Bubble Sort MCQ Quiz

In order to go through a list of 10 elements, we need to iterate over each element once. This requires a single pass or scan. However, the answer provided is 9, which is incorrect. It is possible that the question is incomplete or there is missing information that would justify the answer of 9. Without further context, it is not possible to provide a clear explanation for this answer.

The given statement is false. Bubble sorting is a simple sorting algorithm that works by repeatedly swapping adjacent elements if they are in the wrong order. It is called "bubble sorting" because during each iteration, the largest unsorted element "bubbles" up to its correct position in the sorted portion of the array. The statement about a Bubble gum company using it for the first time is not true.

The correct answer is two for loops, one nested in the other. In a bubble sort structure, the outer loop iterates through the entire array, while the inner loop compares adjacent elements and swaps them if they are in the wrong order. This process is repeated until the array is sorted.

Bubble sort is a simple sorting algorithm that repeatedly steps through the list, compares adjacent elements, and swaps them if they are in the wrong order. The algorithm gets its name because smaller elements "bubble" to the top of the list with each iteration.

Let's walk through the steps:

15, 20, 10, 18: In the first pass, we compare 15 and 20 (no swap), then 20 and 10 (swap to get 10, 20, 15, 18), and finally, 20 and 18 (no swap). The largest element, 20, bubbles up to the end.

10, 15, 20, 18: In the second pass, we compare 10 and 15 (no swap), then 15 and 20 (no swap), and finally 20 and 18 (swap to get 10, 15, 18, 20). Now, the second largest element, 15, is in its correct position.

10, 15, 18, 20: In the third pass, no swaps are needed as all elements are already in order.

So, the correct intermediate steps are:

15, 20, 10, 18

15, 10, 20, 18

10, 15, 20, 18

10, 15, 18, 20

This matches option C.

The number of passes or scans through a list being sorted using selection sort is equal to the size of the array minus one. In each pass, the algorithm selects the smallest element from the unsorted portion of the list and swaps it with the first unsorted element. This process is repeated until the entire list is sorted. Since the last element does not need to be compared with any other elements, there is no need for a final pass. Therefore, the number of passes is equal to the size of the array minus one.

In a selection sort algorithm, the first step is to find the minimum value in the list. This is done by comparing each element with the current minimum value and updating the minimum value if a smaller element is found. Once the minimum value is found, it is swapped with the first element in the list. This process is repeated for the remaining elements in the list, finding the minimum value and swapping it with the next element. This continues until the list is sorted in ascending order.

The maximum number of comparisons that can take place when a bubble sort is implemented is (1/2)n(n-1). In a bubble sort, each element is compared with its adjacent element and swapped if necessary. The number of comparisons decreases by 1 with each pass through the array, as the largest element "bubbles" to its correct position. Therefore, the total number of comparisons can be calculated by summing the numbers from 1 to n-1, which is equal to (1/2)n(n-1).

Bubble sort is a simple sorting algorithm that repeatedly steps through the list, compares adjacent elements and swaps them if they are in the wrong order. In the best-case scenario, when the list is already sorted, the algorithm only needs to make one pass through the list to confirm that it is sorted, resulting in a time complexity of O(n). However, in the worst-case scenario, when the list is in reverse order, the algorithm needs to make n-1 passes through the list and perform comparisons and swaps at each step, resulting in a time complexity of O(n^2).

If there are 5 elements in array x, the maximum number of comparisons can be calculated using the formula n*(n-1)/2, where n is the number of elements in the array. In this case, n=5, so the maximum number of comparisons is 5*(5-1)/2 = 10.

Here’s how Bubble Sort would sort the list:

First pass: 8,7,22,5,13,931 (3 swaps: 22 and 7, 22 and 5, 22 and 13)

Second pass: 7,8,5,13,22,931 (2 swaps: 8 and 5, 8 and 13)

Third pass: 7,5,8,13,22,931 (1 swap: 7 and 5)

Fourth pass: 5,7,8,13,22,931 (0 swaps)

Fifth pass: 5,7,8,13,22,931 (0 swaps)

So, a total of 3 + 2 + 1 + 0 + 0 = 6 passes and 12 swaps are required to sort the list in ascending order. Please note that understanding the principles of algorithms, such as bubble sort, is crucial for effective software development. Always ensure to follow best coding practices when working with algorithms.