# Independent And Dependent Events Day 2

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| By Etjersland
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Etjersland
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Quizzes Created: 3 | Total Attempts: 6,384
Questions: 5 | Attempts: 578

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Answer multiple choice questions based on independent and dependent events.

• 1.

### In a class of 12 boys and 14 girls, Find P(Boy then boy without replacement)

• A.

66/325

• B.

17/38

• C.

36/169

• D.

4/13

A. 66/325
Explanation
The probability of selecting a boy on the first draw is 12/26. After the first boy is selected, there are 11 boys left out of a total of 25 students. Therefore, the probability of selecting another boy on the second draw without replacement is 11/25. Multiplying these probabilities together gives (12/26) * (11/25) = 132/650, which simplifies to 66/325.

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• 2.

### In a class of 12 boys and 14 girls, Find P(Girl then boy with replacement)

• A.

1/2

• B.

42/169

• C.

77/325

• D.

49/169

B. 42/169
Explanation
The probability of selecting a girl and then a boy with replacement can be found by multiplying the probability of selecting a girl (14/26) by the probability of selecting a boy (12/26). This can be simplified to (14/26) * (12/26) = 168/676 = 42/169.

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• 3.

### Using a standard deck of 52 cards, Find P(King then King without replacement)

• A.

1/169

• B.

4/663

• C.

5/663

• D.

1/221

D. 1/221
Explanation
The probability of drawing a King from a standard deck of 52 cards is 4/52 since there are 4 Kings in the deck. After drawing the first King, there are only 51 cards left in the deck, and 3 Kings remaining. Therefore, the probability of drawing another King without replacement is 3/51. To find the probability of both events happening, we multiply the probabilities together: (4/52) * (3/51) = 1/221.

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• 4.

### Using a standard deck of 52 cards, Find P(Ace then Jack with replacement)

• A.

2/169

• B.

1/13

• C.

1/169

• D.

4/663

C. 1/169
Explanation
The probability of drawing an Ace from a standard deck of 52 cards is 4/52, since there are 4 Aces in the deck. After replacing the card, the probability of drawing a Jack is also 4/52. To find the probability of both events happening, we multiply the probabilities together: (4/52) * (4/52) = 16/2704 = 1/169. Therefore, the correct answer is 1/169.

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• 5.

### If you roll a standard die and flip a coin, find P(5 then a tail)

• A.

1/12

• B.

5/12

• C.

1/4

• D.

1/8

A. 1/12
Explanation
The probability of rolling a 5 on a standard die is 1/6, and the probability of flipping a tail on a coin is 1/2. Since the events of rolling a 5 and flipping a tail are independent, we can multiply the probabilities together to find the probability of both events occurring. Therefore, the probability of rolling a 5 and then flipping a tail is (1/6) * (1/2) = 1/12.

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• Current Version
• Mar 21, 2023
Quiz Edited by
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• Feb 24, 2010
Quiz Created by
Etjersland

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