# 5.1.1 - 5.1.3 Electric Circuits

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Electric Circuits

• 1.

### How much KE is given to 2C of charge when it passes across a PD of 6V.

• A.

2J

• B.

3J

• C.

12J

• D.

1/3 J

C. 12J
Explanation
When a charge moves across a potential difference (PD), it gains kinetic energy (KE). The formula to calculate the KE is KE = qV, where q is the charge and V is the potential difference. In this question, the charge given is 2C and the PD is 6V. Plugging in these values into the formula, we get KE = 2C * 6V = 12J. Therefore, the correct answer is 12J.

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• 2.

### How much KE is given to an electron when it passes across a PD of 6V?

• A.

6J

• B.

1/6 J

• C.

6eV

• D.

1/6 eV

C. 6eV
Explanation
When an electron passes across a potential difference (PD) of 6V, it gains kinetic energy (KE) equal to the amount of work done on it. The formula to calculate the KE is KE = qV, where q is the charge of the electron and V is the potential difference. The charge of an electron is 1.6 x 10^-19 C. Therefore, the KE gained by the electron is 1.6 x 10^-19 C x 6V = 9.6 x 10^-19 J, which is equivalent to 6eV.

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• 3.

### How much KE is given to an electron when it passes across a PD of 6V??

• A.

6J

• B.

1/6 J

• C.

9.6 exp(-19) J

• D.

1.6 exp(-19) J

C. 9.6 exp(-19) J
Explanation
The correct answer is 9.6 exp(-19) J. The kinetic energy (KE) of an electron can be calculated using the formula KE = qV, where q is the charge of the electron and V is the potential difference (PD) across which it passes. In this case, the charge of an electron is approximately 1.6 exp(-19) C and the PD is given as 6V. Therefore, the KE of the electron is 1.6 exp(-19) C * 6V = 9.6 exp(-19) J.

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• 4.

### What PD is needed to stop a 400eV electron?

• A.

100eV

• B.

100V

• C.

400eV

• D.

400V

D. 400V
Explanation
To stop a 400eV electron, a potential difference (PD) of 400V is required. This is because the PD is directly proportional to the energy of the electron. Therefore, in order to counteract the kinetic energy of the electron, the PD needs to be equal to or greater than the energy of the electron. In this case, since the electron has an energy of 400eV, a PD of 400V is needed to stop it.

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• 5.

### How much KE is given to 2micro coulombs when accelerated through a PD of 500V?

• A.

4 exp(-3) J

• B.

2 exp(-3) J

• C.

1 exp(-3) J

• D.

0.5 exp(-3) J

C. 1 exp(-3) J
Explanation
When a charge is accelerated through a potential difference (PD), it gains kinetic energy (KE). The formula to calculate the KE is KE = qV, where q is the charge and V is the potential difference. In this question, the charge is given as 2 micro coulombs (2 x 10^-6 C) and the potential difference is given as 500V. Plugging these values into the formula, we get KE = (2 x 10^-6 C) x (500V) = 1 x 10^-3 J. Therefore, the correct answer is 1 exp(-3) J.

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• 6.

### Are there any parts of this section of the syllabus that you do not understand?

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• Current Version
• Mar 20, 2023
Quiz Edited by
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• Jan 10, 2013
Quiz Created by
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