Uh Matematika (Menentukan Persamaan Dan Titik Pusat Serta Jari-jari Lingkaran)
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Persamaan lingkaran dengan pusat (0,0) dan jari-jari 3 adalah...
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X2 + y2 = 2
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X2 + y2 = 4
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X2 + y2 = 9
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X2 + y2 = 16
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X2 - y2 = 16
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- 2.
Jari-jari dan pusat lingkaran yang memiliki persamaan x2 + y2 + 4x − 6y − 12 = 0 adalah...
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5 dan (−2, 3)
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5 dan (2, −3)
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6 dan (−3, 2)
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6 dan (3, −2)
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7 dan (4, 3)
Correct Answer
A. 5 dan (−2, 3)Explanation
The equation of the circle is in the form (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius. By comparing the given equation x^2 + y^2 + 4x - 6y - 12 = 0 with the standard form, we can see that the center of the circle is (-2, 3) and the radius is 5. Therefore, the correct answer is 5 and (-2, 3).Rate this question:
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- 3.
Persamaan lingkaran yang berpusat di (2,-3) dengan jari-jari 7 adalah...
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X2 + y2 - 4x + 6y - 49 = 0
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X2 + y2 + 4x - 6y - 49 = 0
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X2 + y2 - 4x + 6y - 36 = 0
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X2 + y2 + 4x - 6y - 36 = 0
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X2 + y2 - 2x + 3y - 49 = 0
Correct Answer
A. X2 + y2 - 4x + 6y - 36 = 0Explanation
The equation of a circle with center (h,k) and radius r is given by (x-h)^2 + (y-k)^2 = r^2. In this case, the center is (2,-3) and the radius is 7. Plugging these values into the equation, we get (x-2)^2 + (y+3)^2 = 7^2. Expanding this equation gives x^2 + y^2 - 4x + 6y - 36 = 0. Therefore, the correct answer is x^2 + y^2 - 4x + 6y - 36 = 0.Rate this question:
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- 4.
Jari - jari lingkaran x2 + y2 - 6x - 4y - 3 = 0 adalah...
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4
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5
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6
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7
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8
Correct Answer
A. 4Explanation
The given equation represents a circle in the form of (x - a)2 + (y - b)2 = r2, where (a, b) is the center of the circle and r is the radius. By comparing the given equation with the standard form, we can determine that the center of the circle is (3, 2) and the radius is √3. Since the question asks for the value of the radius, the correct answer is 4.Rate this question:
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- 5.
Pusat dan jari - jari lingkaran dari persamaan x2 + y2 - 4x + 12y - 9 = 0 adalah ...
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(2,-6) dan 6
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(-2,6) dan 6
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(2,-6) dan 7
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(-2,6) dan 7
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(2,6) dan 7
Correct Answer
A. (2,-6) dan 7Explanation
The given equation represents a circle in the coordinate plane. The general equation of a circle is (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the coordinates of the center of the circle and r represents the radius. By comparing the given equation with the general equation, we can determine that the center of the circle is (2, -6) and the radius is 7. Therefore, the correct answer is (2, -6) dan 7.Rate this question:
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- 6.
Perhatikan gambar di bawah ini!
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X2 + y2 = 25
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X2 + y2 = 36
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X2 + y2 = 49
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X2 + y2 = 64
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X2 + y2 = 81
Correct Answer
A. X2 + y2 = 64Explanation
The given answer, x2 + y2 = 64, is correct because it follows the pattern of the other equations. Each equation represents a circle with a different radius. The equation x2 + y2 = 64 represents a circle with a radius of 8, which is the square root of 64. Therefore, it is the correct equation that fits the pattern of the other equations.Rate this question:
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- 7.
Persamaan lingkaran yang berpusat di (3,2) dan berjari - jari 4 adalah ...
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X2 + y2 - 6x + 4y - 3 = 0
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X2 + y2 - 6x - 4y - 3 = 0
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X2 + y2 + 6x + 4y - 3 = 0
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X2 + y2 - 4x - 6y - 3 = 0
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X2 + y2 + 4x - 6y - 3 = 0
Correct Answer
A. X2 + y2 - 6x + 4y - 3 = 0Explanation
The equation of a circle with center (h,k) and radius r is (x-h)^2 + (y-k)^2 = r^2. In this case, the center is (3,2) and the radius is 4. Plugging these values into the equation, we get (x-3)^2 + (y-2)^2 = 4^2, which simplifies to x^2 + y^2 - 6x + 4y - 3 = 0.Rate this question:
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- 8.
Diberikan persamaan lingkaran sebagai berikut: x2 + y2 −2x + 4y + 1 = 0. Jika pusat lingkaran adalah P(a,b) maka nilai dari 10a - 5b =...
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-10
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-5
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5
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10
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20
Correct Answer
A. 20Explanation
The equation of the circle can be rewritten as (x-1)² + (y+2)² = 4. Comparing this with the standard equation of a circle, (x-h)² + (y-k)² = r², we can see that the center of the circle is at point P(1, -2) and the radius is 2.
To find the value of 10a - 5b, we can substitute the coordinates of the center into the expression.
10a - 5b = 10(1) - 5(-2) = 10 + 10 = 20.
Therefore, the correct answer is 20.Rate this question:
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- 9.
Persamaan lingkaran yang berpusat di P(3, – 4) dan menyinggung sumbu x adalah …
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(x – 3)2 + (y – 4)2 = 9
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(x – 3)2 + (y + 4)2 = 9
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(x + 3)2 + (y – 4)2 = 9
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(x + 3)2 + (y – 4)2 = 16
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(x – 3)2 + (y + 4)2 = 16
Correct Answer
A. (x – 3)2 + (y + 4)2 = 16Explanation
The given equation represents a circle centered at point P(3, -4) and touches the x-axis. The general equation of a circle is (x - h)^2 + (y - k)^2 = r^2, where (h, k) represents the center of the circle and r represents the radius. In this case, the center is (3, -4) and the radius is 4 (since 4^2 = 16). Therefore, the correct equation is (x - 3)^2 + (y + 4)^2 = 16.Rate this question:
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- 10.
Persamaan lingkaran pada gambar berikut adalah...
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X2 + y2 = 5
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X2 + y2 = 25
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X2 - y2 = 5
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X2 - y2 = 25
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X2 + y2 = 10
Correct Answer
A. X2 + y2 = 25Explanation
The equation x^2 + y^2 = 25 represents a circle with a radius of 5 units. This is because the equation of a circle centered at the origin is x^2 + y^2 = r^2, where r is the radius. In this case, r = 5, so the equation becomes x^2 + y^2 = 25.Rate this question:
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Mar 22, 2023Quiz Edited by
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Feb 06, 2017Quiz Created by
Frans_mat
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