Straight Motion For Grade 7

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By Tiari
T
Tiari
Community Contributor
Quizzes Created: 1 | Total Attempts: 252
| Attempts: 252
SettingsSettings
Please wait...
  • 1/10 Questions

    Look at the picture below! Speed in that picture is ... .

    • 200 km/h
    • 140 mph
    • 180 km/h
    • 160 mph
Please wait...
About This Quiz

Kerjakan kuis berikut ini dengan teliti! Success for your exam!

Straight Motion For Grade 7 - Quiz

Quiz Preview

  • 2. 

    Sebuah mobil bergerak ditunjukkan dengan grafik di bawah ini, kecepatan yang ditempuh bus adalah … .

    • 1 m/s

    • 2 m/s

    • 4 m/s

    • 6 m/s

    Correct Answer
    A. 1 m/s
    Explanation
    The graph shows a straight horizontal line, indicating that the velocity of the car is constant. Since the graph does not show any change in velocity, it can be concluded that the speed of the car is 1 m/s.

    Rate this question:

  • 3. 

    Yoga berlari mengelilingi lapangan sambil mengenakan sepatu. Pernyataan yang benar adalah … .

    • Sepatu diam terhadap Yoga

    • Sepatu bergerak terhadap Yoga

    • Yoga bergerak terhadap sepatu

    • Yoga diam terhadap penonton

    Correct Answer
    A. Sepatu diam terhadap Yoga
    Explanation
    The correct answer is "Sepatu diam terhadap Yoga". This means that the shoes are stationary or not moving in relation to Yoga. The sentence implies that Yoga is the one who is moving around the field while wearing the shoes.

    Rate this question:

  • 4. 

    Jarak antara rumah Wima dan Dhiva adalah 5 km. Wima berangkat dari rumah pukul 09.00 WIB menuju rumah Dhiva mengendarai sepeda dengan kecepatan rata-rata 20 km/jam. Wima akan tiba di rumah Dhiva pukul … .

    • 09.05 WIB

    • 09.10 WIB

    • 09.15 WIB

    • 09.20 WIB

    Correct Answer
    A. 09.15 WIB
    Explanation
    Wima berangkat pada pukul 09.00 WIB dan kecepatan rata-ratanya adalah 20 km/jam. Jarak antara rumah Wima dan Dhiva adalah 5 km. Untuk menentukan waktu yang dibutuhkan oleh Wima untuk tiba di rumah Dhiva, kita dapat menggunakan rumus waktu yang ditempuh = jarak / kecepatan. Dalam hal ini, waktu yang dibutuhkan = 5 km / 20 km/jam = 0.25 jam = 15 menit. Jadi, Wima akan tiba di rumah Dhiva pada pukul 09.15 WIB.

    Rate this question:

  • 5. 

    Berikut ini merupakan gerak benda.
    1. Bola yang jatuh bebas ke tanah.
    2. Bola menggelinding di atas pasir.
    3. Bola menuruni bidang miring.
    4. Bola yang dilempar vertikal ke atas.
    Yang termasuk gerak lurus berubah beraturan dipercepat terdapat pada pernyataan nomor … .

    • 1 dan 2

    • 1 dan 3

    • 2 dan 3

    • 2 dan 4

    Correct Answer
    A. 1 dan 3
    Explanation
    The correct answer is 1 dan 3 because both statement 1 (Bola yang jatuh bebas ke tanah) and statement 3 (Bola menuruni bidang miring) describe objects undergoing motion that can be categorized as "gerak lurus berubah beraturan dipercepat" or "uniformly accelerated rectilinear motion". In both cases, the objects are experiencing acceleration due to the force of gravity. In statement 1, the ball is falling freely towards the ground, while in statement 3, the ball is rolling down a sloping surface.

    Rate this question:

  • 6. 

    Look at the picture of ticker tape below! The resulting pattern shows that a body moves in a … .

    • Uniform motion

    • Uniformly accelerated motion

    • Uniformly decelerated motion

    • Changing acceleration

    Correct Answer
    A. Uniformly accelerated motion
    Explanation
    The resulting pattern on the ticker tape shows a series of equally spaced dots, indicating that the body is moving with a constant acceleration. This means that its velocity is changing at a constant rate over time. If the body was moving with uniform motion, the dots on the ticker tape would be equally spaced but with no change in velocity. If the body was moving with uniformly decelerated motion, the dots would be spaced closer together over time. Therefore, the correct answer is uniformly accelerated motion.

    Rate this question:

  • 7. 

    Look at the picture below! The above experiments indicate that the "peti" is … .

    • Uniform motion

    • Uniformly accelerated motion

    • Uniformly decelerated motion

    • Changing acceleration

    Correct Answer
    A. Uniformly decelerated motion
    Explanation
    The picture shows a graph with a straight line that slopes downward from left to right. This indicates that the object's velocity is decreasing at a constant rate over time. Therefore, the motion can be described as uniformly decelerated.

    Rate this question:

  • 8. 

    Daniel Pedrosa mengendarai sepeda motor ke arah barat sejauh 20 km, kemudian berbalik arah ke timur sejauh 12 km. Maka, perpindahan yang ditempuh Daniel Pedrosa adalah … .

    • 8 km

    • 8 km ke arah barat

    • 8 km ke arah timur

    • 32 km

    Correct Answer
    A. 8 km ke arah barat
    Explanation
    Daniel Pedrosa mengendarai sepeda motor ke arah barat sejauh 20 km, kemudian berbalik arah ke timur sejauh 12 km. Jadi, perpindahan yang ditempuh Daniel Pedrosa adalah 8 km ke arah barat. Ini dapat dihitung dengan mengurangi jarak yang ditempuh ke arah timur (12 km) dari jarak yang ditempuh ke arah barat (20 km), sehingga 20 km - 12 km = 8 km.

    Rate this question:

  • 9. 

    Sebuah mobil dengan kecepatan awal 10 m/s menabrak tumpukan peti seperti animasi berikut.   Selang waktu hingga mobil itu berhenti adalah 20 detik. Maka, perlambatan mobil adalah ... .

    • 0,5 

    • 1,0 

    • 1,5 

    • 2,0 

    Correct Answer
    A. 0,5 
    Explanation
    The correct answer is 0,5. The explanation for this answer is that the question states that the car stops after 20 seconds. To find the acceleration, we can use the formula a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time taken. In this case, the initial velocity is 10 m/s, the final velocity is 0 m/s (since the car stops), and the time taken is 20 seconds. Plugging these values into the formula, we get a = (0 - 10) / 20 = -10/20 = -0.5 m/s^2. Since acceleration is defined as a positive value, the acceleration is 0.5 m/s^2.

    Rate this question:

  • 10. 

    The car moves with a velocity of 20 m/s, then its velocity increases to 60 m/s in 5 seconds. The acceleration of the car is … .

    Correct Answer
    A. 8 
    Explanation
    The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. In this case, the final velocity is 60 m/s, the initial velocity is 20 m/s, and the time is 5 seconds. Plugging in these values into the formula, we get: acceleration = (60 m/s - 20 m/s) / 5 seconds = 8 m/s². Therefore, the acceleration of the car is 8 m/s².

    Rate this question:

Quiz Review Timeline (Updated): Jul 22, 2024 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Jul 22, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Jun 07, 2013
    Quiz Created by
    Tiari
Back to Top Back to top
Advertisement