Airport Engineering Multiple Choice Questions and Answers
Are you into airport engineering or wish to pursue this field? Take this quiz with airport engineering multiple-choice questions to see how much you know. Airport engineering involves an airport facility's design, building, and maintenance. You can try this quiz to test your knowledge if you understand it well. All the best! Go for a perfect score with all the correct answers. Do not forget to share the quiz with other aspirants of airport engineering.
- 1.
Pick up the correct statement from the following:
- A.
Landing speed is directly proportional to the wing loading
- B.
Wing loading remaining constant, the take-off distance is directly proportional to the powder loading
- C.
Both of the above
- D.
None of the above
Correct Answer
C. Both of the aboveExplanation
The correct statement is that both landing speed and take-off distance are directly proportional to wing loading and powder loading, respectively. This means that as the wing loading increases, the landing speed will also increase. Similarly, as the powder loading remains constant, the take-off distance will increase.Rate this question:
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- 2.
According to the International Civil Aviation Organization (I.C.A.O.), the runway lengths of aerodromes have been coded by
- A.
Last Seven English alphabets
- B.
First Seven English alphabets
- C.
First Seven Natural numbers
- D.
Seven English alphabets
Correct Answer
B. First Seven English alphabetsExplanation
The correct answer is "First Seven English alphabets". The International Civil Aviation Organization (I.C.A.O.) has coded the runway lengths of aerodromes using the first seven English alphabets. This coding system allows for easy communication and understanding between pilots, air traffic controllers, and other aviation personnel. By using a simple and standardized coding system, it helps to ensure safety and efficiency in air travel operations.Rate this question:
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- 3.
The runway orientation is made so that landing and takeoff are
- A.
Against the wind direction
- B.
Along the wind direction
- C.
Perpendicular to wind direction
- D.
None of the above
Correct Answer
A. Against the wind directionExplanation
The runway orientation is made so that landing and takeoff are against the wind direction. This is because flying against the wind provides better control and reduces the ground speed of the aircraft, allowing for shorter takeoff and landing distances. It also helps to increase the lift generated by the wings, making the aircraft more stable and safer during these critical phases of flight. Therefore, having the runway aligned against the wind direction is the most optimal choice for ensuring safe and efficient operations.Rate this question:
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- 4.
Airport elevation is the reduced level above M.S.L. of
- A.
Lowest point of the landing area
- B.
Highest point of the landing area
- C.
Control tower
- D.
None of these
Correct Answer
B. Highest point of the landing areaExplanation
The correct answer is "highest point of the landing area." The airport elevation refers to the reduced level above Mean Sea Level (M.S.L.) of the highest point of the landing area. This is important information for pilots as it helps them determine the altitude at which they are operating and plan their approach and landing accordingly. The control tower and the lowest point of the landing area may have their own elevations, but they are not relevant to the airport elevation.Rate this question:
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- 5.
The depressions and undulations in the pavement are caused due to
- A.
Improper compaction of sub-grade
- B.
Impact of heavy wheel loads
- C.
Punching effect
- D.
All of the above
Correct Answer
D. All of the aboveExplanation
The depressions and undulations in the pavement can be caused by a combination of factors. Improper compaction of the sub-grade can lead to uneven settling of the pavement, creating depressions. The impact of heavy wheel loads can also cause the pavement to deform and create undulations. Additionally, the punching effect, which is the repeated loading and unloading of the pavement surface, can contribute to the formation of depressions and undulations. Therefore, all of the mentioned factors can contribute to the problem.Rate this question:
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- 6.
The reduced level of the proposed site of an airport is 2500 m above M.S.L. If the length by I.C.A.O. for the runway at sea level is 2500 m. What is the required length of the runway?
- A.
1258 m
- B.
2235 m
- C.
3476 m
- D.
3725 m
Correct Answer
D. 3725 mExplanation
The required length of the runway is 3725 m because the proposed site of the airport is already 2500 m above mean sea level (MSL). Therefore, the runway needs to be long enough to accommodate the additional height above MSL, which is 2500 m. Adding this to the length specified by I.C.A.O. for a runway at sea level (2500 m) gives us a total required length of 3725 m.Rate this question:
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- 7.
The thickness design of the pavement is decided on the load carried by
- A.
Tail wheel
- B.
Main gears
- C.
Nose wheel
- D.
None of the above
Correct Answer
B. Main gearsExplanation
The thickness design of the pavement is decided on the load carried by the main gears. The main gears of an aircraft are responsible for bearing the majority of the weight during landing and takeoff. Therefore, the pavement needs to be designed to withstand the load and pressure exerted by the main gears to ensure safe and efficient operations. The thickness of the pavement will depend on factors such as the aircraft type, maximum takeoff weight, and the number and arrangement of the main gears.Rate this question:
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- 8.
Beaufort scale is used to determine
- A.
Direction of winds
- B.
Height of air-crafts
- C.
Strength of winds
- D.
All of the above
Correct Answer
C. Strength of windsExplanation
The Beaufort scale is a measurement scale used to determine the strength of winds. It categorizes wind speeds based on observable effects on the environment, such as the movement of leaves, trees, and waves. The scale ranges from 0 (calm) to 12 (hurricane force), providing a standardized way to describe and compare wind strengths. This information is crucial for various activities, including aviation, sailing, and weather forecasting. The Beaufort scale does not determine the direction of winds or the height of aircraft; it solely focuses on assessing the strength of winds.Rate this question:
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- 9.
The bearing of the runway at the threshold is 290°, and the runway number is
- A.
W 20° N
- B.
29°
- C.
290°
- D.
N 70° W
Correct Answer
B. 29°Explanation
The correct answer is 29°. The bearing of the runway at the threshold is given as 290°. In order to determine the runway number, we need to subtract 18 from the bearing. So, 290° - 18° = 272°. However, since the bearing is given as N 70° W, we need to convert it to a clockwise bearing. N 70° W is equivalent to 360° - 70° + 90° = 380°. Now, subtracting 18° from 380° gives us 362°. However, since the bearing is in the western hemisphere, we need to subtract 180° to get the final runway number. 362° - 180° = 182°. But since the runway number should be between 01 and 36, we subtract 180° again to get the final answer of 2°.Rate this question:
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- 10.
The distance between the main gears is 10 m. Along with that, the distance of the nose gear from the center of the main gears is 30 m. What is the distance of the center of rotation from the nearer main gear if the angle of turning is 60°?
- A.
9.30 m
- B.
10.30 m
- C.
11.30 m
- D.
12.30 m
Correct Answer
D. 12.30 mExplanation
The distance between the main gears is given as 10 m. Since the angle of turning is 60°, the center of rotation will lie on the perpendicular bisector of the line joining the two main gears. This perpendicular bisector will pass through the midpoint of the line joining the two main gears. Therefore, the distance from the center of rotation to the nearer main gear is half of the distance between the main gears, which is 5 m. Additionally, the distance of the nose gear from the center of the main gears is given as 30 m. Therefore, the total distance from the center of rotation to the nearer main gear is 5 m + 30 m = 35 m. However, the question asks for the distance in terms of the nearer main gear, so we subtract the distance between the main gears from the total distance, which gives us 35 m - 10 m = 25 m. Therefore, the distance of the center of rotation from the nearer main gear is 25 m.Rate this question:
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Current Version
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Aug 16, 2023Quiz Edited by
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Dec 01, 2022Quiz Created by
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