Accumulation & Riemann Sums Assessment Test

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By Cripstwick
C
Cripstwick
Community Contributor
Quizzes Created: 636 | Total Attempts: 835,032
| Attempts: 139
Quiz Flashcard
SettingsSettings
Please wait...
  • 1/10 Questions

    Integrate ∫ 3x+2 dx from x=1 to x=4.

    • 28.5
    • 28.6
    • 28
    • 28.7
Please wait...
About This Quiz

Accumulation and Riemann sums are used when the definite integral represents the area under the curve of a function between two vertical lines but we can't go find this area easily, so we can estimate it using simpler shapes like rectangles.

Accumulation & Riemann Sums Assessment Test - Quiz

Quiz Preview

  • 2. 
    Integrate and solve ∫ cos(x) dx from x=-11 to x=4. - ProProfs

    Integrate and solve ∫ cos(x) dx from x=-11 to x=4.

    • 3.14

    • -1.757

    • -3.14

    • 4.12

    Correct Answer
    A. -1.757
    Explanation
    The given question asks to integrate the function cos(x) with respect to x from x=-11 to x=4. The integral of cos(x) is sin(x), so we need to evaluate sin(x) from x=-11 to x=4. The value of sin(x) at x=-11 is -0.999 and at x=4 is -0.757. Subtracting the two values, we get -0.757 - (-0.999) = -0.757 + 0.999 = 0.242. Therefore, the correct answer is not available.

    Rate this question:

  • 3. 
    Integrate and solve ∫ 2x-cosx dx from x=1 to x=6. - ProProfs

    Integrate and solve ∫ 2x-cosx dx from x=1 to x=6.

    • 36.121

    • 24.75

    • -36.121

    • -24.75

    Correct Answer
    A. 36.121
    Explanation
    The given question asks us to find the definite integral of the function 2x - cosx with respect to x, from x=1 to x=6. By integrating the function and evaluating it at the upper and lower limits, we find that the result is 36.121.

    Rate this question:

  • 4. 
    Approximate the area under the curve of ∫ cos(x) dx from x=1 to x=5. - ProProfs

    Approximate the area under the curve of ∫ cos(x) dx from x=1 to x=5.

    • -3.14

    • 3.14

    • -1.8004

    • 1.8004

    Correct Answer
    A. -1.8004
    Explanation
    The approximate area under the curve of the function cos(x) from x=1 to x=5 is -1.8004. This is calculated using numerical integration methods, such as the trapezoidal rule or Simpson's rule. These methods divide the interval into smaller sub-intervals, approximate the curve within each sub-interval as a straight line or a polynomial, and then sum up the areas of the trapezoids or the Simpson's rule approximations. The result is an approximation of the area under the curve, which in this case is -1.8004.

    Rate this question:

  • 5. 
    Integrate f(x)= x^3+4 from x=-2 to x=2 using left riemann sums with four equal subintervals.  - ProProfs

    Integrate f(x)= x^3+4 from x=-2 to x=2 using left riemann sums with four equal subintervals. 

    • 6

    • 7

    • 8

    • 9

    Correct Answer
    A. 8
    Explanation
    The left Riemann sum approximates the area under the curve by using the left endpoint of each subinterval to determine the height of the rectangle. In this case, we have four equal subintervals: [-2, -1], [-1, 0], [0, 1], and [1, 2]. Evaluating the function at the left endpoints of these intervals gives us the values: f(-2) = -4, f(-1) = 3, f(0) = 4, and f(1) = 5. The width of each rectangle is 1, since each subinterval has a width of 1. Calculating the area of each rectangle and summing them up gives us 8, which is the approximate value of the integral.

    Rate this question:

  • 6. 
    Integrate and solve ∫ cos x dx from x=π to x=3π. - ProProfs

    Integrate and solve ∫ cos x dx from x=π to x=3π.

    • 0

    • 1

    • 2

    • 3

    Correct Answer
    A. 0
    Explanation
    The integral of cos x is sin x. Evaluating the integral from x=π to x=3π gives sin(3π) - sin(π). Since sin(3π) and sin(π) are both equal to 0, the result is 0.

    Rate this question:

  • 7. 
    Integrate and solve ∫1/x +2 dx from x=2 to x=5. - ProProfs

    Integrate and solve ∫1/x +2 dx from x=2 to x=5.

    • 1n (5/2) +6

    • -1n (5/2) +6

    • 1n (3) +2

    • -1n (3) +2

    Correct Answer
    A. 1n (5/2) +6
    Explanation
    The given integral is ∫(1/x + 2) dx from x=2 to x=5. Integrating 1/x with respect to x gives ln|x|, so integrating 1/x + 2 gives ln|x| + 2x. Evaluating this expression from x=2 to x=5 gives ln(5) + 2(5) - ln(2) - 2(2) = ln(5) + 10 - ln(2) - 4 = ln(5/2) + 6.

    Rate this question:

  • 8. 
    Integrate and solve ∫-sin(x)^2-cos(x) from x=12 to x=12. - ProProfs

    Integrate and solve ∫-sin(x)^2-cos(x) from x=12 to x=12.

    • -2

    • -1

    • 0

    • 1

    Correct Answer
    A. 0
    Explanation
    The integral of -sin(x)^2 is -1/2 * (x - sin(x)cos(x)), and the integral of -cos(x) is -sin(x). Evaluating the integral from x=12 to x=12, we get (-1/2 * (12 - sin(12)cos(12)) - sin(12)) - (-1/2 * (12 - sin(12)cos(12)) - sin(12)). Simplifying this expression, we get 0.

    Rate this question:

  • 9. 
    Integrate and solve ∫3x^5 dx from x=-5 to x=1. - ProProfs

    Integrate and solve ∫3x^5 dx from x=-5 to x=1.

    • -42

    • 42

    • 7821

    • -7821

    Correct Answer
    A. -7821
    Explanation
    The given question asks us to find the definite integral of the function 3x^5 from x=-5 to x=1. To solve this, we can use the power rule of integration, which states that the integral of x^n is (x^(n+1))/(n+1). Applying this rule, we get (3/6)(1^6 - (-5)^6) = (1/2)(1 - 15625) = (1/2)(-15624) = -7821. Therefore, the correct answer is -7821.

    Rate this question:

  • 10. 
    Integrate and solve ∫2x dx from intervals x=1 to x=3. - ProProfs

    Integrate and solve ∫2x dx from intervals x=1 to x=3.

    • -12

    • 12

    • -8

    • 8

    Correct Answer
    A. 8
    Explanation
    The given question asks to integrate the function 2x with respect to x, and then evaluate the result within the interval from x=1 to x=3. The integral of 2x is x^2, so we can evaluate the definite integral by substituting the upper limit (x=3) and the lower limit (x=1) into the antiderivative. When we substitute x=3, we get 3^2=9, and when we substitute x=1, we get 1^2=1. Therefore, the result of the definite integral is 9-1=8.

    Rate this question:

Quiz Review Timeline (Updated): Mar 21, 2023 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Mar 21, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Jan 05, 2018
    Quiz Created by
    Cripstwick
Back to Top Back to top
Advertisement
×

Wait!
Here's an interesting quiz for you.

We have other quizzes matching your interest.