Applications Of Definite Integrals Series

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  • 1/10 Questions

    It takes 505050 minutes for Joe to notice that his cola bottling machine has sprung a leak. Joe is able to stop the leak in 1010 minutes. The graph below shows the rate at which cola leaks from the machine as a function of time. How much cola does Joe lose in this bottling disaster?

    • 300
    • 200
    • 490
    • 100
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About This Quiz

Integrals can be used to measure a lot of phenomena that affect us in our everyday life. We've set up a series of exercise to help you conceptualize and practice this section of mathematics. Complete this quiz and see if you understand all the principles behind them.

Applications Of Definite Integrals Series - Quiz

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  • 2. 
    The cumulative profit a business has earned is changing at a rate of r(t)r(t)r, left parenthesis, t, right parenthesis dollars per day (where ttt is the time in days). In the first 3030 days, the business earned a cumulative profit of $1700dollar sign, 1700. What does 1700+∫3090r(t)dt1700+\displaystyle\int_{30}^{90}r(t)\,dt1700+∫​30​90​​r(t)dt1700, plus, integral, start subscript, 30, end subscript, start superscript, 90, end superscript, r, left parenthesis, t, right parenthesis, space, d, t represent? - ProProfs

    The cumulative profit a business has earned is changing at a rate of r(t)r(t)r, left parenthesis, t, right parenthesis dollars per day (where ttt is the time in days). In the first 3030 days, the business earned a cumulative profit of $1700dollar sign, 1700. What does 1700+∫3090r(t)dt1700+\displaystyle\int_{30}^{90}r(t)\,dt1700+∫​30​90​​r(t)dt1700, plus, integral, start subscript, 30, end subscript, start superscript, 90, end superscript, r, left parenthesis, t, right parenthesis, space, d, t represent?

    • The rate at which the cumulative profit was increasing when t=90.

    • The change in the cumulative profit between days 30 and 90

    • The cumulative profit the business has earned as of day is 90

    • The time it takes for the cumulative profit to increase another 1700 after the first 30 days

    Correct Answer
    A. The cumulative profit the business has earned as of day is 90
    Explanation
    The expression 1700+∫3090r(t)dt represents the cumulative profit the business has earned as of day 90. The integral represents the change in profit over time, and by adding it to the initial profit of 1700, we get the total cumulative profit up to day 90. Therefore, the correct answer is the cumulative profit the business has earned as of day 90.

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  • 3. 
    The velocity of a particle moving along the xxx-axis is v(t)=3v(t)=3t+2v, left parenthesis, t, right parenthesis, equals, 3, t, plus, 2. At t=0t=0t, equals, 0, its position is 33. What is the position of the particle, ss(t)s, left parenthesis, t, right parenthesis, at any time ttt? - ProProfs

    The velocity of a particle moving along the xxx-axis is v(t)=3v(t)=3t+2v, left parenthesis, t, right parenthesis, equals, 3, t, plus, 2. At t=0t=0t, equals, 0, its position is 33. What is the position of the particle, ss(t)s, left parenthesis, t, right parenthesis, at any time ttt?

    • S(t)=3

    • S(t)=3t​2​​+2t+3

    • S(t)=​2/​​3​​t​2​​+2t

    • S(t)=​2​​/3​​t​2​​+2t+3

    Correct Answer
    A. S(t)=​2​​/3​​t​2​​+2t+3
    Explanation
    The position of the particle at any time t is given by the equation s(t)=2/3t^2+2t+3. This equation is obtained by integrating the velocity function v(t)=3t+2 with respect to time. The constant term 3 in the position equation represents the initial position of the particle at t=0, which is given as 3 in the question.

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  • 4. 
    What is the area of the region between the graphs of f(x)=8x+6f(x)=8x+6f, left parenthesis, x, right parenthesis, equals, 8, x, plus, 6 and g(x)=x−x2g(x)=x-x^2, ​​g, left parenthesis, x, right parenthesis, equals, x, minus, x, start superscript, 2, end sup, from x=−6x, equals, minus to x=−1x=-1x, equals, minus, 1 ? - ProProfs

    What is the area of the region between the graphs of f(x)=8x+6f(x)=8x+6f, left parenthesis, x, right parenthesis, equals, 8, x, plus, 6 and g(x)=x−x2g(x)=x-x^2, ​​g, left parenthesis, x, right parenthesis, equals, x, minus, x, start superscript, 2, end sup, from x=−6x, equals, minus to x=−1x=-1x, equals, minus, 1 ?

    • 485/6

    • 643/6

    • 1195/6

    • 125/6

    Correct Answer
    A. 125/6
    Explanation
    The area of the region between the graphs of f(x)=8x+6 and g(x)=x-x^2 from x=-6 to x=-1 can be found by taking the definite integral of the difference between the two functions over the given interval. The integral of f(x)-g(x) from x=-6 to x=-1 is equal to the area of the region between the graphs. Evaluating this integral gives the answer of 125/6.

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  • 5. 
    Jackson received the following problem: A particle moves in a straight line with velocity v(t)=6t−20v(t)=6t-20v, left parenthesis, t, right parenthesis, equals, 6, t, minus, 2 meters per second, where tttt is time in seconds. At t=1t, equals, 1, the particle's distance from the starting point was 99 meters in the positive direction. What is the particle's position at t=4t=4t, equals, 4 seconds? Which expression should Jackson use to solve the problem? - ProProfs

    Jackson received the following problem: A particle moves in a straight line with velocity v(t)=6t−20v(t)=6t-20v, left parenthesis, t, right parenthesis, equals, 6, t, minus, 2 meters per second, where tttt is time in seconds. At t=1t, equals, 1, the particle's distance from the starting point was 99 meters in the positive direction. What is the particle's position at t=4t=4t, equals, 4 seconds? Which expression should Jackson use to solve the problem?

    • 9+∫​1​ 4​​v​′​​(t)dt

    • ∫​1​4​​v​′​​(t)dt

    • 9+∫​1​4​​v(t)dt

    • ∫​1​4​​v(t)dt

    Correct Answer
    A. 9+∫​1​4​​v(t)dt
    Explanation
    The correct answer is 9+∫​1​4​​v(t)dt. This expression represents the definite integral of the velocity function v(t) from t=1 to t=4, which gives the displacement of the particle during that time interval. Adding 9 to the integral accounts for the initial distance of 99 meters in the positive direction at t=1. Therefore, this expression will give the particle's position at t=4.

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  • 6. 
    The depth of the water in Harsha's bird bath is changing at a rate of r(t)=0.25t-0.1r(t)=0.25t−0.1r, left parenthesis, t, right parenthesis, equals, 0, point, 25, t, minus, 0, poin millimeters per hour (where tt is the time in hours). At time t=t=0t, equals, 0, the depth of the water is 353535 millimeters. What is the depth of the water at t=t3t, equals, hours? - ProProfs

    The depth of the water in Harsha's bird bath is changing at a rate of r(t)=0.25t-0.1r(t)=0.25t−0.1r, left parenthesis, t, right parenthesis, equals, 0, point, 25, t, minus, 0, poin millimeters per hour (where tt is the time in hours). At time t=t=0t, equals, 0, the depth of the water is 353535 millimeters. What is the depth of the water at t=t3t, equals, hours?

    • 35+∫​3​3​​r(t)dt

    • 35+∫​3​4​​r(t)dt

    • 35+∫​2​3​​r(t)dt

    • 35+∫​0​3​​r(t)dt

    Correct Answer
    A. 35+∫​0​3​​r(t)dt
    Explanation
    The given question asks for the depth of the water at time t=3 hours. To find this, we need to calculate the integral of r(t) from t=0 to t=3 and add it to 35. The correct answer is 35+∫​0​3​​r(t)dt.

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  • 7. 
    By approximately how many micromoles does the plasma concentration increase between x=x=1100x, equals, 100 and x=200x, equals, 200? - ProProfs

    By approximately how many micromoles does the plasma concentration increase between x=x=1100x, equals, 100 and x=200x, equals, 200?

    • 0.067

    • 0.15

    • 7.42

    • 33.5

    Correct Answer
    A. 7.42
    Explanation
    The plasma concentration increases by approximately 7.42 micromoles between x=100 and x=200.

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  • 8. 
    The base of a solid SS is the region bounded by the circle x2+y2=16x^2+y^2=16x, start superscript, 2, end superscript, plus, y, start superscript, 2, end superscript, equals, 16. Cross-sections perpendicular to the xx-axis are rectangles with heights twice as large as their bases. Determine the exact volume of solid SSS. - ProProfs

    The base of a solid SS is the region bounded by the circle x2+y2=16x^2+y^2=16x, start superscript, 2, end superscript, plus, y, start superscript, 2, end superscript, equals, 16. Cross-sections perpendicular to the xx-axis are rectangles with heights twice as large as their bases. Determine the exact volume of solid SSS.

    • 2048/3

    • 2048/4

    • 148/3

    • 148/4

    Correct Answer
    A. 2048/3
    Explanation
    The solid SS is a circular region with radius 4, centered at (4,0). The cross-sections perpendicular to the x-axis are rectangles with bases parallel to the x-axis. Since the heights of the rectangles are twice the length of their bases, the height of each rectangle is 2 times the distance from the x-axis to the circle. This distance can be found by solving the equation x^2 + y^2 = 16 for y when x = 0. Using the equation of the circle, we get y = √(16 - x^2), so the height of each rectangle is 2√(16 - x^2). The volume of each rectangle is the base (which is the length of the rectangle, given by 2x) multiplied by the height (2√(16 - x^2)). Integrating this expression from x = -4 to x = 4 will give us the volume of the solid. Evaluating the integral will result in the answer 2048/3.

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  • 9. 
    What is the area of the region enclosed by the graphs of f(x)=x2+2x+11f(x)=x^2+2x+11f, left parenthesis, x, right parenthesis, equals, x, start superscript, 2, end superscript, plus, 2, x, plus, 11 , g(x)=−4x+2g, left parenthesis, x, right parenthesis, equals, minus, 4, x, , and x=x=0x, equals, 0? - ProProfs

    What is the area of the region enclosed by the graphs of f(x)=x2+2x+11f(x)=x^2+2x+11f, left parenthesis, x, right parenthesis, equals, x, start superscript, 2, end superscript, plus, 2, x, plus, 11 , g(x)=−4x+2g, left parenthesis, x, right parenthesis, equals, minus, 4, x, , and x=x=0x, equals, 0?

    • 21

    • 6

    • 9

    • 63

    Correct Answer
    A. 9
    Explanation
    The area of the region enclosed by the graphs of f(x) and g(x) can be found by calculating the definite integral of the absolute difference between the two functions over the interval where they intersect. In this case, the two functions intersect at x=0. By evaluating the integral of |f(x)-g(x)| from -∞ to 0, we find that the area enclosed by the graphs is equal to 9.

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  • 10. 
    A region is enclosed by the yyy-axis, the line y=1yy, equals, 1, and the curve y=x3y=x^3​​​y, equals, x, start superscript, 3, end superscri. What is the volume of the solid generated when this region is rotated around the xx-axis? - ProProfs

    A region is enclosed by the yyy-axis, the line y=1yy, equals, 1, and the curve y=x3y=x^3​​​y, equals, x, start superscript, 3, end superscri. What is the volume of the solid generated when this region is rotated around the xx-axis?

    • 6.33

    • 5

    • 0.67

    • 6π​​/7

    Correct Answer
    A. 6π​​/7
    Explanation
    The volume of the solid generated when the region is rotated around the x-axis can be found using the method of cylindrical shells. Since the region is bounded by the y-axis, the line y=1, and the curve y=x^3, the limits of integration for the volume formula will be from x=0 to x=1. The radius of each cylindrical shell will be x, and the height of each shell will be 1 - x^3. Integrating the formula for the volume of a cylindrical shell over the given limits will result in the answer of 6Ï€/7.

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  • Current Version
  • Mar 22, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Jan 15, 2018
    Quiz Created by
    Anouchka
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