Ulangan Kimia Xi Mia

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| By Marlinaleni692
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Marlinaleni692
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Quizzes Created: 1 | Total Attempts: 2,213
Questions: 14 | Attempts: 2,213

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Ulangan Kimia Xi Mia - Quiz


Questions and Answers
  • 1. 

    Adanya senyawa karbon dalam suatu zat dapat diketahui dengan cara membakar zat tersebut. Jika zat mengandung senyawa karbon, pembakaran sempurna zat akan menghasilkan . . . . . 

    • A.

      Gas oksigen

    • B.

      Gas karbon dioksida

    • C.

      Gas karbon monoksida

    • D.

      Air kapur

    • E.

      Endapan kapur

    Correct Answer
    B. Gas karbon dioksida
    Explanation
    When a substance containing carbon is burned completely, it produces carbon dioxide gas. This is because carbon reacts with oxygen during combustion to form carbon dioxide. Therefore, the correct answer is gas karbon dioksida (carbon dioxide gas).

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  • 2. 

    Senyawa karbon anorganik umumnya mempunyai sifat-sifat . . . . .

    • A.

      Hanya dapat disintesis oleh makhluk hidup

    • B.

      Molekulnya mempunyai rantai atom karbon

    • C.

      .mudah rusak oleh pemanasan pada suhu tinggi

    • D.

      Titik didih dan titik lemburnya relatif rendah

    • E.

      Mudah larut dalam pelarut polar

    Correct Answer
    E. Mudah larut dalam pelarut polar
    Explanation
    The correct answer is "mudah larut dalam pelarut polar" because it is stating a characteristic of inorganic carbon compounds. Inorganic carbon compounds are generally soluble in polar solvents due to their ionic or polar nature. This is in contrast to organic carbon compounds, which are typically insoluble in polar solvents.

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  • 3. 

    Kekhasan atom karbon yang menyebabkan unsur karbon mempunyai banyak ragam senyawa adalah . . . . . . 

    • A.

      Mempunyai 4 elektron valensi yang dapat digunakan untuk berikatan kovalen

    • B.

      Dapat membentuk rantai karbon dengan berbagai bentuk

    • C.

      Mempunyai konfigurasi elektron yang belum stabil seperti gas mulia

    • D.

      Bentuk ruang ikatan pada atom karbon adalah tetrahedron

    • E.

      Merupakan zat padat yang sangat stabil pada suhu kamar

    Correct Answer
    A. Mempunyai 4 elektron valensi yang dapat digunakan untuk berikatan kovalen
    Explanation
    The uniqueness of carbon atoms lies in their ability to form four covalent bonds due to having four valence electrons. This allows carbon to bond with a wide variety of other atoms, resulting in the formation of numerous compounds.

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  • 4. 

    Senyawa hidrokarbon paling sederhana yang hanya terdiri dari sebuah atom karbon adalah  . . . . . . 

    • A.

      Metana

    • B.

      Metena

    • C.

      Metuna

    • D.

      Karbon monoksida

    • E.

      Asetilena

    Correct Answer
    A. Metana
    Explanation
    Metana is the correct answer because it is the simplest hydrocarbon compound consisting of only one carbon atom bonded to four hydrogen atoms. The other options, metena, metuna, karbon monoksida, and asetilena, do not meet the criteria of being the simplest hydrocarbon with only one carbon atom.

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  • 5. 

    Rumus molekul yang menyatakan hidrokarbon jenuh adalah . . . . 

    • A.

      C3H4

    • B.

      C3H6

    • C.

      C4H8

    • D.

      C4H6

    • E.

      C4H10

    Correct Answer
    E. C4H10
    Explanation
    The molecular formula C4H10 represents a saturated hydrocarbon. This is because the ratio of carbon to hydrogen atoms in the formula is 1:2, which is characteristic of saturated hydrocarbons. Additionally, the presence of 4 carbon atoms and 10 hydrogen atoms indicates that the hydrocarbon is an alkane, specifically butane.

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  • 6. 

    Di dalam senyawa 2,3-dimetilpentana terdapat atom karbon primer, sekunder, dan tersier masing – masing sebanyak . . . . 

    • A.

      1, 2, dan 4

    • B.

      2, 1, dan 4

    • C.

      2, 4, dan 1

    • D.

      4, 1, dan 2

    • E.

      4, 2, dan 1

    Correct Answer
    D. 4, 1, dan 2
    Explanation
    The correct answer is 4, 1, dan 2. In the compound 2,3-dimethylpentane, there are 4 primary carbon atoms, 1 secondary carbon atom, and 2 tertiary carbon atoms. Primary carbon atoms are bonded to only one other carbon atom, secondary carbon atoms are bonded to two other carbon atoms, and tertiary carbon atoms are bonded to three other carbon atoms.

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  • 7. 

    Berikut ini yang bukan merupakan sifat deret homolog adalah . . . . .  

    • A.

      Dapat dinyatakan dengan suatu rumus umum

    • B.

      Titik didihnya meningkat dengan panjangnya rantai

    • C.

      Anggotanya mempunyai sifat kimia yang serupa

    • D.

      Mempunyai rumus empiris yang sama

    • E.

      Dari satu anggota ke anggota berikutnya berbeda CH2

    Correct Answer
    D. Mempunyai rumus empiris yang sama
    Explanation
    The correct answer is "Mempunyai rumus empiris yang sama". This is because the concept of homologous series is based on compounds having the same functional group and a similar chemical structure, but with a gradual increase in the number of CH2 groups. The empirical formula represents the simplest ratio of elements in a compound, and in a homologous series, the number of CH2 groups changes, resulting in different empirical formulas for each compound.

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  • 8. 

    Jumlah isomer alkana dengan rumus C5H12 adalah . . . . 

    • A.

      2

    • B.

      3

    • C.

      4

    • D.

      5

    • E.

      6

    Correct Answer
    B. 3
    Explanation
    The correct answer is 3. This is because the given formula C5H12 represents pentane, which is an alkane. Alkanes are hydrocarbons with only single bonds between carbon atoms. For pentane, there are three possible isomers: n-pentane, isopentane, and neopentane. These isomers have the same molecular formula but differ in the arrangement of their carbon atoms, resulting in different chemical and physical properties. Therefore, the correct answer is 3.

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  • 9. 

    Senyawa CH3CH2CH2CH3  dan ( CH3 )3 CH keduanya merupakan . . . . .

    • A.

      Anggota deret homolog yag berbeda

    • B.

      Hidrokarbon jenuh dan tidak jenuh

    • C.

      Saling berisomeri

    • D.

      Mempunyai sifat fisis dan kimia yang sama

    • E.

      Mempunyai titik didih yang sama

    Correct Answer
    C. Saling berisomeri
    Explanation
    The compounds CH3CH2CH2CH3 and (CH3)3CH are isomers of each other. Isomers are compounds that have the same molecular formula but different structural arrangements. In this case, the two compounds have the same number and type of atoms (carbon and hydrogen), but they are arranged differently. CH3CH2CH2CH3 is a straight-chain alkane, while (CH3)3CH is a branched alkane. Therefore, they exhibit isomerism.

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  • 10. 

    Perhatikan struktur hidrokarbon berikut.
    1. CH3 CH(CH3)CH2CH3
    2. CH3CHCH2
    3. CH3CH2CH2CH3
    4. CH3CHC(CH3)CH3
              Hidrokarbom yang termasuk anggota deret homoglog alkana adalah . . . .  

    • A.

      I dan ii

    • B.

      I dan iii

    • C.

      I, ii, dan iii

    • D.

      Ii dan iv

    • E.

      iv saja

    Correct Answer
    B. I dan iii
    Explanation
    The given structure is a branched hydrocarbon with multiple substituents. The first structure (i) is a straight-chain alkane with 10 carbon atoms, while the third structure (iii) is a branched alkane with 9 carbon atoms. Both structures belong to the homologous series of alkanes because they have only carbon and hydrogen atoms and follow the general formula CnH2n+2. Therefore, the correct answer is "i dan iii" (i and iii).

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  • 11. 

    Penamaan hidrokarbon berikut yang tidak tepat adalah . . . . .

    • A.

      2-metilbutana

    • B.

      1,2-dimetilbutana

    • C.

      2,2,3-trimetilbutana

    • D.

      3-metil-1- butena

    • E.

      3-etilpentana

    Correct Answer
    B. 1,2-dimetilbutana
    Explanation
    The correct answer is 1,2-dimetilbutana. The reason why this is the incorrect naming of a hydrocarbon is because the numbering of the carbon atoms in the parent chain should start from the end closest to the substituents. In this case, the substituents are methyl groups attached to the second and third carbon atoms. Therefore, the correct name should be 2,3-dimetilbutana.

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  • 12. 

    Penamaan hidrokarbon berikut yang tidak tepat adalah . . . . . 

    • A.

      2-metilbutana

    • B.

      1,2-dimetilbutana

    • C.

      3-etilpentana

    • D.

      2,2,3-trimetilbutana

    • E.

      3-metil-1- butena

    Correct Answer
    B. 1,2-dimetilbutana
  • 13. 

    Jumlah isomer alkana dengan rumus molekul C4H10 adalah . . .  .

    • A.

      2

    • B.

      3

    • C.

      4

    • D.

      5

    • E.

      6

    Correct Answer
    A. 2
    Explanation
    The correct answer is 2 because with the molecular formula C4H10, there are two possible isomers of alkane: butane and isobutane. Butane has a straight chain of four carbon atoms, while isobutane has a branched structure with three carbon atoms in a chain and one carbon atom branching off.

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  • 14. 

    Fraksi minyak bumi yang digunakan sebagai bahan bakar dengan oktan tinggi adalah . . . . 

    • A.

      Kerosin

    • B.

      Residu

    • C.

      Solar

    • D.

      Bensin

    • E.

      Bitumen

    • F.

      Bitumen

    Correct Answer
    D. Bensin
    Explanation
    Bensin adalah fraksi minyak bumi yang digunakan sebagai bahan bakar dengan oktan tinggi.

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