Reasoning with Universal Quantifiers and Logical Inference Quiz

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| Questions: 15 | Updated: Dec 1, 2025
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1) "All primes greater than 2 are odd" has form:

Explanation

The natural-language statement restricts attention to primes that are greater than 2 and then asserts they are odd. The correct formalization places the conjunction Prime(x) ∧ x > 2 in the antecedent of an implication whose consequent is Odd(x), and then universally quantifies over x. Writing the condition as ∀x(Prime(x) ∧ x > 2 → Odd(x)) precisely captures “for every x, if x is prime and x > 2, then x is odd.” The other forms either assert every object is both prime and odd or merely assert existence rather than the required universal conditional.

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About This Quiz
Reasoning With Universal Quantifiers And Logical Inference Quiz - Quiz

Want to see how universal statements power real logical reasoning? This quiz highlights how ∀x P(x) interacts with conditionals, conjunctions, and existence claims in proofs. You’ll formalize statements such as “All primes greater than 2 are odd” and “All squares are rectangles,” then use rules like universal instantiation and modus... see moreponens to derive conclusions like Q(c) from ∀x (P(x) → Q(x)) and P(c). You’ll also explore how universals combine (e.g., ∀x P(x) ∧ ∀x Q(x) ≡ ∀x (P(x) ∧ Q(x)), and how they relate to ∃x P(x) in nonempty domains. Along the way, you’ll encounter vacuous truth, the law of excluded middle ∀x (P(x) ∨ ¬P(x)), and real-world readings like “All respondents liked the product.” By the end, using universal statements inside proofs will feel much more natural and systematic. see less

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2) If "∀x(P(x) → Q(x))" and "P(c)" are both true in a model, what can we conclude?

Explanation

From the universal statement ∀x(P(x) → Q(x)), by universal instantiation we can derive P(c) → Q(c). Given that P(c) is true, we can apply modus ponens to conclude Q(c) must be true. This is a fundamental pattern of reasoning with universally quantified conditionals.

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3) ∀x(P(x) → Q(x)) allows that:

Explanation

A universally quantified implication requires only that no x make P true and Q false simultaneously. It places no restriction on elements for which P(x) is false; such elements make the implication true vacuously and they may or may not satisfy Q(x). Hence it is perfectly consistent with ∀x(P → Q) that there exist x with ¬P(x) ∧ Q(x). Option B would contradict the universal implication, option C is an independent stronger claim, and option D is unrelated and possibly compatible but not what the implication specifically allows as a typical instance.

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4) From ∀xP(x) and a specific object c, we can infer:

Explanation

Universal instantiation is a standard rule: from ∀xP(x) we may substitute any specific object c from the domain to conclude P(c). This is a direct application of the meaning of the universal quantifier. While ∀xP(x) also entails ∃xP(x) in any nonempty domain, the immediate and precise inference from the universal assumption and an arbitrary constant c is P(c).

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5) Assuming a non-empty domain, the statement “∀xP(x) is true, then ∃xP(x)” is:

Explanation

In any nonempty domain, a true universal statement ∀xP(x) guarantees that at least one element satisfies P, hence ∃xP(x) follows. This relies on the domain being nonempty; the standard meta-assumption in most mathematical contexts is a nonempty domain, and under that assumption ∀xP(x) implies ∃xP(x). If the logic explicitly allows empty domains, then one must treat this implication with the empty-domain caveat, but in ordinary treatments the existential follows from the universal.

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6) ∀xP(x) ∧ ∀xQ(x) is equivalent to:

Explanation

Conjoining two universal statements is equivalent to a single universal statement whose matrix is the conjunction of the two predicates: if every x satisfies P and every x satisfies Q, then every x satisfies both P and Q, and conversely if every x satisfies P ∧ Q then each of ∀xP and ∀xQ holds. This equivalence follows from the distributive behavior of quantifiers over logical conjunction.

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7) ∀xP(x) ∨ ∀xQ(x) implies:

Explanation

If either every x satisfies P or every x satisfies Q, then in either case every x satisfies the disjunction P ∨ Q. Formally, from ∀xP(x) we get ∀x(P(x) ∨ Q(x)) by weakening, and similarly from ∀xQ(x) we get the same result; thus the disjunction of the universals yields ∀x(P ∨ Q). Note that the converse need not hold: ∀x(P ∨ Q) does not imply one of the universals must hold.

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8) The statement ∀x∃yP(x,y) means:

Explanation

The quantifier order matters: ∀x∃yP(x,y) asserts that for every x in the domain we can find (possibly depending on x) a y such that P(x,y) holds. This is different from ∃y∀xP(x,y) which would assert a single y that works for all x. The correct reading matches the indicated nesting: universal over x, existential over y.

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9) If domain = {1,2}, then ∀x(x > 0) is:

Explanation

With domain {1,2} both elements satisfy x > 0, so the universal claim holds because every element in the finite domain meets the predicate. Finite-domain universals reduce to finite conjunctions: here x > 0 must hold for x = 1 and x = 2, which it does, so the universally quantified statement is true.

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10) ∀x(P(x) → Q(x)) and P(c) together imply:

Explanation

From the universal implication we may instantiate to get P(c) → Q(c). Given P(c) as well, modus ponens yields Q(c). This is the standard pattern of reasoning: universal instantiation followed by modus ponens on the specific instance produces the consequent for that particular object.

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11) In a survey, "All respondents liked the product" means:

Explanation

The plain reading of “all respondents” is universal: every individual who responded to the survey is included and is asserted to have liked the product. This differs from “some” or “most,” and it equivalently means there are no respondents who did not like the product.

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12) In law, "All citizens have rights" means:

Explanation

The phrase “all citizens” denotes universality over the set of citizens; the legal formulation intends to assert that every individual who qualifies as a citizen holds rights. The statement attributes rights to each member of the specified class, not merely to some or most.

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13) ∀x(P(x) ∨ ¬P(x)) is:

Explanation

For any proposition P(x), the disjunction P(x) ∨ ¬P(x) is an instance of the law of excluded middle, which is classically true for each x. Universal quantification over x preserves that truth, yielding a formula true for every x in any classical interpretation. Hence the whole universally quantified disjunction is a logical truth (always true) in classical logic.

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14) “All squares are rectangles” means:

Explanation

The statement “All squares are rectangles” asserts that for every individual x, if x is a square then x is a rectangle. This is most naturally and directly formalized as ∀x (Square(x) → Rectangle(x)). The existential options do not express the universal claim, and stating that no squares exist contradicts the intended meaning. The universal implication is the correct representation.

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15) In “∀x (P(x) → Q(x)),” if P(x) is false for some x, the statement is:

Explanation

An implication P(x) → Q(x) is always true when P(x) is false, regardless of Q(x)’s truth value. This is known as vacuous truth. Therefore, for any element x for which P(x) fails, the implication automatically evaluates to true. The universal statement requires that all such implications be true, and vacuous truth ensures this requirement is met for any x with false antecedent.

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"All primes greater than 2 are odd" has form:
If "∀x(P(x) → Q(x))" and "P(c)" are both true in a model, what can...
∀x(P(x) → Q(x)) allows that:
From ∀xP(x) and a specific object c, we can infer:
Assuming a non-empty domain, the statement “∀xP(x) is true, then...
∀xP(x) ∧ ∀xQ(x) is equivalent to:
∀xP(x) ∨ ∀xQ(x) implies:
The statement ∀x∃yP(x,y) means:
If domain = {1,2}, then ∀x(x > 0) is:
∀x(P(x) → Q(x)) and P(c) together imply:
In a survey, "All respondents liked the product" means:
In law, "All citizens have rights" means:
∀x(P(x) ∨ ¬P(x)) is:
“All squares are rectangles” means:
In “∀x (P(x) → Q(x)),” if P(x) is false for some x, the...
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