Structural 02 Philippines
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It is a structural system without complete vertical local carrying space frame. (NSCP 208.20)
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Braced frame
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Bearing wall system
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Rigid component
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Concentric braced frame
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About This Quiz
(National Structural Code of the Philippines-NSCP)
Prepared by:
Arch. /EnP. RSGabitan
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- 2.
Is a component including its attachments having fundamental period less than or equal to 0.06 sec. (NSCP 208.20)
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Braced frame
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Bearing wall system
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Rigid component
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Flexible component
Correct Answer
A. Rigid componentExplanation
A rigid component refers to a structural element that is stiff and does not deform significantly under load. In the context of the question, a rigid component would have a high stiffness and would not exhibit much flexibility or movement. If a component, along with its attachments, has a fundamental period (the time taken for one complete cycle of vibration) less than or equal to 0.06 seconds, it means that it has a high natural frequency and is not prone to significant vibrations or deformations. Therefore, a rigid component would be expected to have a fundamental period less than or equal to 0.06 seconds.Rate this question:
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- 3.
Is a component including its attachments having fundamental period greater than 0.60 sec. (NSCP 208.20)
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Braced frame
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Bearing wall system
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Rigid component
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Flexible component
Correct Answer
A. Flexible componentExplanation
A flexible component is one that can undergo significant deformation or movement under load. In the context of this question, a flexible component with attachments that have a fundamental period greater than 0.60 sec means that the component and its attachments are capable of oscillating or vibrating with a longer period of time. This suggests that the flexible component is more flexible and can absorb or dissipate energy effectively during seismic events, making it a suitable choice for structures in earthquake-prone areas.Rate this question:
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- 4.
Concrete filled driven piles of uniform section shall have a nominal outside diameter of not less than (NSCP 307.7.3)
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200 mm
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250 mm
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300 mm
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350 mm
Correct Answer
A. 200 mmExplanation
According to NSCP 307.7.3, concrete filled driven piles of uniform section should have a nominal outside diameter of not less than 200 mm.Rate this question:
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- 5.
A complete record of test of materials and of concrete shall be available for inspection during the progress of work and _______ years after completion of the project and shall be preserved by the inspecting engineer or architect for that purpose, (NSCP 403.20)
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2 years
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5 years
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10 years
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15 years
Correct Answer
A. 2 yearsExplanation
According to NSCP 403.20, a complete record of test of materials and of concrete shall be available for inspection during the progress of work and 2 years after completion of the project. This means that the records should be kept for a period of 2 years by the inspecting engineer or architect for inspection purposes.Rate this question:
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- 6.
The minimum bend diameter for 10mm Ø through 25mm Ø bars (NSCP 407.30)
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12 db
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6 db
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8 db
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10 db
Correct Answer
A. 6 dbExplanation
The minimum bend diameter for 10mm Ø through 25mm Ø bars is 6 db. This means that the bars should not be bent to a radius smaller than 6 times their diameter. This requirement ensures that the bars maintain their structural integrity and do not suffer from excessive stress or deformation during bending.Rate this question:
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- 7.
The minimum bend diameter for 28mm Ø through 36mm Ø bars (NSCP 407.30)
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12 db
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6 db
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8 db
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10 db
Correct Answer
A. 8 dbExplanation
The correct answer is 8 db. The minimum bend diameter for 28mm Ø through 36mm Ø bars according to NSCP 407.30 is 8 db. This means that the minimum bend diameter should be 8 times the diameter of the bar.Rate this question:
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- 8.
The minimum clear spacing between parallel bars in a layer must be db but not less than? (NSCP 407.7.3)
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50mm
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25mm
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75mm
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100mm
Correct Answer
A. 25mmExplanation
The minimum clear spacing between parallel bars in a layer must be db but not less than 25mm. This means that the spacing between the bars can be equal to the diameter of the bars, but it cannot be less than 25mm. This requirement ensures that there is enough space between the bars for proper concrete flow and consolidation during construction. It also helps to prevent the bars from getting too close together, which could affect the structural integrity of the reinforced concrete element.Rate this question:
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- 9.
In walls and slabs other than concrete joist construction, primary flexural reinforcement shall not be spaced farther apart than 3 times wall or slab thickness nor farther than? (NSCP 407.7.5)
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375mm
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450mm
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500mm
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300mm
Correct Answer
A. 450mmExplanation
In walls and slabs other than concrete joist construction, the primary flexural reinforcement should not be spaced farther apart than 3 times the wall or slab thickness. This ensures that the reinforcement is adequately distributed to provide sufficient strength and prevent excessive deflection or cracking. Therefore, the correct answer is 450mm, as it falls within the specified limit.Rate this question:
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- 10.
Groups of parallel reinforcing bars bundled in contact to act as one unit shall be united to ___ pieces in one bundle. (NSCP 407.7.6.1)
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4
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3
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2
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5
Correct Answer
A. 4Explanation
According to NSCP 407.7.6.1, groups of parallel reinforcing bars bundled in contact to act as one unit should be united to 4 pieces in one bundle. This means that the reinforcing bars should be grouped together in bundles of four, ensuring that they are in contact with each other to function as a single unit.Rate this question:
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- 11.
Bars larger than ___mm shall not be bundled in beams: (NSCP 407.7.6.3)
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25mm
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16mm
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28mm
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36mm
Correct Answer
A. 36mmExplanation
According to NSCP 407.7.6.3, bars larger than 36mm should not be bundled in beams. This means that if the diameter of the bars is greater than 36mm, they should not be grouped together in a beam. This could be due to structural considerations or to ensure proper spacing and distribution of the bars within the beam.Rate this question:
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- 12.
Individual bars within a bundle terminated within the span of flexural members shall terminate at different points with at least ____ stagger: (NSCP 407.7.6.4)
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12 db
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10 db
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50 db
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40 db
Correct Answer
A. 40 dbExplanation
In accordance with NSCP 407.7.6.4, individual bars within a bundle terminated within the span of flexural members should terminate at different points with at least a stagger of 40 db. This means that the bars should not all end at the same point, but rather should be staggered by a distance equal to or greater than 40 times the diameter of the bar. This helps to distribute the load more evenly and prevent concentrated stress points, ensuring the structural integrity of the flexural members.Rate this question:
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- 13.
Minimum concrete cover cast against and permanently exposed to earth: (NSCP 407.8.1)
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100 mm
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75 mm
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50 mm
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150 mm
Correct Answer
A. 75 mmExplanation
The minimum concrete cover cast against and permanently exposed to earth is 75 mm. This means that when concrete is used in construction and is in direct contact with the earth, there must be a minimum thickness of 75 mm of concrete covering it. This is important to protect the reinforcement bars within the concrete from corrosion and damage caused by exposure to moisture and other elements present in the earth. A thinner cover may not provide sufficient protection, while a thicker cover may be unnecessary and result in wastage of materials.Rate this question:
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- 14.
The minimum clear concrete covering for cast in place slab: (NSCP 407.8.1)
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20mm
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25mm
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40mm
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50mm
Correct Answer
A. 20mmExplanation
The minimum clear concrete covering for a cast-in-place slab is 20mm. This means that there should be at least 20mm of concrete covering the reinforcement bars in the slab to ensure proper protection and durability. This requirement is specified in the NSCP (National Structural Code of the Philippines) in section 407.8.1.Rate this question:
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- 15.
In ultimate strength design, the strength reduction factor Ø for flexure without axial loads: (NSCP 409.2.1)
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0.85
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0.75
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0.90
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0.70
Correct Answer
A. 0.90Explanation
In ultimate strength design, the strength reduction factor Ø is used to reduce the calculated strength of a member to account for uncertainties and safety factors. A higher reduction factor implies a more conservative design approach, as it reduces the strength of the member further. Therefore, a reduction factor of 0.90 indicates that the calculated strength of the member without axial loads should be reduced by 10% to ensure a safe design.Rate this question:
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- 16.
In ultimate strength design, the strength reduction factor Ø for shear and torsion: (NSCP 409.4.2.3)
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0.70
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0.75
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0.85
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0.90
Correct Answer
A. 0.85Explanation
In ultimate strength design, the strength reduction factor Ø for shear and torsion is 0.85. This factor is used to reduce the calculated strength of a structural element in order to provide a safety margin and account for uncertainties in material properties and construction methods. A reduction factor of 0.85 means that the actual strength of the element is considered to be 85% of its calculated strength. This ensures that the structure is designed to safely withstand the expected loads and prevent failure.Rate this question:
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- 17.
The minimum one way slab thickness for a ONE end continuous slab is: (NSCP 409.6.2)
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L/20
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L/24
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L/10
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L/28
Correct Answer
A. L/24Explanation
The correct answer for the minimum one-way slab thickness for a one-end continuous slab is L/24. This is in accordance with NSCP 409.6.2, which specifies that the minimum thickness should be L/24, where L is the clear span of the slab.Rate this question:
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- 18.
The minimum one way slab thickness for a BOTH ends continuous slab is: (NSCP 409.6.2)
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L/20
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L/24
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L/10
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L/28
Correct Answer
A. L/28Explanation
The correct answer is L/28. According to NSCP 409.6.2, the minimum one-way slab thickness for a both ends continuous slab is L/28. This means that the slab thickness should be equal to or greater than the span length divided by 28. This requirement ensures that the slab is strong enough to support the imposed loads and prevents excessive deflection.Rate this question:
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- 19.
The minimum cantilevered slab thickness is : (NSCP 409.6.2)
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L/20
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L/24
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L/10
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L/28
Correct Answer
A. L/10Explanation
The correct answer is L/10. According to NSCP 409.6.2, the minimum cantilevered slab thickness should be L/10. This means that the thickness of the slab should be equal to the length of the cantilever divided by 10. This requirement ensures that the cantilevered slab has sufficient strength and stability to support the load and prevent any deflection or failure. A thicker slab will provide better support and minimize the risk of structural issues.Rate this question:
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- 20.
Deep continuous flexural members has overall depth to clear span ratio greater than: (NSCP 410.8.10)
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0.40
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0.60
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0.75
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0.70
Correct Answer
A. 0.40 -
- 21.
Deep simple span flexural members has overall depth to clear span ratio greater than: (NSCP 307.4.2)
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0.40
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0.60
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0.75
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0.70
Correct Answer
A. 0.75 -
- 22.
Spacing of shear reinforcement placed perpendicular to axis of non-prestressed member shall not exceed: (NSCP 411.6.4.1)
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D/2
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D/4
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¾ d
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D/5
Correct Answer
A. D/2 -
- 23.
Is an essentially vertical truss system of the concentric or eccentric type that is provided to resist lateral forces: (NCSP 208.1)
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Building frame system
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Braced frame
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Diaphragm
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Collector
Correct Answer
A. Braced frame -
- 24.
Is a frame in which members and joints are capable of resisting forces primarily by flexure:
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Moment resisting frame
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Ordinary braced frame
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Truss
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Eccentric braced frame
Correct Answer
A. Moment resisting frame -
- 25.
. In the determination of seismic dead load with a minimum of ________% of floor live load shall be applicable for storage and warehouse occupancies. (NSCP 208.5.1.1)
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50%
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25%
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30%
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35%
Correct Answer
A. 25% -
- 26.
The slope of cut surfaces shall be no steeper than _______% slope. (NSCP 302.2.2)
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50%
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60%
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30%
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40%
Correct Answer
A. 50%Explanation
According to NSCP 302.2.2, the slope of cut surfaces should not exceed 50%. This means that any cut surfaces, such as those created during excavation or construction, should have a maximum slope of 50% to ensure stability and prevent erosion. A steeper slope could lead to instability, landslides, or other safety hazards. Therefore, it is important to adhere to this guideline to maintain the integrity and safety of the cut surfaces.Rate this question:
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Current Version
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Mar 22, 2023Quiz Edited by
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Feb 22, 2009Quiz Created by
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