Rrb (Group A Officers) Exam 2012 Question Paper: Reasoning Ability

In each alternae step square shift one step and 2 step ACW directioni while T shin one and half step and half step CW direction.

If follow 1→2,→ 3→4, then 5→6 rule. In each step, upper elements shin "2 step and rotate 90° ACW, middle, elements

In each step one line is added in each figure

In each step, the figure rotates 45° Cw.

Except 'SU', all the pairs of letters belong to the first half.

From I: Possible months: January, February, March, April,
May or June,
From II: Rahul's son correctly remembers that his father
went on vacation after 31st March but before Ist May,
So his father went on vacation in the month of April.
Hence' only II is' sufficient.

From I: Two-digit marks is less than or equal to 20.
Possible marks: 10, 11,12,13,14,15,16,17,18, 19 and 20.
From II: Suman scored more than 9 marks.
Possible marks: 10, 11, 12., 13, 14, 15,16.17.18, 19 and 20.
Hence statement 1 and II together are not sufficient.

facing problems with health → mlp hIt ngi snk ... (i) health problems on rise → hIt sa rtv mlp ... (ii) rise with every challenge → snk rtv Ine riy …(iii) facing challenge each day → ngi riy nop hus…(iv) From (i) and (iv), facing → ngi (v) From (i) and (iii), with → snk (vi) From (ii) and (iiii), rise → rtv (vii) From (iii) and (iv), challenge → riy ... (viii) From (iii), (vi), (vii) and (viii), every → Ine ... (ix) From (i) and (ii), health → mlp or hIt problems → mlp or hIt ... (x) From (iv), (v) and (viii), each → nopor hus day → nop or hus ... (xi) From (ii), (vii) and (x), on → sa ... (xii)

facing problems with health → mlp hIt ngi snk ... (i) health problems on rise → hIt sa rtv mlp ... (ii) rise with every challenge → snk rtv Ine riy …(iii) facing challenge each day → ngi riy nop hus…(iv) From (i) and (iv), facing → ngi (v) From (i) and (iii), with → snk (vi) From (ii) and (iiii), rise → rtv (vii) From (iii) and (iv), challenge → riy ... (viii) From (iii), (vi), (vii) and (viii), every → Ine ... (ix) From (i) and (ii), health → mlp or hIt problems → mlp or hIt ... (x) From (iv), (v) and (viii), each → nopor hus day → nop or hus ... (xi) From (ii), (vii) and (x), on → sa ... (xii)

From I: The possible day of exam is Wednesday,
From II: The third day of the week is Wednesday, _
Hence, 'either statement I alone or statement 11 alone is, sufficient.

Only one word HARD can be formed.

Except Trouble all others are synonyms.

Except Trained all others are same in meaning.

Except Quiet all others are synonyms.

not-available-via-ai

In each step the side-upper corner and side-middle element , interchange positions and both the lower corner elements are replaced by new clements, and one of the middle elements
rotates 90° CW.

facing problems with health → mlp hIt ngi snk ... (i) health problems on rise → hIt sa rtv mlp ... (ii) rise with every challenge → snk rtv Ine riy …(iii) facing challenge each day → ngi riy nop hus…(iv) From (i) and (iv), facing → ngi (v) From (i) and (iii), with → snk (vi) From (ii) and (iiii), rise → rtv (vii) From (iii) and (iv), challenge → riy ... (viii) From (iii), (vi), (vii) and (viii), every → Ine ... (ix) From (i) and (ii), health → mlp or hIt problems → mlp or hIt ... (x) From (iv), (v) and (viii), each → nopor hus day → nop or hus ... (xi) From (ii), (vii) and (x), on → sa ... (xii)

The given code "riy snk mlp" corresponds to "challenge with health" based on the information provided in the code. The word "challenge" is represented by "riy", "with" is represented by "snk", and "health" is represented by "mlp". Therefore, the correct answer is "challenge with health".

facing problems with health → mlp hIt ngi snk ... (i) health problems on rise → hIt sa rtv mlp ... (ii) rise with every challenge → snk rtv Ine riy …(iii) facing challenge each day → ngi riy nop hus…(iv) From (i) and (iv), facing → ngi (v) From (i) and (iii), with → snk (vi) From (ii) and (iiii), rise → rtv (vii) From (iii) and (iv), challenge → riy ... (viii) From (iii), (vi), (vii) and (viii), every → Ine ... (ix) From (i) and (ii), health → mlp or hIt problems → mlp or hIt ... (x) From (iv), (v) and (viii), each → nopor hus day → nop or hus ... (xi) From (ii), (vii) and (x), on → sa ... (xii)

A>B=C ……(i) ; (ii);

E D>C …….(iii)

The figures (1) and (4) are the same; figure (2) and (5) are the same. So figures (3) and (6) are the same.

The question asks who amongst P, Q, R, S, and T is the tallest. Statement I tells us that P is taller than Q, but it does not provide any information about the heights of R, S, or T. Statement II tells us that R is taller than P and S is not the tallest, but it also does not provide any information about the heights of Q or T. Therefore, neither statement alone is sufficient to answer the question. However, when we combine both statements, we know that P is shorter than R, and S is shorter than R. Therefore, the only possibility is that R is the tallest. Thus, the data in both statements I and II together are necessary to answer the question.

From (I) to (2). One line is removed, From (2) to (3), two ones are added. From (3) to (4), three lines are removed. From (4) to (5)~ four lines are added and from (5) to (6), five lines are removed while whole figure move in each alternate step 45° CW and 90° ACW.

In alternate steps, the elements at each end shift one side ACW. The second from the top and the second from the bottom interchange their places, So do the second from the left and the second tram the right The middle element is replaced by a new element.

Because there is no negative statement Hence conclusion
I does not follow,
But conclusion II is inherent in the first statement

Some bottles are papers (I) + No paper is a calendar (E) = I + E = 0 = Some bottles are not calendars, Hence conclusion I does not follow, And there is no definite positive or negative relation between star and calendar, Hence conclusion II does not follow.

Some pencils are blankets (I) + All blankets are erasers (A) = I + A = I = Some pencils are erasers, Hence conclusion I follows,
Now, Some pencils are erasers; it means All erasers being pencils is a possibility, Hence conclusion II follows.

All stars are bottles (A) + Some bottles are papers (I) = A + I = No conclusion. However. Neither statement is negative. Hence, All stars being papers is a possibility.
Hence conclusion I follows.
Again, Some bottles are papers (I) + No paper is a calendar
(E) = I + E = 0 = Some bottles are not calendars. Hence
conclusion II does not follow.

All stars are bottles → conversion → Some bottles are
stars, Hence conclusion II follows,
Only, Some bottles are not calendars, Hence conclusion II
follows,

In each step one additional figure is added