Basics Of C Language: Trivia Quiz!

2.

What will happen if the below program is executed? #include int main() { int main = 3; printf("%d", main); return 0; }

It will cause a compile-time error.
It will cause a run-time error.
It will run without any error and prints 3.
No output and program will terminate abnormally.

Correct Answer

A. It will run without any error and prints 3.

Explanation

In a function a variable can take the same name as that of the function

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3.

What is the output of the following C code? #include int main() { signed char chr; chr = 128; printf("%d\n", chr); return 0; }

128
-128
Depends on the compiler
Compile time error as char can't be assigned an int value

Correct Answer

A. -128

Explanation

When we exceed the maximum limit of char, it starts taking values from the beginning i.e. -128.

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4.

What is the output of the following C code? #include int main() { int i; if(i=0,2,3) printf("Hello "); else printf("World "); printf("%d",i); return 0; }

World 3
World 0
Hello 0
Hello 3

Correct Answer

A. Hello 0

Explanation

The code first initializes the variable i without assigning any value to it. Then, it checks the condition (i=0,2,3). In this condition, the comma operator is used, which evaluates each expression separated by commas and returns the value of the last expression. In this case, the value of the condition is 3. Since the condition is true, the code executes the printf("Hello ") statement. After that, it prints the value of i, which is 0. Therefore, the output is "Hello 0".

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5.

What is the output of the following C code? #include <stdio.h> int main() { int i=0,j=0; while(i<5,j<10) { i++; j++; } printf("%d %d",i,j); return 0; }

5 5
10 10
10 5
5 10

Correct Answer

A. 10 10

Explanation

Here, ‘,’ operator in while() will act as LOGICAL OR operator i.e. (i

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6.

What will be the output of this C code? #include <stdio.h> int main() { float f1 = 0.1; if (f1 == 0.1) printf("equal\n"); else printf("not equal\n"); return 0; }

Equal
Not equal
Output depends upon compiler
Compile-time error

Correct Answer

A. Not equal

Explanation

Here, 0.1 is taken as double (by default) by the compiler. So. a float value is not equal to a double value.

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7.

What is ‘short int’ in C programming?

A basic data type
Qualifier
Modifier
‘short’ is qualifier, ‘int’ is basic data type.

Correct Answer

A. ‘short’ is qualifier, ‘int’ is basic data type.

Explanation

In C programming, 'short int' is a data type that combines the 'short' qualifier with the 'int' basic data type. The 'short' qualifier is used to reduce the range of values that can be stored in the variable, while the 'int' data type is a basic data type used to represent integer values. Therefore, 'short int' is a combination of a qualifier and a basic data type.

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8.

Does this code compile without error(s)? // no header files included int main() { int k; { int k; for (k = 0; k < 10; k++); // there’s a semicolon in the end! } return 0; }

Yes
No
Depends on the compiler
Depends on the C standard you are using

Correct Answer

A. Yes

Explanation

Header files are only required for inbuilt fuctions(like: printf(),scanf()).
Data-types(like:int, float etc) are already known to the compiler.
When variable ‘k’ is declared second time, it’s declared inside another block, hence no contradiction of having two variables with same name. Also, putting a ‘;’ at the end of ‘for’ loop takes it as an empty statement.

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9.

What is the output of this C code? #include int main() { int i; scanf(“%d”, &i); // inputting 071 printf(“%d”, i); return 0; }

071
71
57
56

Correct Answer

A. 71

Explanation

When we declare or assign an int variable starting with 0, the compiler considers it as Hexadecimal value. But when, printf() prints, it prints it in its decimal equivalent. ‘071’ in Hexadecimal = ‘57’ in decimal But if we take input by scanf() it ignore the first digit '0'.

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10.

What is the output of this C code? #include<stdio.h> int main() { printf(“%d”, printf(“Hello 2018! ”)); return 0; }

Compile time error
Hello 2018!
12
Hello 2018! 12

Correct Answer

A. Hello 2018! 12

Explanation

printf() function returns the number of characters it has printed.

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11.

What is the output of this C code? #include <stdio.h> int main() { if(printf("foo")) switch(printf("bar")) while(printf("infinite")); return 0; }

Foobarinfiniteinfiniteinfinite………∞
Foobar
Foobarinfinite
Compile-time error

Correct Answer

A. Foobar

Explanation

Since printf() return the no. of characters printed so, in if it would be 3 and ‘foo’ is printed. Similarly, in switch it would also be 3, due to ‘bar’. Also, switch will search for ‘case 3’ but, it doesn’t find any ‘case 3’, so it comes out of switch and hence program terminates.

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12.

What is the output of this C code? #include <stdio.h> **#define square(x) x*x int main() { int a = 2; int sqr = square(a+1); printf(“%d”,sqr); return 0;** }

3
4
5
6

Correct Answer

A. 5

Explanation

#define replaces the square(x) with x*x with the value of ‘x’ provided before compiling the code.
Therefore, square(a+1) would become a+1*a+1, which is 2+1*2+1 = 2+2+1 = 5

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13.

What will be the value of d in the following program? #include int main() { int a = 10, b = 5, c = 5; int d; d = b + (c == a); printf("%d", d); }

Syntax Error
1
5
10

Correct Answer

A. 5

Explanation

In the given program, the value of d is determined by the expression "b + (c == a)". Here, (c == a) is a comparison expression which evaluates to false because c is not equal to a. In C language, false is represented by 0 and true is represented by 1. So, the expression becomes "b + 0" which is equal to b. Therefore, the value of d will be 5, as the value of b is 5.

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14.

What is the output of this C code? #include <stdio.h> int main() { int i = 3; int l = i / -2; int k = i % -2; printf("%d %d\n", l, k); return 0; }

Compile time error
-1 1
1 -1
Implementation defined

Correct Answer

A. -1 1

Explanation

The code initializes the variable i with the value 3. It then performs integer division between i and -2, resulting in l being assigned the value -1. It also calculates the remainder of the division, which is assigned to k. Since the remainder of dividing 3 by -2 is 1, k is assigned the value 1. The printf statement then prints the values of l and k, resulting in the output -1 1.

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15.

What is the Output of this C code? #include <stdio.h> int main() { int a = 10; if (a == a--) printf("TRUE 1\t"); a = 10; if (a == --a) printf("TRUE 2\t"); }

TRUE 1
TRUE 2
TRUE 1 TRUE 2
Compiler Dependent

Correct Answer

A. Compiler Dependent

Explanation

The output of this C code is Compiler Dependent. This is because the behavior of the code depends on how the compiler evaluates the expressions and the order in which the side effects of the expressions are applied. In the first if statement, the expression "a == a--" compares the value of a with the value of a before it is decremented. Some compilers may evaluate the expression as true because the value of a is copied before it is decremented, while others may evaluate it as false because the value of a is decremented before the comparison. In the second if statement, the expression "a == --a" compares the value of a with the value of a after it is decremented. Again, the behavior may vary depending on the compiler.

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Basics Of C Language: Trivia Quiz!

Which of the following is not a valid variable name declaration in the C programming language?

Quiz Preview

What will happen if the below program is executed? #include int main() { int main = 3; printf("%d", main); return 0; }

What is the output of the following C code? #include int main() { signed char chr; chr = 128; printf("%d\n", chr); return 0; }

What is the output of the following C code? #include int main() { int i; if(i=0,2,3) printf("Hello "); else printf("World "); printf("%d",i); return 0; }

What is the output of the following C code? #include <stdio.h> int main() { int i=0,j=0; while(i<5,j<10) { i++; j++; } printf("%d %d",i,j); return 0; }

What will be the output of this C code? #include <stdio.h> int main() { float f1 = 0.1; if (f1 == 0.1) printf("equal\n"); else printf("not equal\n"); return 0; }

What is ‘short int’ in C programming?

Does this code compile without error(s)? // no header files included int main() { int k; { int k; for (k = 0; k < 10; k++); // there’s a semicolon in the end! } return 0; }

What is the output of this C code? #include int main() { int i; scanf(“%d”, &i); // inputting 071 printf(“%d”, i); return 0; }

What is the output of this C code? #include<stdio.h> int main() { printf(“%d”, printf(“Hello 2018! ”)); return 0; }

What is the output of this C code? #include <stdio.h> int main() { if(printf("foo")) switch(printf("bar")) while(printf("infinite")); return 0; }

What is the output of this C code? #include <stdio.h> **#define square(x) x*x int main() { int a = 2; int sqr = square(a+1); printf(“%d”,sqr); return 0;** }

What will be the value of d in the following program? #include int main() { int a = 10, b = 5, c = 5; int d; d = b + (c == a); printf("%d", d); }

What is the output of this C code? #include <stdio.h> int main() { int i = 3; int l = i / -2; int k = i % -2; printf("%d %d\n", l, k); return 0; }

What is the Output of this C code? #include <stdio.h> int main() { int a = 10; if (a == a--) printf("TRUE 1\t"); a = 10; if (a == --a) printf("TRUE 2\t"); }

Basics Of C Language: Trivia Quiz!

Which of the following is not a valid variable name declaration in the C programming language?

Quiz Preview

What will happen if the below program is executed? #include int main() { int main = 3; printf("%d", main); return 0; }

What is the output of the following C code? #include int main() { signed char chr; chr = 128; printf("%d\n", chr); return 0; }

What is the output of the following C code? #include int main() { int i; if(i=0,2,3) printf("Hello "); else printf("World "); printf("%d",i); return 0; }

What is the output of the following C code? #include <stdio.h> int main() { int i=0,j=0; while(i<5,j<10) { i++; j++; } printf("%d %d",i,j); return 0; }

What will be the output of this C code? #include <stdio.h> int main() { float f1 = 0.1; if (f1 == 0.1) printf("equal\n"); else printf("not equal\n"); return 0; }

What is ‘short int’ in C programming?

Does this code compile without error(s)? // no header files included int main() { int k; { int k; for (k = 0; k < 10; k++); // there’s a semicolon in the end! } return 0; }

What is the output of this C code? #include int main() { int i; scanf(“%d”, &i); // inputting 071 printf(“%d”, i); return 0; }

What is the output of this C code? #include<stdio.h> int main() { printf(“%d”, printf(“Hello 2018! ”)); return 0; }

What is the output of this C code? #include <stdio.h> int main() { if(printf("foo")) switch(printf("bar")) while(printf("infinite")); return 0; }

What is the output of this C code? #include <stdio.h> #define square(x) x*x int main() { int a = 2; int sqr = square(a+1); printf(“%d”,sqr); return 0; }

What will be the value of d in the following program? #include int main() { int a = 10, b = 5, c = 5; int d; d = b + (c == a); printf("%d", d); }

What is the output of this C code? #include <stdio.h> int main() { int i = 3; int l = i / -2; int k = i % -2; printf("%d %d\n", l, k); return 0; }

What is the Output of this C code? #include <stdio.h> int main() { int a = 10; if (a == a--) printf("TRUE 1\t"); a = 10; if (a == --a) printf("TRUE 2\t"); }

What is the output of this C code? #include <stdio.h> **#define square(x) x*x int main() { int a = 2; int sqr = square(a+1); printf(“%d”,sqr); return 0;** }