5.1.1 - 5.1.3 Electric Circuits

1. How much KE is given to 2C of charge when it passes across a PD of 6V.

2J

3J

12J

1/3 J

When a charge moves across a potential difference (PD), it gains kinetic energy (KE). The formula to calculate the KE is KE = qV, where q is the charge and V is the potential difference. In this question, the charge given is 2C and the PD is 6V. Plugging in these values into the formula, we get KE = 2C * 6V = 12J. Therefore, the correct answer is 12J.

Explanation

When a charge moves across a potential difference (PD), it gains kinetic energy (KE). The formula to calculate the KE is KE = qV, where q is the charge and V is the potential difference. In this question, the charge given is 2C and the PD is 6V. Plugging in these values into the formula, we get KE = 2C * 6V = 12J. Therefore, the correct answer is 12J.

2. What PD is needed to stop a 400eV electron?

100eV

100V

400eV

400V

To stop a 400eV electron, a potential difference (PD) of 400V is required. This is because the PD is directly proportional to the energy of the electron. Therefore, in order to counteract the kinetic energy of the electron, the PD needs to be equal to or greater than the energy of the electron. In this case, since the electron has an energy of 400eV, a PD of 400V is needed to stop it.

Explanation

To stop a 400eV electron, a potential difference (PD) of 400V is required. This is because the PD is directly proportional to the energy of the electron. Therefore, in order to counteract the kinetic energy of the electron, the PD needs to be equal to or greater than the energy of the electron. In this case, since the electron has an energy of 400eV, a PD of 400V is needed to stop it.

3. How much KE is given to an electron when it passes across a PD of 6V?

6J

1/6 J

6eV

1/6 eV

When an electron passes across a potential difference (PD) of 6V, it gains kinetic energy (KE) equal to the amount of work done on it. The formula to calculate the KE is KE = qV, where q is the charge of the electron and V is the potential difference. The charge of an electron is 1.6 x 10^-19 C. Therefore, the KE gained by the electron is 1.6 x 10^-19 C x 6V = 9.6 x 10^-19 J, which is equivalent to 6eV.

Explanation

When an electron passes across a potential difference (PD) of 6V, it gains kinetic energy (KE) equal to the amount of work done on it. The formula to calculate the KE is KE = qV, where q is the charge of the electron and V is the potential difference. The charge of an electron is 1.6 x 10^-19 C. Therefore, the KE gained by the electron is 1.6 x 10^-19 C x 6V = 9.6 x 10^-19 J, which is equivalent to 6eV.

4. How much KE is given to an electron when it passes across a PD of 6V??

6J

1/6 J

9.6 exp(-19) J

1.6 exp(-19) J

The correct answer is 9.6 exp(-19) J. The kinetic energy (KE) of an electron can be calculated using the formula KE = qV, where q is the charge of the electron and V is the potential difference (PD) across which it passes. In this case, the charge of an electron is approximately 1.6 exp(-19) C and the PD is given as 6V. Therefore, the KE of the electron is 1.6 exp(-19) C * 6V = 9.6 exp(-19) J.

Explanation

The correct answer is 9.6 exp(-19) J. The kinetic energy (KE) of an electron can be calculated using the formula KE = qV, where q is the charge of the electron and V is the potential difference (PD) across which it passes. In this case, the charge of an electron is approximately 1.6 exp(-19) C and the PD is given as 6V. Therefore, the KE of the electron is 1.6 exp(-19) C * 6V = 9.6 exp(-19) J.

5. How much KE is given to 2micro coulombs when accelerated through a PD of 500V?

4 exp(-3) J

2 exp(-3) J

1 exp(-3) J

0.5 exp(-3) J

When a charge is accelerated through a potential difference (PD), it gains kinetic energy (KE). The formula to calculate the KE is KE = qV, where q is the charge and V is the potential difference. In this question, the charge is given as 2 micro coulombs (2 x 10^-6 C) and the potential difference is given as 500V. Plugging these values into the formula, we get KE = (2 x 10^-6 C) x (500V) = 1 x 10^-3 J. Therefore, the correct answer is 1 exp(-3) J.

Explanation

When a charge is accelerated through a potential difference (PD), it gains kinetic energy (KE). The formula to calculate the KE is KE = qV, where q is the charge and V is the potential difference. In this question, the charge is given as 2 micro coulombs (2 x 10^-6 C) and the potential difference is given as 500V. Plugging these values into the formula, we get KE = (2 x 10^-6 C) x (500V) = 1 x 10^-3 J. Therefore, the correct answer is 1 exp(-3) J.