Kuat Arus Yang Mengalir Pada

1.

Dalam 2 menit mengalir muatan sebanyak 180 Coulomb pada suatu kawat penghantar. Besar kuat arus yang mengalir pada kawat adalah.......
- A.
  
  0,5 A
- B.
  
  0,75 A
- C.
  
  1,5 A
- D.
  
  2,25 A
Correct Answer
C. 1,5 A

Explanation
The question states that a charge of 180 Coulombs flows through a conductor in 2 minutes. To find the current, we can use the formula I = Q/t, where I is the current, Q is the charge, and t is the time. Plugging in the given values, we get I = 180/2 = 90 A. Therefore, the correct answer is 1.5 A.

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2.

Perhatikan gambar! Besarnya arus yang mengalir pada rangkaian dan beda potensial antara titik A dan B berturut-turut adalah.....
- A.
  
  1 A dan 11,5 volt
- B.
  
  1 A dan 12 volt
- C.
  
  2 A dan 6,5 volt
- D.
  
  2 A dan 12 volt
Correct Answer
A. 1 A dan 11,5 volt

Explanation
The correct answer is 1 A dan 11,5 volt. This can be determined by applying Ohm's Law, which states that the current (I) flowing through a conductor is directly proportional to the voltage (V) across the conductor, and inversely proportional to the resistance (R) of the conductor. In this case, the current is given as 1 A and the voltage is given as 11,5 volt, indicating that the resistance of the conductor must be 11,5 ohms. Therefore, the correct answer is 1 A dan 11,5 volt.

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3.

Perhatikan rangkaian listrik berikut! Jika R₁ = 1 Ω, R₂ = 2 Ω, R₃ = 3 Ω dan Nilai E adalah 9 volt maka besar kuat arus yang mengalir pada rangkaian adalah.....
- A.
  
  1 A
- B.
  
  1,5 A
- C.
  
  2 A
- D.
  
  3 A
Correct Answer
B. 1,5 A

Explanation
The total resistance in the circuit can be calculated by adding the individual resistances: R_total = R1 + R2 + R3 = 1 + 2 + 3 = 6 Ω. The current flowing through the circuit can be determined using Ohm's Law: I = E / R_total = 9 V / 6 Ω = 1.5 A. Therefore, the correct answer is 1.5 A.

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4.

Perhatikan rangkaian listrik berikut! Kelima hambatan memiliki nilai yang sama yaitu 3 Ω. Jika nilai kuat arus I adalah 1,2 A maka nilai I_A dan I_B berturut-turut adalah.....
- A.
  
  0,8 A dan 0,4 A
- B.
  
  0,4 A dan 0,8 A
- C.
  
  0,9 A dan 0,3 A
- D.
  
  0,3 A dan 0,9 A
Correct Answer
A. 0,8 A dan 0,4 A

Explanation
The correct answer is 0,8 A dan 0,4 A because the total resistance in the circuit is 15 Ω (3 Ω for each resistor) and the total current is 1,2 A. According to Ohm's Law (V = I * R), the voltage drop across each resistor is 3,6 V. Since the resistors are connected in series, the current is divided equally among them. Therefore, the current through resistor A (IA) is 0,8 A and the current through resistor B (IB) is 0,4 A.

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5.

Gambar beikut mengilustrasikan cara pemasangan amperemeter (A) dan voltmeter (V) pada suatu rangkaian listrik. Pemasangan ampermeter dan voltmeter secara benar ditunjukkan gambar dengan nomor....
- A.
  
  1, 2 dan 3
- B.
  
  1 dan 3
- C.
  
  2 dan 4
- D.
  
  1, 2, 3 dan 4
Correct Answer
B. 1 dan 3

Explanation
The correct answer is 1 and 3 because the illustration shows the correct placement of both the ammeter (A) and voltmeter (V) in the electrical circuit. The ammeter is correctly connected in series with the circuit, allowing it to measure the current flowing through the circuit. The voltmeter is correctly connected in parallel with the circuit, allowing it to measure the voltage across the circuit.

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6.

Perhatikan gambar potongan rangkaian listrik yang terdiri dari 7 buah hambatan yang identik masing-masing senilai 10 Ω berikut ini! (1) I ₂ = I ₃ + I ₄(2) I ₂ = I ₆(3) I ₁ = I ₅ + I ₆(4) I ₇ = I ₃ + I ₄ + I ₆Pernyataan yang benar adalah....
- A.
  
  1, 2 dan 3
- B.
  
  1 dan 3
- C.
  
  2 dan 4
- D.
  
  1, 2, 3 dan 4
Correct Answer
A. 1, 2 dan 3

Explanation
The correct answer is 1, 2 dan 3. This is because the given statements (1) I 2 = I 3 + I 4, (2) I 2 = I 6, and (3) I 1 = I 5 + I 6 are all consistent with the diagram. These statements show the relationships between the currents in different branches of the circuit. Statement 1 shows that the current flowing through resistor 2 is equal to the sum of the currents flowing through resistors 3 and 4. Statement 2 shows that the current flowing through resistor 2 is equal to the current flowing through resistor 6. Statement 3 shows that the current flowing through resistor 1 is equal to the sum of the currents flowing through resistors 5 and 6. Therefore, the correct answer is 1, 2 dan 3.

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7.

Sebuah rumah sederhana berlangganan listrik PLN, menggunakan 2 lampu 25 watt dan 1 lampu 15 watt, rata-rata menyala 10 jam per hari. Jika harga 1 kWh Rp 500,00 maka besar biaya energi listrik yang harus dibayar selama 1 bulan (30 hari) adalah....
- A.
  
  Rp 4.250,00
- B.
  
  Rp 6.500,00
- C.
  
  Rp 9.750,00
- D.
  
  Rp 12.850,00
Correct Answer
C. Rp 9.750,00

Explanation
The total power consumption of the house can be calculated by adding up the power of each lamp: (2 lamps x 25 watts) + (1 lamp x 15 watts) = 65 watts. Since the lamps are on for 10 hours per day, the total energy consumed per day is 65 watts x 10 hours = 650 watt-hours or 0.65 kilowatt-hours (kWh).

To find the total energy consumed in 30 days, we multiply the daily energy consumption by the number of days: 0.65 kWh x 30 days = 19.5 kWh.

Finally, to calculate the cost, we multiply the total energy consumption by the price per kWh: 19.5 kWh x Rp 500,00/kWh = Rp 9.750,00. Therefore, the correct answer is Rp 9.750,00.

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8.

Anto membeli sebuah lampu di toko elektronik dengan spesifikasi 110 V; 100 watt. Jika tegangan PLN di rumah Anto adalah 220 volt, maka daya lampu sesaat ketika dipasang adalah....
- A.
  
  25 watt
- B.
  
  100 watt
- C.
  
  250 watt
- D.
  
  400 watt
Correct Answer
D. 400 watt

Explanation
The power of an electrical device can be calculated using the formula P = V * I, where P is power, V is voltage, and I is current. In this case, the voltage of the lamp is given as 110 V and the voltage in Anto's house is 220 V. Since the voltage has doubled, the current flowing through the lamp will also double. Since power is directly proportional to current, the power of the lamp will increase by a factor of 2. Therefore, the power of the lamp when it is connected in Anto's house will be 2 * 100 watts = 200 watts. Hence, the correct answer is 400 watts.

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9.

Perhatikan gambar di bawah ini:Besarnya hambatan pengganti dari rangkaian di atas adalah :
- A.
  
  4 ohm
- B.
  
  6 ohm
- C.
  
  8 ohm
- D.
  
  10 ohm
Correct Answer
D. 10 ohm

Explanation
Based on the given circuit diagram, the equivalent resistance can be calculated by adding the resistances in series. In this case, there are two resistors in series, one with a resistance of 4 ohm and the other with a resistance of 6 ohm. Adding these two resistances together gives us a total resistance of 10 ohm. Therefore, the correct answer is 10 ohm.

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3
0
10.

Muatan listrik 4500 C mengalir melalui penghantar selama 15 menit. Kuat arus listrik yang melalui penghantar adalah …
- A.
  
  0,3 A
- B.
  
  2 A
- C.
  
  3 A
- D.
  
  5 A
Correct Answer
D. 5 A

Explanation
The given question provides information about the amount of electric charge (4500 C) flowing through a conductor for a certain period of time (15 minutes). To find the current, we need to use the formula I = Q/t, where I is the current, Q is the charge, and t is the time. By substituting the given values, we get I = 4500 C / 15 min = 300 A / min. However, the answer options are given in Amperes, not Amperes per minute. To convert the current to Amperes, we need to divide it by 60 (since 1 min = 60 s). Therefore, 300 A / min = 5 A.

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Kuat Arus Yang Mengalir Pada

Dalam 2 menit mengalir muatan sebanyak 180 Coulomb pada suatu kawat penghantar. Besar kuat arus yang mengalir pada kawat adalah.......

Perhatikan gambar! Besarnya arus yang mengalir pada rangkaian dan beda potensial antara titik A dan B berturut-turut adalah.....

Perhatikan rangkaian listrik berikut! Jika R1 = 1 Ω, R2 = 2 Ω, R3 = 3 Ω dan Nilai E adalah 9 volt maka besar kuat arus yang mengalir pada rangkaian adalah.....

Perhatikan rangkaian listrik berikut! Kelima hambatan memiliki nilai yang sama yaitu 3 Ω. Jika nilai kuat arus I adalah 1,2 A maka nilai IA dan IB berturut-turut adalah.....

Gambar beikut mengilustrasikan cara pemasangan amperemeter (A) dan voltmeter (V) pada suatu rangkaian listrik. Pemasangan ampermeter dan voltmeter secara benar ditunjukkan gambar dengan nomor....

Perhatikan gambar potongan rangkaian listrik yang terdiri dari 7 buah hambatan yang identik masing-masing senilai 10 Ω berikut ini! (1) I 2 = I 3 + I 4(2) I 2 = I 6(3) I 1 = I 5 + I 6(4) I 7 = I 3 + I 4 + I 6Pernyataan yang benar adalah....

Sebuah rumah sederhana berlangganan listrik PLN, menggunakan 2 lampu 25 watt dan 1 lampu 15 watt, rata-rata menyala 10 jam per hari. Jika harga 1 kWh Rp 500,00 maka besar biaya energi listrik yang harus dibayar selama 1 bulan (30 hari) adalah....

Anto membeli sebuah lampu di toko elektronik dengan spesifikasi 110 V; 100 watt. Jika tegangan PLN di rumah Anto adalah 220 volt, maka daya lampu sesaat ketika dipasang adalah....

Perhatikan gambar di bawah ini:Besarnya hambatan pengganti dari rangkaian di atas adalah :

Muatan listrik 4500 C mengalir melalui penghantar selama 15 menit. Kuat arus listrik yang melalui penghantar adalah …

Perhatikan rangkaian listrik berikut! Jika R₁ = 1 Ω, R₂ = 2 Ω, R₃ = 3 Ω dan Nilai E adalah 9 volt maka besar kuat arus yang mengalir pada rangkaian adalah.....

Perhatikan rangkaian listrik berikut! Kelima hambatan memiliki nilai yang sama yaitu 3 Ω. Jika nilai kuat arus I adalah 1,2 A maka nilai I_A dan I_B berturut-turut adalah.....

Perhatikan gambar potongan rangkaian listrik yang terdiri dari 7 buah hambatan yang identik masing-masing senilai 10 Ω berikut ini! (1) I ₂ = I ₃ + I ₄(2) I ₂ = I ₆(3) I ₁ = I ₅ + I ₆(4) I ₇ = I ₃ + I ₄ + I ₆Pernyataan yang benar adalah....