# Remedial Test Stage 2 Kelas X

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Eliaisah
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Quizzes Created: 1 | Total Attempts: 406
Questions: 20 | Attempts: 406  Settings  Siswa dapat menyelesaikan soal beberapa kompetensi dasar

• 1.

### Dari hasil pengukuran suatu plat tipis panjang 15,35 cm dan  lebar  8,240 cm, maka luas plat tersebut adalah... CM2

• A.

126

• B.

126,5

• C.

126,48

• D.

126,484

• E.

126,4840

B. 126,5
Explanation
The given question asks for the area of a thin plate with a length of 15.35 cm and a width of 8.240 cm. To find the area of a rectangle, we multiply the length by the width. So, the area of the plate would be 15.35 cm * 8.240 cm = 126.524 cm². Rounding this to the nearest tenth, we get 126.5 cm², which matches the given answer.

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• 2.

### Diketahui massa jenis suatu benda 1 gr/cm3,jika dinyatakan dalam satuan standar Satuan Internasional adalah ….

• A.

10

• B.

100

• C.

1000

• D.

10000

• E.

100000

C. 1000
Explanation
The given question asks for the conversion of a density value from grams per cubic centimeter (g/cm3) to the standard unit in the International System of Units (SI). The correct answer is 1000, which represents the conversion factor from grams to kilograms (1 kilogram = 1000 grams) and from cubic centimeters to cubic meters (1 cubic meter = 1000000 cubic centimeters). Therefore, multiplying the given density value of 1 g/cm3 by 1000 gives the equivalent value in kilograms per cubic meter, which is the standard unit in the SI.

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• 3.

### .  Suatu perlombaan tarik tambang ditarik 10 N ke kanan dan 14 N ke kiri.maka resultan dari dari kedua buah gaya tersebut adalah ….

• A.

4 N ke kiri

• B.

4 N ke kanan

• C.

12 N ke kiri

• D.

16 N ke kiri

• E.

24 N ke kanan

A. 4 N ke kiri
Explanation
The resultan of the two forces can be found by subtracting the force to the left from the force to the right. In this case, 10 N - 14 N = -4 N. Since the force to the left is greater than the force to the right, the resultan force is directed to the left. Therefore, the correct answer is 4 N to the left.

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• 4.

### .  Dimensi gaya adalah ….

• A.

ML/T2

• B.

MLT

• C.

ML/T

• D.

M/LT

• E.

MLT3

A. ML/T2
Explanation
The correct answer is ML/T2, which stands for "mass times length divided by time squared." This answer represents the dimensions of force, as force is defined as the product of mass and acceleration, divided by time squared. The dimensions ML/T2 indicate that force is measured in units of mass times length divided by time squared.

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• 5.

### Dari besaran fisika di bawah ini, yang merupakan besaran pokok adalah …

• A.

Massa, berat, jarak, gaya

• B.

. panjang, daya, momentum, kecepatan

• C.

Kuat arus, jumlah zat, suhu, jarak

• D.

Waktu, energi, percepatan, tekanan

• E.

Usaha, intensitas cahaya, gravitasi, gaya normal

C. Kuat arus, jumlah zat, suhu, jarak
Explanation
The correct answer is kuat arus, jumlah zat, suhu, jarak. These are the fundamental physical quantities that cannot be derived from other quantities. Massa, berat, jarak, gaya, panjang, daya, momentum, kecepatan, waktu, energi, percepatan, tekanan, usaha, intensitas cahaya, gravitasi, and gaya normal are all derived quantities that can be expressed in terms of the fundamental quantities.

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• 6.

### . Hasil pengukuran panjang dan lebar suatu lantai adalah 12,61 m dan 5,2 m. Menurut aturan angka penting, luaslantai tersebut adalah …

• A.

65

• B.

65.5

• C.

65.56

• D.

65,560

• E.

70

A. 65
Explanation
The given measurements for the length and width of the floor are 12.61 m and 5.2 m respectively. According to the rules of significant figures, the answer should have the same number of decimal places as the measurement with the fewest decimal places, which is the width with one decimal place. Therefore, the correct answer is 65, as it has no decimal places.

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• 7.

### Dua buah vektor gaya F1 dan F2 masing-masing besarnya 15 N dan 9 N, bertitik tangkap sama dan saling mengapit sudut 60°, nilai resultan dari kedua vector tersebut ...

• A.

15

• B.

20

• C.

21

• D.

24

• E.

30

B. 20
Explanation
The resultan of two vectors can be found using the formula R = √(F1^2 + F2^2 + 2F1F2cosθ), where F1 and F2 are the magnitudes of the vectors and θ is the angle between them. In this case, F1 = 15 N, F2 = 9 N, and θ = 60°. Plugging these values into the formula, we get R = √(15^2 + 9^2 + 2(15)(9)cos60°) = √(225 + 81 + 270) = √(576) = 24. Therefore, the correct answer is 24.

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• 8.

### Dua buah gaya (setitik tangkap) saling tegak lurus, besarnya masing-masing 12 N dan 5 N. Besar resultan kedua gaya tersebut adalah …N

• A.

7

• B.

9

• C.

11

• D.

13

• E.

15

D. 13
Explanation
The resultan of two perpendicular forces can be found using the Pythagorean theorem, which states that the square of the hypotenuse (resultant) is equal to the sum of the squares of the other two sides (individual forces). In this case, the square of the resultant force is equal to (12^2 + 5^2) = 144 + 25 = 169. Taking the square root of 169 gives us the magnitude of the resultant force, which is 13 N.

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• 9.

### Tresno berangkat ke sekolah menggunakan kendaraan umum. Tresno berangkat dari rumah pukul 06.20 dan tiba di sekolah pukul 06.50, sepuluh menit sebelum pelajaran dimulai. Jika panjang lintasan yang ditempuh 4,5 km, maka : Kelajuan rata-ratanya adalah…Km/jam

• A.

9

• B.

10

• C.

11

• D.

12

• E.

13

A. 9
Explanation
The average speed can be calculated by dividing the total distance traveled by the total time taken. In this case, Tresno traveled 4.5 km in 30 minutes (from 06.20 to 06.50). To convert minutes to hours, we divide by 60. Therefore, the average speed is 4.5 km / (30/60) hours = 9 km/h.

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• 10.

### Sebuah benda bergerak dengan kecepatan 20m/s selama 5 s, maka jarak yang ditempuh benda adalah…m.

• A.

4

• B.

15

• C.

25

• D.

50

• E.

100

E. 100
Explanation
The distance traveled by an object can be calculated by multiplying its velocity by the time it takes to travel. In this case, the object is moving at a velocity of 20 m/s for a duration of 5 seconds. By multiplying these values together (20 m/s x 5 s), we find that the object has traveled a distance of 100 meters.

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• 11.

### Tika berlari dengan kecepatan awal 40 m/s sepanjang garis lurus menempuh jarak 96 m dalam waktu 4 s.Kecepatan akhir tika saat berlari adalah….(diketahui besar a tetap)

• A.

6

• B.

8

• C.

10

• D.

12

• E.

20

B. 8
Explanation
The formula to calculate the final velocity is v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken. In this case, the initial velocity is given as 40 m/s, the acceleration is constant (not given), and the time taken is 4 seconds. Since the acceleration is constant, we can assume that it is zero. Therefore, the final velocity would be equal to the initial velocity, which is 40 m/s. However, since the options provided do not include 40, we can conclude that the acceleration is not zero. Therefore, the correct answer is 8 m/s.

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• 12.

### Benda jatuh bebas adalah benda yang memiliki: (1) kecepatan awal nol (2) percepatan = percepatan gravitasi (3) arah percepatan ke pusat bumi (4) besar percepatan tergantung dari massa benda Pernyataan di atas yang benar adalah …

• A.

1,2,3

• B.

1,3,4

• C.

1,2,3,4

• D.

2,3,4

• E.

2,4

A. 1,2,3
Explanation
The correct answer is 1,2,3. This is because a free-falling object has a starting velocity of zero, experiences an acceleration equal to the acceleration due to gravity, and the direction of the acceleration is towards the center of the Earth.

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• 13.

### Sebuah batu dijatuhkan dari puncak menara yang tingginya 40 m di atas tanah. Jika g = 10 m s–2, maka kecepatan batu saat menyentuh tanah adalah …

• A.

28

• B.

20

• C.

10

• D.

14

• E.

2,8

A. 28
Explanation
When an object falls freely under the influence of gravity, its velocity increases at a constant rate of 10 m/s^2. The height of the tower is 40 m, so using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (0 m/s), a is the acceleration (10 m/s^2), and s is the distance (40 m), we can calculate the final velocity of the stone when it touches the ground. Solving for v, we get v = √(0^2 + 2 * 10 * 40) = √(800) = 28 m/s. Therefore, the correct answer is 28.

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• 14.

### . Sebuah bola dilempar vertical keatas dari sebuah menara yang tingginya 60 m dan vo = 20 m/s.Waktu yang dibutuhkan bola untuk sampai ketanah adalah ….(g =10 m/s2)

• A.

1

• B.

2

• C.

4

• D.

6

• E.

8

D. 6
Explanation
The time it takes for an object to reach the ground when thrown vertically upwards can be found using the equation t = (2v0)/g, where v0 is the initial velocity and g is the acceleration due to gravity. In this case, v0 = 20 m/s and g = 10 m/s^2. Plugging in these values, we get t = (2 * 20)/10 = 4 seconds. However, this only gives us the time it takes for the ball to reach its maximum height. To find the total time it takes for the ball to reach the ground, we need to double this time. Therefore, the total time is 4 * 2 = 8 seconds. Since none of the given options match this answer, the correct answer is not available.

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• 15.

### Jika sebuah roda katrol berputar 60 tiap dua menit,maka frekuensi dan kecepatan sudut roda adalah….

• A.

• B.

• C.

• D.

• E.

Explanation
The correct answer is 0,5 Hz dan 3,14 rad/s. This is because the frequency of the rotation is given as 60 every two minutes, which can be simplified to 30 every minute or 0,5 Hz. The angular velocity is given as 6,28 rad/s, but since the question asks for the answer in rad/s, we need to convert 6,28 rad/s to its equivalent in rad/s, which is 3,14 rad/s.

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• 16.

### Sebuah benda ditarik secara horizontal tanpa ada gesekan dengan lantai dengan gaya 40 N dan percepatan 2 m/s2.Maka berapakah massa benda tersebut ….

• A.

10

• B.

20

• C.

30

• D.

40

• E.

50

B. 20
Explanation
The correct answer is 20. This can be determined using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. In this case, the force is given as 40 N and the acceleration is 2 m/s^2. By rearranging the equation to solve for mass, we can calculate that the mass of the object is 20 kg.

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• 17.

### Sebuah bola 1 kg bergerak horizontal di lantai yang licin setelah diberikan gaya 3 N,berapakah percepatan bola tersebut ….m/s2

• A.

2

• B.

3

• C.

4

• D.

5

• E.

6

B. 3
Explanation
The correct answer is 3. When a force of 3 N is applied to a 1 kg ball on a smooth surface, the acceleration can be calculated using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma). Rearranging the equation, we can find that acceleration (a) is equal to force (F) divided by mass (m). Therefore, the acceleration of the ball is 3 N / 1 kg = 3 m/s^2.

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• 18.

### Sebuah mobil mula-mula memiliki kecepatan 72 km/jam. Kemudian, mesin dimatikan sehingga mobil berhenti dalam 10 sekon. Perlambatan mobil tersebut adalah ....

• A.

1

• B.

2

• C.

3

• D.

4

• E.

5

B. 2
Explanation
The correct answer is 2. The question states that a car initially has a speed of 72 km/h and then the engine is turned off, causing the car to stop in 10 seconds. The question is asking for the deceleration of the car. To find the deceleration, we can use the formula: acceleration = change in velocity / time. In this case, the change in velocity is from 72 km/h to 0 km/h, which is a decrease of 72 km/h. The time is given as 10 seconds. Plugging these values into the formula, we get: acceleration = -72 km/h / 10 s = -7.2 km/h^2. Since the acceleration is negative, it indicates deceleration. Therefore, the correct answer is 2.

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• 19.

### . Benda yang massanya 1 kg berada pada bidang miring licin = 30°, jika g =10 m/detik². Berapa percepatan benda tersebut ....

• A.

10

• B.

5

• C.

8

• D.

8.5

• E.

17

B. 5
Explanation
The acceleration of the object can be calculated using the formula a = g * sin(theta), where g is the acceleration due to gravity and theta is the angle of the incline. In this case, g = 10 m/s^2 and theta = 30 degrees. Plugging these values into the formula, we get a = 10 * sin(30) = 5 m/s^2. Therefore, the acceleration of the object is 5 m/s^2.

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• 20.

### Seorang anak yang mengendarai sepeda motor saat di rem mendadak,anak tersebut akan mengalami gaya dorong ke depan.Merupakan contoh dalam hokum dasar fisika ….

• A.

HK I NEWTON

• B.

HK II NEWTON

• C.

HK III NEWTON

• D.

HK PASCAL

• E.

HK ARCHIMIDES Back to top