# C Programming Skills Test: Quiz!

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| By Shrenya Mathur
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Shrenya Mathur
Community Contributor
Quizzes Created: 2 | Total Attempts: 807
Questions: 10 | Attempts: 468

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• 1.

### Find Error/Output in following code: How many times "Placement Question" will print. int main()  {   int x;   for(x=-1; x<=10; x++)   {     if(x < 5)       continue;     else       break;     printf("Placement Question");   }    return 0; }

• A.

Infinite Time

• B.

11 Times

• C.

0 Times

• D.

10 Times

C. 0 Times
Explanation
The code will not print "Placement Question" any times. This is because the loop condition is x

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• 2.

### Find Error/Output in following code: int main() {   int a = 10, b = 25;   a = b++ + a++;   b = ++b + ++a;   printf("%d %d n", a, b); }

• A.

36 64

• B.

35 62

• C.

36 63

• D.

20 28

C. 36 63
Explanation
The code starts by assigning the value of 10 to variable 'a' and the value of 25 to variable 'b'. Then, the expression 'b++ + a++' is evaluated. Since 'b++' is a post-increment operator, the current value of 'b' (25) is used in the expression, but it is incremented after the expression is evaluated. Similarly, 'a++' is also a post-increment operator, so the current value of 'a' (10) is used in the expression and incremented afterwards. The result of this expression is then assigned to 'a'.

Next, the expression '++b + ++a' is evaluated. The '++b' is a pre-increment operator, so the value of 'b' (26) is incremented before the expression is evaluated. Similarly, '++a' is also a pre-increment operator, so the value of 'a' (11) is incremented before the expression is evaluated. The result of this expression is then assigned to 'b'.

Finally, the values of 'a' and 'b' are printed, which are 36 and 63 respectively.

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• 3.

### Find Error/Output in following code: void fn() {   static int i = 10;   printf("%d ", ++i); } int main() {   fn();   fn(); }

• A.

10 10

• B.

11 11

• C.

11 12

• D.

12 12

C. 11 12
Explanation
The code defines a function "fn" which has a static variable "i" initialized to 10. Inside the function, the value of "i" is incremented by 1 and then printed. The main function calls the "fn" function twice.

When the "fn" function is called for the first time, the value of "i" is incremented to 11 and printed.

When the "fn" function is called for the second time, the value of "i" is incremented again to 12 and printed.

Therefore, the output will be "11 12".

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• 4.

### Find Error/Output in following code: int main() {   int m = -10, n = 20;   n = (m < 0) ? 0 : 1;   printf("%d %d", m, n); }

• A.

-10 0

• B.

10 20

• C.

20 -10

• D.

0 1

A. -10 0
Explanation
The code initializes two variables, m and n, to -10 and 20 respectively. It then assigns the value of 0 to n if m is less than 0, otherwise it assigns the value of 1 to n. Finally, it prints the values of m and n, which are -10 and 0 respectively.

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• 5.

### Find Error/Output in following code: int main() {   int x = 0, y = 0;   if(x > 0)     if(y > 0)       printf("True");    else     printf("False");  }

• A.

No Output

• B.

True

• C.

False

• D.

Error - Dangling Problem

A. No Output
Explanation
The code will not produce any output. This is because the if statement for y > 0 is nested inside the if statement for x > 0. Since x is initialized to 0, the condition x > 0 is false, and the nested if statement for y > 0 is never evaluated. Therefore, no output is printed.

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• 6.

### What is output : #include <stdio.h> int main() { printf("crazyfor\\code\n"); return 0; }

• A.

Crazyforcode

• B.

Crazyfor code

• C.

Crazyfor\code

• D.

Crazyfor

C. Crazyfor\code
Explanation
The printf statement is used to print the string "crazyfor\code\n" to the standard output. The backslash (\) is an escape character in C, and when followed by another backslash (\\), it represents a single literal backslash in the output.

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• 7.

### Output of following program? # include <stdio.h> void fun(int *ptr) {     *ptr = 30; }   int main() {   int y = 20;   fun(&y);   printf("%d", y);     return 0; }

• A.

20

• B.

30

• C.

Compile Error

• D.

Runtime Error

B. 30
Explanation
The program defines a function `fun` that takes a pointer to an integer as a parameter. Inside the function, the value at the memory address pointed to by `ptr` is changed to 30.

In the `main` function, an integer variable `y` is declared and initialized to 20. The function `fun` is called with the address of `y` as an argument. This means that the function will modify the value at the memory address of `y`, changing it to 30.

Finally, the value of `y` is printed, which is now 30. Therefore, the output of the program is 30.

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• 8.

### char *ptr; char myString[]="abcdefg"; ptr=myString ptr+=5; The pointer ptr points to which string?

• A.

Fg

• B.

Efg

• C.

Defg

• D.

Cdefg

A. Fg
Explanation
The pointer ptr points to the string "fg". This is because the pointer initially points to the start of the string "abcdefg" and then it is incremented by 5, causing it to point to the character 'f' in the string.

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• 9.

### Given float *pf; int *pi; Which of the following is true?

• A.

Sizeof(pf) > sizeof(pi)

• B.

Sizeof(pi) < sizeof(pf)

• C.

Sizeof(pf) == sizeof(pi)

• D.

None

C. Sizeof(pf) == sizeof(pi)
Explanation
The correct answer is "sizeof(pf) == sizeof(pi)". This is because the sizeof operator returns the size in bytes of its operand. In this case, both pf and pi are pointers, and the size of a pointer is typically the same regardless of the type it points to. Therefore, the sizes of pf and pi will be the same.

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• 10.

### Which of the following is not a valid C variable name?

• A.

int number;

• B.

Float rate;

• C.

Int variable_count

• D.

Int \$main;

D. Int \$main;
Explanation
The variable name "int \$main;" is not a valid C variable name because variable names in C cannot start with a special character such as "\$". Variable names in C can only start with a letter or an underscore.

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