5.1.1 - 5.1.3 Electric Circuits

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| By Gboulton
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Quizzes Created: 18 | Total Attempts: 10,840
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About This Quiz

This quiz, titled '5.1. 1 - 5.1. 3 Electric Circuits', tests understanding of kinetic energy changes in charged particles across potential differences. It covers calculations for electron energy, stopping potentials, and the kinetic energy for various charges, essential for learners in physics.

Electricity Quizzes & Trivia

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  • 2. 

    How much KE is given to 2C of charge when it passes across a PD of 6V.

    • 2J

    • 3J

    • 12J

    • 1/3 J

    Correct Answer
    A. 12J
    Explanation
    When a charge moves across a potential difference (PD), it gains kinetic energy (KE). The formula to calculate the KE is KE = qV, where q is the charge and V is the potential difference. In this question, the charge given is 2C and the PD is 6V. Plugging in these values into the formula, we get KE = 2C * 6V = 12J. Therefore, the correct answer is 12J.

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  • 3. 

    What PD is needed to stop a 400eV electron?

    • 100eV

    • 100V

    • 400eV

    • 400V

    Correct Answer
    A. 400V
    Explanation
    To stop a 400eV electron, a potential difference (PD) of 400V is required. This is because the PD is directly proportional to the energy of the electron. Therefore, in order to counteract the kinetic energy of the electron, the PD needs to be equal to or greater than the energy of the electron. In this case, since the electron has an energy of 400eV, a PD of 400V is needed to stop it.

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  • 4. 

      How much KE is given to an electron when it passes across a PD of 6V?

    • 6J

    • 1/6 J

    • 6eV

    • 1/6 eV

    Correct Answer
    A. 6eV
    Explanation
    When an electron passes across a potential difference (PD) of 6V, it gains kinetic energy (KE) equal to the amount of work done on it. The formula to calculate the KE is KE = qV, where q is the charge of the electron and V is the potential difference. The charge of an electron is 1.6 x 10^-19 C. Therefore, the KE gained by the electron is 1.6 x 10^-19 C x 6V = 9.6 x 10^-19 J, which is equivalent to 6eV.

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  • 5. 

    How much KE is given to an electron when it passes across a PD of 6V??

    • 6J

    • 1/6 J

    • 9.6 exp(-19) J

    • 1.6 exp(-19) J

    Correct Answer
    A. 9.6 exp(-19) J
    Explanation
    The correct answer is 9.6 exp(-19) J. The kinetic energy (KE) of an electron can be calculated using the formula KE = qV, where q is the charge of the electron and V is the potential difference (PD) across which it passes. In this case, the charge of an electron is approximately 1.6 exp(-19) C and the PD is given as 6V. Therefore, the KE of the electron is 1.6 exp(-19) C * 6V = 9.6 exp(-19) J.

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  • 6. 

    How much KE is given to 2micro coulombs when accelerated through a PD of 500V?

    • 4 exp(-3) J

    • 2 exp(-3) J

    • 1 exp(-3) J

    • 0.5 exp(-3) J

    Correct Answer
    A. 1 exp(-3) J
    Explanation
    When a charge is accelerated through a potential difference (PD), it gains kinetic energy (KE). The formula to calculate the KE is KE = qV, where q is the charge and V is the potential difference. In this question, the charge is given as 2 micro coulombs (2 x 10^-6 C) and the potential difference is given as 500V. Plugging these values into the formula, we get KE = (2 x 10^-6 C) x (500V) = 1 x 10^-3 J. Therefore, the correct answer is 1 exp(-3) J.

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  • Mar 20, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Jan 10, 2013
    Quiz Created by
    Gboulton
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