# Quiz ; Fluida Statis

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Quizzes Created: 2 | Total Attempts: 1,329
Questions: 10 | Attempts: 522  Settings  Pikirkan terlebih dahulu sebelum mimilih jawaban... !

• 1.

### Jika anda iseng-iseng mencoba menyelundupkan batangan emas (massa jenis emas = 19.300 Kg/m3) dengan dimensi 60 cm x 25 cm x 15 cm dengan memasukkanya ke ransel anda , berapakah massanya ?

• A.

100 kg

• B.

230 kg

• C.

350 kg

• D.

430 kg

• E.

500 kg

D. 430 kg
Explanation
The question asks for the mass of a gold bar with dimensions 60 cm x 25 cm x 15 cm. To find the mass, we need to calculate the volume of the gold bar by multiplying its dimensions. The volume is then multiplied by the density of gold (19,300 Kg/m3) to find the mass. The correct answer is 430 kg, which is the result of the calculations.

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• 2.

### Tentukan tekanan yang diberikan pada lantai oleh seorang model yang bermassa 50 kg yang berdiri sesaat pada satu hak sepatu ( luas = 0,05 cm2 ) !

• A.

10 x 106 N/m2

• B.

12 x 106 N/m2

• C.

8 x 106 N/m2

• D.

10 x 107 N/m2

• E.

5 x 107 N/m2

D. 10 x 107 N/m2
Explanation
The correct answer is 10 x 107 N/m2. This is because the pressure exerted on the floor is equal to the force divided by the area. In this case, the force is the weight of the model, which is mass times gravity (50 kg x 9.8 m/s2). The area is given as 0.05 cm2, which needs to be converted to square meters (0.05 cm2 = 0.05 x 10-4 m2). Plugging in the values, we get pressure = (50 kg x 9.8 m/s2) / (0.05 x 10-4 m2) = 10 x 107 N/m2.

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• 3.

### Piston besar pada pengangkat hidrolik mempunyai penampang berbentuk lingkaran yang jari-jarinya 20 cm. Berapakah besar gaya yang harus diberikan pada piston kecil yang jari-jarinya 2 cm agar dapat mengangkat mobil yang masanya 1500 kg?

• A.

147 N

• B.

200 N

• C.

250 N

• D.

175 N

• E.

127 N

A. 147 N
Explanation
The force exerted by a hydraulic system is determined by the ratio of the areas of the two pistons. In this case, the ratio of the areas is (20 cm)^2 / (2 cm)^2 = 100. Therefore, the force exerted on the small piston is 1/100th of the force exerted on the large piston. Since the force exerted on the large piston is equal to the weight of the car (1500 kg) multiplied by the acceleration due to gravity (9.8 m/s^2), the force exerted on the small piston is (1500 kg * 9.8 m/s^2) / 100 = 147 N.

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• 4.

### Sebuah bola dengan volume 32 cm² mengapung dipermukaan air dengan setengah bagian di bawah permukaan air. Jika massa jenis air adalah 1000 kg/m³, berapakah massa bola ?

• A.

1,6 x 10-2 kg

• B.

3,5 x ​10-2 kg

• C.

7,6 x ​10-3 kg

• D.

5 x ​10-3 kg

• E.

1,6 x ​10-4 kg

A. 1,6 x 10-2 kg
Explanation
The volume of the ball is given as 32 cm² and it is floating with half of its volume submerged in water. To find the mass of the ball, we need to calculate the volume of the submerged part and then use the formula mass = density x volume. The volume of the submerged part can be found by dividing the given volume by 2. Then, we convert the volume from cm² to m³ by dividing by 1000000. Finally, we multiply the density of water (1000 kg/m³) by the volume to find the mass. The correct answer is 1,6 x 10-2 kg.

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• 5.

### Jika massa jenis air laut 1300 kg/ m³ dan Po = 2,5 x 105 N/m2. Berapakah tekanan mutlak pada kedalaman 400 m dari permukaan laut?

• A.

5,45 x 106 N/m²

• B.

2,45 x 105 N/m²

• C.

4,5 x 106 N/m²

• D.

6,75 x 107 N/m²

• E.

5,45 x 107 N/m²

A. 5,45 x 106 N/m²
Explanation
The correct answer is 5,45 x 106 N/m². This can be calculated using the formula for absolute pressure, which is given by P = Po + ρgh, where P is the absolute pressure, Po is the atmospheric pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth. In this case, the density of seawater is given as 1300 kg/m³, the atmospheric pressure is 2,5 x 105 N/m², and the depth is 400 m. Plugging these values into the formula, we get P = 2,5 x 105 + (1300)(9.8)(400) = 5,45 x 106 N/m².

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• 6.

### Seekor ikan berada pada kedalaman 15 meter di bawah permukaan air. Jika massa jenis air 1000 kg/m3 , percepatan gravitasi bumi 10 m/s2 dan tekanan udara luar 105 N/m, maka tekanan hidrostatis yang dialami ikan adalah ...

• A.

150000 Pa

• B.

15000 Pa

• C.

1500000 Pa

• D.

250000 Pa

• E.

200000 Pa

A. 150000 Pa
Explanation
The pressure experienced by an object submerged in a fluid is given by the equation P = ρgh, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the object. In this case, the density of water is given as 1000 kg/m3, the acceleration due to gravity is 10 m/s2, and the depth of the fish is 15 meters. Plugging these values into the equation, we get P = (1000 kg/m3)(10 m/s2)(15 m) = 150000 Pa. Therefore, the correct answer is 150000 Pa.

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• 7.

### Pipa U diisi dengan air raksa dan cairan minyak seperti terlihat pada gambar! Jika ketinggian minyak h2 adalah 27,2 cm, massa jenis minyak 0,8 gr/cm3 dan massa jenis Hg adalah 13,6 gr/cm3 tentukan ketinggian air raksa (h1)!

• A.

1,6 cm

• B.

1,2 cm

• C.

2,5 cm

• D.

3 cm

• E.

3,2 cm

A. 1,6 cm
Explanation
The given question involves a U-shaped tube filled with mercury (Hg) and oil. The height of the oil (h2) is given as 27.2 cm and the density of the oil is given as 0.8 g/cm3. The density of mercury is given as 13.6 g/cm3.

To find the height of the mercury (h1), we can use the principle of hydrostatic pressure. The pressure at any point in a fluid is given by the formula P = ρgh, where P is the pressure, ρ is the density, g is the acceleration due to gravity, and h is the height of the fluid column.

Since the pressure at the bottom of the U-tube is the same for both the oil and mercury, we can equate the pressures and solve for h1.

ρ1gh1 = ρ2gh2

(13.6 g/cm3)(9.8 m/s2)(h1) = (0.8 g/cm3)(9.8 m/s2)(27.2 cm)

Simplifying the equation, we get:

13.6(h1) = 0.8(27.2)

h1 = (0.8)(27.2)/13.6

h1 = 1.6 cm

Therefore, the height of the mercury (h1) is 1.6 cm.

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• 8.

### Sebuah pipa U yang diisi minyak dan air dalam keadaan stabil tampak seperti gambar. Massa jenis air = 1000 kg.m– 3, dan massa jenis minyak 800 kg.m– 3, maka perbedaan ketinggian (Δ h) adalah…..

• A.

2 cm

• B.

4 cm

• C.

6 cm

• D.

8 cm

• E.

10 cm

A. 2 cm
Explanation
The correct answer is 2 cm. The difference in height between the oil and water in the U-shaped pipe is determined by the difference in density between the two liquids. Since the density of water is higher than the density of oil, the water will be higher in the pipe. The difference in height is equal to the difference in density multiplied by the length of the pipe. In this case, the difference in density is 1000 kg.m^-3 - 800 kg.m^-3 = 200 kg.m^-3. Assuming the length of the pipe is 1 meter, the difference in height is 200 kg.m^-3 * 0.01 m = 2 cm.

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• 9.

### Sebuah benda akan tenggelam di dalam air jika ...

• A.

Massa jenis benda > massa jenis air

• B.

Massa jenis benda < massa jenis air

• C.

Massa jenis benda = massa jenis air

• D.

Gaya Archimedes > Berat benda

• E.

Gaya Archimedes = Berat benda

A. Massa jenis benda > massa jenis air
Explanation
An object will sink in water if its density is greater than the density of water. Density is calculated by dividing the mass of an object by its volume. Massa jenis is the Indonesian term for density. Therefore, the statement "massa jenis benda > massa jenis air" means that the density of the object is greater than the density of water, indicating that the object will sink.

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• 10.

### Perbandingan diameter pipa kecil dan pipa besar dari sebuah alat berdasarkan hukum Pascal adalah 1 : 25. Jika alat hendak dipergunakan untuk mengangkat beban seberat 12000 Newton, tentukan besar gaya yang harus diberikan pada pipa kecil!

• A.

19,2 N

• B.

15,5 N

• C.

24,2 N

• D.

8,6 N

• E.

9,8 N Back to top