Periodic Table: Ionisation Energy & Periodicity

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1. Why does fluorine have a lower electron affinity than chlorine?

Explanation

Fluorine, being a smaller atom, has its electrons more closely packed, leading to increased electron-electron repulsion when an additional electron is added. This repulsion counteracts the attractive force from the nucleus, resulting in a lower electron affinity compared to chlorine. Chlorine, having a larger atomic size, experiences less repulsion when gaining an electron, allowing it to have a higher electron affinity. Thus, the smaller volume and greater electron-electron repulsion in fluorine are key factors in its lower electron affinity relative to chlorine.

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Periodic Table: Ionisation Energy & Periodicity - Quiz

This assessment focuses on ionisation energy and periodic trends in the periodic table. It evaluates understanding of key concepts such as factors affecting ionisation energy, electron affinity, electronegativity, and the properties of elements in different groups and periods. This knowledge is essential for grasping chemical behavior and reactivity, making it... see morerelevant for students studying chemistry. see less

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2. Why does silicon (Si) have a very high boiling point compared to phosphorus (P) in Period 3?

Explanation

Silicon's high boiling point compared to phosphorus can be attributed to its giant covalent structure, where each silicon atom is covalently bonded to four neighboring atoms, forming a robust three-dimensional network. This arrangement necessitates the disruption of numerous strong covalent bonds to transition from solid to vapor, resulting in a significantly higher boiling point. In contrast, phosphorus exists as discrete molecules with weaker van der Waals forces, requiring less energy to break these interactions, hence it has a lower boiling point.

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3. Element Y has successive ionisation energies: I₁ = 743, I₂ = 1800, I₃ = 8703, I₄ = 10499 kJ/mol. To which group does Y belong?

Explanation

Element Y's successive ionization energies show a significant increase between the second and third ionization energies (from 1800 to 8703 kJ/mol). This large jump indicates that after removing two electrons, the next electron is being removed from a much more stable electron configuration, characteristic of Group 2 elements that have two valence electrons. Group 2 elements, or alkaline earth metals, readily lose these two outer electrons, leading to this pattern in ionization energies.

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4. Across Period 3, how does the acid-base character of oxides change from left to right?

Explanation

As one moves across Period 3 of the periodic table from left to right, the elements transition from metals to nonmetals. This shift is accompanied by an increase in electronegativity, which enhances the ability of an element to attract electrons. Consequently, the oxides formed by these elements exhibit greater acidic character, as nonmetal oxides tend to react with water to form acids. For example, phosphorus oxide (P2O5) and sulfur trioxide (SO3) are acidic, while sodium oxide (Na2O) is basic, illustrating this trend.

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5. What happens when SO₂ reacts with water?

Explanation

When sulfur dioxide (SO₂) reacts with water, it forms sulfurous acid (H₂SO₃). This reaction is represented by the equation: SO₂ + H₂O → H₂SO₃. Sulfurous acid is a weak acid, which means it can donate protons (H⁺ ions) in solution, resulting in an acidic environment. This process is significant in atmospheric chemistry, where SO₂ can contribute to acid rain when it combines with moisture in the air. Therefore, the reaction leads to the formation of an acidic solution rather than a neutral or basic one.

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6. Which of the following is an example of an amphoteric oxide?

Explanation

Al₂O₃, or aluminum oxide, is classified as an amphoteric oxide because it can react with both acids and bases. In acidic conditions, it can neutralize acids to form salts and water, while in basic conditions, it can react with bases to form complex ions. This dual behavior distinguishes amphoteric oxides from basic or acidic oxides, making Al₂O₃ a prime example of this category.

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7. Why do the melting and boiling points of Group 1 metals decrease down the group?

Explanation

As we move down Group 1 metals, the atomic size increases due to the addition of electron shells. This greater distance between the nucleus and the outermost electrons results in a weaker attraction between the positively charged nucleus and the negatively charged electrons. Consequently, the metallic bonds, which rely on this attraction, become weaker. Weaker metallic bonds lead to lower melting and boiling points as less energy is required to overcome these bonds during phase changes.

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8. What type of bonding is present in Group 14 elements across Period 3?

Explanation

Group 14 elements, such as silicon and germanium, exhibit covalent bonding due to their ability to share electrons and form strong bonds with other atoms. In Period 3, these elements can create extensive networks of covalent bonds, resulting in a giant molecular structure. This structure is characterized by a high melting point and hardness, typical of covalent compounds, distinguishing them from metals and ionic compounds, which have different bonding characteristics. Thus, the presence of covalent bonding leads to the formation of these robust giant molecular structures in Group 14 elements.

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9. Which of the following correctly describes the trend in electronegativity down a group?

Explanation

As you move down a group in the periodic table, the atomic size increases due to the addition of electron shells. This increase in distance between the nucleus and the valence electrons results in a weaker attraction for bonding electrons. Additionally, the effective nuclear charge (Zeff) experienced by the outermost electrons decreases because of increased electron shielding from inner shells. Together, these factors lead to a decrease in electronegativity down a group, as atoms become less capable of attracting electrons in a bond.

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10. How does electronegativity change across a period from left to right?

Explanation

Electronegativity increases across a period from left to right because the effective nuclear charge experienced by the electrons increases. As protons are added to the nucleus, the positive charge attracts electrons more strongly. Simultaneously, atomic size decreases due to the increased attraction between the nucleus and the electrons, which allows the atoms to hold onto their valence electrons more tightly. This combination of increased nuclear charge and reduced atomic radius enhances the ability of an atom to attract electrons, resulting in higher electronegativity.

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11. What is the first ionisation energy?

Explanation

First ionisation energy refers to the amount of energy needed to remove the outermost electron from a neutral gaseous atom, transforming it into a positively charged ion. This process is crucial in understanding the reactivity and chemical properties of elements, as it indicates how easily an atom can lose an electron. The other options do not accurately describe this concept, as they pertain to different processes involving electron addition, nuclear components, or atomic bonding.

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12. Why does beryllium (Be) show an endothermic electron affinity?

Explanation

Beryllium's electron configuration includes a completely filled 2s orbital, which contributes to its stability. When an electron is added, it must occupy a higher energy level, leading to increased electron-electron repulsion and instability. This unfavorable interaction results in an endothermic process, as energy is required to overcome the stability of the filled 2s orbital. Consequently, the addition of an electron does not release energy, instead absorbing it, thereby making the overall electron affinity of beryllium endothermic.

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13. What does electron affinity measure?

Explanation

Electron affinity quantifies the energy change associated with the addition of an electron to a neutral atom in the gas phase, resulting in the formation of a negatively charged ion (anion). This process typically releases energy, reflecting the atom's tendency to attract and hold onto the added electron. A higher electron affinity indicates a stronger attraction between the atom and the incoming electron, making it more favorable for the atom to gain an electron and form an anion.

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14. If element X (from the previous question) belongs to Period 3, what is its complete electronic configuration?

Explanation

Element X belongs to Period 3, indicating it has three electron shells. The electronic configuration starts with filling the first two shells (1s², 2s², 2p⁶), which accounts for 10 electrons. In Period 3, elements have their outermost electrons in the 3s and 3p orbitals. The configuration 3s² 3p⁴ suggests that there are 2 electrons in the 3s subshell and 4 electrons in the 3p subshell, totaling 16 electrons. This matches the atomic number of sulfur, which is in Period 3 and has the electronic configuration of 1s² 2s² 2p⁶ 3s² 3p⁴.

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15. An element X has successive ionisation energies (kJ/mol): 999.6, 2260, 3380, 4565, 6996, 8490, 28080, 31720. To which group does element X belong?

Explanation

The successive ionization energies of element X show a significant increase between the fifth and sixth ionization energies (from 6996 to 28080 kJ/mol). This large jump indicates that removing an electron from a stable electron configuration (likely a noble gas configuration) is much more difficult, suggesting that the element has six valence electrons. Elements in Group 16 of the periodic table have six valence electrons, aligning with the observed ionization energy pattern, thus confirming that element X belongs to Group 16.

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16. Why does nitrogen (N) have a higher first ionisation energy than oxygen (O)?

Explanation

Oxygen has a higher number of electrons in its outer shell compared to nitrogen, leading to paired electrons in the 2p orbital. These paired electrons experience increased electron-electron repulsion, which weakens the attraction between the nucleus and the electrons. As a result, it requires less energy to remove one of these electrons compared to nitrogen, where the electrons are unpaired, resulting in a stronger attraction and higher ionization energy. Thus, the presence of paired electrons in oxygen facilitates easier ionization.

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17. Why does boron (B) have a lower first ionisation energy than beryllium (Be)?

Explanation

Boron has a lower first ionisation energy than beryllium because it loses an electron from a 2p orbital, while beryllium loses an electron from a more stable 2s orbital. The 2p electrons are higher in energy and experience less effective nuclear charge compared to 2s electrons, making them easier to remove. This results in boron requiring less energy to ionize compared to beryllium, which has a filled 2s orbital that is more stable and requires more energy to remove an electron.

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18. Why does the first ionisation energy decrease down a group?

Explanation

As you move down a group in the periodic table, the atomic size increases due to the addition of electron shells. This increase in distance between the nucleus and the outermost electrons weakens the attraction between them. Additionally, the shielding effect also increases because inner-shell electrons repel outer-shell electrons, further reducing the effective nuclear charge (Zeff) felt by the outermost electrons. Consequently, more energy is required to remove an electron, resulting in a decrease in the first ionisation energy.

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19. Why does the first ionisation energy generally increase across a period from left to right?

Explanation

As you move across a period from left to right, the number of protons in the nucleus increases, leading to a higher effective nuclear charge. This greater positive charge attracts the electrons more strongly. Although additional electrons are added, they occupy the same principal energy level and do not shield each other effectively, particularly the p electrons. As a result, the increased nuclear attraction makes it more difficult to remove an electron, leading to a higher first ionisation energy.

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20. Which equation correctly represents the second ionisation energy of magnesium?

Explanation

The second ionisation energy of magnesium refers to the energy required to remove a second electron from a singly charged ion (Mg⁺) to form a doubly charged ion (Mg²⁺). The equation Mg⁺(g) → Mg²⁺(g) + e⁻ accurately represents this process, as it shows the removal of an electron from the Mg⁺ ion, resulting in the formation of Mg²⁺ and the release of an electron. This step is crucial in understanding the ionisation energies of elements and their behavior in chemical reactions.

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Why does fluorine have a lower electron affinity than chlorine?
Why does silicon (Si) have a very high boiling point compared to...
Element Y has successive ionisation energies: I₁ = 743, I₂ = 1800,...
Across Period 3, how does the acid-base character of oxides change...
What happens when SO₂ reacts with water?
Which of the following is an example of an amphoteric oxide?
Why do the melting and boiling points of Group 1 metals decrease down...
What type of bonding is present in Group 14 elements across Period 3?
Which of the following correctly describes the trend in...
How does electronegativity change across a period from left to right?
What is the first ionisation energy?
Why does beryllium (Be) show an endothermic electron affinity?
What does electron affinity measure?
If element X (from the previous question) belongs to Period 3, what is...
An element X has successive ionisation energies (kJ/mol): 999.6, 2260,...
Why does nitrogen (N) have a higher first ionisation energy than...
Why does boron (B) have a lower first ionisation energy than beryllium...
Why does the first ionisation energy decrease down a group?
Why does the first ionisation energy generally increase across a...
Which equation correctly represents the second ionisation energy of...
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