Compound Statements

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| By Thames
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Thames
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Quizzes Created: 7288 | Total Attempts: 9,526,515
| Questions: 10 | Updated: Nov 12, 2025
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1) P → q for p = T, q = F.

Explanation

Implication is false only when p = T and q = F.

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About This Quiz
Compound Statements - Quiz

How do “and,” “or,” and “not” shape truth? In this quiz, you’ll practice working with compound statements and truth values. Take this quiz to strengthen your grasp of logical building blocks.

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2) P ↔ q for p = T, q = F.

Explanation

Values differ, so biconditional is false.

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3) ¬(p → q) for p = F, q = T.

Explanation

p → q = T; negation of T = F.

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4) (p → q) ∧ (q → p) for p = T, q = F.

Explanation

p → q = F; F ∧ anything = F.

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5) (p ↔ q) ∨ (p ∧ q) for p = T, q = T.

Explanation

p ↔ q = T; T ∨ anything = T.

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6) P → q for p = F, q = F.

Explanation

False implies false is considered true in logic.

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7) P ↔ q for p = T, q = T.

Explanation

Both values equal (T, T), so biconditional is true.

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8) ¬(p → q) for p = T, q = F.

Explanation

p → q = F; negation of F = T.

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9) (p → q) ∧ (q → p) for p = T, q = T.

Explanation

Both implications are true, so conjunction = T.

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10) (p ↔ q) ∨ (p ∧ q) for p = T, q = F.

Explanation

p ↔ q = F; p ∧ q = F; F ∨ F = F.

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P → q for p = T, q = F.
P ↔ q for p = T, q = F.
¬(p → q) for p = F, q = T.
(p → q) ∧ (q → p) for p = T, q = F.
(p ↔ q) ∨ (p ∧ q) for p = T, q = T.
P → q for p = F, q = F.
P ↔ q for p = T, q = T.
¬(p → q) for p = T, q = F.
(p → q) ∧ (q → p) for p = T, q = T.
(p ↔ q) ∨ (p ∧ q) for p = T, q = F.
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