SEC-a PC Quiz-4 (April 2019)

Approved & Edited by ProProfs Editorial Team

The editorial team at ProProfs Quizzes consists of a select group of subject experts, trivia writers, and quiz masters who have authored over 10,000 quizzes taken by more than 100 million users. This team includes our in-house seasoned quiz moderators and subject matter experts. Our editorial experts, spread across the world, are rigorously trained using our comprehensive guidelines to ensure that you receive the highest quality quizzes.

Learn about Our Editorial Process

| By Manipalq4

Manipalq4

Community Contributor

Quizzes Created: 1 | Total Attempts: 94

Questions: 54 | Attempts: 94 | Updated: Dec 14, 2023

Questions

Settings

Feedback

During the Quiz End of Quiz

Play as

Quiz Flashcard

Create your own Quiz

Questions and Answers

Quiz Review Timeline +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

Current Version
Dec 14, 2023

Quiz Edited by
ProProfs Editorial Team
Apr 04, 2019

Quiz Created by
Manipalq4

SEC-a PC Quiz-4 (April 2019)

Which of the following is not a pointer declaration?

What will be the output? int main(){ int i = 5; int j = i / -2; int k = i % -2; printf("%d %d\n", j, k); return 0; }

What will be the output/error? int main(){ float i = 6.2; float j = i % -2; printf("%d\n", j); return 0; }

What will be the output/error? int main() { int a = 10, b = 20, c = 30; if(!a >= 50) b = 300; c = 400; printf("%d,%d,%d", a, b, c); return 0; }

How to catch multi word string using scanf ?

What will be the output/error? void fun(int*); int main() { int i = 10; int *j = &i; fun(j++); return 0; } void fun(int *k) { printf("%d\n", *k); }

What will be the output/error? void fun(int*); int main() { int i = 10; int *j = &i; fun(++j); return 0; } void fun(int *k) { printf("%d\n", *k); }

void fun(int*); int main() { int i = 10; int *j = &i; fun(&i); printf("%d ", *j); return 0; } void fun(int *j) { int k=2; j=&k; printf("%d ", *j); }

Void main () { int a[4] = {1,2,3,4}; max(&a[3]); } void max(int *z) { printf("%d",*z); }

Void main () { int a[4] = {1,2,3,4}; max(a[2]); } void max(int z) { printf("%d",*z); }

Void main () { int a[4] = {1,2,3,4}, i; for(i=0; i < 4 ; i++) { max(&a[i]); } } void max(int *z) { int i; printf("%d",*z); }

Void main () { int a[4] = {1,2,3,4}, i; max(a); } void max(int z[]) { int i; for(i=0; i < 4; i++) { printf("%d\n", z[i]); } }

Size of pointer in gcc32 compiler is

Void main () { int a[4] = {1,2,3,4}, i; max(a); } void max(int *z) { int i; for(i=0;i < 4 ; i++) { printf("%d\n", z[i]); } }

Void main () { int a[4] = {1,2,3,4}, i; max(&a); } void max(int *z) { int i; for(i=3;i>=0;i++) { printf("%d\n", z[i]); } }

Void main () { int a=10; int *p = &a; int **q = &p; printf("%d, %d", *p, **q); }

Which of the following is a correct format for declaration of function?

Which of the following function declaration is illegal?

Which function definition will run correctly?

The value obtained in the function is given back to main by using ________ keyword.

Can we use a function as a parameter of another function? [ Eg: void wow(int func()) ].

void f(char**); int main() { char *argv[] = { "ab", "cd", "ef", "gh", "ij", "kl" }; f(argv); return 0; } void f(char **p) { char *t; t = (p += sizeof(int))[-1]; printf("%sn", t); }

int main() { int a[5] = {1,2,3,4,5}; int *ptr = (int*)(&a+1); printf("%d %d", *(a+1), *(ptr-1)); return 0; }

#define R 10 #define C 20 int main() { int (*p)[R][C]; printf("%d", sizeof(*p)); getchar(); return 0; }

Int fun(int *c) { int q = 10; c = &q; return *c; } int main() { int r = 20; int *p = &r; *p=fun(p); printf("%d", *p); return 0; }

Void fun(int *p) { int q = 10; p = &q; } int main() { int r = 20; int *p = &r; fun(p); printf("%d", *p); return 0; }

int main() { int x = 10; int *y, **z; y = &x; z = &y; printf("x = %d, y = %d, z = %d\n", x, *y, **z); return 0; }

int main() { int a = 5; int *ptr ; ptr = &a; *ptr = *ptr * 3; printf("%d", a); return 0; }

int main() { int a[] = { 1, 2, 3, 4, 5} ; int *ptr; ptr = a; printf(" %d ", *( ptr + 1) ); return 0; }

Int f(int *p, int n) { if (n <= 1) return 0; else return max(f(p+1,n-1),p[0]-p[1]); } int main() { int a[] = {3,5,2,6,4}; printf("%d", f(a,5)); }

int f(int n, int k) { if (n == 0) return 0; else if (n % 2) return f(n/2, 2*k) + k; else return f(n/2, 2*k) - k; } int main () { printf("%d", f(20, 1)); return 0; }

int funcf (int x); int funcg (int y); main() { int x = 5, y = 10, count; for (count = 1; count <= 2; ++count) { y += funcf(x) + funcg(x); printf ("%d ", y); } } funcf(int x) { int y; y = funcg(x); return (y); } funcg(int x) { static int y = 10; y += 1; return (y+x); }

Void f1 (int a, int b) { int c; c=a; a=b; b=c; } void f2 (int *a, int *b) { int c; c=*a; *a=*b;*b=c; } int main() { int a=4, b=5, c=6; f1(a, b); f2(&b, &c); printf (“%d”, c-a-b); return 0; }

Write Correct function call to swap values of two variables void swap (int a, int b) { int temp; temp = a; a = b; b = temp; }

Double foo (double); int main() { double da, db; db = foo(da); } double foo(double a) { return a; }

Void foo(int n, int sum) { int k = 0, j = 0; if (n == 0) return; k = n % 10; j = n / 10; sum = sum + k; foo (j, sum); printf ("%d,", k); } int main () { int a = 2048, sum = 0; foo (a, sum); printf ("%dn", sum); getchar(); }

What will be the size of this array in term of memory byte? char a[20];

What will be the outpur of this code? void main() {int a[]={1,2,3,4,5}; printf("%d",a[5])}

Which declaration is incorrect?

What does the following declaration mean? int (*ptr)[10]

In C, if you pass an array as an argument to a function, what actually gets passed?

int main() { int arr[1]={10}; printf("%d", 0[arr]); return 0; }

int main() { int arr[] = {12, 14, 15, 23, 45}; printf("%u, %u", arr, &arr); return 0; } // Base address is 65486

int main() { float arr[] = {12.4, 2.3, 4.5, 6.7}; printf("%d", sizeof(arr)/sizeof(arr[0])); return 0; }

int main() { int arr[]={2, 3, 4, 1, 6}; printf("%u, %u, %u", arr, &arr[0], &arr); return 0; }

Which one of the following is one of the feature of array?

Arguments that take input by user before running a program are called?

Void m(int *p, int *q) { int temp = *p; *p = *q; *q = temp; } void main() { int a = 6, b = 5; m(&a, &b); printf("%d %d\n", a, b); }

Void m(int *p) { int i = 0; for(i = 0;i < 5; i++) printf("%d\t", p[i]); } void main() { int a[5] = {6, 5, 3}; m(&a); }

void fun(int *ptr) { *ptr = 30; } int main() { int x = 20; fun(&x); printf("x = %d", x); return 0; }

What will be the output/error? void fun(int); int main() { int i = 10; int j = &i; fun(j++); return 0; } void fun(int k) { printf("%d\n", k); }

What will be the output/error? void fun(int); int main() { int i = 10; int j = &i; fun(++j); return 0; } void fun(int k) { printf("%d\n", k); }

void fun(int); int main() { int i = 10; int j = &i; fun(&i); printf("%d ", j); return 0; } void fun(int j) { int k=2; j=&k; printf("%d ", *j); }

Void main () { int a[4] = {1,2,3,4}; max(&a[3]); } void max(int z) { printf("%d",z); }

Void main () { int a[4] = {1,2,3,4}, i; for(i=0; i < 4 ; i++) { max(&a[i]); } } void max(int z) { int i; printf("%d",z); }

int main() { int a[5] = {1,2,3,4,5}; int ptr = (int)(&a+1); printf("%d %d", (a+1), (ptr-1)); return 0; }

#define R 10 #define C 20 int main() { int (p)[R][C]; printf("%d", sizeof(p)); getchar(); return 0; }

Int fun(int c) { int q = 10; c = &q; return c; } int main() { int r = 20; int p = &r; p=fun(p); printf("%d", *p); return 0; }

Void fun(int p) { int q = 10; p = &q; } int main() { int r = 20; int p = &r; fun(p); printf("%d", *p); return 0; }

int main() { int a = 5; int ptr ; ptr = &a; ptr = ptr 3; printf("%d", a); return 0; }

int main() { int a[] = { 1, 2, 3, 4, 5} ; int ptr; ptr = a; printf(" %d ", ( ptr + 1) ); return 0; }

int f(int n, int k) { if (n == 0) return 0; else if (n % 2) return f(n/2, 2k) + k; else return f(n/2, 2k) - k; } int main () { printf("%d", f(20, 1)); return 0; }

Void f1 (int a, int b) { int c; c=a; a=b; b=c; } void f2 (int a, int b) { int c; c=a; a=b;b=c; } int main() { int a=4, b=5, c=6; f1(a, b); f2(&b, &c); printf (“%d”, c-a-b); return 0; }

Void m(int p, int q) { int temp = p; p = q; q = temp; } void main() { int a = 6, b = 5; m(&a, &b); printf("%d %d\n", a, b); }

void fun(int ptr) { ptr = 30; } int main() { int x = 20; fun(&x); printf("x = %d", x); return 0; }