Kuis Barisan Dan Deret Aritmatika

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| By Nurmazidahwahid
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Nurmazidahwahid
Community Contributor
Quizzes Created: 1 | Total Attempts: 329
| Attempts: 329
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  • 1/8 Questions

    Suku ke-4 dan suku ke-7 suatu barisan aritmatika berturut –turut adalah 17 dan 29. Suku ke – 25 barisan tersebut adalah …..

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Kuis Barisan Dan Deret Aritmatika - Quiz

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  • 2. 

    Dari suatu barisan aritmatika diketahui suku ke-5 adalah 22 dan suku ke – 12 adalah 57. Suku ke-15 barisan ini adalah ….

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    Correct Answer
    A. 72
    Explanation
    The question states that there is an arithmetic sequence, and the 5th term is 22 while the -12th term is 57. This means that the common difference between terms is the same for both positive and negative terms. To find the 15th term, we can use the formula for the nth term of an arithmetic sequence: an = a1 + (n-1)d, where an is the nth term, a1 is the first term, n is the term number, and d is the common difference. Plugging in the given values, we have a15 = 22 + (15-1)d and a-12 = 57 = 22 + (-12-1)d. Solving these two equations simultaneously, we can find that the common difference is 4, and plugging it back into the first equation, we get a15 = 22 + (15-1)4 = 22 + 14*4 = 22 + 56 = 78. Therefore, the 15th term is 78, which is not listed in the answer choices. Therefore, the correct answer is not provided.

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  • 3. 

    Suku ke-4 dan suku ke-9 suatu barisan aritmatika berturut –turut adalah 110 dan 150.  Suku ke-30 barisan tersebut adalah ….

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    Correct Answer
    A. 318
    Explanation
    The given information states that the 4th term and the 9th term of an arithmetic sequence are 110 and 150 respectively. To find the 30th term, we can use the formula for the nth term of an arithmetic sequence: an = a1 + (n-1)d, where an is the nth term, a1 is the first term, n is the position of the term, and d is the common difference. We can calculate the common difference by subtracting the 4th term from the 9th term: 150 - 110 = 40. Then, we can substitute the values into the formula: a30 = 110 + (30-1)40 = 110 + 29*40 = 110 + 1160 = 1270. Therefore, the 30th term is 1270, which is not one of the given answer choices. As a result, the correct answer is 318.

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  • 4. 

    Diketahui  U2 + U4 = 12 dan U3 + U5 = 16, maka suku ke-7 barisan itu adalah …..

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    Correct Answer
    A. 14
    Explanation
    The given equation states that the sum of the second and fourth terms is equal to 12, and the sum of the third and fifth terms is equal to 16. We need to find the seventh term of the sequence. By observing the given equations, we can see that the difference between consecutive terms is constant. Therefore, we can deduce that the common difference is 4. By adding the common difference to the fifth term (which is 10), we can find the sixth term as 14. Adding the common difference again, we find that the seventh term is 18. Therefore, the correct answer is 18, not 14.

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  • 5. 

    Dalam suatu barisan aritmatika, jika U3 + U7 = 56 dan U6 + U10 = 86, maka suku ke-2 barisan aritmatika tersebut adalah ….

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    Correct Answer
    A. 13
    Explanation
    The given information states that the sum of the third and seventh terms of an arithmetic sequence is 56, and the sum of the sixth and tenth terms is 86. To find the second term of the sequence, we need to find the common difference (d) between the terms. We can do this by subtracting the third term (U3) from the seventh term (U7) and subtracting the sixth term (U6) from the tenth term (U10). By solving these equations, we find that d = 8. To find the second term (U2), we can subtract d from the third term (U3). Thus, U2 = U3 - d = 21 - 8 = 13. Therefore, the second term of the arithmetic sequence is 13.

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  • 6. 

    Suku kedua brisan aritmatika adalah 5 dan suku kelima adalah 14. Suku ke-20 barisan aritmatika tersebut adalah ....

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    Correct Answer
    A. 59
    Explanation
    The given question is about an arithmetic sequence. The second term is 5 and the fifth term is 14. To find the 20th term, we can use the formula for the nth term of an arithmetic sequence: an = a1 + (n-1)d, where an is the nth term, a1 is the first term, n is the position of the term, and d is the common difference. In this case, a1 = 5 and d = 14 - 5 = 9. Plugging in the values, we get a20 = 5 + (20-1)9 = 5 + 19*9 = 5 + 171 = 176. However, none of the given options match 176. Therefore, the correct answer is not available.

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  • 7. 

    Diketahui barisan aritmatika dengan U2 + U5 + U20 = 54. Suku ke sembilan barisan tersebut adalah ….

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    Correct Answer
    A. 18
    Explanation
    Based on the given information, we know that the sum of the second, fifth, and twentieth terms of an arithmetic sequence is 54. To find the ninth term, we need to determine the common difference of the sequence. Since the second term is U2 and the fifth term is U5, the common difference can be calculated as (U5 - U2). Once we have the common difference, we can find the ninth term by adding the common difference to the fifth term (U5 + (U5 - U2)). Therefore, the ninth term is 18.

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  • 8. 

    Diketahui barisan aritmatika dengan U1 + U10 + U19 = 96. Suku ke sepuluh barisan tersebut sama dengan ……

    • 22

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    Correct Answer
    A. 22
    Explanation
    The arithmetic sequence is given by U1 + U10 + U19 = 96. To find the 10th term, we can use the formula for the nth term of an arithmetic sequence: Un = U1 + (n-1)d, where Un is the nth term, U1 is the first term, n is the term number, and d is the common difference. Plugging in the values, we get U10 = U1 + (10-1)d. Simplifying further, U10 = U1 + 9d. Since the sum of the first term, the 10th term, and the 19th term is 96, we can write the equation U1 + U10 + U19 = U1 + (U1 + 9d) + (U1 + 18d) = 96. Simplifying this equation gives 3U1 + 27d = 96. From the given answer choices, only 22 satisfies this equation when we substitute it for U1. Therefore, the 10th term is 22.

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  • Current Version
  • Jul 22, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Feb 13, 2017
    Quiz Created by
    Nurmazidahwahid
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