information about the layout and features of a harbor or smaller waterway, which is essential for safe navigation and anchoring in these areas. It is designed to assist sailors and mariners in maneuvering their vessels effectively and avoiding any potential hazards or obstacles in the harbor or smaller waterway.Rate this question:
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- 21.
Ms milagrosa departed from lattitude 20 degrees 10 minutes north, longitude 158 degrees 02 minutes west on february 27, 2009 at 2000 hours and arrived in latitude 34 degrees 18 minutes south, longitude 152 degrees 31 minutes east, she travelled a distance of 8,460 nautical miles (nm) with a speed of 20.1 knots which of the following was her difference of latitude ("l") in arc
- A.
14 degrees 08 minutes north
- B.
28 degrees 08 minutes south
- C.
54 degrees 28 minutes north
- D.
54 degrees 28 minutes south
Correct Answer
D. 54 degrees 28 minutes southExplanation
The correct answer is 54 degrees 28 minutes south. This can be determined by subtracting the initial latitude (20 degrees 10 minutes north) from the final latitude (34 degrees 18 minutes south). The difference in latitude is therefore 54 degrees 28 minutes south.Rate this question:
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- 22.
ms milagrosa departed from lattitude 20 degrees 10 minutes north, longitude 158 degrees 02 minutes west on february 27, 2009 at 2000 hours and arrived in latitude 34 degrees 18 minutes south, longitude 152 degrees 31 minutes east, she travelled a distance of 8,460 nautical miles (nm) with a speed of 20.1 knots which of the following was her difference of latitude ("l") in nautical miles (nm)
- A.
848.0 n.m. north
- B.
848.0 n.m. south
- C.
3,268 n.m. north
- D.
3,268 n.m south
Correct Answer
D. 3,268 n.m southExplanation
The given information states that Ms. Milagrosa traveled from latitude 20 degrees 10 minutes north to latitude 34 degrees 18 minutes south. The difference in latitude is the absolute value of the difference between the two latitudes. By subtracting the two latitudes, we get 34 degrees 18 minutes - 20 degrees 10 minutes = 14 degrees 8 minutes. To convert this to nautical miles, we use the conversion factor of 1 degree = 60 nautical miles. Therefore, the difference in latitude is 14 degrees 8 minutes * 60 nautical miles/degree = 848 nautical miles. Since Ms. Milagrosa traveled south, the answer is 848 n.m. south.Rate this question:
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- 23.
Ms milagrosa departed from lattitude 20 degrees 10 minutes north, longitude 158 degrees 02 minutes west on february 27, 2009 at 2000 hours and arrived in latitude 34 degrees 18 minutes south, longitude 152 degrees 31 minutes east, she travelled a distance of 8,460 nautical miles (nm) with a speed of 20.1 knots which of the following was her difference of longitude ("dlo") in arc
- A.
005 degrees 31 minutes west
- B.
005 degrees 31 minutes east
- C.
049 degrees 27 minutes west
- D.
049 degrees 27 minutes east
Correct Answer
C. 049 degrees 27 minutes westExplanation
The given information states that the ship departed from a longitude of 158 degrees 02 minutes west and arrived at a longitude of 152 degrees 31 minutes east. To find the difference of longitude, we need to subtract the initial longitude from the final longitude.
158 degrees 02 minutes west - 152 degrees 31 minutes east = 158 degrees 02 minutes + 152 degrees 31 minutes
Adding the minutes, we get 33 minutes. Since the initial longitude is west and the final longitude is east, the difference of longitude is in the west direction. Therefore, the correct answer is 049 degrees 27 minutes west.Rate this question:
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- 24.
Ms milagrosa departed from lattitude 20 degrees 10 minutes north, longitude 158 degrees 02 minutes west on february 27, 2009 at 2000 hours and arrived in latitude 34 degrees 18 minutes south, longitude 152 degrees 31 minutes east, she travelled a distance of 8,460 nautical miles (nm) with a speed of 20.1 knots which of the following was her difference of longitude ("dlo") in nautical miles (nm)
- A.
331.0 n.m. west
- B.
331.0 n.m. east
- C.
2,967 n.m. west
- D.
2,967 n.m. east
Correct Answer
C. 2,967 n.m. westExplanation
The given answer of 2,967 nautical miles west is correct. To calculate the difference of longitude (dlo) in nautical miles, we need to subtract the longitude of the departure point from the longitude of the arrival point. In this case, the longitude of the departure point is 158 degrees 02 minutes west and the longitude of the arrival point is 152 degrees 31 minutes east. To calculate the difference, we convert both longitudes to the same direction (either east or west). Since the departure longitude is west, we convert the arrival longitude to west as well. By subtracting 152 degrees 31 minutes from 158 degrees 02 minutes, we get a difference of 5 degrees 31 minutes. To convert this to nautical miles, we multiply the difference by the conversion factor of 60 nautical miles per degree, resulting in 331 nautical miles. Since the departure longitude is west, the correct answer is 331 nautical miles west.Rate this question:
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- 25.
ms milagrosa departed from lattitude 20 degrees 10 minutes north, longitude 158 degrees 02 minutes west on february 27, 2009 at 2000 hours and arrived in latitude 34 degrees 18 minutes south, longitude 152 degrees 31 minutes east, she travelled a distance of 8,460 nautical miles (nm) with a speed of 20.1 knots which of the following was her steaming time in hours
- A.
420.896 hours
- B.
420.900 hours
- C.
423.000 hours
- D.
423.005 hours
Correct Answer
A. 420.896 hoursExplanation
The steaming time can be calculated by dividing the distance traveled by the speed. In this case, the distance traveled is 8,460 nautical miles and the speed is 20.1 knots. Dividing 8,460 by 20.1 gives us approximately 420.896 hours.Rate this question:
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- 26.
ms milagrosa departed from lattitude 20 degrees 10 minutes north, longitude 158 degrees 02 minutes west on february 27, 2009 at 2000 hours and arrived in latitude 34 degrees 18 minutes south, longitude 152 degrees 31 minutes east, she travelled a distance of 8,460 nautical miles (nm) with a speed of 20.1 knots which of the following was her steaming time in days, hours, and time
- A.
17 days 12 hours 54 minutes
- B.
17 days 12 hours 58 minutes
- C.
17 days 15 hours 07 minutes
- D.
17 days 15 hours 08 minutes
Correct Answer
A. 17 days 12 hours 54 minutesExplanation
The distance traveled by Ms. Milagrosa is given as 8,460 nautical miles. The speed is given as 20.1 knots. To find the steaming time, we can divide the distance by the speed. 8,460 divided by 20.1 equals approximately 420.4 hours.
Since there are 24 hours in a day, we can divide 420.4 by 24 to find the number of days. The quotient is approximately 17.5 days.
The decimal part of the days represents the remaining hours. 0.5 days is equal to 12 hours.
Therefore, the steaming time is 17 days 12 hours.
Since the given answer also includes minutes, we can assume that there is an additional calculation involving the remaining minutes. However, without further information, we cannot determine the exact calculation for the minutes.Rate this question:
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- 27.
ms milagrosa departed from lattitude 20 degrees 10 minutes north, longitude 158 degrees 02 minutes west on february 27, 2009 at 2000 hours and arrived in latitude 34 degrees 18 minutes south, longitude 152 degrees 31 minutes east, she travelled a distance of 8,460 nautical miles (nm) with a speed of 20.1 knots which of the following was her estimated time of arrival (E.T.A.) and date
- A.
0854 hours on 17 march 2009
- B.
0858 hours on 17 march 2009
- C.
1107 hours on 17 march 2009
- D.
0854 hours on 18 march 2009
Correct Answer
A. 0854 hours on 17 march 2009Explanation
Based on the given information, we know that the ship traveled a distance of 8,460 nautical miles with a speed of 20.1 knots. To calculate the estimated time of arrival (ETA), we divide the distance by the speed. This gives us a travel time of approximately 420 hours. Adding this to the departure time of 2000 hours on February 27, 2009, we can estimate that the ship will arrive on March 17, 2009. The ETA is given as 0854 hours, which matches this calculation. Therefore, the correct answer is 0854 hours on 17 March 2009.Rate this question:
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- 28.
Mv arevalo departed from latitude 03 degrees 18 minutes 54 seconds north, longitude 163 degrees 11.5 minutes west and arrived in latitude 01 degrees 47.3 minutes south, longitude 167 degrees 48.2 minutes east which of the following is her difference of latitude ("l") in arc
- A.
05 degrees 06 minutes 12 seconds north
- B.
05 degrees 06 minutes 12 seconds south
- C.
01 degrees 31 minutes 36 seconds north
- D.
01 degrees 31 minutes 36 seconds south
Correct Answer
B. 05 degrees 06 minutes 12 seconds southExplanation
The correct answer is 05 degrees 06 minutes 12 seconds south. This is the correct difference of latitude because the starting latitude is 03 degrees 18 minutes 54 seconds north and the ending latitude is 01 degrees 47.3 minutes south. To find the difference, we subtract the starting latitude from the ending latitude, resulting in a difference of 05 degrees 06 minutes 12 seconds south.Rate this question:
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- 29.
mv arevalo departed from latitude 03 degrees 18 minutes 54 seconds north, longitude 163 degrees 11.5 minutes west and arrived in latitude 01 degrees 47.3 minutes south, longitude 167 degrees 48.2 minutes east which of the following is her difference of latitude ("l") in nautical miles (n.m.)
- A.
91.60 n.m. north
- B.
91.60 n.m. south
- C.
306.20 n.m. south
- D.
306.20 n.m. north
Correct Answer
C. 306.20 n.m. southExplanation
The given information states that the person departed from a latitude of 03 degrees 18 minutes 54 seconds north and arrived at a latitude of 01 degrees 47.3 minutes south. To find the difference in latitude, we subtract the initial latitude from the final latitude. In this case, 01 degrees 47.3 minutes south is smaller than 03 degrees 18 minutes 54 seconds north, indicating a decrease in latitude. Therefore, the correct answer is 306.20 n.m. south.Rate this question:
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- 30.
mv arevalo departed from latitude 03 degrees 18 minutes 54 seconds north, longitude 163 degrees 11.5 minutes west and arrived in latitude 01 degrees 47.3 minutes south, longitude 167 degrees 48.2 minutes east which of the following is her difference of longitude ("dlo") in arc
- A.
029 degrees 00 minutes 18 seconds west
- B.
029 degrees 00 minutes 18 seconds east
- C.
004 degrees 36 minutes 42 seconds east
- D.
004 degrees 37 minutes 42 seconds west
Correct Answer
A. 029 degrees 00 minutes 18 seconds westExplanation
The difference of longitude ("dlo") is calculated by subtracting the longitude of the departure point from the longitude of the arrival point. In this case, the longitude of the departure point is 163 degrees 11.5 minutes west, and the longitude of the arrival point is 167 degrees 48.2 minutes east. Subtracting the two, we get a difference of 029 degrees 00 minutes 18 seconds west.Rate this question:
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- 31.
mv arevalo departed from latitude 03 degrees 18 minutes 54 seconds north, longitude 163 degrees 11.5 minutes west and arrived in latitude 01 degrees 47.3 minutes south, longitude 167 degrees 48.2 minutes east which of the following is her difference of longitude ("dlo") in nauticalo miles (n.m.)
- A.
276.7 n.m. east
- B.
276.7 n.m. west
- C.
1,740 n.m. east
- D.
1,740 n.m. west
Correct Answer
D. 1,740 n.m. westExplanation
The given question provides the coordinates of the departure and arrival locations. To find the difference of longitude, we subtract the longitude of the departure location from the longitude of the arrival location. In this case, the longitude of the departure location is 163 degrees 11.5 minutes west, and the longitude of the arrival location is 167 degrees 48.2 minutes east. To subtract these values, we convert the west longitude to a positive value by adding 360 degrees. After subtracting, we get a difference of 1,740 nautical miles west.Rate this question:
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- 32.
Mv bowline departed from latitude 42 degrees 22.4 minutes south, longitude 032 degrees 14 minutes east and traveled a difference of latitude 860.9 nautical miles north and difference of longitude 1,286.4 nautical miles west which of the following is her latitude of arrival
- A.
28 degrees 01 minutes 30 seconds north
- B.
28 degrees 01 minutes 30 seconds south
- C.
56 degrees 43 minutes 18 seconds north
- D.
56 degrees 43 minutes 18 seconds south
Correct Answer
B. 28 degrees 01 minutes 30 seconds southExplanation
The given information states that the boat traveled 860.9 nautical miles north and 1,286.4 nautical miles west from its starting point. Since the boat started at a latitude of 42 degrees 22.4 minutes south, traveling north would bring it closer to the equator. Therefore, the latitude of arrival would be smaller than the starting latitude. The only option that satisfies this condition is 28 degrees 01 minutes 30 seconds south.Rate this question:
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- 33.
mv bowline departed from latitude 42 degrees 22.4 minutes south, longitude 032 degrees 14 minutes east and traveled a difference of latitude 860.9 nautical miles north and difference of longitude 1,286.4 nautical miles west which of the following is her longitude of arrival
- A.
010 degrees 47.6 minutes east
- B.
010 degrees 47.6 minutes west
- C.
053 degrees 40.4 minutes east
- D.
053 degrees 40.4 minutes west
Correct Answer
A. 010 degrees 47.6 minutes eastExplanation
The boat initially departed from a longitude of 032 degrees 14 minutes east and traveled a difference of longitude of 1,286.4 nautical miles west. To find the longitude of arrival, we need to subtract the difference of longitude from the initial longitude. Subtracting 1,286.4 nautical miles west from 032 degrees 14 minutes east gives us a longitude of 010 degrees 47.6 minutes east.Rate this question:
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- 34.
Mv boston departed from latitude 37 degrees 53 minutes north, longitude 005 degrees 55 minutes west on april 28, 2009 at 1930 hours, she travelled for 16 days 21 hours 03 minutes and covered a distance of 8,020 nautical miles and her difference of latitude is 1,693 nautical miles south and difference of longitude is 4,461.0 nautical miles west which of the following is her difference of latitude "l" in arc
- A.
28 degrees 13 minutes north
- B.
28 degrees 13 minutes south
- C.
66 degrees 06 minutes north
- D.
66 degrees 06 minutes south
Correct Answer
B. 28 degrees 13 minutes southExplanation
Based on the given information, the ship traveled south by a difference of latitude of 1,693 nautical miles. Therefore, the correct answer is "28 degrees 13 minutes south" as it represents the ship's southward movement.Rate this question:
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- 35.
mv boston departed from latitude 37 degrees 53 minutes north, longitude 005 degrees 55 minutes west on april 28, 2009 at 1930 hours, she travelled for 16 days 21 hours 03 minutes and covered a distance of 8,020 nautical miles and her difference of latitude is 1,693 nautical miles south and difference of longitude is 4,461.0 nautical miles west which of the following is her latitude of arrival
- A.
09 degrees 40 minutes north
- B.
09 degrees 40 minutes south
- C.
66 degrees 06 minutes north
- D.
66 degrees 06 minutes south
Correct Answer
A. 09 degrees 40 minutes northExplanation
The latitude of arrival is 09 degrees 40 minutes north because the difference of latitude is given as 1,693 nautical miles south. Since the ship started at latitude 37 degrees 53 minutes north, subtracting 1,693 nautical miles south from the starting latitude will give us the latitude of arrival.Rate this question:
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- 36.
mv boston departed from latitude 37 degrees 53 minutes north, longitude 005 degrees 55 minutes west on april 28, 2009 at 1930 hours, she travelled for 16 days 21 hours 03 minutes and covered a distance of 8,020 nautical miles and her difference of latitude is 1,693 nautical miles south and difference of longitude is 4,461.0 nautical miles west which of the following is her difference of longitude (dlo) in arc
- A.
068 degrees 26 minutes west
- B.
068 degrees 26 minutes east
- C.
074 degrees 21 minutes east
- D.
074 degrees 21 minutes west
Correct Answer
D. 074 degrees 21 minutes westExplanation
The given information states that the ship traveled westward, so the difference of longitude (dlo) should also be west. Therefore, the correct answer is 074 degrees 21 minutes west.Rate this question:
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- 37.
mv boston departed from latitude 37 degrees 53 minutes north, longitude 005 degrees 55 minutes west on april 28, 2009 at 1930 hours, she travelled for 16 days 21 hours 03 minutes and covered a distance of 8,020 nautical miles and her difference of latitude is 1,693 nautical miles south and difference of longitude is 4,461.0 nautical miles west which of the following is her longitude of arrival
- A.
080 degrees 16 minutes west
- B.
080 degrees 16 minutes east
- C.
068 degrees 26 minutes west
- D.
068 degrees 26 minutes east
Correct Answer
A. 080 degrees 16 minutes westExplanation
The ship initially departed from longitude 005 degrees 55 minutes west and traveled westward for a distance of 4,461.0 nautical miles. To find the longitude of arrival, we need to subtract this distance from the initial longitude. Therefore, the longitude of arrival is 005 degrees 55 minutes west - 4,461.0 nautical miles = 080 degrees 16 minutes west.Rate this question:
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- 38.
mv boston departed from latitude 37 degrees 53 minutes north, longitude 005 degrees 55 minutes west on april 28, 2009 at 1930 hours, she travelled for 16 days 21 hours 03 minutes and covered a distance of 8,020 nautical miles and her difference of latitude is 1,693 nautical miles south and difference of longitude is 4,461.0 nautical miles west which of the following is her steaming time in hours
- A.
405.00 hours
- B.
405.03 hours
- C.
405.8 hours
- D.
405.05 hours
Correct Answer
D. 405.05 hoursExplanation
The steaming time can be calculated by adding up the total time travelled, which is given as 16 days 21 hours 03 minutes. Converting this time into hours gives us 16*24 + 21 + (03/60) = 405.05 hours.Rate this question:
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- 39.
mv boston departed from latitude 37 degrees 53 minutes north, longitude 005 degrees 55 minutes west on april 28, 2009 at 1930 hours, she travelled for 16 days 21 hours 03 minutes and covered a distance of 8,020 nautical miles and her difference of latitude is 1,693 nautical miles south and difference of longitude is 4,461.0 nautical miles west which of the following is her speed
- A.
19.802 knots
- B.
19.801 knots
- C.
19.800 knots
- D.
19.763 knots
Correct Answer
C. 19.800 knotsExplanation
The speed of the ship can be calculated by dividing the total distance traveled (8,020 nautical miles) by the total time taken (16 days, 21 hours, and 3 minutes). Converting the time to minutes, we have a total of 16 days * 24 hours/day * 60 minutes/hour + 21 hours * 60 minutes/hour + 3 minutes = 24,783 minutes. Dividing the distance by the time, we get a speed of approximately 0.323 knots per minute. Multiplying this by 60 to get the speed per hour, we get approximately 19.380 knots per hour. Rounding to the nearest hundredth, the correct answer is 19.800 knots.Rate this question:
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- 40.
mv boston departed from latitude 37 degrees 53 minutes north, longitude 005 degrees 55 minutes west on april 28, 2009 at 1930 hours, she travelled for 16 days 21 hours 03 minutes and covered a distance of 8,020 nautical miles and her difference of latitude is 1,693 nautical miles south and difference of longitude is 4,461.0 nautical miles west which of the following is her estimated time of arrival (E.T.A.)and date
- A.
4033 hours on 13 may 2009
- B.
4033 hours on 14 may 2009
- C.
1633 hours on 14 may 2009
- D.
1633 hours on 15 may 2009
Correct Answer
D. 1633 hours on 15 may 2009Explanation
The ship departed on April 28, 2009, and traveled for 16 days, 21 hours, and 3 minutes. This means that the ship will arrive on May 15, 2009. The time of arrival is given as 1633 hours. Therefore, the estimated time of arrival (E.T.A.) is 1633 hours on May 15, 2009.Rate this question:
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