Simulasi Online Ujian Nasional Fisika 2016/2017

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| By Ifanwk
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Ifanwk
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Quizzes Created: 1 | Total Attempts: 560
| Attempts: 561
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  • 1/7 Pertanyaan

    Seorang teknisi mobil mengukur diameter gotri roda menggunakan mikrometer sekrup seperti tampak pada gambar. Diameter gotri tersebut adalah ....

    • 1,00 mm
    • 1,50 mm
    • 9,15 mm
    • 10,00 mm
    • 10,05 mm
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  • 2. 
    Vektor a dan b dilukiskan seperti pada gambar! Besar resultan vektor tersebut adalah .... - ProProfs

    Vektor a dan b dilukiskan seperti pada gambar! Besar resultan vektor tersebut adalah ....

    • 8 satuan

    • 10 satuan

    • 28 satuan

    • 36 satuan

    • 64 satuan

    Correct Answer
    A. 10 satuan
    Explanation
    The magnitude of the resultant vector can be determined by using the Pythagorean theorem. In this case, the vectors a and b are perpendicular to each other, forming a right triangle. The magnitude of the resultant vector is equal to the square root of the sum of the squares of the magnitudes of vectors a and b. Since the magnitude of vector a is 8 satuan and the magnitude of vector b is 6 satuan, the magnitude of the resultant vector is sqrt(8^2 + 6^2) = sqrt(64 + 36) = sqrt(100) = 10 satuan.

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  • 3. 
    Dari kelima diagram tersebut. Yang menggambarkan D = A + B + C adalah .... - ProProfs

    Dari kelima diagram tersebut. Yang menggambarkan D = A + B + C adalah ....

    • (1)

    • (2)

    • (3)

    • (4)

    • (5)

    Correct Answer
    A. (5)
    Explanation
    Diagram (5) represents D = A + B + C because it shows three separate circles, each representing A, B, and C, with an overlapping section in the middle representing the sum of A, B, and C, which is D.

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  • 4. 

    Sebuah benda yang massanya 10 kg bergerak melingkar beraturan dengan kecepatan 4 m/s. Jika jari-jari lingkaran 0,5 meter, maka:
    1. Frekuensi putarannya 4/π Hz
    2. Percepatan sentripetalnya 32 m/s2
    3. Gaya sentripetalnya 320 N
    4. Periodenya 4π sekon
    Pernyataan yang benar adalah ....

    • (1), (2), (3), dan (4)

    • (1), (2), dan (3)

    • (1) dan (3) saja

    • (2) dan (4) saja

    • (3) dan (4) saja

    Correct Answer
    A. (1), (2), dan (3)
    Explanation
    The correct answer is (1), (2), dan (3).


    (1) Frekuensi putarannya 4/π Hz: Frekuensi putaran dapat dihitung dengan rumus f = v / (2πr), dimana v adalah kecepatan dan r adalah jari-jari lingkaran. Dalam kasus ini, kecepatan adalah 4 m/s dan jari-jari adalah 0,5 meter. Menggantikan nilai ke dalam rumus, f = 4 / (2π * 0,5) = 4/π Hz.

    (2) Percepatan sentripetalnya 32 m/s2: Percepatan sentripetal dapat dihitung dengan rumus a = v^2 / r, dimana v adalah kecepatan dan r adalah jari-jari lingkaran. Dalam kasus ini, kecepatan adalah 4 m/s dan jari-jari adalah 0,5 meter. Menggantikan nilai ke dalam rumus, a = (4^2) / 0,5 = 32 m/s^2.

    (3) Gaya sentripetalnya 320 N: Gaya sentripetal dapat dihitung dengan rumus F = m * a, dimana m adalah massa dan a adalah percepatan sentripetal. Dalam kasus ini, massa adalah 10 kg dan percepatan sentripetal adalah 32 m/s^2. Menggantikan nilai ke dalam rumus, F = 10 * 32 = 320 N.

    Therefore, statements (1), (2), and (3) are correct explanations.

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  • 5. 

    Sebuah batu dilempar ke atas dan mendarat di sebuah papan yang terletak 2 m di atas titik pelemparan. Jika kecepatan awal batu dilempar ke atas adalah 7 m/s, maka kecepatan batu ketika mengenai papan adalah .... (petunjuk: arah ke atas adalah positif)

    • 0 m/s

    • - 3 m/s

    • 3 m/s

    • 3,5 m/s

    • - 2 m/s

    Correct Answer
    A. - 3 m/s
    Explanation
    When the stone is thrown upwards, it will experience a decrease in velocity due to the force of gravity pulling it downwards. The stone will reach its highest point when its velocity becomes zero. As it starts to descend, its velocity will become negative because it is moving in the opposite direction of the initial throw. When the stone lands on the board, its velocity will still be negative, indicating that it is moving downwards. Therefore, the correct answer is -3 m/s.

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  • 6. 
    Perhatikan gambar di samping! Jika koefisien gesek kinetik antara balok A dan meja 0,1 dan percepatan gravitasi 10 m/s2 , gaya yang harus diberikan pada A agar sistem bergerak ke kiri dengan percepatan 2 m/s2 adalah .... - ProProfs

    Perhatikan gambar di samping! Jika koefisien gesek kinetik antara balok A dan meja 0,1 dan percepatan gravitasi 10 m/s2 , gaya yang harus diberikan pada A agar sistem bergerak ke kiri dengan percepatan 2 m/s2 adalah ....

    • 70 N

    • 90 N

    • 150 N

    • 250 N

    • 330 N

    Correct Answer
    A. 330 N
    Explanation
    The correct answer is 330 N because to find the force required to move the system to the left with an acceleration of 2 m/s^2, we need to consider the frictional force between block A and the table. The frictional force can be calculated using the formula F_friction = μ * N, where μ is the coefficient of kinetic friction and N is the normal force. The normal force is equal to the weight of the block, which is given by the formula N = m * g, where m is the mass of the block and g is the acceleration due to gravity. By substituting the given values into the formulas and solving, we find that the frictional force is 33 N. Since the system is moving to the left, we need to apply a force in the opposite direction, which is equal in magnitude but opposite in direction to the frictional force. Therefore, the force required to move the system to the left with an acceleration of 2 m/s^2 is 330 N.

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  • 7. 

    Sebuah bintang yang baru terbentuk memiliki kerapatan ρ, jari-jari R, dan percepatan gravitasi pada permukaan sebesar g. Dalam perkembangannya bintang tersebut memiliki kerapatan ρ1 = 0,75ρ dan jari-jari R1 = 1,25 R. Besarnya percepatan gravitasi di permukaannya pada keadaan tersebut adalah ....

    • (9/25) g

    • (18/25) g

    • (9/16) g

    • (15/16) g

    • G

    Correct Answer
    A. (15/16) g
    Explanation
    The density of the star is directly proportional to its mass, and the mass is directly proportional to the cube of the radius. Therefore, if the density increases by a factor of 0.75, the mass will also decrease by a factor of 0.75. Since the radius increases by a factor of 1.25, the acceleration due to gravity at the surface will decrease by a factor of (0.75/1.25)^2 = 0.45. Therefore, the new acceleration due to gravity at the surface is 0.45 times the original acceleration, which is equivalent to (15/16) g.

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  • Current Version
  • Mar 22, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Feb 13, 2017
    Quiz Created by
    Ifanwk

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