Remed Uts Genap Xi IPA-1 Smanio (The Number Of Students Absent 21-30)

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| By Srilestari
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  • 1/10 Questions

    Lakmus merah akan berubah warnanya menjadi biru jika dimasukkan ke dalam larutan ....

    • Air jeruk
    • Air cuka
    • Akuadest
    • Air sabun
    • Asam klorida
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Remed Uts Genap Xi IPA-1 Smanio (The Number Of Students Absent 21-30) - Quiz
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  • 2. 

    Dari beberapa larutan berikut HCl, NH3, CH3COOH, HF, dan HNO3 yang termasuk larutan asam lemah adalah ....

    • HCl dan NH3

    • CH3COOH dan HF

    • HCl dan HNO3

    • HF dan HNO3

    • CH3COOH dan HNO3

    Correct Answer
    A. CH3COOH dan HF
    Explanation
    The correct answer is CH3COOH dan HF. This is because CH3COOH (acetic acid) and HF (hydrofluoric acid) are weak acids. Weak acids are substances that do not completely ionize in water, resulting in a lower concentration of hydrogen ions (H+). HCl (hydrochloric acid) and HNO3 (nitric acid) are strong acids that completely ionize in water, producing a high concentration of H+. NH3 (ammonia) is a weak base, not an acid. Therefore, the only combination of weak acids is CH3COOH and HF.

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  • 3. 

    Sebanyak 25 mL CH3COOH 0,2 M (Ka = 10 –5 M) dicampurkan dengan 25 mL NaOH 0,1 M membentuk larutan penyangga dengan pH ....

    • 2,0

    • 2,5

    • 3,0

    • 5,0

    • 5,5

    Correct Answer
    A. 5,0
    Explanation
    The given question states that 25 mL of 0.2 M CH3COOH (acetic acid) is mixed with 25 mL of 0.1 M NaOH (sodium hydroxide) to form a buffer solution. Acetic acid is a weak acid with a Ka value of 10^-5 M. When acetic acid reacts with sodium hydroxide, it forms sodium acetate (CH3COONa) and water. The acetic acid and its conjugate base, acetate, act as a buffer system in the solution. The pH of a buffer solution is determined by the ratio of the concentrations of the weak acid and its conjugate base. In this case, the ratio of acetic acid to acetate is 1:1, resulting in a pH of 5.0, which is the correct answer.

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  • 4. 

    Sebanyak 4,8 gram logam Mg (Ar = 24) direaksikan dengan larutan HCl 1 M. Jika semua logam Mg habis bereaksi, maka volume gas hidrogen yang terjadi (pada keadaan STP) adalah ... L.

    • 2,24 L

    • 4,48 L

    • 5,6 L

    • 11,2 L

    • 22,4 L

    Correct Answer
    A. 4,48 L
    Explanation
    When magnesium (Mg) reacts with hydrochloric acid (HCl), it produces hydrogen gas (H2) and magnesium chloride (MgCl2). The balanced chemical equation for this reaction is: Mg + 2HCl -> MgCl2 + H2.

    From the equation, we can see that 1 mole of magnesium reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

    Given that 4.8 grams of magnesium is reacted, we need to convert this mass to moles. The molar mass of magnesium is 24 grams/mol, so 4.8 grams is equal to 0.2 moles.

    Since the ratio of magnesium to hydrogen gas in the reaction is 1:1, we can conclude that 0.2 moles of magnesium will produce 0.2 moles of hydrogen gas.

    At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters. Therefore, 0.2 moles of hydrogen gas will occupy 0.2 * 22.4 = 4.48 liters.

    Thus, the correct answer is 4.48 L.

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  • 5. 

    Garam-garam berikut yang mengalami hidrolisis sempurna jika dilarutkan ke dalam air adalah ....

    • Tembaga sulfat

    • Natrium karbonat

    • Amonium asetat

    • Aluminium klorida

    • Amonium sulfat

    Correct Answer
    A. Amonium asetat
    Explanation
    Amonium asetat mengalami hidrolisis sempurna jika dilarutkan ke dalam air. Hidrolisis adalah reaksi kimia di mana senyawa terurai menjadi dua atau lebih senyawa baru karena reaksi dengan air. Dalam kasus amonium asetat, reaksi hidrolisisnya menghasilkan ion asetat (CH3COO-) dan ion amonium (NH4+). Kedua ion ini terbentuk karena gugus amonium (NH4+) dalam amonium asetat melepaskan satu ion H+ ke dalam air, sehingga membentuk ion amonium, sementara gugus asetat (CH3COO-) membentuk ion asetat. Karena reaksi ini terjadi secara sempurna, amonium asetat dapat dianggap mengalami hidrolisis sempurna.

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  • 6. 

    Larutan penyangga adalah larutan yang mampu mempertahankan pH pada kisarannya kecuali pada pengaruh ....

    • Penambahan air 5 kali semula

    • Penambahan sedikit asam lemah

    • Penambahan sedikit asam kuat

    • Penambahan banyak asam kuat

    • Penambahan sedikit basa kuat

    Correct Answer
    A. Penambahan banyak asam kuat
    Explanation
    The correct answer is "penambahan banyak asam kuat." This is because a buffer solution is able to maintain its pH within a certain range by resisting changes in pH when small amounts of acid or base are added. However, if a large amount of strong acid is added to the buffer solution, it will overpower the buffer capacity and cause a significant change in pH. Therefore, the addition of a large amount of strong acid disrupts the ability of the buffer solution to maintain its pH.

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  • 7. 

    Dari campuran larutan berikut yang menghasilkan garam terhidrolisis sebagian dan bersifat basa adalah ....

    • 50 mL 0,5 M HCl + 50 mL 0,5 M NaOH

    • 50 mL 0,5 M HCl + 50 mL 0,5 M NH3

    • 50 mL 0,5 M HCl + 100 mL 0,5 M NH3

    • 50 mL 0,5 M CH3COOH + 50 mL 0,5 M NH3

    • 50 mL 0,5 M CH3COOH + 50 mL 0,5 M NaOH

    Correct Answer
    A. 50 mL 0,5 M CH3COOH + 50 mL 0,5 M NaOH
    Explanation
    Campuran larutan 50 mL 0,5 M CH3COOH + 50 mL 0,5 M NaOH menghasilkan garam terhidrolisis sebagian dan bersifat basa karena CH3COOH adalah asam lemah dan NaOH adalah basa kuat. Ketika kedua larutan dicampur, CH3COOH akan bereaksi dengan NaOH membentuk garam CH3COONa dan air. Garam CH3COONa adalah garam yang terhidrolisis sebagian, artinya akan ada ion OH- yang terhidrolisis. Ion OH- yang terhidrolisis akan meningkatkan konsentrasi OH- dalam larutan, sehingga larutan bersifat basa.

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  • 8. 

    Jika tetapan ionisasi basa lemah BOH adalah 10–5 M, maka larutan BOH 0,1 M akan mempunyai pH sebesar ….

    • 3

    • 5

    • 7

    • 9

    • 11

    Correct Answer
    A. 11
    Explanation
    If the ionization constant of a weak base BOH is 10^-5 M, then a 0.1 M solution of BOH will have a pH of 11. This is because the ionization constant (Ka) of a weak base is the equilibrium constant for the reaction of the base with water to produce hydroxide ions (OH-) and the conjugate acid (BH+). A higher Ka value indicates a stronger base and a higher concentration of hydroxide ions. Since the Ka value is relatively small (10^-5 M), the concentration of hydroxide ions in the solution is low, resulting in a high pH value of 11.

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  • 9. 

    Garam berikut yang larutannya di dalam air bersifat basa adalah ….

    • KCN

    • NH4Cl

    • NH4CN

    • (NH4)2SO4

    • K2SO4

    Correct Answer
    A. KCN
    Explanation
    KCN is the correct answer because it is a salt that is formed from a strong base (KOH) and a weak acid (HCN). When KCN is dissolved in water, it undergoes hydrolysis to produce OH- ions, which makes the solution basic. This is because the weak acid, HCN, partially dissociates in water to form H+ ions and CN- ions. The CN- ions react with water to form OH- ions, increasing the concentration of OH- ions and making the solution basic.

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  • 10. 

    Larutan NH3 0,1 M mempunyai pH = 11, pH larutan NH4Cl 0,1 M adalah ….

    • 11

    • 9

    • 7

    • 5

    • 3

    Correct Answer
    A. 5
    Explanation
    The pH of a solution is a measure of its acidity or alkalinity. A pH of 11 indicates that the solution is highly alkaline. In this case, the solution is made of NH3, which is ammonia. Ammonia is a weak base that ionizes to produce hydroxide ions (OH-) in water. The higher the concentration of hydroxide ions, the higher the pH. Therefore, a solution of NH4Cl, which is the conjugate acid of NH3, would have a lower pH than 11. Among the given options, a pH of 5 is the closest to being lower than 11, making it the correct answer.

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  • Jul 22, 2024
    Quiz Edited by
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  • Apr 22, 2012
    Quiz Created by
    Srilestari
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