Nav 1 Midterm (40 Items)

Knots is the correct answer because it is the unit of speed commonly used in navigation. It is a nautical mile per hour and is used to measure the speed of ships and aircrafts.

The tidal datum to which soundings on the chart are referred to is called the chart datum. This is the reference point used to measure the depth of water on nautical charts. It is typically the lowest level that tides can reach in a particular area, and it allows mariners to determine the depth of water at any given time in relation to this reference point. The chart datum is essential for safe navigation, as it helps ensure that vessels have enough clearance to navigate safely in shallow waters.

One minute of latitude is equivalent to 1 mile. This means that for every minute of latitude traveled, the distance covered is approximately 1 mile.

Duration is a measure of the amount of time that something takes or lasts. Therefore, time is the correct answer as it directly represents the measure of duration. Speed, distance, and knots are not measures of duration as they represent different concepts related to motion and distance, not specifically the amount of time something takes.

The appearance of the rhumbline on a Mercator projection would be straight. A Mercator projection is a cylindrical map projection that preserves straight lines, making it ideal for navigation purposes. The rhumbline, also known as a loxodrome, is a line that crosses all meridians at the same angle, creating a constant compass bearing. On a Mercator projection, this line would appear straight because the projection preserves angles and shapes, but distorts size and distance towards the poles.

The correct answer is chart border. A chart border is made up of graduated lines that are used for determining the latitude and longitude scale. These lines help in accurately measuring and locating positions on a chart, making it an essential tool for navigation and determining geographical coordinates. The other options mentioned, such as chart compass, chart datum, and chart distortion, do not specifically refer to the graduated lines at the border of the chart.

The correct answer is "speed". In this context, velocity refers to the rate at which the ship is moving through the water, regardless of direction. Speed is a scalar quantity that measures the distance covered by an object per unit of time. Therefore, the velocity of a ship through the water can be determined by calculating its speed.

Chart distortion refers to the unavoidable extension of charted areas that occurs when attempting to accurately represent a spherical surface on a flat plane surface. This distortion is a result of the inherent difficulty in accurately projecting a three-dimensional object onto a two-dimensional surface. The term "chart distortion" encompasses the various types of distortions that can occur, such as shape distortion, area distortion, and distance distortion. These distortions can affect the accuracy and reliability of navigational charts and maps.

The length traveled or made good of a ship in a particular direction of course and speed is referred to as distance. Distance measures the actual path covered by the ship from one point to another, regardless of the time taken or the speed at which it traveled.

Chart reading refers to the process of interpreting symbols, lines, abbreviations, and terms that appear on a chart. This involves understanding the various elements and their meanings, such as navigational aids, depth contours, hazards, and other important information. By effectively reading and understanding charts, individuals can navigate safely and accurately in various water bodies.

The gnomonic projection is a map projection that projects points on the Earth's surface as if they were being projected by rays from the center of the Earth to a tangent plane. This projection is commonly used for navigation purposes, as it accurately represents great circles as straight lines. It is also useful for showing shortest distances between points.

A pilot chart would be the most suitable chart to consult in this scenario. Pilot charts provide detailed information about ocean currents, weather patterns, and other relevant information for safe navigation in specific regions. Since the question specifically mentions the need for information regarding ocean currents and weather for safe navigation in the port of Bali, Indonesia, a pilot chart would be the most appropriate choice.

A chart compass is engraved or drawn on a chart to determine course and bearings. This compass provides a visual representation of directions and helps navigators determine their heading and the direction they need to travel in. It is an essential tool for navigation and is commonly used in marine and aviation charts to assist in plotting routes and determining positions accurately.

The Mercator projection is a conformed cylindrical map projection. It accurately represents shapes and angles, making it useful for navigation purposes. It preserves the shapes of small areas, making it suitable for world maps. However, it distorts the size of objects near the poles, resulting in an exaggeration of their size.

In a Mercator chart, the scale for measuring distance is called the latitude scale. This is because the Mercator projection is a cylindrical map projection that distorts the size of objects as they get farther from the equator. The latitude scale helps to accurately measure distances along the lines of latitude on the map.

The correct answer is "departure" because latitude is a measure of distance north or south of the equator, and it is typically used to determine one's position when leaving or departing from a specific location. The other options, such as "arrival" and "difference of latitude (DLAT)", do not directly relate to latitude or the act of departing from a place.

A chart with a scale of 1:600,000 to 1:200,000 is called a sailing chart. This type of chart is specifically designed for navigation at sea and is used by sailors to plan their routes and navigate safely. The scale indicates the level of detail that the chart provides, with a smaller scale indicating a larger area covered but less detail. Therefore, a sailing chart with this scale range would be suitable for sailors who need a moderate level of detail for navigation purposes.

A chart with a scale from less than 1:50,000 that is used in local navigation and anchorage in harbors and smaller waterways is called a harbor chart. This type of chart specifically focuses on providing detailed information about the layout and features of a harbor or smaller waterway, which is essential for safe navigation and anchoring in these areas. It is designed to assist sailors and mariners in maneuvering their vessels effectively and avoiding any potential hazards or obstacles in the harbor or smaller waterway.

A chart with a scale from 1:150,000 to 1:600,000 is called a general chart. This type of chart provides a broad overview of a large area, such as a coastline or a region. It is designed to show general information rather than specific details, making it useful for planning purposes or for getting a general sense of the area.

The ship initially departed from longitude 005 degrees 55 minutes west and traveled westward for a distance of 4,461.0 nautical miles. To find the longitude of arrival, we need to subtract this distance from the initial longitude. Therefore, the longitude of arrival is 005 degrees 55 minutes west - 4,461.0 nautical miles = 080 degrees 16 minutes west.

The given information states that Ms. Milagrosa traveled from latitude 20 degrees 10 minutes north to latitude 34 degrees 18 minutes south. The difference in latitude is the absolute value of the difference between the two latitudes. By subtracting the two latitudes, we get 34 degrees 18 minutes - 20 degrees 10 minutes = 14 degrees 8 minutes. To convert this to nautical miles, we use the conversion factor of 1 degree = 60 nautical miles. Therefore, the difference in latitude is 14 degrees 8 minutes * 60 nautical miles/degree = 848 nautical miles. Since Ms. Milagrosa traveled south, the answer is 848 n.m. south.

The distance traveled by Ms. Milagrosa is given as 8,460 nautical miles. The speed is given as 20.1 knots. To find the steaming time, we can divide the distance by the speed. 8,460 divided by 20.1 equals approximately 420.4 hours.

Since there are 24 hours in a day, we can divide 420.4 by 24 to find the number of days. The quotient is approximately 17.5 days.

The decimal part of the days represents the remaining hours. 0.5 days is equal to 12 hours.

Therefore, the steaming time is 17 days 12 hours.

Since the given answer also includes minutes, we can assume that there is an additional calculation involving the remaining minutes. However, without further information, we cannot determine the exact calculation for the minutes.

The steaming time can be calculated by dividing the distance traveled by the speed. In this case, the distance traveled is 8,460 nautical miles and the speed is 20.1 knots. Dividing 8,460 by 20.1 gives us approximately 420.896 hours.

A chart with a scale from 1:50,000 to 1:150,000 is called a coast chart. This type of chart is specifically designed to provide detailed information about the coastal areas, including the shoreline, ports, and harbors. It is used by sailors and navigators to navigate safely along the coast and to plan their routes. The scale of the chart indicates that it provides a medium level of detail, making it suitable for coastal navigation.

The given information states that the person departed from a latitude of 03 degrees 18 minutes 54 seconds north and arrived at a latitude of 01 degrees 47.3 minutes south. To find the difference in latitude, we subtract the initial latitude from the final latitude. In this case, 01 degrees 47.3 minutes south is smaller than 03 degrees 18 minutes 54 seconds north, indicating a decrease in latitude. Therefore, the correct answer is 306.20 n.m. south.

The given question provides the coordinates of the departure and arrival locations. To find the difference of longitude, we subtract the longitude of the departure location from the longitude of the arrival location. In this case, the longitude of the departure location is 163 degrees 11.5 minutes west, and the longitude of the arrival location is 167 degrees 48.2 minutes east. To subtract these values, we convert the west longitude to a positive value by adding 360 degrees. After subtracting, we get a difference of 1,740 nautical miles west.

The correct answer is 54 degrees 28 minutes south. This can be determined by subtracting the initial latitude (20 degrees 10 minutes north) from the final latitude (34 degrees 18 minutes south). The difference in latitude is therefore 54 degrees 28 minutes south.

The given information states that the ship departed from a longitude of 158 degrees 02 minutes west and arrived at a longitude of 152 degrees 31 minutes east. To find the difference of longitude, we need to subtract the initial longitude from the final longitude.

158 degrees 02 minutes west - 152 degrees 31 minutes east = 158 degrees 02 minutes + 152 degrees 31 minutes

Adding the minutes, we get 33 minutes. Since the initial longitude is west and the final longitude is east, the difference of longitude is in the west direction. Therefore, the correct answer is 049 degrees 27 minutes west.

The given answer of 2,967 nautical miles west is correct. To calculate the difference of longitude (dlo) in nautical miles, we need to subtract the longitude of the departure point from the longitude of the arrival point. In this case, the longitude of the departure point is 158 degrees 02 minutes west and the longitude of the arrival point is 152 degrees 31 minutes east. To calculate the difference, we convert both longitudes to the same direction (either east or west). Since the departure longitude is west, we convert the arrival longitude to west as well. By subtracting 152 degrees 31 minutes from 158 degrees 02 minutes, we get a difference of 5 degrees 31 minutes. To convert this to nautical miles, we multiply the difference by the conversion factor of 60 nautical miles per degree, resulting in 331 nautical miles. Since the departure longitude is west, the correct answer is 331 nautical miles west.

The difference of longitude ("dlo") is calculated by subtracting the longitude of the departure point from the longitude of the arrival point. In this case, the longitude of the departure point is 163 degrees 11.5 minutes west, and the longitude of the arrival point is 167 degrees 48.2 minutes east. Subtracting the two, we get a difference of 029 degrees 00 minutes 18 seconds west.

Based on the given information, the ship traveled south by a difference of latitude of 1,693 nautical miles. Therefore, the correct answer is "28 degrees 13 minutes south" as it represents the ship's southward movement.

The steaming time can be calculated by adding up the total time travelled, which is given as 16 days 21 hours 03 minutes. Converting this time into hours gives us 16*24 + 21 + (03/60) = 405.05 hours.

The speed of the ship can be calculated by dividing the total distance traveled (8,020 nautical miles) by the total time taken (16 days, 21 hours, and 3 minutes). Converting the time to minutes, we have a total of 16 days * 24 hours/day * 60 minutes/hour + 21 hours * 60 minutes/hour + 3 minutes = 24,783 minutes. Dividing the distance by the time, we get a speed of approximately 0.323 knots per minute. Multiplying this by 60 to get the speed per hour, we get approximately 19.380 knots per hour. Rounding to the nearest hundredth, the correct answer is 19.800 knots.

The ship departed on April 28, 2009, and traveled for 16 days, 21 hours, and 3 minutes. This means that the ship will arrive on May 15, 2009. The time of arrival is given as 1633 hours. Therefore, the estimated time of arrival (E.T.A.) is 1633 hours on May 15, 2009.

The correct answer is 05 degrees 06 minutes 12 seconds south. This is the correct difference of latitude because the starting latitude is 03 degrees 18 minutes 54 seconds north and the ending latitude is 01 degrees 47.3 minutes south. To find the difference, we subtract the starting latitude from the ending latitude, resulting in a difference of 05 degrees 06 minutes 12 seconds south.

The given information states that the boat traveled 860.9 nautical miles north and 1,286.4 nautical miles west from its starting point. Since the boat started at a latitude of 42 degrees 22.4 minutes south, traveling north would bring it closer to the equator. Therefore, the latitude of arrival would be smaller than the starting latitude. The only option that satisfies this condition is 28 degrees 01 minutes 30 seconds south.

The given information states that the ship traveled westward, so the difference of longitude (dlo) should also be west. Therefore, the correct answer is 074 degrees 21 minutes west.

Based on the given information, we know that the ship traveled a distance of 8,460 nautical miles with a speed of 20.1 knots. To calculate the estimated time of arrival (ETA), we divide the distance by the speed. This gives us a travel time of approximately 420 hours. Adding this to the departure time of 2000 hours on February 27, 2009, we can estimate that the ship will arrive on March 17, 2009. The ETA is given as 0854 hours, which matches this calculation. Therefore, the correct answer is 0854 hours on 17 March 2009.

The latitude of arrival is 09 degrees 40 minutes north because the difference of latitude is given as 1,693 nautical miles south. Since the ship started at latitude 37 degrees 53 minutes north, subtracting 1,693 nautical miles south from the starting latitude will give us the latitude of arrival.

The boat initially departed from a longitude of 032 degrees 14 minutes east and traveled a difference of longitude of 1,286.4 nautical miles west. To find the longitude of arrival, we need to subtract the difference of longitude from the initial longitude. Subtracting 1,286.4 nautical miles west from 032 degrees 14 minutes east gives us a longitude of 010 degrees 47.6 minutes east.