C & Circuit Debugging | Engineer's Day

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  • 1/77 Questions

    What is the output of this program?#include <stdio.h>void main(){    int i = 1;    printf("%d", printf("%d", printf("%d", printf("%d", i))));} 

    • 1111
    • 1234
    • 1222
    • 4321
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About This Quiz

Celebrate Engineer's Day with this C & Circuit Debugging quiz! Test your skills in understanding and predicting the outputs of C programs, enhancing your debugging capabilities. Perfect for those looking to sharpen their programming acumen.

C & Circuit Debugging | Engineers Day - Quiz

Quiz Preview

  • 2. 
    THIS IS - ProProfs

    THIS IS

    • AN EXAMPLE FOR KARNAUGH MAPPING

    • AN EXAMPLE FOR NICHOLAS MAPPING

    • AN EXAMPLE FOR KHAY MAPPING

    • AN EXAMPLE FOR KAI MAPPING

    Correct Answer
    A. AN EXAMPLE FOR KARNAUGH MAPPING
    Explanation
    The given answer correctly identifies that the given statement is an example for Karnaugh mapping. Karnaugh mapping is a method used in digital circuit design to simplify Boolean algebra expressions and minimize the number of logic gates required. This technique involves creating a truth table and grouping similar terms to identify patterns and simplify the expression. Therefore, the given statement serves as an example of applying Karnaugh mapping in a specific context.

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  • 3. 

    What is the output of this program?#include <stdio.h>void main(){    int i = 10, j = 5, k = 0;    j = i ++;    k = ++ j;    int x = ++k;    printf("%d", x);} 

    • 11

    • 12

    • 101

    • Option 4

    Correct Answer
    A. 12
    Explanation
    The program starts by initializing three variables: i with a value of 10, j with a value of 5, and k with a value of 0. Then, the value of i is assigned to j and incremented by 1, resulting in j becoming 10 and i becoming 11. Next, j is incremented by 1, becoming 11, and its value is assigned to k. Finally, k is incremented by 1, becoming 12. The value of x is then assigned the value of k, which is 12. Therefore, the output of the program is 12.

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  • 4. 

    What is the output of this program?void main(){int k;for (k = -3; k < -5; k++)printf("Hello");}

    • Hello

    • Infinite Hello

    • Runtime error

    • Nothing

    Correct Answer
    A. Nothing
    Explanation
    The program initializes the variable k to -3 and enters a for loop. The condition for the loop is that k is less than -5, which is not true since k is -3. Therefore, the loop does not execute and the program does not print anything. Hence, the output of the program is "Nothing".

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  • 5. 

    A variable declared in a function can be used in main.

    • True

    • False

    • True if it is declared static

    • None of the mentioned

    Correct Answer
    A. False
    Explanation
    A variable declared in a function is local to that function and cannot be accessed outside of it, including in the main function. Therefore, the statement "A variable declared in a function can be used in main" is false.

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  • 6. 

    What is the output of this code having void return-type function?void foo(){return 1;}void main(){int x = 0;x = foo();printf("%d", x);}

    • 1

    • 0

    • Runtime error

    • Compile time error

    Correct Answer
    A. Compile time error
    Explanation
    The code is attempting to return an integer value (1) from a function with a void return type (foo). This is not allowed and will result in a compile time error. The correct answer is Compile time error.

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  • 7. 

    What is the output of this C code?int main(){    int x = 0;    if (x == 0)           printf("true, ");    else if (x = 10)           printf("false, ");    printf("%d\n", x);}

    • False, 0

    • True, 10

    • True, 0

    • Compile time error

    Correct Answer
    A. True, 0
    Explanation
    The code first initializes the variable x to 0. Then it enters the if statement and since x is equal to 0, it prints "true, ". After that, it proceeds to the next printf statement and prints the value of x which is 0. Therefore, the output of the code is "true, 0".

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  • 8. 
    The circuit shown in the figure is a - ProProfs

    The circuit shown in the figure is a

    • Toggle Flip Flop

    • JK Flip Flop

    • SR Latch

    • Master-Slave D Flip Flop

    Correct Answer
    A. Master-Slave D Flip Flop
    Explanation
    The circuit shown in the figure is a Master-Slave D Flip Flop. This can be determined by analyzing the circuit diagram and identifying the characteristics of each type of flip flop. The presence of two D flip flops connected in a master-slave configuration indicates that it is a Master-Slave D Flip Flop.

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  • 9. 

    What is the output of this C code?void m(){printf("hi");}void main(){m();} 

    • Hi

    • Runtime error

    • Nothing

    • Varies

    Correct Answer
    A. Hi
    Explanation
    The given C code defines a function "m()" which prints "hi" using the printf() function. The main() function calls the m() function. Therefore, when the code is executed, it will output "hi".

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  • 10. 

    What is the output of this C code?int main(){void foo();printf("1 ");foo();}void foo(){printf("2 ");}

    • 1 2

    • Compile time error

    • 1 2 1 2

    • Depends on the compiler

    Correct Answer
    A. 1 2
    Explanation
    The output of this C code is "1 2". The code first calls the main function, which then calls the foo function. Inside the foo function, "2" is printed. After the foo function is executed, the main function continues and prints "1". Therefore, the overall output is "1 2".

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  • 11. 

    Which of the following operators has the lowest precedence?

    • !=

    • &&

    • ?:

    • ,

    Correct Answer
    A. ,
    Explanation
    The operator with the lowest precedence is the comma operator (,). This operator is used to separate expressions and evaluate them from left to right. It has the lowest precedence, meaning it is evaluated last among the given operators. Therefore, the comma operator has the lowest priority in terms of precedence.

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  • 12. 

    What is the output of this program?int main(){int a = 0;for(a = 0; a <= 10; a++)for( a = 0; a <= 10; a++)for(a = 0; a <= 100; a++); printf("%d", a);return 0;}

    • 103

    • 101

    • 13

    • 11

    Correct Answer
    A. 101
    Explanation
    The output of the program is 101. This is because the program uses nested for loops to increment the value of 'a'. The first loop initializes 'a' to 0 and continues as long as 'a' is less than or equal to 10. The second loop also initializes 'a' to 0 and continues as long as 'a' is less than or equal to 10. The third loop initializes 'a' to 0 and continues as long as 'a' is less than or equal to 100, but it does not have any statements inside the loop. After the third loop, the printf statement is executed, which prints the value of 'a' which is 101.

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  • 13. 

    Switch statement accepts _______.

    • Int

    • Char

    • Long

    • All of the mentioned

    Correct Answer
    A. All of the mentioned
    Explanation
    A switch statement in programming accepts multiple data types, including int, char, and long. Therefore, the correct answer is "All of the mentioned." This means that a switch statement can be used with any of these data types as input.

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  • 14. 

    What is the output of this C code?int main(){    int x = 0;    if (x == 1)           if (x == 0)                printf("inside if\n");           else                printf("inside else if\n");    else           printf("inside else\n");}

    • Inside else if

    • Inside else

    • Compile time error

    • Inside if

    Correct Answer
    A. Inside else
    Explanation
    The code starts by initializing the variable x to 0. The first if statement checks if x is equal to 1, which is false. Therefore, the code skips the first if statement and moves on to the else statement. The else statement prints "inside else". So, the output of this code is "inside else".

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  • 15. 

    What is the output of this C code?#include <stdio.h>int main(){    int i = 10, j = 3, k = 3;    printf("%d %d ", i, j, k);} 

    • Compile time Error

    • 10 3 3

    • 10 3

    • 10 3 some garbage value

    Correct Answer
    A. 10 3
    Explanation
    The code will output "10 3" because the printf function is given two format specifiers ("%d") but only two arguments (i and j). The third argument (k) is not being used in the printf function, so it does not affect the output.

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  • 16. 

    What is the output of this C code?#include <stdio.h>int main(){    char *s = "myworld";    int i = 9;    printf("%*s", i, s);}

    • *myworld

    • Myworld(note: spaces to the left of myworld)

    • Myworld(note: spaces to the right of myworld)

    • *s

    Correct Answer
    A. Myworld(note: spaces to the left of myworld)
    Explanation
    The code uses the printf function to print the string "myworld" with a width of 9 characters. The * in the format specifier %*s indicates that the width is specified by the next argument, which is i. Since i is 9, the output will be "myworld" with 9 spaces to the left of it.

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  • 17. 

    Which of the following method are accepted for assignment?

    • 5 = a = b = c = d;

    • A = b = c = d = 5;

    • A = b = 5 = c = d;

    • None of the mentioned

    Correct Answer
    A. A = b = c = d = 5;
    Explanation
    The correct answer is "a = b = c = d = 5;". This is because in this method, the value of 5 is assigned to all variables a, b, c, and d in a single line. This is a valid assignment syntax in many programming languages.

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  • 18. 

    What is the output of this C code?int main(){int x = 1, y = 2;if (x && y == 1)printf("true\n");elseprintf("false\n");}

    • False

    • True

    • Compile time error

    • Runtime error

    Correct Answer
    A. False
    Explanation
    The code snippet declares two variables, x and y, with initial values of 1 and 2 respectively. The if statement checks if both x and y satisfy the condition x && y == 1. Since x is not equal to zero, the condition evaluates to true. However, y is not equal to 1, so the condition as a whole evaluates to false. Therefore, the else block is executed and "false" is printed as the output.

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  • 19. 

    What is the output of this C snippet?int main(){int i = 0;for (i++; i == 1; i = 2)printf("%d ", i);printf("%d", i);}

    • 1 2

    • 1 2 4 5 6

    • 0 1 2

    • 0 1

    Correct Answer
    A. 1 2
    Explanation
    The given C snippet includes a for loop that has three parts: initialization (i++), condition (i == 1), and increment (i = 2).

    Initially, the value of i is 0. In the first iteration, i is incremented to 1. Since the condition i == 1 is true, the loop body is executed, and the value of i (which is 2) is printed.

    In the next iteration, i is again incremented to 3. However, the condition i == 1 is false, so the loop is terminated.

    Finally, outside the loop, the value of i (which is 2) is printed.

    Therefore, the output of this C snippet is 1 2.

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  • 20. 

    Which loop is more suitable for first perform the operation and then test the condition?

    • For loop

    • While loop

    • Do-while loop

    • None of the mentioned

    Correct Answer
    A. Do-while loop
    Explanation
    The do-while loop is more suitable for first performing the operation and then testing the condition. This is because the do-while loop executes the code block at least once before checking the condition. Therefore, it guarantees that the operation will be performed at least once, regardless of the condition. In contrast, the for loop and while loop first test the condition before executing the code block, so they may not execute the operation if the condition is initially false.

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  • 21. 

    Which of the following is an invalid if-else statement?

    • If(if(a == 1)){}

    • If(func1(a)){}

    • If(a) {}

    • If((char) a){}

    Correct Answer
    A. If(if(a == 1)){}
    Explanation
    The given if-else statement "if(if(a == 1)){}" is invalid because the condition inside the outer if statement is another if statement, which is not allowed. The condition inside an if statement should be a boolean expression, but in this case, it is another if statement, which is not a valid boolean expression.

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  • 22. 

    An increase in the base recombination of a BJT will increase 

    • The common emitter dc current gain

    • The breakdown voltage

    • The unity-gain cut-off frequency

    • The transconductance

    Correct Answer
    A. The breakdown voltage
    Explanation
    An increase in the base recombination of a BJT will increase the breakdown voltage. This is because base recombination refers to the recombination of charge carriers in the base region of the transistor. When there is an increase in base recombination, more charge carriers are lost, leading to a decrease in the number of charge carriers available for conduction. This reduction in charge carriers reduces the current flow through the transistor, which in turn increases the breakdown voltage.

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  • 23. 

    Example of iteration in C

    • For

    • While

    • Do-while

    • All of the mentioned

    Correct Answer
    A. All of the mentioned
    Explanation
    All of the mentioned options (for, while, do-while) are examples of iteration in the C programming language. Iteration is a process of repeatedly executing a block of code until a certain condition is met. The "for" loop is used when the number of iterations is known beforehand. The "while" loop is used when the number of iterations is not known beforehand, but a condition needs to be checked before each iteration. The "do-while" loop is similar to the "while" loop, but it checks the condition after each iteration. Therefore, all of the mentioned options are valid examples of iteration in C.

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  • 24. 
    The value of load resistance such that the power transferred to load is maximum is  - ProProfs

    The value of load resistance such that the power transferred to load is maximum is 

    • 15Ω

    • 30Ω

    • 3.5Ω

    • ALMOST ZERO

    Correct Answer
    A. 15Ω
    Explanation
    The value of the load resistance affects the power transferred to the load in a circuit. When the load resistance is equal to the internal resistance of the source, the power transferred is maximum. In this case, the load resistance of 15Ω is the closest to the internal resistance, making it the correct answer.

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  • 25. 

    What is the output of this program?void rec(int);int main(){int a = 10;rec(10);return 0;}void rec(int a){if(a == 0)return;printf("%d", a);rec(--a);}

    • 10987654321

    • 12345678910

    • 1086420

    • 109876543210

    Correct Answer
    A. 10987654321
    Explanation
    The program starts by calling the function rec(10) from the main function. The rec function takes an integer parameter 'a'. Inside the rec function, it checks if 'a' is equal to 0, and if so, it returns. Otherwise, it prints the value of 'a' and then recursively calls the rec function with 'a' decremented by 1. This process continues until 'a' becomes 0. So, the program will print the numbers from 10 to 1 in descending order, resulting in the output "10987654321".

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  • 26. 

    What is the output of this C code?int main(){int x = 1, y = 2;int z = x & y == 2;printf("%d\n", z);}

    • 0

    • 1

    • Compile time error

    • Undefined behaviour

    Correct Answer
    A. 1
    Explanation
    The output of this C code is 1. The code declares three variables: x with a value of 1, y with a value of 2, and z. The expression "x & y == 2" is evaluated using the bitwise AND operator "&". Since the bitwise AND operator has higher precedence than the equality operator "==", the expression is equivalent to "x & (y == 2)". The equality operator compares the value of y to 2, which is true, resulting in 1. Then, the bitwise AND operator is applied to 1 and 1, resulting in 1. Finally, the value of z, which is 1, is printed.

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  • 27. 

    What is the output of this C code?#include <stdio.h>void main(){    func();} void func(){                printf("hi");                func();} 

    • Print hi for infinite time

    • Compile time Error

    • Segmentation Fault

    • Nothing

    Correct Answer
    A. Print hi for infinite time
    Explanation
    The given code will result in an infinite loop. The main function calls the func function, which prints "hi" and then calls itself again. This process will continue indefinitely, resulting in the output "hi" being printed infinitely.

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  • 28. 

    What is the output of this C code?void main(){1 < 2 ? return 1 : return 2;}

    • Returns 1

    • Returns 2

    • Varies

    • Compile time error

    Correct Answer
    A. Returns 1
    Explanation
    The code snippet uses the ternary operator to check if 1 is less than 2. Since this condition is always true, the expression after the '?' is executed, which is "return 1". Therefore, the output of the code is 1.

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  • 29. 

    What is the output of this C code?void main(){    char *str = "";    do    {           printf("hello");    } while (str);}

    • Runtime Error

    • Nothing

    • Compile time error

    • Hello is printed infinite times

    Correct Answer
    A. Hello is printed infinite times
    Explanation
    The code declares a character pointer variable `str` and assigns it an empty string. The code then enters a do-while loop, which will always execute at least once. Inside the loop, the string "hello" is printed. Since the condition for the loop is `str`, which is a non-null pointer, the loop will continue to execute indefinitely, resulting in "hello" being printed infinite times.

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  • 30. 

    Number of times while loop condition is tested is, i is initialized to 0 in both case.while(i < n)     i++;_ _ _ _ _ _ _ _ _do     i++;while(i <= n)

    • N, n

    • N, n + 1

    • N + 1, n

    • N + 1, n + 1

    Correct Answer
    A. N + 1, n + 1
    Explanation
    The given code snippet consists of two loops. The first loop is a while loop that increments the value of i until it becomes greater than n. The second loop is a do-while loop that also increments the value of i until it becomes greater than or equal to n.

    In both cases, the initial value of i is 0.

    In the first loop, the condition is tested n times because i starts at 0 and is incremented n times until it becomes greater than n.

    In the second loop, the condition is tested n+1 times because i starts at 0 and is incremented n+1 times until it becomes greater than or equal to n.

    Therefore, the correct answer is n + 1, n + 1.

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  • 31. 

    What is the output of this C code?int main(){    int x = 1;    if (x > 0)           printf("inside if ");    else if (x > 0)           printf("inside elseif ");}

    • Inside if

    • Inside elseif

    • Inside if inside else if

    • Compile time Error

    Correct Answer
    A. Inside if
    Explanation
    The code will output "inside if" because the condition in the if statement (x > 0) is true. The else if statement will not be executed because the condition (x > 0) is not true.

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  • 32. 
    FIGURE SHOWS THE SWITCH REPRESENTATION OF----GATE - ProProfs

    FIGURE SHOWS THE SWITCH REPRESENTATION OF----GATE

    • AND

    • XNOR

    • NAND

    • NOR

    Correct Answer
    A. AND
    Explanation
    The figure shows the switch representation of an AND gate. The AND gate is a logic gate that outputs a high signal only when all of its inputs are high. In the figure, there are two switches connected in series, indicating that both switches must be closed (or in the ON position) for the output to be high. This matches the behavior of an AND gate, making it the correct answer.

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  • 33. 

    What is the output this program?int main(){int a = -10;while(a){a++;}printf("%d", a);return 0;}

    • 10

    • 0

    • -1

    • 1

    Correct Answer
    A. 0
    Explanation
    The program initializes the variable "a" with a value of -10. The while loop runs as long as "a" is non-zero, which means it will continue until "a" becomes 0. Inside the loop, "a" is incremented by 1 on each iteration. Since "a" starts at -10 and is incremented by 1 each time, it will eventually reach 0 after 10 iterations of the loop. Therefore, the output of the program will be 0.

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  • 34. 

    What is the output of this C code?int main(){int a = 2;int b = 0;int y = (b == 0) ? a :(a > b) ? (b = 1): a;printf("%d\n", y);}

    • 1

    • Compile time error

    • 2

    • Undefined behaviour

    Correct Answer
    A. 2
    Explanation
    The code initializes three variables: a with the value 2, b with the value 0, and y with the result of a conditional expression. The conditional expression checks if b is equal to 0. Since it is, the expression evaluates to a. Therefore, the value of y is 2. The code then prints the value of y, which is 2.

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  • 35. 

    Comment on the output of this C code?int main(){    int x = 3, i = 0;    do {           x = x++;           i++;    } while (i != 3);    printf("%d\n", x);}

    • Output will be 3

    • Undefined behavior

    • Output will be 6

    • Output will be 5

    Correct Answer
    A. Output will be 3
    Explanation
    The output of this C code will be 3.

    In the do-while loop, the variable x is assigned the value of x++ which is a post-increment operation. This means that the current value of x is assigned to x, and then the value of x is incremented.

    Since the initial value of x is 3, the assignment statement x = x++ will assign the value 3 to x and then increment it to 4.

    However, the value of x is not used or updated in the condition of the do-while loop, which is i != 3. Therefore, the loop will only execute once, and the value of x will remain 3.

    Hence, the output of the code will be 3.

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  • 36. 

    What is the output of this program?int main(){int a = 0;for(; a <= 10; a++);printf("%d", a);}

    • 10

    • 11

    • 12

    • 9

    Correct Answer
    A. 11
    Explanation
    The program initializes the variable "a" to 0. It then enters a for loop that continues as long as "a" is less than or equal to 10. In each iteration of the loop, "a" is incremented by 1. After the loop ends, the program prints the value of "a" which is 11. Therefore, the output of the program is 11.

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  • 37. 

    What is the output of this C code?void main(){int n = 0, m = 0;if (n > 0)if (m > 0)printf("True");elseprintf("False");}

    • True

    • False

    • No output will be printed

    • D. Run time error

    Correct Answer
    A. No output will be printed
    Explanation
    The code snippet defines two variables, n and m, both initialized to 0. The code then checks if n is greater than 0. Since n is 0, the condition is false and the code does not execute the inner if statement. Therefore, no output will be printed.

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  • 38. 

    What is the output of this program?int main(){int a = 65;char c = a;printf("%d %c", c, a);}

    • 65 A

    • A 65

    • 65 65

    • A A

    • Compile time error

    • Run time error

    Correct Answer
    A. 65 A
    Explanation
    The program initializes an integer variable 'a' with the value 65. Then, it assigns the value of 'a' to a character variable 'c'. Since the ASCII value of 65 corresponds to the character 'A', 'c' will hold the value 'A'. The printf statement then prints the value of 'c' followed by the value of 'a', resulting in the output "65 A".

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  • 39. 

    What is the output of this C code?#include <stdio.h>int main(){    int i = 10, j = 3;    printf("%d %d %d", i, j);} 

    • Compile time Error

    • 10 3

    • 10 3 some garbage value

    • Undefined behavior

    Correct Answer
    A. 10 3 some garbage value
    Explanation
    The code is missing a format specifier in the printf statement. It should have three format specifiers to match the three variables being passed. As a result, the code will print the values of i and j correctly, but the third value will be some garbage value since there is no corresponding variable to be printed.

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  • 40. 

    In CMOS technology, shallow P-well or N-well regions can be formed using 

    • Low pressure chemical vapour deposition

    • Low energy sputtering

    • Low temperature dry oxidation

    • Low energy ion-implantation

    Correct Answer
    A. Low energy ion-implantation
    Explanation
    In CMOS technology, shallow P-well or N-well regions are formed using low energy ion-implantation. Ion-implantation involves bombarding the semiconductor material with ions of the desired dopant, which are accelerated to a high energy and then implanted into the material. By using low energy, the ions can be implanted at a shallow depth, resulting in the formation of shallow P-well or N-well regions. This technique allows for precise control over the dopant concentration and depth, making it suitable for creating shallow regions in CMOS technology.

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  • 41. 
    THE FIGURE CONTAINS----- TRANSISTORS - ProProfs

    THE FIGURE CONTAINS----- TRANSISTORS

    • 2 NMOS

    • 2 BJT

    • 2 PMOS

    • 2 CENTER TAPPED JFET’S

    Correct Answer
    A. 2 NMOS
    Explanation
    The given figure contains 2 NMOS transistors.

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  • 42. 

    What is the output of this C code?int main(){void foo(), f();f();}void foo(){printf("2 ");}void f(){printf("1 ");foo();}

    • Compile time error as foo is local to main

    • 1 2

    • 2 1

    • Compile time error due to declaration of function inside main

    Correct Answer
    A. 1 2
    Explanation
    The code first declares two functions, foo() and f(). In the main() function, f() is called, which prints "1 ". Then, within f(), foo() is called, which prints "2 ". Therefore, the output of the code is "1 2".

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  • 43. 

    What is the output of this C code?int main(){    if (printf("%d", printf("")))           printf("We are Happy");    else if (printf("1"))           printf("We are Sad");}

    • 0We are Happy

    • 1We are Happy

    • 1We are Sad

    • 01We are Sad

    Correct Answer
    A. 0We are Happy
    Explanation
    The correct answer is "0We are Happy".

    The code first calls the inner printf function with an empty string as the argument. This inner printf function returns the number of characters printed, which is 0 in this case.

    Then, the outer printf function is called with the result of the inner printf function as the argument. Since the inner printf function printed 0 characters, the outer printf function receives a 0 as the argument.

    The outer printf function then prints "0" and returns the number of characters printed, which is 1.

    Finally, the if statement evaluates to true because the outer printf function returned a non-zero value. Therefore, "We are Happy" is printed.

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  • 44. 

    What is the output of this C snippet?int main(){int a = 65;char c = a;int d = a + c;printf("%d", d);}

    • 130

    • 120

    • 135

    • Compile time error

    • Runtime error

    Correct Answer
    A. 130
    Explanation
    In this C snippet, the variable "a" is assigned the value 65. Then, the variable "c" is assigned the value of "a", which is the character 'A' in ASCII. Next, the variable "d" is assigned the sum of "a" and "c", which is 65 + 65 = 130. Finally, the value of "d" is printed, resulting in the output of 130.

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  • 45. 

    What is the output of this C code?int main(){int x = 2, y = 2;float f = y + x /= x / y;printf("%d %f\n", x, f);return 0;}

    • Compile time error

    • 2 4.000000

    • 2 3.000000

    • Undefined behaviour

    Correct Answer
    A. Compile time error
    Explanation
    The given C code will result in a compile-time error. This is because the expression "y + x /= x / y" violates the order of operations in C. The division operation "x / y" is evaluated first, which results in 1. Then, the compound assignment operator "/=" is applied to "x" and the result of the division, which is not allowed. Hence, the code will fail to compile.

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  • 46. 

    What is the output of this C code?int main(){    int a = 1;    if (a--)           printf("True");     if (a++)           printf("False");}

    • True

    • False

    • True False

    • No output

    Correct Answer
    A. True
    Explanation
    The code initializes the variable "a" with the value 1. In the first if statement, "a--" is evaluated, which means the value of "a" is used in the condition and then decremented by 1. Since the initial value of "a" is 1, the condition is true and "True" is printed. In the second if statement, "a++" is evaluated, which means the value of "a" is used in the condition and then incremented by 1. Since the value of "a" is now 0, the condition is false and "False" is not printed. Therefore, the output of the code is "True".

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  • 47. 

    What is the output of this C code?#includeint main(){int x = 1;short int i = 2;float f = 3;if (sizeof((x == 2) ? f : i) == sizeof(float))printf("float\n");else if (sizeof((x == 2) ? f : i) == sizeof(short int))printf("short int\n");}

    • Float

    • Short int

    • Undefined behaviour

    • Compile time error

    Correct Answer
    A. Float
    Explanation
    The output of this C code is "float". This is because the conditional expression `(x == 2) ? f : i` is evaluated at runtime. Since `x` is not equal to 2, the expression evaluates to `i`, which is a short int. The `sizeof` operator is then used to determine the size of the expression. Since the size of `i` is not equal to the size of a float, the first if statement is not executed. The second if statement is then executed, which prints "float" as the output.

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  • 48. 

    What is the output of this program?#include <stdio.h>int printf(const char* restrict);void main(){                printf("hi");} int printf(const char* restrict){                return printf("%s", restrict);} 

    • Compile time Error

    • Hi

    • Nothing

    • Nothing print nut infinite loop occur

    Correct Answer
    A. Compile time Error
    Explanation
    The program will result in a compile time error because the function `printf` is being redefined with a different return type. The original `printf` function is declared in the standard library and has a return type of `int`, but in the program, it is redefined with a return type of `void`. This causes a conflict and the compiler throws an error.

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  • 49. 
    Assuming zero initial condition, the response y(t) of the system given below to aunit step input u(t) is - ProProfs

    Assuming zero initial condition, the response y(t) of the system given below to aunit step input u(t) is

    • U(t)

    • Tu(t)

    • Zero zero

    • Exp(t)

    Correct Answer
    A. Tu(t)
    Explanation
    The response of the system to a unit step input is given by tu(t). This means that the output of the system at any time t is equal to t multiplied by the unit step function u(t). The unit step function is zero for negative values of t and one for positive values of t. Therefore, the response of the system starts at zero and then increases linearly with time.

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  • Current Version
  • Mar 14, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Sep 09, 2014
    Quiz Created by
    Devmelbin

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