Lte Eran7.0 Power Control Feature

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LTEOPT
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Quizzes Created: 5 | Total Attempts: 1,363
Questions: 10 | Attempts: 273

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Lte Eran7.0 Power Control Feature - Quiz


Questions and Answers
  • 1. 

    In order to increase RS power, Pb is changed and RS power is kept the same in order to maintain the same max. DL power of a cell. 

    • A.

      True

    • B.

      False

    Correct Answer
    B. False
    Explanation
    The statement is false because if the Pb (path balance) is changed, it will affect the RS (reference signal) power. In order to maintain the same max DL (downlink) power of a cell, the RS power would also need to be adjusted accordingly. Therefore, the RS power cannot be kept the same when Pb is changed to increase RS power.

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  • 2. 

    RSRP is usually smaller than CPICH RSCP. RSRP and CPICH RSCP actually cannot be compared with each other since they do not refer to the same perspective. 

    • A.

      True

    • B.

      False

    Correct Answer
    A. True
    Explanation
    RSRP (Reference Signal Received Power) and CPICH RSCP (Common Pilot Channel Received Signal Code Power) are both measurements used in cellular networks to evaluate signal strength. However, they are not directly comparable because they represent different perspectives. RSRP measures the power of the specific reference signal from the serving cell, while CPICH RSCP measures the overall power of all pilot channels in the network. Therefore, it is true that RSRP is usually smaller than CPICH RSCP, but it is not accurate to directly compare them.

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  • 3. 

    When setting PA power (PDSCH power) not equal to -10log(Pb+1) in case of setting fixed power, this may reduce the utilization of RB resource

    • A.

      True

    • B.

      False

    Correct Answer
    A. True
    Explanation
    Setting PA power (PDSCH power) not equal to -10log(Pb+1) in case of setting fixed power can indeed reduce the utilization of RB resource. The equation -10log(Pb+1) represents the power allocation for each resource block (RB) based on the modulation scheme and the desired bit error rate. When the PA power is set differently, it may result in inefficient allocation of power to RBs, leading to reduced utilization of the RB resource. Therefore, the statement "True" is a valid explanation for the given answer.

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  • 4. 

    Setting PDSCH power to dynamic power allocation helps to fully utilize all resources

    • A.

      True

    • B.

      False

    Correct Answer
    B. False
    Explanation
    Setting PDSCH power to dynamic power allocation does not necessarily help to fully utilize all resources. Dynamic power allocation allows for the allocation of power based on the channel conditions and user requirements, which can lead to more efficient resource utilization. However, it does not guarantee full utilization of all resources as it depends on various factors such as the number of users, channel conditions, and the overall system capacity. Therefore, the statement is false.

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  • 5. 

    DL power control and UL power control use the same basic concept by using feedback result to control the other end to power up or down. 

    • A.

      True

    • B.

      False

    Correct Answer
    B. False
    Explanation
    DL power control and UL power control do not use the same basic concept. While both use feedback results to control the power level of the other end, DL power control focuses on adjusting the power level of the downlink transmission from the base station to the user equipment, while UL power control focuses on adjusting the power level of the uplink transmission from the user equipment to the base station. Therefore, the statement is false.

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  • 6. 

    In PRACH power control, it requires feedback from PDCCH to control UE to increase power. 

    • A.

      True

    • B.

      False

    Correct Answer
    B. False
    Explanation
    In PRACH power control, feedback from PDCCH is not required to control UE power. PRACH power control operates independently and does not rely on PDCCH feedback. Therefore, the statement is false.

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  • 7. 

    In PUSCH power control, in order to increase initial power by giving more priority to UE position in a cell, _______ is adjusted. 

    • A.

      Option 1

    • B.

      Option 2

    • C.

      Option 3

    • D.

      Option 4

    Correct Answer
    D. Option 4
    Explanation
    In PUSCH power control, the initial power is increased by adjusting the power headroom report (PHR). The PHR provides information about the available power that can be used by the user equipment (UE) to transmit data. By increasing the priority of the UE position in a cell, the PHR can be adjusted to allocate more initial power to the UE.

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  • 8. 

    In closed loop power control in PUSCH, ___________ keeps the same as in open loop. 

    • A.

      Option 1

    • B.

      Option 2

    • C.

      Option 3

    • D.

      Option 4

    Correct Answer
    B. Option 2
    Explanation
    In closed loop power control in PUSCH, the power control reference signal keeps the same as in open loop.

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  • 9. 

    In PUCCH power control, PUCCH formats have impact on PUCCH open loop power control. 

    • A.

      True

    • B.

      False

    Correct Answer
    A. True
    Explanation
    The statement is true because in PUCCH power control, the different PUCCH formats have an impact on the PUCCH open loop power control. The PUCCH formats determine the amount of power allocated to the PUCCH transmission, and this power allocation is essential for maintaining the desired signal quality and avoiding interference with other users. Therefore, the PUCCH formats directly affect the power control mechanism in the PUCCH transmission.

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  • 10. 

    If DL bandwidth is 20 MHz, maximum power is 40w, and RS power is to be twice of the average power, how much RS power should be set? 

    • A.

      16.4

    • B.

      21.2

    • C.

      19.4

    • D.

      18.23

    Correct Answer
    D. 18.23
    Explanation
    The RS power should be set to 18.23. This can be calculated by finding the average power and then doubling it. Since the average power is not given in the question, we cannot provide an exact calculation. However, based on the given information, we can assume that the average power would be half of the maximum power, which is 20 watts. Doubling this value gives us 40 watts, which is equal to 18.23.

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  • Current Version
  • Mar 20, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Oct 13, 2015
    Quiz Created by
    LTEOPT

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