Basic Of Digital Electronic
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............ are Universal gates.
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NAND & NOR
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EX-OR
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NOT gate
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None of above
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Explore the basics of Digital Electronics through this quiz. Covering universal gates, logic gate behaviors, binary sequences in octal, and coding systems, this quiz enhances understanding of core digital concepts and practical applications in electronics and computing.
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- 2.
When the output of NAND gate is LOW
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When both input are same
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When one is high and other is low
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When both input are 1
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When both input are 0
Correct Answer
A. When both input are 1Explanation
The output of a NAND gate is LOW when both inputs are 1. A NAND gate is a type of logic gate that produces an output that is the inverse of the AND gate. In other words, if both inputs of a NAND gate are 1, the output will be 0. Therefore, when both inputs are 1, the output of the NAND gate will be LOW.Rate this question:
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- 3.
What will the next number of this series, when the base is octal 656, 657, .....
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658
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670
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660
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700
Correct Answer
A. 660Explanation
The series is in octal form, and each number is increasing by 1. The given numbers are 656, 657, 658, 659, and the next number should be 660.Rate this question:
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- 4.
Which Universal gate is sufficient to implement, when function is in POS form
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OR gate
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NAND gate
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EX-NOR gate
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NOR gate
Correct Answer
A. NOR gateExplanation
When a function is in POS (Product of Sums) form, it means that it is expressed as the logical sum of multiple terms, each of which is a logical product. The NOR gate is sufficient to implement this function because it is a universal gate, which means it can be used to implement any logic function. The NOR gate can be used to create the logical sum by connecting the inputs of multiple NOR gates in parallel, and then connecting their outputs to the inputs of another NOR gate in series. This configuration effectively implements the function expressed in POS form.Rate this question:
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- 5.
A parity bit is an extra bit that is attached with a message to make total number of......... either even or odd.
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0
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1
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Both 0 & 1
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None of above
Correct Answer
A. 1Explanation
A parity bit is used to ensure the integrity of data transmission. It is an extra bit that is added to a message to make the total number of bits either even or odd. By checking the parity bit, the receiver can determine if any errors occurred during the transmission. In this case, the correct answer is 1 because the parity bit is used to make the total number of bits odd.Rate this question:
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- 6.
Which one is non-weighted code
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84-2-1
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BCD
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Excess-3
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2421
Correct Answer
A. Excess-3Explanation
Excess-3 is a non-weighted code because it does not assign specific weights to each digit. In a non-weighted code, the value of each digit is not dependent on its position. Excess-3 is a self-complementing code where each digit is represented by adding 3 to the corresponding BCD digit. This code is commonly used in digital systems to perform arithmetic operations and is not based on a weighted system like BCD or 2421.Rate this question:
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- 7.
To design a BCD adder which number would you add if the sum is incorrect
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0110(6)
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0101(5)
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1000(8)
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1001(9)
Correct Answer
A. 0110(6)Explanation
If the sum is incorrect, you would add the number 6 (0110) to design a BCD adder. This is because adding 6 to the incorrect sum would help in adjusting the result and obtaining the correct sum.Rate this question:
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- 8.
This device always gives single output.
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Encoder
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Multiplexer
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De-Multiplexer
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Code converter
Correct Answer
A. MultiplexerExplanation
A multiplexer is a device that selects one input from multiple inputs and forwards it to a single output. It acts as a data selector, allowing only one input to pass through based on the control signals. Therefore, a multiplexer always gives a single output, making it the correct answer.Rate this question:
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- 9.
A 1024x6 ROM has....... input
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6
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1024
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5
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10
Correct Answer
A. 10Explanation
A 1024x6 ROM has 10 input. This means that the ROM can store and retrieve data from 10 different input lines. The "1024x6" notation indicates that the ROM has 1024 memory locations, each capable of storing 6 bits of data. Therefore, the ROM can handle 10 different input lines, allowing for a wide range of data retrieval and storage possibilities.Rate this question:
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Current Version
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Feb 06, 2024Quiz Edited by
ProProfs Editorial Team -
Nov 08, 2010Quiz Created by
Neelimabudhani
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