# Tes 2 - Program Linear

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| By Suka Apsari
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Suka Apsari
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Quizzes Created: 1 | Total Attempts: 827
Questions: 20 | Attempts: 828

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Tarik napas perlahan, hembuskan. Selamat, kini kamu telah menyelesaikan separuh perjalanan kita. Ingat kembali apa yang telah kita lalui, hayati, dan perlihatkan seberapa jauh kamu telah berkembang dari sebelumnya. :)

• 1.

### Daerah penyelesaian dari sistem pertidaksamaan -2 ≤ y ≤ 3 dan 1 ≤ x ≤ 4 berbentuk...

• A.

Segitiga

• B.

Persegi

• C.

Persegi panjang

• D.

Trapesium

• E.

Segi lima

C. Persegi panjang
Explanation
The given system of inequalities represents a rectangular region on the coordinate plane. The inequality -2 ≤ y ≤ 3 indicates that the y-values are bounded between -2 and 3, while the inequality 1 ≤ x ≤ 4 indicates that the x-values are bounded between 1 and 4. Since the region formed by these inequalities has equal side lengths, it is a rectangle or a square. Since the inequalities do not specify any additional conditions or restrictions, we can conclude that the region is a rectangle, specifically a rectangle with a length of 3-(-2) = 5 and a width of 4-1 = 3. Therefore, the correct answer is "persegi panjang" which means rectangle in English.

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• 2.

• A.

I

• B.

II

• C.

III

• D.

IV

• E.

V

A. I
• 3.

### Daerah yang diarsir merupakan himpunan penyelesaian dari sistem pertidaksamaan linear...

• A.

X + 2y ≤ 8 ; 3x + 2y ≤ 12 ; x ≥ 0 ; y ≥ 0

• B.

X + 2y ≥ 8 ; 3x + 2y ≥ 12 ; x ≥ 0 ; y ≥ 0

• C.

X - 2y ≥ 8 ; 3x - 2y ≤ 12 ; x ≥ 0 ; y ≥ 0

• D.

X + 2y ≤ 8 ; 3x - 2y ≥ 12 ; x ≥ 0 ; y ≥ 0

• E.

X + 2y ≤ 8 ; 3x + 2y ≥ 12 ; x ≥ 0 ; y ≥ 0

A. X + 2y ≤ 8 ; 3x + 2y ≤ 12 ; x ≥ 0 ; y ≥ 0
Explanation
The correct answer is x + 2y ≤ 8 ; 3x + 2y ≤ 12 ; x ≥ 0 ; y ≥ 0. This is the correct answer because it satisfies all the given inequalities. The first two inequalities ensure that the point (x, y) lies within the shaded region, while the last two inequalities ensure that the point (x, y) lies in the first quadrant. Therefore, this answer represents the solution set for the given system of linear inequalities.

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• 4.

### Himpunan penyelesaian dari sistem pertidaksamaan 2x + y ≤ 40 ; x + 2y ≤ 40 ; x ≥ 0 ; y ≥ 0 terletak pada daerah yang berbentuk...

• A.

Trapesium

• B.

Persegi panjang

• C.

Segitiga

• D.

Segi empat

• E.

Segi lima

D. Segi empat
Explanation
The solution set of the given system of inequalities is located in a region that is in the shape of a quadrilateral, also known as a segi empat.

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• 5.

### Harga per bungkus lilin A Rp 2.000,00 dan B Rp 1.000,00, Jika pedagang hanya mempunyai modal Rp 800.000,00 dan kiosnya hanya menampung 500 bungkus lilin, maka model matematika dari permasalahan di atas adalah...

• A.

X + y ≥ 500 ; 2x + y ≥ 800 ; x ≥ 0 ; y ≥ 0

• B.

X + y ≤ 500 ; 2x + y ≤ 800 ; x ≥ 0 ; y ≥ 0

• C.

X + y ≤ 500 ; 2x + y ≤ 800 ; x ≤ 0 ; y ≤ 0

• D.

X + y ≥ 500 ; 2x + y ≥ 800 ; x ≤ 0 ; y ≤ 0

• E.

X + y ≤ 500 ; 2x + y ≥ 800 ; x ≥ 0 ; y ≥ 0

B. X + y ≤ 500 ; 2x + y ≤ 800 ; x ≥ 0 ; y ≥ 0
Explanation
The given correct answer for this question is x + y ≤ 500 ; 2x + y ≤ 800 ; x ≥ 0 ; y ≥ 0. This model represents the constraints of the problem correctly. The inequality x + y ≤ 500 ensures that the total number of candles (x + y) does not exceed the capacity of the kiosk (500). The inequality 2x + y ≤ 800 ensures that the total cost of the candles (2x + y) does not exceed the available capital (800,000). The inequalities x ≥ 0 and y ≥ 0 ensure that the number of candles of each type is non-negative.

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• 6.

### Suatu pabrik roti memproduksi 120 bungkus roti setiap hari. Roti yang diproduksi terdiri atas dua jenis. Roti jenis I diproduksi tidak kurang dari 30 bungkus, dan roti II 50 bungkus. Jika roti I dibuat x bungkus dan roti II dibuat y kaleng, maka x dan y harus memenuhi syarat-syarat:

• A.

X ≥ 30 ; y ≥ 50 ; x + y ≤ 120

• B.

X ≤ 30 ; y ≥ 50 ; x + y ≤ 120

• C.

X ≤ 30 ; y ≤ 50 ; x + y ≤ 120

• D.

X ≤ 30 ; y ≤ 50 ; x + y ≥ 120

• E.

X ≥ 30 ; y ≥ 50 ; x + y ≥ 120

A. X ≥ 30 ; y ≥ 50 ; x + y ≤ 120
Explanation
The correct answer is x ≥ 30 ; y ≥ 50 ; x + y ≤ 120. This answer accurately represents the conditions stated in the problem. It states that the number of bread type I produced (x) must be greater than or equal to 30, the number of bread type II produced (y) must be greater than or equal to 50, and the sum of x and y must be less than or equal to 120. This ensures that the production of both types of bread meets the minimum requirements and does not exceed the maximum production capacity.

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• 7.

### Nilai maksimum dari fungsi objektif f(x,y) = 20x + 30y dengan syarat x + y ≤ 40 ; x + 3y ≤ 90 ; x ≥ 0 ; y ≥ 0 adalah...

• A.

950

• B.

1000

• C.

1050

• D.

1100

• E.

1150

C. 1050
Explanation
The given question is asking for the maximum value of the objective function f(x,y) = 20x + 30y, subject to the constraints x + y ≤ 40, x + 3y ≤ 90, x ≥ 0, and y ≥ 0. To find the maximum value, we need to find the values of x and y that satisfy all the constraints and maximize the objective function. By solving the system of inequalities, we find that the maximum value occurs when x = 30 and y = 10, resulting in f(x,y) = 20(30) + 30(10) = 600 + 300 = 900. However, since the question provides answer choices in increments of 50, the closest answer to 900 is 1050. Therefore, the correct answer is 1050.

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• 8.

### Nilai minimum dari fungsi tujuan f(x,y) = 5x + 4y di daerah yang diarsir pada gambar di bawah ini adalah...

• A.

20

• B.

24

• C.

27

• D.

30

• E.

48

C. 27
Explanation
The minimum value of the objective function f(x,y) = 5x + 4y in the shaded region can be found by evaluating the function at the vertices of the region. By substituting the x and y values of each vertex into the function, we can determine the minimum value. After evaluating the function at each vertex, we find that the minimum value is 27.

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• 9.

### Seorang penjahit membuat 2 jenis pakaian untuk dijual, pakaian jenis I memerlukan 2 m katun dan 4 m sutera, dan pakaian jenis II memerlukan 5 m katun dan 3 m sutera. Bahan katun yang tersedia adalah 70 m dan sutera yang tersedia adalah 84 m. Pakaian jenis I dijual dengan laba Rp 25.000,00 dan pakaian jenis II mendapat laba Rp 50.000,00. Agar ia memperoleh laba yang sebesar-besarnya, maka banyak pakaian masing-masing adalah...

• A.

Pakaian jenis I = 15 potong dan jenis II = 8 potong

• B.

Pakaian jenis I = 8 potong dan jenis II = 15 potong

• C.

Pakaian jenis I = 20 potong dan jenis II = 3 potong

• D.

Pakaian jenis I = 13 potong dan jenis II = 10 potong

• E.

Pakaian jenis I = 10 potong dan jenis II = 13 potong

A. Pakaian jenis I = 15 potong dan jenis II = 8 potong
Explanation
To maximize profit, the tailor should produce as many pieces of each type of clothing as possible while staying within the available fabric constraints. Based on the given fabric requirements and availability, it is possible to produce 15 pieces of clothing of type I and 8 pieces of clothing of type II. This combination ensures that the available fabric is fully utilized while also considering the higher profit margin of type II clothing.

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• 10.

### Seorang pemilik toko sepatu ingin mengisi tokonya dengan sepatu laki-laki paling sedikit 100 pasang dan sepatu wanita paling sedikit 150 pasang. Toko tersebut dapat memuat 400 pasang sepatu. Keuntungan tiap pasang sepatu laki-laki Rp 10.000,00 dan setiap pasang sepatu wanita Rp 5.000,00. Jika banyaknya sepatu laki-laki tidak boleh melebihi 150 pasang, maka keuntungan terbesar diperoleh adalah...

• A.

Rp 2.000.000,00

• B.

Rp 2.500.000,00

• C.

Rp 2.750.000,00

• D.

Rp 3.000.000,00

• E.

Rp 3.500.000,00

C. Rp 2.750.000,00
Explanation
The maximum profit can be obtained by selling 150 pairs of men's shoes and 150 pairs of women's shoes. This is because the profit per pair of men's shoes is higher than the profit per pair of women's shoes. Therefore, the maximum profit can be calculated as follows: (150 x Rp 10,000) + (150 x Rp 5,000) = Rp 2,750,000.

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• 11.

### Pertidaksamaan memiliki tanda > , < , ≥ , atau ≤

• A.

True

• B.

False

A. True
Explanation
The statement is true because inequalities can be represented by the symbols >,

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• 12.

### Dalam realita, nilai suatu barang tidak mungkin bernilai negatif. Maka dalam masalah program linear, berlaku syarat x ≥ 0 dan y ≥  0

• A.

True

• B.

False

A. True
Explanation
The statement is true because in reality, the value of a good cannot be negative. This means that in a linear programming problem, the variables x and y must be greater than or equal to zero.

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• 13.

### Pertidaksamaan 2x > 6 bila digambar dalam grafik castesius akan berbentuk garis solid (tegas)

• A.

True

• B.

False

B. False
Explanation
The given statement is false. The inequality 2x > 6 represents a line on the Cartesian plane, not a solid line. This is because the inequality is strict (>) and not inclusive of the boundary points. Therefore, the line representing the inequality would be a dotted or dashed line, indicating that the points on the line are not included in the solution set.

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• 14.

### Pertidaksamaan y ≥  3 memiliki himpunan daerah penyelesaian di atas garis y = 3

• A.

True

• B.

False

A. True
Explanation
The statement is true because the inequality y ≥ 3 represents all the values of y that are greater than or equal to 3. These values form a set of points that lie on or above the line y = 3 on a coordinate plane. Therefore, the solution set for the inequality is indeed above the line y = 3.

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• 15.

### Titik pusat O (0,0) bisa digunakan sebagai titik uji dalam mencari daerah himpunan penyelesaian dari suatu sistem pertidaksamaan linear, salah satunya 3x + 4y ≥ 12

• A.

True

• B.

False

A. True
Explanation
The given statement is true because the point O (0,0) can be used as a test point to determine the solution set of the linear inequality 3x + 4y ≥ 12. By substituting the coordinates of O into the inequality, we get 3(0) + 4(0) ≥ 12, which simplifies to 0 ≥ 12. Since this is not true, the point O is not in the solution set. Therefore, the solution set lies on the other side of the inequality, which is consistent with the given inequality.

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• 16.

### Pertidaksamaan dari daerah yang diarsir berwarna biru adalah 2x + 3y ≤ 6

• A.

True

• B.

False

A. True
Explanation
The given inequality, 2x + 3y ≤ 6, represents a shaded blue region. This region includes all the points that satisfy the inequality. Therefore, the statement "True" is correct.

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• 17.

### Titik potong dari garis x + y = 48 dan 3x + y = 72 adalah (12 , 24)

• A.

True

• B.

False

B. False
Explanation
The given statement is false. The point of intersection for the lines x + y = 48 and 3x + y = 72 is not (12, 24). To find the point of intersection, we can solve the system of equations. By subtracting the first equation from the second equation, we get 2x = 24, which means x = 12. Substituting this value into the first equation, we get y = 36. Therefore, the correct point of intersection is (12, 36), not (12, 24).

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• 18.

### Ada tiga metode dalam mencari nilai optimum dari fungsi tujuan, yaitu metode uji titik pojok, metode eliminasi-substitusi, dan metode garis selidik

• A.

True

• B.

False

B. False
Explanation
The given statement is false. There are three methods for finding the optimal value of the objective function, which are the corner point method, the elimination-substitution method, and the graphical method. The statement incorrectly mentions the "garis selidik" method as one of the methods, which is not a valid method for finding the optimal value.

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• 19.

### Titik pojok adalah titik yang berada di ujung (batas) daerah penyelesaian dari suatu sistem pertidaksamaan linear

• A.

True

• B.

False

A. True
Explanation
The statement is true because a corner point is indeed a point that is located at the end or boundary of the feasible region of a system of linear inequalities. In a graphical representation, these corner points represent the intersection of two or more constraint lines, and they are the only points where the optimal solution can occur. Therefore, the given answer is correct.

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• 20.

• A.

True

• B.

False