Forces In 2D Challenge 1

1. Find the vertical component of this vector.

35 N

17.6 N

24.7 N

32.6 N

The vertical component of a vector refers to the part of the vector that is in the vertical direction, perpendicular to the horizontal plane. In this case, the given options represent different magnitudes of force (N). The correct answer is 24.7 N, which means that the vector has a vertical component of 24.7 N.

Explanation

The vertical component of a vector refers to the part of the vector that is in the vertical direction, perpendicular to the horizontal plane. In this case, the given options represent different magnitudes of force (N). The correct answer is 24.7 N, which means that the vector has a vertical component of 24.7 N.

2. Your mom tries to drag you out of bed. She pulls you by your feet with a force of 100 N at an angle of 22 degrees. How much of this force is pulling you forward (horizontally)?

75.1 N

87.9 N

37.5 N

92.7 N

The force applied by the mom can be resolved into two components: one in the horizontal direction and one in the vertical direction. The horizontal component is given by the formula F*cos(theta), where F is the magnitude of the force (100 N) and theta is the angle of the force (22 degrees). Plugging in the values, we get 100 N * cos(22 degrees) = 92.7 N. Therefore, 92.7 N of the force is pulling the person forward horizontally.

Explanation

The force applied by the mom can be resolved into two components: one in the horizontal direction and one in the vertical direction. The horizontal component is given by the formula F*cos(theta), where F is the magnitude of the force (100 N) and theta is the angle of the force (22 degrees). Plugging in the values, we get 100 N * cos(22 degrees) = 92.7 N. Therefore, 92.7 N of the force is pulling the person forward horizontally.

3. What is the vertical component of this vector?

68.8 N

102.6 N

98.3 N

77.8 N

The vertical component of a vector refers to the magnitude of the vector in the vertical direction. In this case, the correct answer is 68.8 N, which means that the vector has a magnitude of 68.8 N in the vertical direction.

Explanation

The vertical component of a vector refers to the magnitude of the vector in the vertical direction. In this case, the correct answer is 68.8 N, which means that the vector has a magnitude of 68.8 N in the vertical direction.

4. Find the horizontal component of this vector.

35 N

17.6 N

24.7 N

32.6 N

The horizontal component of a vector refers to the part of the vector that is in the horizontal direction. In this case, the correct answer of 24.7 N represents the horizontal component of the vector.

Explanation

The horizontal component of a vector refers to the part of the vector that is in the horizontal direction. In this case, the correct answer of 24.7 N represents the horizontal component of the vector.

5. What is the horizontal component of this vector?

68.8 N

102.6 N

98.3 N

77.8 N

The horizontal component of a vector refers to the part of the vector that lies along the x-axis. In this case, the correct answer of 98.3 N indicates that the vector has a horizontal component of 98.3 N.

Explanation

The horizontal component of a vector refers to the part of the vector that lies along the x-axis. In this case, the correct answer of 98.3 N indicates that the vector has a horizontal component of 98.3 N.

6. A child drags her backpack across the floor, pulling it with a force of 22 N with an angle of 60 degrees to the floor. Find the horizontal and vertical components of this force.

Horizontal= 19 N, vertical = 11 N

Horizontal = 11 N, vertical = 19 N

Horizontal = 38 N, vertical =17 N

Horizontal=17 N, vertical = 38 N

Horizontal = 8 N, vertical= 21 N

Horizontal =21 N, vertical=8 N

The force applied to the backpack can be broken down into its horizontal and vertical components using trigonometry. The horizontal component is calculated by multiplying the force magnitude (22 N) by the cosine of the angle (60 degrees), resulting in 11 N. The vertical component is calculated by multiplying the force magnitude (22 N) by the sine of the angle (60 degrees), resulting in 19 N. Therefore, the correct answer is horizontal = 11 N, vertical = 19 N.

Explanation

The force applied to the backpack can be broken down into its horizontal and vertical components using trigonometry. The horizontal component is calculated by multiplying the force magnitude (22 N) by the cosine of the angle (60 degrees), resulting in 11 N. The vertical component is calculated by multiplying the force magnitude (22 N) by the sine of the angle (60 degrees), resulting in 19 N. Therefore, the correct answer is horizontal = 11 N, vertical = 19 N.