Soal Biologi IPA Kelas Ix Smp

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  • 1/10 Questions

    Tujuan dari paus secara periodik naik kepermukaan adalah..

    • Mengambil udara untuk bernafas
    • Mengejar ikan kecil untuk dimangsa
    • Mengatur tekanan udara dalam tubuh
    • Menjaga agar kadar air tubuhnya stabil
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  • 2. 

    Perhatikan kelainan penyakit berikut!1. Anemia2.Varises3.Leukemia4. Arteriosklerosis5.Haemofoliakelainan penyakit yang berhubungan dengan sel darah adalah...

    • 1,2 dan 3

    • 1,3 dan 5

    • 2,4 dan 5

    • 3,4 dan 5

    Correct Answer
    A. 1,3 dan 5
    Explanation
    The correct answer is 1,3 dan 5. The question asks for the abnormalities related to blood cells. Anemia is a condition characterized by a decrease in red blood cells or hemoglobin, which can lead to fatigue and weakness. Leukemia is a type of cancer that affects the white blood cells, causing an abnormal increase in their production. Hemophilia is a genetic disorder that affects the blood's ability to clot, leading to excessive bleeding. Therefore, options 1, 3, and 5 are the correct choices as they all involve abnormalities related to blood cells.

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  • 3. 

    Hasil augmentasi pada proses pembentukan urine pada nefron ginjal adalah...

    • Fitrat tubulus

    • Fitrat glumerulus

    • Urine sekunder

    • Urine sesungguhnya

    Correct Answer
    A. Urine sesungguhnya
    Explanation
    The correct answer is "urine sesungguhnya". In the process of urine formation in the renal nephron, the final product is the true urine. This is the urine that is excreted from the body, containing waste products, excess water, and electrolytes. The other options mentioned, such as tubular filtrate and glomerular filtrate, are intermediate stages in the urine formation process. The true urine is formed after reabsorption and secretion processes occur in the renal tubules.

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  • 4. 

    Perhatikan data berikut!1. rongga paru-paru membesar 2. tekanan udara pada paru-paru3. kontraksi otot diafragma mendatar4. udara dalam paru-paru keluarfase ekspirasi pada pernafasan perut ditunjukkan oleh nomer...

    • 1,2 dan 3

    • 1,2 dan 4

    • 2,3 dan 4

    • 3,4 dan 1

    Correct Answer
    A. 2,3 dan 4
    Explanation
    The correct answer is 2, 3, and 4. This is because during the expiratory phase of abdominal breathing, the following events occur: 2) the pressure in the lungs increases, 3) the diaphragm contracts and moves downward, and 4) the air in the lungs is expelled. These actions contribute to the process of exhaling air from the lungs.

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  • 5. 

    Faktor eksternal yang mempengaruhi  proses pertumbuhan dan perkembangan pada tumbuhan diantaranya adalah..

    • Genetik dan hormon

    • Hormon dan nutrisi

    • Nutrisi dan kelembaban

    • Suhu dan genetik

    Correct Answer
    A. Nutrisi dan kelembaban
    Explanation
    Nutrisi dan kelembaban adalah faktor eksternal yang mempengaruhi proses pertumbuhan dan perkembangan pada tumbuhan. Nutrisi yang cukup dan seimbang diperlukan oleh tumbuhan untuk melakukan proses fotosintesis dan sintesis zat-zat penting lainnya. Kelembaban juga penting karena tumbuhan membutuhkan air untuk melakukan proses fotosintesis dan menjaga keseimbangan air dalam tubuhnya. Faktor-faktor lain seperti genetik, hormon, dan suhu juga mempengaruhi pertumbuhan dan perkembangan tumbuhan, tetapi dalam konteks pertanyaan ini, nutrisi dan kelembaban adalah jawaban yang paling tepat.

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  • 6. 

    Reaksi kimia fotosintesis yang benar adalah..

    • 6CO2+6 H2O - C6H12O6+6O2

    • 6CO2+6O2 - 6C6H12O6+6H2O

    • 6C6H12O6+6H2O - 6CO2+6O2

    • 6CO2+H2O - 6C6H12O6+6O2

    Correct Answer
    A. 6CO2+6 H2O - C6H12O6+6O2
    Explanation
    The correct answer is 6CO2+6 H2O - C6H12O6+6O2. This equation represents the balanced chemical reaction for photosynthesis, where carbon dioxide (CO2) and water (H2O) react to form glucose (C6H12O6) and oxygen (O2). This equation follows the law of conservation of mass, as the number of atoms of each element is the same on both sides of the equation.

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  • 7. 

    Mikroba yang dimanfaatkan dalam pembuatan produk keju adalah...

    • Lactobacillus plantarum

    • Lactobacillus lacris

    • Aspergillus soyae

    • Saccaromyces cereviceae

    Correct Answer
    A. Lactobacillus plantarum
    Explanation
    Lactobacillus plantarum is a type of bacteria that is commonly used in the production of cheese. This bacteria plays a crucial role in the fermentation process of milk, where it helps convert lactose into lactic acid. The production of lactic acid is important for the development of the desired texture, flavor, and aroma of cheese. Lactobacillus plantarum also helps in inhibiting the growth of harmful bacteria, contributing to the safety and shelf life of the cheese. Therefore, it is an essential microorganism utilized in the making of cheese.

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  • 8. 

    Contoh interaksi antara dua makhluk  hidup berikuat yang merupakan simbiosis komensalisme adalah.. 

    • Bakteri patogen dengan jamur Pennicillium notatum

    • Interaksi yang erat antara harimau dengan rusa

    • Tanaman Azzola pinata dengan bakteri nitrogen

    • Tanaman paku dengan inang yang ditumpangi

    Correct Answer
    A. Tanaman paku dengan inang yang ditumpangi
    Explanation
    The correct answer is "tanaman paku dengan inang yang ditumpangi". This is an example of commensalism symbiosis because the fern plant benefits by using the host plant for support, while the host plant is neither harmed nor benefited.

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  • 9. 

    Persilangan antara tanaman ercisberbiji bulat dengan tanaman ercis berbiji kerut menghasilkan tanaman ercis berbiji bulat. Apabila F1 disilangkan dengan sesamanya maka akan diperoleh perbandingan fenotip F2..

    • 1:1

    • 1:2

    • 2:1

    • 3:1

    Correct Answer
    A. 2:1
    Explanation
    The given information states that crossing a round-seeded pea plant with a wrinkled-seeded pea plant produces a round-seeded pea plant. When the F1 generation is crossed with itself, the phenotypic ratio in the F2 generation is 2:1. This means that for every 2 plants with the round seed phenotype, there is 1 plant with the wrinkled seed phenotype.

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  • 10. 

    Perhatikan contoh gerakan pada tumbuhan berikut ini !1. Pecahnya polong biji kacang-kacangan yang sudah dewasa saat udara kering2. Tanaman putri malu akan mekar bunganya saat disentuh3. Arah tumbuh ujung kecambah menuju cahaya4. Gerakan membuka daun tanaman bunga pukul empat menjelang petangperubahan ini disebabkan karena rangsangan suasana gelap. pernyataan diatas yang sesuai ditunjuk pada nomor... 

    • 1 dan 2

    • 1 dan 3

    • 2 dan 3

    • 2 dan 4

    Correct Answer
    A. 2 dan 4
    Explanation
    The correct answer is 2 and 4. This is because in option 2, the plant mimosa pudica (putri malu) exhibits a response called thigmonasty, where its leaves fold up when touched. This is a direct response to a stimulus. In option 4, certain plants like the evening primrose (tanaman bunga pukul empat) exhibit nyctinasty, where their flowers open in the evening and close during the day. This is also a direct response to a stimulus, in this case, darkness. Therefore, both options 2 and 4 involve plant movements that are triggered by specific stimuli.

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  • Jul 22, 2024
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  • Jan 20, 2015
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