# Rt Simulation Examination 1

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This is a Simulated Examination for Gulf RT Examinations taken from Last Month's HAAD Feedbacks.
This examination contains 100 of the most UPDATED EXAMS from Abu Dhabi, KSA, and UAE.
Take this examination for 120 minutes. You need to get 86% to pass the HAAD. 60% to pass MOH, DHA, or Prometrics.
Please text 0919-286-29-29 in the Philippines or visit our website www. Rtonline. Weebly. Com THIS IS YOUR ASSESSMENT FOR ANY GULF RT EXAMINATIONS INCLUDING HAAD RT, SAUDI PROMETRICS, DUBAI DHA, AND UAE MOH. THE QUESTIONS HERE ARE TAKEN FROM THIS ACTUAL EXAMINATIONS, SO PASSING THIS Read moreASSESSMENT EXAM WILL GIVE YOU A HIGH PROBABILITY OF PASSING THE SAID EXAMINATIONS

• 1.

### What are the four types of Radiation?

• A.

• B.

• C.

Beta, Electromagnetic, Ultra violet and Proton

• D.

Alpha, Beta, Gamma and Background

D. Alpha, Beta, Gamma and Background
Explanation

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• 2.

### What Radiation is used in smoke detectors?

• A.

Beta

• B.

Alpha

• C.

Gamma

• D.

Background

B. Alpha
Explanation
This is a hard questionn so dont be worryed if uyou got it wrong.

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• 3.

### What piece of equipment is used to measure the radioactive decay count?

• A.

Decay Tube

• B.

Geiger Muller Tube

• C.

Fordy Decay Count

• D.

Muller Rice Tube

• E.

Hodgsonator Decay Count Tube

B. Geiger Muller Tube
Explanation
How can you not get this right.

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• 4.

### What radiation is used to kill cancer cells.

• A.

Alpha

• B.

Beta

• C.

Gamma

• D.

• E.

Hooperium

C. Gamma
Explanation
Gamma radiation is used to kill cancer cells because it has high energy and can penetrate deep into tissues. This type of radiation damages the DNA of cancer cells, preventing them from dividing and growing. Gamma radiation is often used in radiation therapy, where targeted doses of radiation are delivered to specific areas of the body to destroy cancer cells. It is a highly effective treatment option for various types of cancer.

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• 5.

### Terra / BTX uses X-rays to produce the desired X-ray diffraction pattern or X-ray fluorescence spectrum.  These X-rays are produced from:

• A.

A radioactive isotope within the instrument

• B.

A gamma ray neutron source within the instrument

• C.

An X-ray tube operating at 30Kv

• D.

None of the above

C. An X-ray tube operating at 30Kv
Explanation
An X-ray tube operating at 30Kv is used to produce the desired X-ray diffraction pattern or X-ray fluorescence spectrum in Terra/BTX. The X-ray tube generates X-rays by accelerating electrons using a high voltage of 30Kv. These accelerated electrons collide with a metal target in the tube, resulting in the emission of X-rays. These X-rays are then used to produce the desired patterns or spectra for analysis.

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• 6.

### Radiation which has sufficient energy to remove electrons from atoms in materials through which the radiation passes is called ionizing radiation.  Examples of ionizing radiation include all but:

• A.

• B.

Neutrons

• C.

X-rays

• D.

Explanation
Ionizing radiation refers to radiation that has enough energy to remove electrons from atoms in materials. This process, known as ionization, can have harmful effects on living organisms and materials. Alpha particle radiation, neutrons, and x-rays are all examples of ionizing radiation, as they possess sufficient energy to ionize atoms. On the other hand, radio waves do not have enough energy to remove electrons from atoms and therefore do not fall under the category of ionizing radiation.

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• 7.

### The damaging effects of radiation depend not only on its intensity and duration, but also the type of radiation.  For instance, 1 millicurie of tritium a centimeter from the body poses a much different hazard than 1 millicurie of phosphorus-32 a centimeter from the body. Consequently, it is often preferable to measure radiation by describing the effect of that radiation on the materials through which it passes.  The units for biological effects of radiation are:

• A.

Exposure

• B.

Absorbed Dose

• C.

Dose Equivalent

• D.

REM/Sievert

D. REM/Sievert
Explanation
The units for biological effects of radiation are REM/Sievert because they take into account not only the intensity and duration of the radiation, but also the type of radiation and its effect on the materials it passes through. REM (Roentgen Equivalent Man) is a unit that measures the biological effect of radiation on human tissue, while Sievert is the International System of Units (SI) equivalent of REM. These units provide a more comprehensive measurement of the potential harm caused by radiation exposure.

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• 8.

### The amount of radiation exposure allowable is defined by the international commission on radiological protection (ICRP).

• A.

True

• B.

False

A. True
Explanation
The explanation for the given answer is that the international commission on radiological protection (ICRP) sets the standards for the amount of radiation exposure that is considered safe. These standards are based on extensive research and scientific evidence to ensure that individuals are not exposed to harmful levels of radiation. Therefore, it is true that the amount of radiation exposure allowable is defined by the ICRP.

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• 9.

### Radiation control for instruments, such as Terra / BTX is controlled by the US Federal government for instruments operated in the United States.

• A.

True

• B.

False

B. False
Explanation
The statement is false because radiation control for instruments like Terra/BTX is not controlled by the US Federal government.

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• 10.

### It is not necessary to contact your local radiation protection control authority (State, Federal, etc) in order to operate your Terra or BTX.

• A.

True

• B.

False

B. False
Explanation
The statement is false because it is necessary to contact the local radiation protection control authority in order to operate Terra or BTX. These devices are likely to emit radiation, and therefore, proper authorization and compliance with regulations are required to ensure safety and adherence to legal requirements. Failing to contact the local radiation protection control authority may result in legal consequences and potential harm to individuals and the environment.

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• 11.

### Terra / BTX when operated properly does not produce measurable radiation on any external surface of the instrument.

• A.

True

• B.

False

A. True
Explanation
The statement suggests that when Terra / BTX is operated correctly, it does not emit any detectable radiation on any external surface of the instrument. This implies that the instrument is designed and functioning properly, ensuring that radiation is contained within the instrument and does not pose any risk to the external environment or individuals. Therefore, the correct answer is true.

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• 12.

### Terra / BTX feature multiple interlock circuits, which prevent the possible operation of the X-ray generating source when these interlocks are activated.

• A.

True

• B.

False

A. True
Explanation
The statement is explaining that the Terra/BTX feature multiple interlock circuits that prevent the X-ray generating source from operating when these interlocks are activated. This means that if any of the interlocks are activated, the X-ray generating source will not be able to function. Therefore, the statement is true.

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• 13.

### Should an interlock circuit activate, an amber light will display on the main instrument panel.

• A.

True

• B.

False

A. True
Explanation
If an interlock circuit is activated, it means that there is a safety mechanism in place that prevents certain functions or operations until certain conditions are met. In this case, if the interlock circuit is activated, it will trigger the display of an amber light on the main instrument panel. Therefore, the statement is true.

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• 14.

### InXitu expects that the operator will need to remove the acess panel in order to properly use the instrument. That is, the instrument has user-serviced parts inside.

• A.

True

• B.

False

B. False
Explanation
The explanation for the given answer "False" is that inXitu does not expect the operator to remove the access panel in order to properly use the instrument. The instrument does not have user-serviced parts inside.

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• 15.

### Terra / BTX has the ability to perform the following experiments except:

• A.

X-ray Diffraction

• B.

X-ray Fluorescence

• C.

X-ray Time of Flight

C. X-ray Time of Flight
Explanation
Terra / BTX has the ability to perform X-ray Diffraction and X-ray Fluorescence experiments, but it does not have the ability to perform X-ray Time of Flight experiments.

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• 16.

### Terra / BTX have been designed such that proper operation will not result in any radiation exposure.

• A.

True

• B.

False

A. True
Explanation
Terra/BTX has been specifically designed to ensure that it operates without causing any radiation exposure. This means that when used correctly, there will be no harmful radiation emitted from Terra/BTX. Therefore, the statement is true.

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• 17.

### Which is not an acoustic variable?

• A.

Density

• B.

Pressure

• C.

Distance

• D.

Intensity

D. Intensity
Explanation
Intensity is not an acoustic variable because it refers to the amount of energy carried by sound waves per unit area. Acoustic variables, on the other hand, are physical quantities that describe the characteristics of sound waves, such as density, pressure, and distance.

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• 18.

### All of the following are true EXCEPT:

• A.

Two waves with identical frequencies must interfere constructively

• B.

Constructive interference is associated with waves that are in phase

• C.

Out of phase waves interfere destructively

• D.

Waves of different frequencies may exhibit both contructive and destructive interference at different times

A. Two waves with identical frequencies must interfere constructively
Explanation
This statement is false because waves with identical frequencies can interfere destructively if they are out of phase. Constructive interference occurs when waves are in phase, meaning their crests and troughs align, resulting in a larger amplitude. However, if the waves are out of phase, their crests and troughs do not align, leading to destructive interference and a smaller overall amplitude.

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• 19.

### Put in decreasing order

• A.

Deca

• B.

Deci

• C.

Micro

• D.

Centi

A. Deca
B. Deci
C. Micro
D. Centi
Explanation
The given words are units of measurement prefixes, representing different magnitudes. "Deca" is the largest prefix, representing a factor of 10, followed by "deci" which represents a factor of 0.1. "Micro" represents a factor of 0.000001, making it smaller than both "deca" and "deci". "Centi" represents a factor of 0.01, making it the smallest prefix among the given options. Therefore, the correct order from largest to smallest is "deca, deci, micro, centi".

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• 20.

### Which of the following sound waves is ultrasonic and least useful in diagnostic imaging?

• A.

30 KHZ

• B.

8 MHz

• C.

8,000 Hz

• D.

3,000 kHz

• E.

15 Hz

A. 30 KHZ
Explanation
The correct answer is 30 KHZ. Ultrasonic sound waves have a frequency above the range of human hearing, typically above 20 kHz. Diagnostic imaging techniques such as ultrasound use high-frequency sound waves to create images of internal body structures. Since 30 KHZ is the lowest frequency among the given options, it is the least useful in diagnostic imaging as it falls below the typical range of ultrasonic frequencies used in this field.

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• 21.

### What is the frequency of a wave with 1msec period?

• A.

10,000 Hz

• B.

1,000 kHz

• C.

1kHz

• D.

1MHz

C. 1kHz
Explanation
The frequency of a wave is the number of complete cycles it completes in one second. In this question, it is given that the wave has a period of 1 millisecond. The period is the time taken for one complete cycle. Since there are 1,000 milliseconds in one second, the wave completes 1,000 cycles in one second. Therefore, the frequency of the wave is 1kHz (1,000 Hz).

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• 22.

### If the frequency of an US wave is doubled, what happens to the period?

• A.

Doubles

• B.

Halved

• C.

Remains the same

• D.

4 times greater

B. Halved
Explanation
When the frequency of an ultrasound wave is doubled, the period of the wave is halved. This is because frequency and period are inversely proportional to each other. Frequency is the number of wave cycles per second, while period is the time it takes for one complete wave cycle. When the frequency is doubled, it means that the number of wave cycles per second has increased, so each wave cycle takes less time to complete, resulting in a halved period.

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• 23.

### The units of pulse repetition frequency are:

• A.

Per minute

• B.

Msec

• C.

Mm/us

• D.

MHx

A. Per minute
Explanation
The pulse repetition frequency measures the number of pulses that occur in one minute. It is a unit used to quantify the rate at which pulses are repeated in a given time period. Therefore, the correct answer is "per minute." The other options, msec (milliseconds), mm/us (millimeters per microsecond), and MHx (megahertz), do not accurately represent the units of pulse repetition frequency.

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• 24.

### The time from the beginning of a pulse until its end is__________?

• A.

Period

• B.

Pulse duration

• C.

Pulse length

• D.

PRF

B. Pulse duration
Explanation
The time from the beginning of a pulse until its end is referred to as the pulse duration. This term specifically measures the length of time that a pulse of energy or signal is active or present. It is important in various fields such as telecommunications, radar systems, and medical imaging, where the duration of a pulse directly affects the quality and accuracy of the transmitted or received information.

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• 25.

### The time that a transducer is pulsing is measured at 18 seconds in one hour of total elapsed time.  What is the duty factor?

• A.

0.3

• B.

0.005

• C.

0.5Hz

• D.

0.005msec

B. 0.005
Explanation
60 seconds equal 1 minute. There are 60 minutes in 1 hour so 60 seconds X 60 minutes = 18 divided by 3600 = 0.005

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• 26.

### If a wave's amplitude is doubled, what happens to the power?

• A.

Nothing

• B.

Halved

• C.

Dpib;ed

• D.

Explanation
When a wave's amplitude is doubled, the power of the wave increases by a factor of four, or it becomes quadrupled. This is because power is directly proportional to the square of the amplitude of the wave. Therefore, if the amplitude is doubled, the power will increase by four times.

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• 27.

### If the level of an acoustic variable ranges from 55 to 105, what is the amplitude?

• A.

105

• B.

50

• C.

25

• D.

55

C. 25
Explanation
The amplitude of an acoustic variable refers to the maximum displacement or distance from the equilibrium position. In this case, the level of the acoustic variable ranges from 55 to 105. Since the amplitude is the maximum displacement, it would be the difference between the highest and lowest values, which is 105 - 55 = 50. Therefore, the correct answer is 50.

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• 28.

### If the intensity of a sound beam remains unchanged while the beam area is reduced in half, what happened to the power?

• A.

• B.

Doubled

• C.

Halved

• D.

Unchanged

C. Halved
Explanation
When the beam area is reduced in half, the same amount of power is spread over a smaller area. This means that the power density (power per unit area) increases. Since power is directly proportional to the product of intensity and area, and the intensity remains unchanged, the only way for the power to decrease is if the area is halved. Therefore, the power is halved when the beam area is reduced in half.

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• 29.

### Put these intensities in decreasing order

• A.

SATP

• B.

SPTP

• C.

SATA

• D.

SPTP, SATP, SATA

• E.

SPTP SATA, SATP

D. SPTP, SATP, SATA
Explanation
The given answer is in the correct order because it lists the intensities in decreasing order. "SPTP" has the highest intensity, followed by "SATP", and then "SATA" has the lowest intensity.

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• 30.

### The duty factor for continuous wave ultrasound is

• A.

10.0

• B.

1%

• C.

1.0

• D.

0.0%

C. 1.0
Explanation
The duty factor for continuous wave ultrasound refers to the percentage of time that the ultrasound machine is emitting ultrasound waves. A duty factor of 1.0 means that the machine is emitting ultrasound waves 100% of the time. This indicates that the ultrasound waves are continuously being transmitted without any interruptions or breaks.

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• 31.

### What is the minimum value of the SP/SA factor?

• A.

10.0

• B.

1%

• C.

1.0

• D.

0.0%

C. 1.0
Explanation
The minimum value of the SP/SA factor is 1.0. This means that the selling price (SP) is equal to the selling amount (SA). In other words, there is no markup or discount applied to the selling price.

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• 32.

### Which pair of intensities has the same value for continuous wave US?

• A.

Spatial peak & spatial average

• B.

Temporal peak & spatial peak

• C.

Pulse average & temporal average

• D.

Spatial average & temporal average

C. Pulse average & temporal average
Explanation
The pulse average and temporal average intensities have the same value for continuous wave US. The pulse average intensity is the average intensity over one pulse duration, while the temporal average intensity is the average intensity over a longer time period. Since continuous wave US has a constant intensity, the pulse average and temporal average intensities will be equal.

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• 33.

### The fundamental frequency of a transcucer is 2.5 MHz.  What is the second harmonic frequency?

• A.

1.25 MHz

• B.

4.5 MHz

• C.

4.8 MHz

• D.

5 cm

C. 4.8 MHz
Explanation
The second harmonic frequency is double the fundamental frequency. Therefore, if the fundamental frequency is 2.5 MHz, the second harmonic frequency would be 5 MHz. However, none of the options provided match this value. Therefore, the correct answer is not available.

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• 34.

### A pulse is emitted by a transducer and is traveling in soft tissue.  The go-return time, or time of flight, of a sound pulse is 130 microseconds.  What is the reflector depth?

• A.

10 cm

• B.

10 mm

• C.

10 m

• D.

130 mm

• E.

13 cm

A. 10 cm
Explanation
PRP(us) = imaging depth x 13 us/cm
130 us = ? x 13 us/cm
130 divide by 13 = 10 cm or
Depth(mm) = 1.54mm/us x go return time(us)/2
= 1.54 x 130/2
= 200.2/2
mm = 100.1 or 10 cm

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• 35.

### What is the approximate attenuation coefficient of 1MHz US in soft tissue?

• A.

0.5 dBcm

• B.

1cm

• C.

3dBcm

• D.

1dB

A. 0.5 dBcm
Explanation
The approximate attenuation coefficient of 1MHz ultrasound in soft tissue is 0.5 dBcm. Attenuation coefficient refers to the rate at which the ultrasound waves decrease in intensity as they pass through the tissue. In this case, the attenuation coefficient is given in units of decibels per centimeter (dBcm), indicating that the intensity of the ultrasound waves decreases by 0.5 decibels for every centimeter of tissue they pass through.

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• 36.

### The relaive output of an US instrument is calibrated in dB and the operator increases the output by 60 dB.  The beam intensity is increased by which of the following?

• A.

5%

• B.

Two times

• C.

Twenty times

• D.

One hundred times

• E.

One million times

E. One million times
Explanation
3dB means 2 x bigger 6dB is 3dB + 3dB, therefore 6dB means 2 x 2 or 4 times bigger. 60dB = 10x10x10x10x10x10 or 1,000,000

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• 37.

### The more pixels per inch:

• A.

The better the temporal resolution

• B.

The better is the spatial resolution

• C.

• D.

The higher the reliability

B. The better is the spatial resolution
Explanation
A higher number of pixels per inch indicates a higher spatial resolution. Spatial resolution refers to the level of detail that can be captured and displayed in an image. With more pixels per inch, there are more individual dots of color or shades of gray in the image, allowing for finer details to be represented. Therefore, the better the spatial resolution is.

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• 38.

### If we increase the transducer diameter, the beam diameter in the far zone is:

• A.

Increased

• B.

Decreased

• C.

Unchanges

B. Decreased
Explanation
When the transducer diameter is increased, the beam diameter in the far zone is decreased. This is because the far zone is the region where the beam has already diverged and spread out. Increasing the transducer diameter means that the beam will have a larger initial width, causing it to diverge less as it propagates. As a result, the beam diameter in the far zone will be smaller, leading to a decrease in size.

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• 39.

### If the transducer diameter increases, the lateral resolution at its smallest dimension is

• A.

Increased

• B.

Decreased

• C.

Unchanged

A. Increased
Explanation
When the transducer diameter increases, the lateral resolution at its smallest dimension is increased. This is because a larger transducer diameter allows for a wider beam width, which results in a larger focal zone. As a result, the ultrasound waves diverge less and can provide better lateral resolution, allowing for more detailed imaging and distinguishing smaller structures.

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• 40.

### If we increase the frequency the near zone length is

• A.

Increased

• B.

Decreased

• C.

Unchanged

A. Increased
Explanation
When the frequency is increased, the near zone length is increased. This is because the near zone length is inversely proportional to the frequency. As the frequency increases, the wavelength decreases, causing the near zone length to increase.

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• 41.

### If the frequency is decreased, the numerical value of the radial resolution is

• A.

Increased

• B.

Decreased

• C.

Unchanged

A. Increased
Explanation
When the frequency is decreased, the numerical value of the radial resolution is increased. Radial resolution refers to the ability to distinguish between two closely spaced objects. Decreasing the frequency means that the wavelength becomes longer, resulting in a larger distance between consecutive wave peaks. This larger distance allows for better differentiation between objects, leading to an increased radial resolution.

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• 42.

### If the spatial pulse length is 10 mm, what is the axial resolution?

• A.

0.5 cm

• B.

5 cm

• C.

10 mm

• D.

1 cm

A. 0.5 cm
Explanation
The axial resolution is determined by the spatial pulse length, which is the distance between the start and end of a pulse. In this case, the spatial pulse length is given as 10 mm. The axial resolution is typically half of the spatial pulse length, so the axial resolution would be 0.5 cm.

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• 43.

### Which of the following is the best lateral resolution?

• A.

15 mm

• B.

6 mm

• C.

0.06 cm

• D.

2 cm

C. 0.06 cm
Explanation
The best lateral resolution is 0.06 cm. Lateral resolution refers to the ability of an imaging system to distinguish between two closely spaced objects. A smaller value indicates a higher resolution, meaning that the system can differentiate between objects that are closer together. Therefore, a lateral resolution of 0.06 cm is the best option among the given choices as it provides the highest level of detail and accuracy in distinguishing objects.

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• 44.

### What is the meaning of thermal index = 37

• A.

A tissue temperature may rise 3 degrees Farenheit

• B.

Tissue temperature will rise 3 degrees Celcius

• C.

Tissue temperature may rise 3 degrees Celcius

• D.

Microbubbles 3mm in diameter will burst

C. Tissue temperature may rise 3 degrees Celcius
Explanation
The thermal index is a measure of the potential for heating or mechanical effects in tissue when exposed to ultrasound. A thermal index of 37 indicates that the tissue temperature may rise by 3 degrees Celsius. This means that there is a possibility of heating in the tissue when exposed to ultrasound at this level.

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• 45.

### The interaction of microscopic bubbles and ultrasound form the basis for cavitation bioeffects.  Which of the following forms of cavitation are most likely to produce microstreaming in the intracellular fluid and shear stresses?

• A.

Stable cavitation

• B.

Normal cavitation

• C.

Transient cavitation

• D.

Inertial cavitation

• E.

Active cavitation

A. Stable cavitation
Explanation
Stable cavitation is the most likely form of cavitation to produce microstreaming in the intracellular fluid and shear stresses. In stable cavitation, the bubbles oscillate in size and shape but do not collapse completely. This oscillation creates microstreaming, which refers to the movement of fluid around the bubbles. The microstreaming effect can cause shear stresses on the surrounding intracellular fluid, leading to various bioeffects.

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• 46.

### Which of the following has the greatest output intensity

• A.

B-Mode

• B.

Gray scale imaging

• C.

CW Doppler

• D.

Pulsed Doppler

D. Pulsed Doppler
Explanation
Pulsed Doppler has the greatest output intensity among the given options. Pulsed Doppler is a technique used in ultrasound imaging to measure blood flow velocity. It uses short bursts of ultrasound waves and measures the intensity of the reflected waves to determine the velocity of blood flow. The intensity of the reflected waves is higher in pulsed Doppler compared to other options such as B-Mode or gray scale imaging, which are used for visualizing anatomical structures, or CW Doppler, which uses a continuous wave of ultrasound.

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• 47.

### Which of the following best decribes the empirical approach to the study of bioeffects?

• A.

Exposure-response

• B.

Cause-effect

• C.

Risk-benefit

• D.

Causation-reaction

• E.

Effect-microstreaming

A. Exposure-response
Explanation
The empirical approach to the study of bioeffects involves examining the relationship between exposure to a certain factor and the resulting response or effect. It focuses on gathering and analyzing data to determine the extent and nature of the relationship between exposure and response. This approach aims to provide evidence-based information on the effects of various factors on biological systems.

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• 48.

### Which of the following best describes the mechanistic approach to the study of bioeffects?

• A.

Cause-effect

• B.

Exposure-response

• C.

Risk-benefit

• D.

Causation-reaction

• E.

Effect-microstreaming

A. Cause-effect
Explanation
The mechanistic approach to the study of bioeffects focuses on understanding the cause-effect relationship between a specific exposure and its resulting effects. This approach aims to identify and explain the underlying mechanisms by which an exposure leads to a particular biological response or outcome. It seeks to establish a direct link between the cause (exposure) and the effect (biological response), providing a detailed understanding of the processes involved. This approach is important in assessing the potential risks and impacts of various exposures on living organisms.

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• 49.

### The propagation speed of US in the AIUM test object is?

• A.

1m/s

• B.

1.54 m/s

• C.

1.54 mm/us

• D.

1 km/s

C. 1.54 mm/us
Explanation
The correct answer is 1.54 mm/us. This is because ultrasound waves travel at different speeds in different materials. In the AIUM test object, the ultrasound waves travel at a speed of 1.54 mm/us.

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• 50.

### Enhancement, multipath and side lobes result in:

• A.

Image distortion

• B.

Clearer images

• C.

Artifact

• D.

Resolution problems

C. Artifact
Explanation
Enhancement, multipath, and side lobes can result in artifacts. These are unwanted distortions or anomalies in an image that can occur due to various factors such as noise, interference, or imperfections in the imaging system. These artifacts can degrade the quality and accuracy of the image, making it less reliable for analysis or interpretation. Therefore, the presence of enhancement, multipath, and side lobes can contribute to the occurrence of artifacts in the image.

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• Current Version
• Mar 21, 2023
Quiz Edited by
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• Jul 21, 2016
Quiz Created by
Wantunine

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