Quadratic Equations Practice Test Questions And Answers - Quiz

The given equation is a quadratic equation of the form ax^2 + bx + c = 0. By factoring or using the quadratic formula, we can find the values of x that satisfy the equation. In this case, the equation can be factored as (x - 7)(x + 7) = 0, which means that x = 7 and x = -7 are the solutions to the equation.

The given equation is a quadratic equation. To find the values of x, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

where a = -1, b = 2, and c = 48.

Substituting these values into the quadratic formula, we get:

x = (-2 ± √(2² - 4 * -1 * 48)) / 2 * -1 x = (-2 ± √(4 + 192)) / -2 x = (-2 ± √196) / -2 x = (-2 ± 14) / -2

This gives us two possible solutions:

x = (-2 + 14) / -2 = 12 / -2 = -6 x = (-2 - 14) / -2 = -16 / -2 = 8

Therefore, the values of x that satisfy the equation are x = 8 and x = -6.

The given quadratic function is in the form of f(x) = x^2 - 8x + 15. To find the axis of symmetry, we can use the formula x = -b/2a, where a, b, and c are coefficients of the quadratic equation. In this case, a = 1 and b = -8. Substituting these values into the formula, we get x = -(-8)/2(1), which simplifies to x = 4. Therefore, the correct answer is "Axis: x=4".

To find the range of the function, we need to determine the set of all possible y-values that the function can produce. Since the coefficient of x^2 is positive, the parabola opens upward and the minimum value occurs at the vertex. The y-coordinate of the vertex can be found by substituting the x-coordinate of the axis of symmetry (4) into the function. f(4) = (4)^2 - 8(4) + 15 = 16 - 32 + 15 = -1. Hence, the range of the function is (-1, infinity). Therefore, the correct answer is "Range: (-1, infinity)".

The vertex of a quadratic equation in the form of y = ax^2 + bx + c is given by the coordinates (-b/2a, f(-b/2a)). In this equation, a = 1, b = -8, and c = 15. Plugging these values into the formula, we get (-(-8)/2(1), f(-(-8)/2(1))). Simplifying further, we get (4, f(4)). To find the y-coordinate, we substitute x = 4 into the equation: 4^2 - 8(4) + 15 = 1. Therefore, the vertex is (4, -1).

The vertex of a quadratic equation in the form of y = ax^2 + bx + c can be found using the formula x = -b/2a. In this equation, a = -1 and b = -9. Plugging these values into the formula, we get x = -(-9)/2(-1) = 9/-2 = -4.5. To find the y-coordinate of the vertex, we substitute this value of x back into the equation: y = -(-4.5)^2 - 9(-4.5) - 8 = -20.25 + 40.5 - 8 = 12.25. Therefore, the vertex is (-4.5, 12.25). 

For the given quadratic function  -x² + 2x + 8 = 0, it forms a downward-opening parabola. This means that the highest point of the parabola, known as the vertex, represents the maximum value of the function.

By calculating the vertex of the parabola, we find that it occurs at the point (1, 9), where the x-coordinate is 1 and the y-coordinate (or function value) is 9.

Since the parabola opens downwards, the maximum value of the function is 9. Therefore, the range of the function consists of all real numbers less than or equal to 9. In simpler terms, the function's range includes all values from negative infinity up to and including 9.

The function -x^2 + 2x + 8 = 0 is a quadratic equation. The domain of a quadratic equation is always the set of all real numbers, which means that the function is defined for any value of x. Therefore, the correct answer is (-infinity, infinity).