Latihan Pecahan, Desimal & Persen Kelas 6 Sd

To solve this expression, we need to follow the order of operations, which is parentheses, multiplication/division (from left to right), and addition/subtraction (from left to right).

First, we solve the expression inside the parentheses: (1 5/6 + 2/3). To add these fractions, we need a common denominator, which is 6.

Converting 1 5/6 to an improper fraction, we get 11/6. Adding 11/6 and 2/3, we get 33/18. Simplifying this fraction, we get 11/6.

Next, we solve the multiplication: (0,5 x 3,6). Multiplying 0.5 and 3.6, we get 1.8.

Now, we can simplify the expression: (1.8 : 1/4 + 11/6). To divide 1.8 by 1/4, we multiply 1.8 by the reciprocal of 1/4, which is 4/1. This gives us 7.2.

Finally, we add 7.2 and 11/6. To add these fractions, we need a common denominator, which is 6.

Converting 7.2 to a fraction, we get 36/5. Adding 36/5 and 11/6, we get 211/30.

Simplifying this fraction, we get 7 1/30, which can be written as 7 3/10.

Therefore, the answer is 9 7/10.

The given expression can be simplified as follows: 1.5 + 3 1/5 = 1.5 + 16/5 = 1.5 + 3.2 = 4.7. Then, 4.7 x 6 = 28.2. Therefore, the correct answer is 20 1/30.

On the first day, Ardi completed 2/5 of the task. On the second day, he completed 1/4 of the task. To find out how much he needs to complete on the third day, we need to subtract the sum of the fractions completed on the first and second days from 1 (since the total task is equivalent to 1). Therefore, the fraction that Ardi needs to complete on the third day is 1 - (2/5 + 1/4) = 1 - (8/20 + 5/20) = 1 - 13/20 = 7/20.

The fisherman initially caught 16.8 kg of tuna and ⁴/₅ kg of mackerel. He then sold 9.25 kg of tuna. To find the remaining unsold fish, we need to subtract the weight of the sold tuna from the total weight of the caught tuna. This can be calculated as 16.8 kg - 9.25 kg = 7.55 kg. Therefore, the correct answer is 8.35 kg, which is the weight of the unsold fish (7.55 kg) plus the weight of the unsold mackerel (⁴/₅ kg).