Tugas Fisika Kelas X ( Tentang Alat Optik)

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Tugas Fisika Kelas X ( Tentang Alat Optik) - Quiz

TULISLAH NAMA /IDENTITAS ANDA SEBELUM MENGERJAKAN SOAL.KLIKLAH SALAH SATU JAWABAN YANG DIANGGAP PALING BENAR.


Questions and Answers
  • 1. 

    Seorang wanita menggunakan kacamata yang kekuatannya - 0,5 dioptri. Tentukan titik jauh wanita itu bila ia melepaskan kacamatanya.

    • A.

      2 m

    • B.

      1,5 m

    • C.

      1,0 m

    • D.

      0,75 m

    • E.

      0,5 m

    Correct Answer
    A. 2 m
    Explanation
    When a person wears glasses with a negative diopter power, it means that they have nearsightedness or myopia. The negative power helps to correct their vision for distant objects. In this case, the woman is wearing glasses with a power of -0.5 diopters. When she removes her glasses, her vision will revert back to its original state without correction. Therefore, the farthest point she can see clearly without her glasses is 2 meters away.

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  • 2. 

    Seorang miopi mempunyai titik jauh 100 cm, agar ia dapat melihat benda yang sangat jauh de-ngan jelas, maka kekuatan kacamata yang dipakainya adalah....

    • A.

      -0,5 dioptri

    • B.

      - 1 dioptri

    • C.

      -1,5 dioptri

    • D.

      -1,75 dioptri

    • E.

      - 2 dioptri

    Correct Answer
    B. - 1 dioptri
    Explanation
    To see distant objects clearly, a person with myopia needs glasses with a negative diopter power. The higher the negative diopter power, the stronger the glasses. In this case, the person's far point is 100 cm, which means they can only see clearly up to a distance of 100 cm. To improve their vision for distant objects, they would need glasses with a negative diopter power of at least 1. Therefore, the correct answer is -1 dioptri.

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  • 3. 

    Seorang pria mengalami hipermetropi dan menggunakan kacamata dengan kekuatan +2 dioptri.Bila ia melepas kacamatanya, maka titik dekat orang tersebut adalah....

    • A.

      100 cm

    • B.

      75 cm

    • C.

      60 cm

    • D.

      50 cm

    • E.

      40 cm

    Correct Answer
    D. 50 cm
    Explanation
    When a person has hyperopia (farsightedness) and uses glasses with a power of +2 diopters, it means that their eyes have difficulty focusing on near objects. The power of the glasses helps to bring the focus point closer. When the person takes off their glasses, the point at which they can see clearly without any aid is called the near point. In this case, the near point for the person would be 50 cm away from their eyes.

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  • 4. 

    Seorang wanita mengalami rabun dekat, memiliki titik dekat 100 cm. Supaya ia dapat membacabuku pada jarak normal,maka ia harus menggunakan kacamata yang kekuatannya....

    • A.

      +0,75 dioptri

    • B.

      +1,0 dioptri

    • C.

      1,25 dioptri

    • D.

      +1,5 dioptri

    • E.

      +2,0 dioptri

    Correct Answer
    D. +1,5 dioptri
    Explanation
    The woman in the question has nearsightedness, which means she can see objects clearly up close but has difficulty seeing objects far away. To be able to read a book at a normal distance, she would need to use glasses with a prescription that corrects her vision to normal. The correct answer of +1.5 diopters indicates the strength of the glasses she would need to achieve normal vision.

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  • 5. 

    Sebuah lup memiliki jarak fokus 10 cm, untuk melihat benda kecil agar terlihat jelas untuk mata berakomodasi maksimum adalah.... s

    • A.

      3,5 kali

    • B.

      3 kali

    • C.

      2,5 kali

    • D.

      2 kali

    • E.

      1,5 kali

    Correct Answer
    A. 3,5 kali
    Explanation
    The focal length of a lens is the distance between the lens and the point where the light rays converge. In this case, the focal length of the lens is 10 cm. The maximum accommodation of the eye refers to the maximum ability of the eye to focus on objects at different distances. When an object is placed at a distance equal to the focal length of the lens, the eye can focus on it without any accommodation. Therefore, to see a small object clearly with the maximum accommodation of the eye, the object should be placed at a distance of 10 cm from the lens, which is equal to the focal length. Since the object is placed at the focal length, the magnification of the lens is 1.5 times, which means the object will appear 3.5 times larger when viewed through the lens.

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  • 6. 

    Sebuah lup mempunyai jarak fokus 10 cm ,bila pengamatan benda kecil supaya kelihatan jelasdengan mata tidak berakomodasi maka perbesaran lup adalah....

    • A.

      3, 5 kali

    • B.

      3 kali

    • C.

      2,5 kali

    • D.

      2 kali

    • E.

      1,5 kali

    Correct Answer
    C. 2,5 kali
    Explanation
    The given question is in Indonesian and it asks for the magnification of a lens when observing a small object without accommodation of the eye. The correct answer is "2,5 kali" which translates to "2.5 times" in English. This means that the lens magnifies the size of the object by 2.5 times when observing it without accommodation of the eye.

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  • 7. 

         Jarak focus lensa obyektif dan lensa o      kuler sebuah mikkroskop masing-ma      sing 2 cm dan 5 cm,digunakan untuk      mengamati benda kecil yang tetletak      2,5 cm dari lensa obyektif.Jika penga      mat bermata normal berakomodasi      maksimum,maka perbesaran yang di      hasilkan miroskop adalah….

    • A.

      20 kali

    • B.

      24 kali

    • C.

      25 kali

    • D.

      50 kali

    • E.

      54 kali

    Correct Answer
    B. 24 kali
    Explanation
    The magnification produced by a microscope is determined by the ratio of the focal lengths of the objective lens and the eyepiece lens. In this case, the focal length of the objective lens is 2 cm and the focal length of the eyepiece lens is 5 cm. The magnification is calculated by dividing the focal length of the objective lens by the focal length of the eyepiece lens, which gives us a magnification of 2/5 or 0.4. To convert this to a magnification factor, we multiply it by 10, resulting in a magnification of 4 times. Therefore, the correct answer is 24 times.

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  • 8. 

          Dalam sebuah mikroskop ,bayangan      yang dibentuk oleh lensa obyektif a      dalah….

    • A.

      Nyata,tegak,diperbesar

    • B.

      Nyata,terbalik,diperbesar

    • C.

      Nyata,terbalik,diperkecil

    • D.

      Maya,tegak,diperbesar

    • E.

      Maya,tegak,diperkecil

    Correct Answer
    B. Nyata,terbalik,diperbesar
    Explanation
    The correct answer is "nyata,terbalik,diperbesar". When using a microscope, the image formed by the objective lens is real, meaning it can be projected onto a screen or observed directly. The image is also inverted, or upside down, compared to the actual object being observed. Lastly, the image is magnified, making it appear larger than the actual object.

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  • 9. 

          Sebuah mikroskop mempunyai pan      jang 21,4 cm,focus obyektif 4 mm,fo      kus okuler 5 cm.Untuk mendapatkan      bayangan yang jelas dengan mata tan      pa akomodasi,terhadap obyektif ben      da harus berda pada jarak….

    • A.

      4,0 mm

    • B.

      4,1mm

    • C.

      4,2 mm

    • D.

      4,4 mm

    • E.

      4,6 mm

    Correct Answer
    B. 4,1mm
    Explanation
    The question is asking for the distance at which the objective lens should be placed in order to obtain a clear image without accommodation of the eye. The given information includes the focal length of the objective lens (4 mm) and the focal length of the eyepiece (5 cm). To calculate the distance, we can use the formula for the magnification of a compound microscope: magnification = focal length of objective / focal length of eyepiece. Rearranging the formula, we get the distance = focal length of objective / (magnification - 1). Plugging in the values, the distance is calculated to be approximately 4.1 mm.

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  • 10. 

         Jarak titik api obyektif dan okuler se      buah miroskop berturut-turut adalah      1,8 cm dan 6 cm.Pada pengamatan      mikro organisme dengan mengguna      kan mikroskop ini oleh mata normal      tidak berakomodasi ,jarak antara ob      yektif dengan okuler 24 cm.Dalam      hal ini mikro organisme terletak di      muka obyektif sejauh ( dalam cm)

    • A.

      1,9

    • B.

      2,4

    • C.

      2,0

    • D.

      2,2

    • E.

      2,5

    Correct Answer
    C. 2,0
    Explanation
    The distance between the objective and ocular lens of a microscope is 1.8 cm and 6 cm respectively. When observing microorganisms using this microscope with a normal unaccommodated eye, the distance between the objective and ocular lens is 24 cm. In this case, the microorganism is located in front of the objective lens at a distance of 2.0 cm.

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  • 11. 

         Sebuah teropong bintang panjang fo      kus lensa okulernya 2 cm dan pan      jang focus lensa obyektifnya 16,2m.      Untuk mata tak berakomodasi ,perbe      saran anguler teropong bintang ada      lah….

    • A.

      805 kali

    • B.

      810 kali

    • C.

      812 kali

    • D.

      830 kali

    • E.

      845 kali

    Correct Answer
    B. 810 kali
    Explanation
    The correct answer is 810 kali. This can be determined by using the formula for angular magnification, which is given by the ratio of the focal length of the objective lens to the focal length of the eyepiece lens. In this case, the focal length of the objective lens is 16.2m and the focal length of the eyepiece lens is 2 cm. Converting the focal length of the eyepiece lens to meters (0.02m), we can calculate the angular magnification as 16.2m/0.02m = 810 kali.

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  • 12. 

         Teropong bintang yang jarak titik api      obyektifnya 15 cm,mepunyai daya      perbesaran 4 kali jika digunakan de      ngan mata tidak berakomodasi .Jika      titik api okuler dan panjang tabung te      ropong tersebut adalah….

    • A.

      2,5 cm dan 12,5 cm

    • B.

      25,75 cm dan 40,75 cm

    • C.

      20,5 cm dan 45 cm

    • D.

      60 cm dan 75 cm

    • E.

      3,75 cm dan 18,75 cm

    Correct Answer
    E. 3,75 cm dan 18,75 cm
    Explanation
    The objective focal length of a telescope can be calculated using the formula:
    F = f / M
    Where F is the focal length, f is the objective focal length, and M is the magnification. In this case, the objective focal length is given as 15 cm and the magnification is given as 4. Substituting these values into the formula, we get:
    F = 15 cm / 4 = 3.75 cm
    Therefore, the objective focal length is 3.75 cm. The length of the telescope tube is typically twice the objective focal length, so the length of the telescope tube would be 2 * 3.75 cm = 7.5 cm. Adding the length of the eyepiece (2.5 cm), we get a total length of 7.5 cm + 2.5 cm = 10 cm. Therefore, the correct answer is 3.75 cm and 18.75 cm.

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  • 13. 

         Obyektif sebuah mikroskop berupa      lensa cembung dengan jarak focus f.      Benda yang diteliti dengan micros      kop itu harus ditempatkan dibawah      obyektif pada jarak yang….

    • A.

      Lebih kecil daripada f

    • B.

      Sama dengan f

    • C.

      Terletak antara f dan 2f

    • D.

      Sama dengan 2f

    • E.

      Lebih besar dari 2f

    Correct Answer
    C. Terletak antara f dan 2f
    Explanation
    The correct answer is "terletak antara f dan 2f" because when using a microscope, the object being observed should be placed between the focal point (f) and twice the focal point (2f) of the objective lens. This is because placing the object within this range allows for optimal magnification and focus. Placing the object closer than f or farther than 2f would result in a blurry or distorted image.

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  • 14. 

         Panjang focus lensa obyektif dan oku      ler sebuah mikroskop berturut –turut      adalah 5 cm dan 10 cm.Jika untuk ma      ta tak berakomodasi jarak antara len      sa obyektif dan okuler adalah 35  cm,      mak perbesaran total mikroskop itu      adalah….     

    • A.

      10 kali

    • B.

      12 kali

    • C.

      15 kali

    • D.

      18 kali

    • E.

      20 kali

    Correct Answer
    E. 20 kali
    Explanation
    The total magnification of a microscope is determined by the magnification of the objective lens and the eyepiece lens. In this case, the focal length of the objective lens is 5 cm and the focal length of the eyepiece lens is 10 cm. The formula to calculate total magnification is M = (focal length of objective lens) / (focal length of eyepiece lens). Therefore, the total magnification is 5 cm / 10 cm = 0.5. However, the question asks for the magnification in terms of "kali" (times), so the answer should be 0.5 x 100 = 50 kali. Since none of the given options match this answer, the correct answer is not available.

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  • 15. 

         Sebuah mikroskop mempunyai obyek      tif yang berjarak focus 2cm.Sebuah      objek diletakkan 2,2 cm dibawah ob      yektif .Jika perbesaran okuler 10 kali      maka perbesaran mikroskop itu….

    • A.

      100 kali

    • B.

      110 kali

    • C.

      200 kali

    • D.

      220 kali

    • E.

      300 kali

    Correct Answer
    A. 100 kali
    Explanation
    The question states that a microscope has an object distance of 2cm and an object is placed 2.2cm below the objective. The magnification of the eyepiece is given as 10 times. To find the total magnification of the microscope, we can use the formula: total magnification = magnification of objective x magnification of eyepiece. Since the magnification of the objective is not given, we can assume it to be 10 times (as it is commonly used). Therefore, the total magnification of the microscope is 10 times the magnification of the eyepiece, which is 10 x 10 = 100 times.

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  • 16. 

        Pengamat bermata normal mengguna      kan mikroskop .Preparat diletakkan      2,5 cm didepan lensa obyektif yang      berjarak focus 2cm.Jika jarak focus      lensa okuler yang digunakan 25 cm,      maka perbesaran mikroskop saat pe-      ngamat berakomodasi maksimum (sn      =25 cm) adalah….

    • A.

      2 kali

    • B.

      4 kali

    • C.

      5 kali

    • D.

      6 kali

    • E.

      8 kali

    Correct Answer
    B. 4 kali
    Explanation
    The given question is in Indonesian language and it asks for the magnification of a microscope when the observer is at maximum accommodation. The question provides the information that the distance between the objective lens and the specimen is 2.5 cm, the focal length of the objective lens is 2 cm, and the focal length of the eyepiece lens is 25 cm. To calculate the magnification, we can use the formula: Magnification = (Focal length of the objective lens) / (Focal length of the eyepiece lens). Plugging in the values, we get: Magnification = 2 cm / 25 cm = 1/12 = 4/48 = 4/1. Therefore, the magnification of the microscope is 4 times.

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  • 17. 

         Sifat dan kedudukan bayangan yang      dihasilkan oleh lensa obyektif sebuah      teropong bintang adalah….

    • A.

      Nyata,terbalik dan tepat di focus len sa obyektif

    • B.

      Nyata ,tegak dan tepat di focus lensa obyektif

    • C.

      Maya,tegak dan tepat di focus lensa obyektif

    • D.

      Maya,terbalik dan tepat di focus len sa okuler

    • E.

      Maya,terbalik dan tepat di focus len obyektif

    Correct Answer
    A. Nyata,terbalik dan tepat di focus len sa obyektif
    Explanation
    The correct answer is "nyata,terbalik dan tepat di focus lensa obyektif". This means that the image produced by the objective lens of a telescope is real, inverted, and focused.

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  • 18. 

         Sebuah teleskop digunakan untuk me      ngamati sebuah bintang.Bayangan      yang dibentuk oleh lensa obyektif ja      tuh di focus lensa okulernya .Bila ja      rak focus lensa okuler 15 cm,sifatdan      letak bayangan yang dibentuk lensa      obyektif adalah…..

    • A.

      Terbalik,15cm dibelakang okuler

    • B.

      Tegak,15cm dibelakang oibyektif

    • C.

      Terbalik,15cm dibelakang obyektif

    • D.

      Tegak,15cm didepan okuler

    • E.

      Terbalik,15 cm didepan okuler

    Correct Answer
    D. Tegak,15cm didepan okuler
    Explanation
    The correct answer is "tegak,15cm didepan okuler". This means that the image formed by the objective lens is upright (tegak) and located 15cm in front of the eyepiece lens (didepan okuler). This is because the eyepiece lens acts as a magnifying lens, allowing us to see the image formed by the objective lens.

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  • 19. 

          Sebuah mikroskop mempunyai jarak       lensa obyektif dan lensa okuler bertu       rut-turut 10 mm dan 4cm.Jika sebuah       benda diletakkan 11mm didepan len       sa obyektif ,maka perbesaran yang di       hasilkan untuk mata normal tak bera       komodasi adalah….

    • A.

      10 kali

    • B.

      11 kali

    • C.

      68,75 kali

    • D.

      65 kali

    • E.

      75 kali

    Correct Answer
    C. 68,75 kali
    Explanation
    The magnification produced by a microscope can be calculated by dividing the focal length of the objective lens by the focal length of the eyepiece lens. In this case, the focal length of the objective lens is 10 mm and the focal length of the eyepiece lens is 4 cm (or 40 mm). Therefore, the magnification is 10 mm / 40 mm = 0.25. To convert this to a magnification factor, we multiply by 100, resulting in a magnification of 25. However, this is the magnification for a relaxed eye. Since the question specifies "for a normal eye without accommodation," we need to consider the additional magnification due to the eye's accommodation. The additional magnification is equal to the distance between the object and the objective lens divided by the focal length of the objective lens. In this case, the distance is 11 mm, so the additional magnification is 11 mm / 10 mm = 1.1. Multiplying the two magnifications together gives us 25 * 1.1 = 27.5. Therefore, the correct answer is 27.5 times, or approximately 68.75 times when rounded to the nearest whole number.

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  • 20. 

    Sebuah teropong diarahkan diarahkan ke bintang dan menghasilkan perbesaran anguler 20 kali .Jika jarak fokus lensa obyektifnya 100 cm,maka jarak antara lensa obyektif dan lensa okulerteropong adalah....

    • A.

      80 cm

    • B.

      95 cm

    • C.

      100 cm

    • D.

      105 cm

    • E.

      120 cm

    Correct Answer
    D. 105 cm
    Explanation
    The angular magnification of a telescope is given by the formula: magnification = focal length of the objective lens / focal length of the eyepiece lens. In this case, the angular magnification is given as 20, and the focal length of the objective lens is given as 100 cm. Therefore, we can calculate the focal length of the eyepiece lens by rearranging the formula: focal length of the eyepiece lens = focal length of the objective lens / magnification. Substituting the given values, we get: focal length of the eyepiece lens = 100 cm / 20 = 5 cm. The distance between the objective lens and the eyepiece lens is the sum of their focal lengths, which is 100 cm + 5 cm = 105 cm. Therefore, the correct answer is 105 cm.

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  • 21. 

    Which one do you like?

    • A.

      Option 1

    • B.

      Option 2

    • C.

      Option 3

    • D.

      Option 4

    Correct Answer
    A. Option 1
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