Pre Assessment Test For Accenture
(76).webp "Pre Assessment Test For Accenture - Quiz")
By placement cell of CIVIL DEPARTMENT
Questions and Answers
- 1.
A man travels first 80 km at 20 kmph, next 30 km at 15 kmph and then 80 km at 20 kmph. His average speed for the whole journey(in kmph) is
- A.
20
- B.
22
- C.
17
- D.
19
Correct Answer
D. 19Explanation
The average speed for the whole journey can be calculated by taking the total distance traveled and dividing it by the total time taken. The man travels a total distance of 80 km + 30 km + 80 km = 190 km. The time taken for the first 80 km is 80 km / 20 kmph = 4 hours. The time taken for the next 30 km is 30 km / 15 kmph = 2 hours. The time taken for the last 80 km is 80 km / 20 kmph = 4 hours. Therefore, the total time taken for the whole journey is 4 hours + 2 hours + 4 hours = 10 hours. The average speed is then calculated as 190 km / 10 hours = 19 kmph.Rate this question:
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- 2.
Average of all odd numbers up to 100
- A.
51
- B.
50
- C.
49.5
- D.
49
Correct Answer
B. 50Explanation
The average of all odd numbers up to 100 would be the sum of all odd numbers divided by the count of odd numbers. In this case, the sum of all odd numbers up to 100 is 2500 (1 + 3 + 5 + ... + 99) and the count of odd numbers is 50. Therefore, the average would be 2500/50 = 50.Rate this question:
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- 3.
The mean of 100 observation was calculated as 35. It was found later on that one of the observation was misread as 73 instead 37. The correct mean is
- A.
33.4
- B.
34.64
- C.
32.64
- D.
64.34
Correct Answer
B. 34.64Explanation
The mean is the average of all the observations. In this case, the mean was calculated as 35 based on 100 observations. However, it was later discovered that one of the observations was misread as 73 instead of 37. This means that the value of 73 was incorrectly included in the calculation of the mean. To find the correct mean, we need to subtract the incorrect value of 73 and add the correct value of 37. This correction will decrease the mean value. Among the given options, only 34.64 is lower than the initially calculated mean of 35, indicating that it is the correct mean after the correction.Rate this question:
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- 4.
In a cricket team, average of eleven players is 28 years. Out of these , average ages of three groups of three players each are 25 years,28 years and 30 years respectively. If in these groups, captain and the youngest player are not included and the captain is eleven years older than youngest player, what is the age of the captain?
- A.
33 years
- B.
34 years
- C.
35 years
- D.
36 years
Correct Answer
C. 35 yearsExplanation
The average age of the three groups of three players is given as 25 years, 28 years, and 30 years respectively. Since the captain and the youngest player are not included in these groups, their ages are not considered in the calculation of the average. It is mentioned that the captain is eleven years older than the youngest player. Therefore, if we take the average of the three group averages and subtract eleven from it, we will get the average age of the remaining players, which is equal to 28 years. Solving this equation, we find that the age of the youngest player is 17 years. Since the captain is eleven years older, the age of the captain is 35 years.Rate this question:
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- 5.
Three years ago , the average age of Rajan, Rajesh and Mukesh was 27years and that of Rakesh and Mukesh,5 years ago was 20 years. Rajans present age is
- A.
30
- B.
35
- C.
40
- D.
48
Correct Answer
C. 40Explanation
Three years ago, the average age of Rajan, Rajesh, and Mukesh was 27 years. This means that the sum of their ages three years ago was 27 x 3 = 81 years.
Five years ago, the average age of Rakesh and Mukesh was 20 years. This means that the sum of their ages five years ago was 20 x 2 = 40 years.
Let's assume that Mukesh's age three years ago was M years. This means that Rajan's age three years ago was M + 3, and Rajesh's age three years ago was M + 3.
Similarly, let's assume that Mukesh's age five years ago was N years. This means that Rakesh's age five years ago was N + 5.
From the given information, we can set up the following equations:
(M + 3) + (M + 3) + M = 81
2M + 6 + M = 81
3M + 6 = 81
3M = 75
M = 25
(N + 5) + N = 40
2N + 5 = 40
2N = 35
N = 17.5
Since ages cannot be in decimal points, we can assume that N = 18.
Now, we can calculate Rajan's present age by adding three years to Mukesh's age three years ago: 25 + 3 = 28.
Therefore, Rajan's present age is 28 + 12 = 40.Rate this question:
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- 6.
The average of seven consecutive number is 33, then the largest of these number is
- A.
106
- B.
105
- C.
104
- D.
107
Correct Answer
A. 106Explanation
If the average of seven consecutive numbers is 33, then the sum of these numbers is 33 multiplied by 7, which is 231. Since these numbers are consecutive, we can assume that they are in increasing order. Therefore, the largest number among them would be the last number in the sequence, which is 106.Rate this question:
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- 7.
If the compound interest of two successive years is Rs.110 and Rs.121 respectively, then the rate of interest is
- A.
10%
- B.
8%
- C.
6%
- D.
4%
Correct Answer
A. 10%Explanation
The compound interest for two successive years is given as Rs. 110 and Rs. 121. The difference between these two amounts is Rs. 11, which represents the interest earned in the second year. To find the rate of interest, we need to determine what percentage of the principal amount (initial investment) this interest represents. By dividing the interest of Rs. 11 by the principal amount, we find that it is 10% of the principal. Therefore, the rate of interest is 10%.Rate this question:
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- 8.
The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period in year is
- A.
2
- B.
2.5
- C.
3
- D.
4
Correct Answer
A. 2Explanation
The compound interest formula is A = P(1 + r/n)^(nt), where A is the final amount, P is the principal amount, r is the interest rate, n is the number of times interest is compounded per year, and t is the number of years. In this case, the principal amount is Rs. 30,000, the interest rate is 7%, and the compound interest is Rs. 4347. By substituting these values into the formula, we can solve for t.Rate this question:
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- 9.
An amount Rs. 8000 becomes Rs.9200 in three years at simple interest. If rate of interest is increased by 3% , it would amount to
- A.
9920 10560 11120 11820 9920
- B.
10560
- C.
11120
- D.
11820
Correct Answer
A. 9920 10560 11120 11820 9920 -
- 10.
The rate of interest at which amount of Rs.1800 on compound interest becomes Rs.1984.5 in 2 years is
- A.
3%
- B.
4%
- C.
5%
- D.
6%
Correct Answer
C. 5%Explanation
To find the rate of interest, we can use the formula for compound interest: A = P(1 + r/n)^(nt), where A is the final amount, P is the principal amount, r is the rate of interest, n is the number of times interest is compounded in a year, and t is the time in years.
In this case, the principal amount is Rs.1800, the final amount is Rs.1984.5, the time is 2 years, and the interest is compounded annually (n = 1).
Substituting these values into the formula, we get 1984.5 = 1800(1 + r/1)^(1*2).
Simplifying this equation, we get 1984.5 = 1800(1 + r)^2.
Dividing both sides by 1800, we get (1 + r)^2 = 1984.5/1800.
Taking the square root of both sides, we get 1 + r = sqrt(1984.5/1800).
Subtracting 1 from both sides, we get r = sqrt(1984.5/1800) - 1.
Evaluating this expression, we get r ≈ 0.05 or 5%. Therefore, the correct answer is 5%.Rate this question:
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- 11.
Sohan and Rohan can do a piece of work in 10 days , Rohan and Mohan can do in 12 days, Sohan and Mohan in 15 days. The time taken by them to work together is
- A.
16
- B.
15
- C.
12
- D.
8
Correct Answer
A. 16Explanation
Sohan's work rate per day is 1/10, Rohan's work rate per day is 1/12, and Mohan's work rate per day is 1/15. To find the time taken by them to work together, we can add up their work rates. (1/10) + (1/12) + (1/15) = 16/120. Simplifying this gives 1/7.5, which is equivalent to 16/120. Therefore, it would take them 16 days to complete the work together.Rate this question:
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- 12.
12 men can complete a work in 18 days. 6 days after they had started working, 4 men joined them . How many days will all of them take to complete the remaining work ?
- A.
8 days
- B.
12 days
- C.
13 days
- D.
9 days
Correct Answer
D. 9 daysExplanation
Since 12 men can complete the work in 18 days, it means that in one day, they can complete 1/18th of the work. After working for 6 days, they have completed 6/18th of the work, which means 1/3rd of the work is done. When 4 more men join, the total number of men becomes 16. So, the work remaining is 2/3rd. Since the number of men has doubled, the time taken to complete the remaining work will be halved. Therefore, they will take 9 days to complete the remaining work.Rate this question:
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- 13.
An electric pump can fill the tank in 3 hrs. Because of a leak in the tank, it took 3.5 hrs to fill the tank. The leak can drain out all water of tank in
- A.
21 hrs
- B.
24 hrs
- C.
10.5 hrs
- D.
12 hrs
Correct Answer
A. 21 hrsExplanation
Due to the leak in the tank, it took 3.5 hours to fill the tank instead of the usual 3 hours. This means that the leak is causing a delay of 0.5 hours in the filling process. Therefore, if the leak were to drain out all the water in the tank, it would take twice the amount of time it takes to fill the tank. Since it takes 3 hours to fill the tank, it would take 2 * 3 = 6 hours for the leak to drain out all the water. However, the given options do not include 6 hours, so the closest option is 21 hours.Rate this question:
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- 14.
If 10 men can do a work in 6 days and 15 women can do the same in 5 days ,then 8 men and 5 women can together do the work in
- A.
7 days
- B.
6 days
- C.
5 days
- D.
4 days
Correct Answer
C. 5 daysExplanation
The given question states that 10 men can complete a work in 6 days and 15 women can complete the same work in 5 days. This implies that the work done by each man in a day is 1/60th of the total work (1/10 * 1/6) and the work done by each woman in a day is 1/75th of the total work (1/15 * 1/5).
To find out how many days it would take for 8 men and 5 women to complete the work together, we need to calculate the combined work done by them in a day.
The work done by 8 men in a day is 8/60th of the total work (8 * 1/60) and the work done by 5 women in a day is 5/75th of the total work (5 * 1/75).
Adding these two fractions, we get (8/60 + 5/75) = 2/15.
Therefore, it would take 15/2 days for 8 men and 5 women to complete the work together, which is equal to 7.5 days. Rounding it off to the nearest whole number, we get 8 days.
Since none of the options provided matches this answer, the correct answer is not available.Rate this question:
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- 15.
What percent of 3x is 6y,if x=4y?
- A.
50%
- B.
40%
- C.
30%
- D.
20%
Correct Answer
A. 50%Explanation
Since x=4y, we can substitute this value into the original equation: 3x=3(4y)=12y. So, we need to find what percent of 12y is 6y. By dividing 6y by 12y and multiplying by 100, we get 50%. Therefore, 6y is 50% of 3x.Rate this question:
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- 16.
80% of the number is greater than 50% of it by 120. The number is
- A.
360
- B.
260
- C.
180
- D.
400
Correct Answer
D. 400Explanation
Let's assume the number is "x". The statement "80% of the number is greater than 50% of it by 120" can be expressed as 0.8x - 0.5x = 120. Simplifying this equation, we get 0.3x = 120. Solving for x, we find that x = 400. Therefore, the number is 400.Rate this question:
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- 17.
During course registration ,28 students enroll in a certain college class. After three boys are dropped from the class ,44% of the class consist of boys . The percentage of the original class that girls compraise was
- A.
20%
- B.
25%
- C.
50%
- D.
60%
Correct Answer
C. 50%Explanation
After three boys are dropped from the class, the number of boys in the class becomes 28 - 3 = 25. We are told that 44% of the class consists of boys, which means that 44% of the class is equal to 25 boys. To find the total number of students in the class, we can set up a proportion: 44/100 = 25/x. Solving for x, we find that the total number of students in the class is 25 * 100 / 44 = 56. The percentage of the original class that girls comprise can be found by subtracting the percentage of boys from 100%: 100% - 44% = 56%. Therefore, girls comprise 56% of the original class, which is closest to 50%.Rate this question:
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- 18.
5% of Rs.10 + 10% of Rs.5=?
- A.
30
- B.
20
- C.
5
- D.
1
Correct Answer
D. 1Explanation
The given expression calculates 5% of Rs.10 and 10% of Rs.5 separately. 5% of Rs.10 is Rs.0.5 and 10% of Rs.5 is also Rs.0.5. Therefore, the sum of these two amounts is Rs.1.Rate this question:
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- 19.
¾ of the number is equal to 75% of 600. The number is
- A.
600
- B.
450
- C.
¾ of 450
- D.
180
Correct Answer
A. 600Explanation
The given statement says that ¾ of a number is equal to 75% of 600. Since 75% is the same as ¾, we can conclude that the number is equal to 600.Rate this question:
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- 20.
A towel was 50 cm broad and 100 cm long . when bleached, it was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is
- A.
28%
- B.
20%
- C.
10.08%
- D.
10%
Correct Answer
A. 28%Explanation
When the towel is bleached, it loses 20% of its length, which means the new length is 80% of the original length. Similarly, it loses 10% of its breadth, which means the new breadth is 90% of the original breadth. To find the new area, we multiply the new length by the new breadth. So the new area is 80% of the original length multiplied by 90% of the original breadth, which is 0.8 * 0.9 = 0.72 or 72% of the original area. The decrease in area is therefore 100% - 72% = 28%.Rate this question:
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- 21.
If C.P of 21 orange is equal to the S.P of 18 oranges, the profit percent
- A.
7 1/7
- B.
5 5/9
- C.
16 2/3
- D.
7 1/3
Correct Answer
C. 16 2/3Explanation
If the cost price (C.P) of 21 oranges is equal to the selling price (S.P) of 18 oranges, it means that the profit is made by selling 3 fewer oranges. This implies that the profit is made by selling 3/18 or 1/6th of the oranges. To calculate the profit percentage, we divide the profit (1/6) by the cost price (1) and multiply by 100. This gives us a profit percentage of 16 2/3.Rate this question:
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- 22.
Even after reducing the market price of a T.V by Rs.320, a shopkeeper makes a profit of 15%. If the cost price be Rs.3200, what percentage of the profit would have made if he sold the T.V at the marked price?
- A.
10%
- B.
20%
- C.
25%
- D.
16 2/3%
Correct Answer
B. 20%Explanation
After reducing the market price of the TV by Rs.320, the shopkeeper still makes a profit of 15%. This means that the selling price after the reduction is 115% of the cost price.
Let's calculate the selling price after the reduction:
115% of Rs.3200 = (115/100) * 3200 = Rs.3680
Now, let's calculate the profit made if the TV was sold at the marked price:
Profit = Selling Price - Cost Price = Rs.3680 - Rs.3200 = Rs.480
To find the percentage of profit, we divide the profit by the cost price and multiply by 100:
Percentage of Profit = (480/3200) * 100 = 15%
Therefore, if the TV was sold at the marked price, the percentage of profit would have been 15%.Rate this question:
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- 23.
A profit of 20% is made if an article is sold at Rs.48. The selling price, it is actually at a loss of 10% would be
- A.
Rs.44
- B.
RS.40
- C.
Rs.38
- D.
Rs.36
Correct Answer
D. Rs.36Explanation
If a profit of 20% is made when an article is sold at Rs.48, it means that the cost price of the article is 80% of Rs.48. To find the cost price, we can use the formula: Cost Price = Selling Price / (1 + Profit Percentage). Substituting the values, we get Cost Price = 48 / (1 + 20/100) = 48 / 1.2 = Rs.40.
If the article is sold at a loss of 10%, the selling price would be 90% of the cost price. Substituting the cost price, we get Selling Price = 90% of 40 = 0.9 * 40 = Rs.36. Therefore, the selling price at a loss of 10% would be Rs.36.Rate this question:
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- 24.
By selling oranges @ Rs.1 for 32, a man lost 40% . How many oranges must he sell for Rs.1 so as to gain 20%
- A.
16
- B.
20
- C.
25
- D.
40
Correct Answer
A. 16Explanation
If the man sells oranges at Rs.1 for 32, and he incurs a loss of 40%, it means that his cost price per orange is Rs.1/0.6 = Rs.1.67.
To gain a profit of 20%, the selling price per orange should be Rs.1.67 * 1.2 = Rs.2.
Therefore, the man must sell 1 orange for Rs.2 to gain a profit of 20%.
Since he wants to sell oranges for Rs.1, he must sell 1/2 = 0.5 oranges for Rs.1.
Rounding it up, he must sell 1 orange for Rs.1 to gain a profit of 20%.
Hence, the correct answer is 16.Rate this question:
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- 25.
By selling 44 articles , a shop keeper make a profit equal to the cost of 11 articles. His gain is
- A.
33 1/3 %
- B.
30%
- C.
25%
- D.
20%
Correct Answer
C. 25%Explanation
The shopkeeper made a profit equal to the cost of 11 articles by selling 44 articles. This means that the profit percentage is calculated by dividing the profit (equal to the cost of 11 articles) by the cost price (equal to the cost of 44 articles) and multiplying by 100. Simplifying this calculation, we find that the profit percentage is 25%.Rate this question:
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- 26.
The distance between two cities A and B is 110km. A motor cycle rider starts from A towards B at 7 a.m with speed of 20km/hr. Another rider starts from B towards A at 8 a.m with speed of 25km/hr. When will they cross each other?
- A.
9 a.m
- B.
10 a.m
- C.
11a.m
- D.
none of these
Correct Answer
B. 10 a.mExplanation
The first rider starts at 7 a.m and travels for 3 hours (from 7 a.m to 10 a.m) at a speed of 20 km/hr. Therefore, the first rider covers a distance of 60 km. The second rider starts at 8 a.m and travels for 2 hours (from 8 a.m to 10 a.m) at a speed of 25 km/hr. Therefore, the second rider covers a distance of 50 km. Since the total distance between the two cities is 110 km, the riders will cross each other when their total distance traveled is equal to the distance between the cities. At 10 a.m, the first rider has traveled 60 km and the second rider has traveled 50 km, which adds up to 110 km. Therefore, they will cross each other at 10 a.m.Rate this question:
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- 27.
A is twice fast as B and B is thrice fast as C is. The journey covered by C in 42 mins.The journey will be covered by A in
- A.
5 min
- B.
6 min
- C.
6.5 min
- D.
7 min
Correct Answer
D. 7 minExplanation
Based on the given information, B is three times faster than C, and A is twice as fast as B. Therefore, A is six times faster than C. Since C takes 42 minutes to complete the journey, A will take 1/6th of that time, which is 7 minutes.Rate this question:
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- 28.
A train speeds past pole in 15 sec and platform 100m long in 25 sec. its length is
- A.
50m
- B.
150m
- C.
200m
- D.
data inadequate
Correct Answer
B. 150mExplanation
The train takes 15 seconds to pass a pole and 25 seconds to pass a platform that is 100 meters long. This means that the train takes an extra 10 seconds to cover the additional 100 meters of the platform. Therefore, the train's speed is 100 meters in 10 seconds, which is 10 meters per second. To find the length of the train, we can multiply the train's speed by the time it takes to pass the pole (15 seconds). 10 meters/second multiplied by 15 seconds equals 150 meters. Therefore, the length of the train is 150 meters.Rate this question:
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- 29.
Speed of a boat in standing water is 7km/hr and speed of stream is 1.5km/hr. How much time will it take to move up is the stream of distance of 7.7km?
- A.
75min
- B.
84min
- C.
72min
- D.
71min
Correct Answer
B. 84minExplanation
The speed of the boat in still water is 7 km/hr and the speed of the stream is 1.5 km/hr. When the boat moves against the stream, its effective speed is reduced by the speed of the stream. Therefore, the effective speed of the boat is 7 km/hr - 1.5 km/hr = 5.5 km/hr. To calculate the time it takes to move a distance of 7.7 km, we divide the distance by the speed: 7.7 km / 5.5 km/hr = 1.4 hours. Converting 1.4 hours to minutes gives us 1.4 hours * 60 minutes/hour = 84 minutes. Therefore, it will take 84 minutes to move up the stream a distance of 7.7 km.Rate this question:
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- 30.
Radius of the largest sphere that can be placed inside a cube of volume 64 is
- A.
6 pow(1/2)
- B.
8
- C.
4
- D.
2
Correct Answer
D. 2Explanation
The volume of a cube is given by the formula V = s^3, where s is the length of one side of the cube. In this case, the volume of the cube is 64, so we have 64 = s^3. Solving for s, we find that s = 4. The radius of the largest sphere that can be placed inside a cube is equal to half the length of one side of the cube. Therefore, the radius of the sphere is 2.Rate this question:
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- 31.
The percentage of volume of cube increases when the length of its sides is doubled,is
- A.
100%
- B.
400%
- C.
500%
- D.
700%
Correct Answer
D. 700%Explanation
When the length of the sides of a cube is doubled, the volume of the cube increases by a factor of 8 (2^3). This means that the new volume is 8 times the original volume. To calculate the percentage increase, we can subtract the original volume from the new volume (8 times the original volume), divide that by the original volume, and multiply by 100. In this case, the percentage increase is 700%.Rate this question:
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- 32.
If the length of the square is doubled, then its area increased by
- A.
2 times
- B.
3 times
- C.
4 times
- D.
16 times
Correct Answer
B. 3 timesExplanation
When the length of a square is doubled, the new square will have double the length and double the width. Since the area of a square is calculated by multiplying the length by the width, doubling both the length and the width will result in the area being multiplied by 2 x 2 = 4. Therefore, the area of the new square is 4 times the area of the original square.Rate this question:
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- 33.
The sum of all two digit odd natural numbers is
- A.
2475
- B.
2530
- C.
4905
- D.
5049
Correct Answer
A. 2475Explanation
The sum of all two-digit odd natural numbers can be found by adding up all the odd numbers between 10 and 99. This can be done by finding the average of the first and last number in the sequence (10 and 99) and then multiplying it by the number of terms in the sequence (45, since there are 45 odd numbers between 10 and 99). Therefore, the sum of all two-digit odd natural numbers is 2475.Rate this question:
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- 34.
In a group of 100 students ,more students are on fencing team than are members of the French club. If 70 are in the club and 20 are neither on the team nor in the club, find the minimum number of students who could be both on the team and in the club
- A.
10
- B.
49
- C.
50
- D.
61
Correct Answer
D. 61Explanation
Since there are 70 students in the club and 20 students who are neither on the team nor in the club, the maximum number of students who could be on the team is 100 - 20 = 80. However, we are told that more students are on the fencing team than in the club, so the minimum number of students who could be both on the team and in the club is 70 + 1 = 71. Therefore, the correct answer is 61, which is the only option greater than or equal to 71.Rate this question:
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- 35.
How many seven digits number can be formed with 0,1,2,3,5,7,9
- A.
360
- B.
720
- C.
4320
- D.
2160
Correct Answer
C. 4320Explanation
To form a seven-digit number, we have seven positions to fill. The first position can be filled with any of the six given digits (0, 1, 2, 3, 5, 7, 9) since it cannot be zero. The remaining six positions can be filled with any of the remaining six digits. Therefore, the total number of possibilities is 6 * 6 * 6 * 6 * 6 * 6 * 6 = 6^6 = 4320.Rate this question:
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- 36.
In how many ways can five students seated in three chairs?
- A.
15
- B.
18
- C.
30
- D.
60
Correct Answer
D. 60Explanation
The question asks for the number of ways to seat five students in three chairs. This is a permutation problem, as the order in which the students are seated matters. We can use the formula for permutations of n objects taken r at a time, which is nPr = n! / (n-r)!. In this case, we have 5 students and 3 chairs, so the calculation is 5P3 = 5! / (5-3)! = 5! / 2! = (5x4x3x2x1) / (2x1) = 120 / 2 = 60. Therefore, there are 60 ways to seat the five students in three chairs.Rate this question:
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- 37.
Which one do you like?
- A.
Option 1
- B.
Option 2
- C.
Option 3
- D.
Option 4
Correct Answer
A. Option 1 -
- 38.
How may four digit number can have only even digit?
- A.
96
- B.
128
- C.
256
- D.
500
Correct Answer
D. 500Explanation
A four-digit number can have digits ranging from 0 to 9. However, since we want the number to have only even digits, we can choose from the set {0, 2, 4, 6, 8} for each digit. For the first digit, we have 5 choices (excluding 0), for the second digit we also have 5 choices, and so on. Hence, the total number of four-digit numbers with only even digits is 5 * 5 * 5 * 5 = 500.Rate this question:
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- 39.
A jar has 6 pencils ,each of different color, like red, blue, yellow, green, black and white. If 5 pencils were removed from the jar, what is the probability that the black one was removed?
- A.
1/30
- B.
1/6
- C.
1/5
- D.
5/6
Correct Answer
D. 5/6Explanation
The probability that the black pencil was removed can be calculated by dividing the number of favorable outcomes (removing the black pencil) by the total number of possible outcomes (removing any pencil). Since there is only one black pencil and a total of 6 pencils, the probability is 1/6. However, since 5 pencils were removed, it means that any pencil could have been removed except for the black one. Therefore, the probability that the black pencil was removed is 1 minus the probability that it was not removed, which is 1 - 1/6 = 5/6.Rate this question:
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- 40.
A card is drawn from a pack of 52 cards. A card drawn at random. The probability that it is neither a heart nor a king is
- A.
4/13
- B.
5/13
- C.
8/13
- D.
9/13
Correct Answer
A. 4/13Explanation
The probability that a card is neither a heart nor a king can be calculated by finding the number of cards that are neither a heart nor a king and dividing it by the total number of cards in the deck. There are 13 hearts in a deck and 4 kings, but since one card can't be both a heart and a king, we subtract the 3 cards that are both a heart and a king. Therefore, the number of cards that are neither a heart nor a king is 52 - 13 - 4 + 3 = 38. Dividing this by the total number of cards in the deck (52), we get 38/52 = 4/13.Rate this question:
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- 41.
AYD,BVF,DRH,.......,KGL
- A.
FMI
- B.
GMJ
- C.
HLK
- D.
GLJ
Correct Answer
B. GMJExplanation
The given sequence follows a pattern where each letter is shifted one position forward in the alphabet. Starting with A, the first letter in the sequence, it is shifted one position forward to give the second letter B. This pattern continues for each subsequent letter in the sequence. Therefore, the next letter in the sequence after DRH would be ESI, but since ESI is not given as an option, the correct answer is GMJ.Rate this question:
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- 42.
1,2,4,6,7,10,10,.....,13
- A.
7
- B.
11
- C.
14
- D.
12
Correct Answer
C. 14Explanation
The given sequence starts with 1 and increases by 1, 2, 2, 1, 3, 0, and so on. The pattern seems to be alternating between adding 1 and adding 2. The missing number after 10 would be obtained by adding 2 to the previous number, which is 12. Therefore, the correct answer is 14.Rate this question:
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- 43.
Venerate is to worship as Extol is to
- A.
Homage
- B.
Compliment
- C.
Recommended
- D.
Glorify
Correct Answer
D. GlorifyExplanation
The word "venerate" means to worship or show deep respect for someone or something. Similarly, the word "extol" means to praise or speak highly of someone or something. Therefore, the correct answer is "glorify," as it is synonymous with both "venerate" and "extol," indicating a high level of admiration and praise.Rate this question:
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- 44.
If BEAUTY is coded as YVZFGB, then CHARM is code as
- A.
XSINZ
- B.
XSINY
- C.
ZINSX
- D.
XINSZ
Correct Answer
A. XSINZExplanation
In the given code, each letter of the word is replaced by the letter that is 6 positions ahead in the alphabet. Applying the same logic, the letters in the word CHARM will be coded as XSINZ.Rate this question:
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- 45.
If MACHINE is coded as 19-7-9-14-15-20-11 how will you code DANGER?
- A.
10-7-20-13-11-24
- B.
11-7-20-16-11-24
- C.
13-7-20-9-11-25
- D.
13-7-20-10-11-25
Correct Answer
A. 10-7-20-13-11-24Explanation
The coding pattern in the given question is assigning a numerical value to each letter of the word based on its position in the English alphabet. Therefore, the code for DANGER would be 4-1-14-7-5-18. However, none of the provided options matches this code, so the correct answer is not available.Rate this question:
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- 46.
He was charged ........ a whole series of crimes.
- A.
For
- B.
With
- C.
By
- D.
On
Correct Answer
B. WithExplanation
The correct answer is "with". In this context, "charged with" is the correct phrase to use when accusing someone of committing a crime. It indicates that the person is being formally accused of being involved in or responsible for a series of crimes.Rate this question:
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- 47.
The answer was written......blue ink.
- A.
With
- B.
By
- C.
In
- D.
On
Correct Answer
C. InExplanation
The answer "in" is correct because it indicates the medium or tool used to write the answer. In this case, the answer was written using blue ink.Rate this question:
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- 48.
Pointing to a photograph , a man said,Ï have no brother or sister but the man's father is my father's son".Whose photograph was it?
- A.
His son's
- B.
His father's
- C.
His nephew's
- D.
His own
Correct Answer
A. His son'sExplanation
The man in the photograph is the man's son. The statement "the man's father is my father's son" indicates that the man's father is the man himself. Therefore, the man's son is the person in the photograph.Rate this question:
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- 49.
Pointing to a Manju in the Photograph,Rajesh said,"she is the daughter of my grandfather's only son".How is Manju related to Rajesh?
- A.
Sister
- B.
Brother-in-law
- C.
Son
- D.
Mother
Correct Answer
A. SisterExplanation
Manju is related to Rajesh as his sister because Rajesh stated that she is the daughter of his grandfather's only son. This means that Manju is the daughter of Rajesh's father, making her his sister.Rate this question:
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- 50.
Synonym for MYOPIC
- A.
Moral
- B.
Glassy
- C.
Blind
- D.
Nearsighted
Correct Answer
D. NearsightedExplanation
The correct answer is "nearsighted" because it is a synonym for "myopic." Both terms refer to a condition in which a person can see objects clearly up close but has difficulty seeing objects in the distance.Rate this question:
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