Straight Motion For Grade 7

1. Look at the picture below!

Speed in that picture is ... .

200 km/h

140 mph

180 km/h

160 mph

not-available-via-ai

Explanation

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2. Sebuah mobil bergerak ditunjukkan dengan grafik di bawah ini, kecepatan yang ditempuh bus adalah … .

1 m/s

2 m/s

4 m/s

6 m/s

The graph shows a straight horizontal line, indicating that the velocity of the car is constant. Since the graph does not show any change in velocity, it can be concluded that the speed of the car is 1 m/s.

Explanation

The graph shows a straight horizontal line, indicating that the velocity of the car is constant. Since the graph does not show any change in velocity, it can be concluded that the speed of the car is 1 m/s.

3. Yoga berlari mengelilingi lapangan sambil mengenakan sepatu. Pernyataan yang benar adalah … . lari

Sepatu diam terhadap Yoga

Sepatu bergerak terhadap Yoga

Yoga bergerak terhadap sepatu

Yoga diam terhadap penonton

The correct answer is "Sepatu diam terhadap Yoga". This means that the shoes are stationary or not moving in relation to Yoga. The sentence implies that Yoga is the one who is moving around the field while wearing the shoes.

Explanation

The correct answer is "Sepatu diam terhadap Yoga". This means that the shoes are stationary or not moving in relation to Yoga. The sentence implies that Yoga is the one who is moving around the field while wearing the shoes.

4. Jarak antara rumah Wima dan Dhiva adalah 5 km. Wima berangkat dari rumah pukul 09.00 WIB menuju rumah Dhiva mengendarai sepeda dengan kecepatan rata-rata 20 km/jam. Wima akan tiba di rumah Dhiva pukul … .

09.05 WIB

09.10 WIB

09.15 WIB

09.20 WIB

Wima berangkat pada pukul 09.00 WIB dan kecepatan rata-ratanya adalah 20 km/jam. Jarak antara rumah Wima dan Dhiva adalah 5 km. Untuk menentukan waktu yang dibutuhkan oleh Wima untuk tiba di rumah Dhiva, kita dapat menggunakan rumus waktu yang ditempuh = jarak / kecepatan. Dalam hal ini, waktu yang dibutuhkan = 5 km / 20 km/jam = 0.25 jam = 15 menit. Jadi, Wima akan tiba di rumah Dhiva pada pukul 09.15 WIB.

Explanation

Wima berangkat pada pukul 09.00 WIB dan kecepatan rata-ratanya adalah 20 km/jam. Jarak antara rumah Wima dan Dhiva adalah 5 km. Untuk menentukan waktu yang dibutuhkan oleh Wima untuk tiba di rumah Dhiva, kita dapat menggunakan rumus waktu yang ditempuh = jarak / kecepatan. Dalam hal ini, waktu yang dibutuhkan = 5 km / 20 km/jam = 0.25 jam = 15 menit. Jadi, Wima akan tiba di rumah Dhiva pada pukul 09.15 WIB.

5. Berikut ini merupakan gerak benda.

Bola yang jatuh bebas ke tanah.
Bola menggelinding di atas pasir.
Bola menuruni bidang miring.
Bola yang dilempar vertikal ke atas.

Yang termasuk gerak lurus berubah beraturan dipercepat terdapat pada pernyataan nomor … .

1 dan 2

1 dan 3

2 dan 3

2 dan 4

The correct answer is 1 dan 3 because both statement 1 (Bola yang jatuh bebas ke tanah) and statement 3 (Bola menuruni bidang miring) describe objects undergoing motion that can be categorized as "gerak lurus berubah beraturan dipercepat" or "uniformly accelerated rectilinear motion". In both cases, the objects are experiencing acceleration due to the force of gravity. In statement 1, the ball is falling freely towards the ground, while in statement 3, the ball is rolling down a sloping surface.

Explanation

The correct answer is 1 dan 3 because both statement 1 (Bola yang jatuh bebas ke tanah) and statement 3 (Bola menuruni bidang miring) describe objects undergoing motion that can be categorized as "gerak lurus berubah beraturan dipercepat" or "uniformly accelerated rectilinear motion". In both cases, the objects are experiencing acceleration due to the force of gravity. In statement 1, the ball is falling freely towards the ground, while in statement 3, the ball is rolling down a sloping surface.

6. Look at the picture below!

The above experiments indicate that the "peti" is … .

Uniform motion

Uniformly accelerated motion

Uniformly decelerated motion

Changing acceleration

The picture shows a graph with a straight line that slopes downward from left to right. This indicates that the object's velocity is decreasing at a constant rate over time. Therefore, the motion can be described as uniformly decelerated.

Explanation

The picture shows a graph with a straight line that slopes downward from left to right. This indicates that the object's velocity is decreasing at a constant rate over time. Therefore, the motion can be described as uniformly decelerated.

7. Look at the picture of ticker tape below!

The resulting pattern shows that a body moves in a … .

Uniform motion

Uniformly accelerated motion

Uniformly decelerated motion

Changing acceleration

The resulting pattern on the ticker tape shows a series of equally spaced dots, indicating that the body is moving with a constant acceleration. This means that its velocity is changing at a constant rate over time. If the body was moving with uniform motion, the dots on the ticker tape would be equally spaced but with no change in velocity. If the body was moving with uniformly decelerated motion, the dots would be spaced closer together over time. Therefore, the correct answer is uniformly accelerated motion.

Explanation

The resulting pattern on the ticker tape shows a series of equally spaced dots, indicating that the body is moving with a constant acceleration. This means that its velocity is changing at a constant rate over time. If the body was moving with uniform motion, the dots on the ticker tape would be equally spaced but with no change in velocity. If the body was moving with uniformly decelerated motion, the dots would be spaced closer together over time. Therefore, the correct answer is uniformly accelerated motion.

8. Sebuah mobil dengan kecepatan awal 10 m/s menabrak tumpukan peti seperti animasi berikut.

Selang waktu hingga mobil itu berhenti adalah 20 detik. Maka, perlambatan mobil adalah ... .

0,5

1,0

1,5

2,0

The correct answer is 0,5. The explanation for this answer is that the question states that the car stops after 20 seconds. To find the acceleration, we can use the formula a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time taken. In this case, the initial velocity is 10 m/s, the final velocity is 0 m/s (since the car stops), and the time taken is 20 seconds. Plugging these values into the formula, we get a = (0 - 10) / 20 = -10/20 = -0.5 m/s^2. Since acceleration is defined as a positive value, the acceleration is 0.5 m/s^2.

Explanation

The correct answer is 0,5. The explanation for this answer is that the question states that the car stops after 20 seconds. To find the acceleration, we can use the formula a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time taken. In this case, the initial velocity is 10 m/s, the final velocity is 0 m/s (since the car stops), and the time taken is 20 seconds. Plugging these values into the formula, we get a = (0 - 10) / 20 = -10/20 = -0.5 m/s^2. Since acceleration is defined as a positive value, the acceleration is 0.5 m/s^2.

9. Daniel Pedrosa mengendarai sepeda motor ke arah barat sejauh 20 km, kemudian berbalik arah ke timur sejauh 12 km. Maka, perpindahan yang ditempuh Daniel Pedrosa adalah … .

8 km

8 km ke arah barat

8 km ke arah timur

32 km

Daniel Pedrosa mengendarai sepeda motor ke arah barat sejauh 20 km, kemudian berbalik arah ke timur sejauh 12 km. Jadi, perpindahan yang ditempuh Daniel Pedrosa adalah 8 km ke arah barat. Ini dapat dihitung dengan mengurangi jarak yang ditempuh ke arah timur (12 km) dari jarak yang ditempuh ke arah barat (20 km), sehingga 20 km - 12 km = 8 km.

Explanation

Daniel Pedrosa mengendarai sepeda motor ke arah barat sejauh 20 km, kemudian berbalik arah ke timur sejauh 12 km. Jadi, perpindahan yang ditempuh Daniel Pedrosa adalah 8 km ke arah barat. Ini dapat dihitung dengan mengurangi jarak yang ditempuh ke arah timur (12 km) dari jarak yang ditempuh ke arah barat (20 km), sehingga 20 km - 12 km = 8 km.

10. The car moves with a velocity of 20 m/s, then its velocity increases to 60 m/s in 5 seconds. The acceleration of the car is … .

2

4

6

8

The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 60 m/s, the initial velocity is 20 m/s, and the time is 5 seconds. Plugging in these values into the formula, we get: acceleration = (60 m/s - 20 m/s) / 5 seconds = 8 m/s². Therefore, the acceleration of the car is 8 m/s².

Explanation

The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 60 m/s, the initial velocity is 20 m/s, and the time is 5 seconds. Plugging in these values into the formula, we get: acceleration = (60 m/s - 20 m/s) / 5 seconds = 8 m/s². Therefore, the acceleration of the car is 8 m/s².