C Programming Practice - Test 4
. Dear Learner, This Assessment consists of questions to test your understanding on - C Programming You may attempt the same and clarify doubts in WP Group. / With your Faculty Member Regards, Team SHIVAM
- 1.What is the output? main() { char val[] = {‘a’,’b’,’c’,’\n’,’c’,’\0’}; char *p, *val1, *val2; p = &val[3]; val1 = val; val2 = val; printf(“%d”, ++*p + ++*val1 – 32); }
- A.
Non-portable pointer conversion
- B.
122
- C.
97
- D.
77
- 2.What is the output? main() { char *arr = “abc defg”, *x; x = arr; while( *arr != ‘\0’ ) ++*arr++; printf(“%s %s”,arr,x); }
- A.
Compiler error
- B.
No output
- C.
Bcd!efgh
- D.
Abc defg
- 3.What is the output? main() { char far *ptr1, *ptr2; printf(“%d %d”,sizeof(ptr1),sizeof(ptr2)); }
- A.
2 2
- B.
4 4
- C.
2 4
- D.
4 2
- 4.What is the output? main() { char family[4][20] = { “jesus”, “ram” , “rahim” , “gurunanak” }; char *temp; int count ; temp = family[1]; family[1] = family[2]; // Lvalue required for this line family[2] = temp; // Lvalue required for this line for(count = 0 ;count
- A.
Non portable pointer conversion
- B.
Compilation error-Lvalue required
- C.
jesus rahim ram gurunanak
- D.
Jesus ram rahim gurunanak
- 5.Int main() { struct Some Name { int size = 5; char tips[] = "LEARN"; }; struct SomeName ss; printf("\n %d %s",ss.size,ss.tips); return 0; }
- A.
Structure cannot be defined inside main()
- B.
5 LEARN
- C.
Structure member can not be initialized
- D.
Structure can not have char[]
- 6.Main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s=malloc(sizeof(struct xx)); printf("%d",s->x); printf("%s",s->name); }
- A.
1
- B.
0
- C.
Compiler error
- D.
None of these
- 7.Main() { char *str1="abcd"; char str2[]="abcd"; printf("%d %d %d",sizeof(str1),sizeof(str2),sizeof("abcd")); }
- A.
2 5 5
- B.
A b c
- C.
Compiler error
- D.
None of these
- 8.Void main() { int array[]={10,20,30,40}; printf("%d",-2[array]); }
- A.
-30
- B.
60
- C.
30
- D.
Garbage Value
- 9.Main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]); }
- A.
Mmmm aaaa nnnn
- B.
Compiler error
- C.
Mmm aaa nnn
- D.
Garbage Value
- 10.What is the the output ? main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j
- A.
2 2 2 2 2 3 4 6 5
- B.
2 2 2 2 2 2 3 4 6 5
- C.
2 2 2 2 2 2 4 6 5
- D.
2 2 2 2 2 2 3 4 6
- 11.What is the output ? main() { int i=-1,j=-1,k=0,l=2,m; m=i++&&j++&&k++||l++; printf("%d %d %d %d %d",i,j,k,l,m); }
- A.
0 0 1 3 1
- B.
0 1 3 1 0
- C.
1 3 1 0 0
- D.
0 0 1 1 3
- 12.What is the output ? void main() { char a[]="12345\0"; int i=strlen(a); printf("here in 3 %d\n",++i); }
- A.
3 3
- B.
6 3
- C.
6 6
- D.
3 6
- 13.Which of the following doesn’t match an array
- A.
Static allocation
- B.
Successive memory
- C.
Heterogeneity
- D.
Fixed size
- 14.Which of the following character is appended with a string
- A.
‘\r’
- B.
‘\n’
- C.
‘\t’
- D.
‘\0’
- 15.What is the output ? #include #include int main() { char *str = "x"; char c = 'x'; char ary[1]; ary[0] = c; printf("%d %d", strlen(str), strlen(ary)); return 0; }
- A.
1 1
- B.
2 1
- C.
2 2
- D.
1 (undefined value)
- 16.What will be the output? void main() { char c=125; c=c+10; printf(“%d”,c); }
- A.
-121
- B.
-8
- C.
135
- D.
Compiler Error
- 17.Void main() { int a[]={0,1,2,3,4}; int * p[]={a,a+1,a+2,a+3.a+4}; printf(“%d”,*(*p)); }
- A.
A
- B.
A+4
- C.
0
- D.
4
- 18.An array is a
- A.
ADT
- B.
Basic datatype
- C.
Derived datatype
- D.
User defined datatype
- 19.The array name indicates
- A.
Const pointer
- B.
Pointer to constant
- C.
Generic pointer
- 20.The difference between a character array and string is
- A.
Appended ‘\0’ in string
- B.
Appended ‘\0’ in character array
- C.
%s can’t be used for character array
- D.
%s can be used for both
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