Graph Numerical Reasoning Test! Trivia Questions Quiz

The runner's initial position is given as 40 m at time t = 0 s. Since he runs at a constant pace of 1.5 m/s, we can calculate his position at t = 45 s by multiplying his velocity (1.5 m/s) by the time interval (45 s) and adding it to his initial position (40 m). Therefore, the runner's position at t = 45 s will be 1.5 m/s * 45 s + 40 m = 67.5 m + 40 m = 107.5 meters.

The runner's position at time t = 0 s is given as 20 m. Since the runner is running at a constant pace of 0.5 m/s, we can calculate his position at t = 45 s by multiplying the pace by the time. Therefore, the runner will have covered a distance of 0.5 m/s * 45 s = 22.5 m. Adding this distance to the initial position of 20 m, we get a final position of 20 m + 22.5 m = 42.5 m.

The object's velocity is constant because the position increases by a consistent amount of 10 meters every second. This indicates that the object is moving at a steady pace without any acceleration or deceleration. The +10 m/sec indicates that the object is moving in the positive direction along the position axis.

The starting position of the object is +30 meters. This can be determined by looking at the position values at time 0.0 seconds, which is given as 30 meters.

The equation X = (+10 m/sec) (t) + 30 m represents the object's position over time. The +10 m/sec indicates that the object's position is increasing by 10 meters per second. The (t) represents the time in seconds. The +30 m indicates that the object's initial position is 30 meters. Therefore, as time increases, the object's position increases by 10 meters per second.

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The interval from 5-7 seconds had the greatest velocity. This can be determined by looking at the graph and observing that the slope of the line during this interval is steeper compared to the other intervals. A steeper slope indicates a higher velocity. Therefore, the 5-7 second interval had the greatest velocity.

The interval from 12-14 seconds had the most negative velocity. This can be determined by looking at the graph and observing that the slope of the line during this interval is the steepest and goes downwards, indicating a negative velocity.

At 10 seconds, the graph shows a horizontal line, indicating that the vehicle's position is not changing over time. This means that the vehicle is not moving. Additionally, since the line is horizontal, it indicates that the vehicle's velocity is constant (not changing) during this time period. Therefore, the correct answer is that the vehicle is at a constant velocity and not moving.

According to the graph, at 10 seconds, the position of the vehicle remains constant, indicating that it is not moving. Additionally, the slope of the graph is zero at this point, which means that the velocity is also constant. Therefore, the correct answer is that the vehicle is at a constant velocity and not moving.

The graph shows that the velocity of the vehicle decreases from 1 m/sec to -1 m/sec between 2-5 seconds. Since the velocity is negative, it indicates that the vehicle is moving in the negative direction, opposite to the positive direction. Therefore, the correct answer is "Velocity = -1 m/sec, traveling in the negative direction."

The answer is correct because it is not possible for a vehicle to be in the same position at the same time value. This would violate the basic principles of physics and the concept of motion. In a single trial, a vehicle can have different positions at different time values, but it cannot occupy the same position at the same time.

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CMV2 has moved more positions overall from 0-15 seconds compared to CMV1.

The answer states that CMV2 has changed more position over this time period than CMV1. This implies that CMV2 has traveled a greater distance or has experienced a greater change in position compared to CMV1.

The velocity from 0-2 seconds is 0m/sec. This means that there is no change in position during this time interval, indicating that the object is not moving. The various options provided are just different ways of representing the same value of velocity, which is 0m/sec.

The correct answer is -3m/sec. The negative sign indicates that the velocity is in the opposite direction of the positive x-axis. The unit "m/sec" represents the rate of change of position with respect to time. Therefore, the velocity from 9-10 seconds is -3 meters per second.

The overall change of position for the object from time 0 to time 11 is -1 meter. This means that the object moved 1 meter in the negative direction along the y-axis during this time interval.