Sankalp Circuit Design Challenge
- 1.Which type of PLD should be used to program basic logic functions?
- A.
PLA
- B.
PAL
- C.
CPLD
- D.
SLD
- 2.Which circuit is used as active load for an amplifier?
- A.
Wildar Current source
- B.
Darlington pair
- C.
Current Mirror
- D.
All of the mentioned
- 3.An ideal op-amp is an ideal
- A.
Voltage controlled current source
- B.
Voltage controlled voltage source
- C.
Current controlled current source
- D.
Current controlled voltage source
- 4.
What is this circuit?- A.
A low-pass filter
- B.
A high-pass filter
- C.
A band-pass filter
- D.
A band-stop filter
- 5.
In this circuit, the race around...
- A.
does not occur
- B.
Occur when CLK = 0
- C.
occur when CLK = 1 and A = B = 1
- D.
Occur when CLK = 1 and A = B = 0
- 6.In the sum of products function f(X,Y,Z)=Σ(2,3,4,5), the prime implicants are:
- A.
X'Y, XY'
- B.
X'Y, XY'Z', XY'Z
- C.
X'YZ',X'YZ,XY'
- D.
X'YZ',X'YZ,XY'Z',XY'Z
- 7.How can a monostable multivibrator be modified into a linear ramp generator?
- A.
Connect a constant current source to trigger input
- B.
Connect a constant current source to trigger output
- C.
Replace resistor by constant current source
- D.
Replace capacitor by constant current source
- 8.A particular p-n junction for which the breakdown voltage is 60 V can dissipate 30 mW while maintaining its junction temperature at a value low enough to avoid permanent junction damage. What continuous reverse current flow appears likely to cause permanent failure
- A.
0.05 mA
- B.
0.5 mA
- C.
5 mA
- D.
0.5 A
- 9.2 inputs were given to a logic gate and the output was obtained. It was found that the purpose of the operation needed 3 inputs. changes in the circuit were made :the output so obtained and the 3rd input were taken as inputs to another similar logic gate to rectify the mistake.The gates that possibly could’ve been used in the circuit are:
- A.
Nor
- B.
And
- C.
Nand
- D.
Xor
- 10.How Do You Detect If Two 8-bit Signals Are Same?
- 11.Given Only Two Xor Gates One Must Function As Buffer And Another As Inverter?
- 12.
- 13.
- 14.
- 15.
- 16.
- 17.
- 18.
In the diagram,
- A.
Y=A'B'+C
- B.
Y=(A+B)C
- C.
Y=(A'+B')C
- D.
Y=AB+C
- 19.
- 20.
- 21.
- A.
Q1: revere active; Q2: saturation; Q3: saturation; Q4: cut-off
- B.
Q1: revere active; Q2: normal active; Q3: saturation; Q4: cut-off
- C.
Q1: normal active; Q2: cut-off; Q3: cut-off; Q4: saturation
- D.
Q1: saturation; Q2: saturation; Q3: saturation; Q4: normal active
- 22.
- 23.
[Blank][Blank]
- 24.
- 25.
The current in the circuit is:
- A.
3.25µA
- B.
62.5µA
- C.
125µA
- D.
250µA
![[Blank][Blank] - ProProfs](https://lh6.googleusercontent.com/pRzPtVHWX1N2sMRsAj4yUCVksXgYninWFEMxEJ5dIpqOid_ZBykQWfNpO4qtiJlZael47_ooiuZCVtF0JLtpQikIoRP7sgK5PpC2bQxxkot6Vgbb6usRAmVOsyDn_H7vtSmROuduf1fEiA7SgQ "[Blank][Blank]")
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