Coa Cse D: Quiz 2
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- 1.In case of, Zero-address instruction method the operands are stored in _____
- A.
Registers
- B.
Accumulators
- C.
Push down stack
- D.
Cache
- 2.In assembly language programming, minimum number of operands required for an instruction is/are
- A.
Zero
- B.
One
- C.
Two
- D.
Both C and D
- 3.In which addressing mode the operand is given explicitly in the instruction?
- A.
Absolute
- B.
Immediate
- C.
Indirect
- D.
Direct
- 4.In the following indexed addressing mode instruction, MOV 5(R1),LOC, the effective address is ______
- A.
EA = 5+R1
- B.
EA = R1
- C.
EA = [R1]
- D.
EA = 5+[R1]
- 5.If a system is 64 bit machine , then the length of each word will be _______
- A.
4 Byte
- B.
8 Byte
- C.
12 Byte
- D.
16 Byte
- 6.When using the Big Endian assignment to store a number, the sign bit of the number is stored in _____
- A.
The higher order byte of the word
- B.
The lower order byte of the word
- C.
Can’t say
- D.
None of the mentioned
- 7.A _______ gate is used to detect the occurrence of an overflow.
- A.
NAND
- B.
XOR
- C.
XNOR
- D.
AND
- 8.In a normal adder circuit the delay obtained in generation of the output is _______
- A.
2n + 2
- B.
2n
- C.
n + 2
- D.
None of the mentioned
- 9.A subtractor is not usually present in a computer because
- A.
It is expensive
- B.
It is not possible to design it
- C.
The full adder will take care of subtraction
- D.
None of these
- 10.Which condition code register flags will be set to 1 when result is negative?
- A.
N
- B.
Z
- C.
V
- D.
C
- 11.The 32 bit number 5A938AF2 is held in (Byte Addressed) memory using the big-endian method starting at location 100.The number held in memory location 102 is
- A.
1100 0011
- B.
1000 1010
- C.
1000 0011
- D.
1100 0111
- 12.The words are said to be ______ in memory if they begin at a byte address that is multiple of number of bytes in a word
- A.
Aligned
- B.
Unaligned
- C.
Byte Addressable
- D.
Memory words
- 13.The 64 bit number A526FFAD4AC38BF2X is held in (Byte Addressed) memory using the big-endian method starting at location 100.The number held in memory location 105 is transferred to Register R1 . What would be the binary contents of R1 ?
- A.
1100 0011
- B.
1100 0010
- C.
1000 0011
- D.
1100 0111
- 14.The instruction, Add #45,R1 does
- A.
Adds the value of 45 to the address of R1 and stores 45 in that address
- B.
Adds 45 to the value of R1 and stores it in R1
- C.
Finds the memory location 45 and adds that content to that of R1
- D.
None of these
- 15.Consider the byte register R1 = ABH . What will be contents of R1 after the execution of AShiftL #2, R1?
- A.
EA
- B.
2B
- C.
A3
- D.
F5
- 16.Which condition code register flags will be tested by Branch > 0 instruction?
- A.
Zero
- B.
Overflow
- C.
Zero and carry
- D.
Zero and negative
- 17.Addressing mode used in instruction Add r1,r2,r3 is______
- A.
Registers
- B.
Index addressing mode
- C.
Indirect addressing mode
- D.
Offset addressing mode
- 18.Match each of the high level language statements given on the left hand side with the most natural addressing mode from those listed on the right hand side. 1. A[1] = B[J]; a. Indirect addressing 2. while [*A++]; b. Indexed addressing 3. int temp = *x; c. Autoincrement
- A.
(1, c), (2, b), (3, a)
- B.
(1, a), (2, c), (3, b)
- C.
(1, b), (2, c), (3, a)
- D.
(1, a), (2, b), (3, c)
- 19.The instruction ADD R1, 30FF is of _____
- A.
A 3-address instruction format
- B.
A 2-address instruction format
- C.
A 1-address instruction format
- D.
A 0-address instruction format
- 20.Displacement addressing mode will have example
- A.
Add R4,R3
- B.
Add R4,#3
- C.
Add R4,100(R1)
- D.
Add R3,(R1 + R2)
- 21.When using the Little Endian assignment to store a number, the sign bit of the number is stored in _____
- A.
The higher order byte of the word
- B.
The lower order byte of the word
- C.
Can’t say
- D.
None of the mentioned
- 22.Whenever a memory location is used, then actual memory address specified through addressing mode, is called the
- A.
Effective address
- B.
Registry
- C.
Immediate address
- D.
None of the mentioned
- 23.Let’s say that the word EFBACDFE16 is stored in a memory which is byte addressable, little endianness is followed and 1 word = 2 bytes. Which of the following gives the correct order of bytes storage of the word in memory?
- A.
EF DC AB FE
- B.
BA EF FE CD
- C.
FE CD BA EF
- D.
EF BA CD FE
- 24.Consider the byte registers R0 = ABH and R1 = ABH (H stands for Hexadecimal). What will be contents of R0 and R1 after the execution of the instruction Compare R1, R0?
- A.
R0 = ABH and R1 = ABH
- B.
R0 = ABH and R1 = 00H
- C.
R0 = 00H and R1 = 00H
- D.
R0 = 00H and R1 = ABH
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