LeChatelier's Principle

2.

When the pressure on a gaseous reaction system at equilibrium is increased, the equilibrium will shift...

In favor of the side with the least gas molecules
In favor of the side with the most gas molecules
There will be no change
To the product side
To the reactant side

Correct Answer

A. In favor of the side with the least gas molecules

Explanation

When the pressure on a gaseous reaction system at equilibrium is increased, the equilibrium will shift in favor of the side with the least gas molecules. This is because increasing the pressure will cause the system to try to reduce the number of gas molecules in order to decrease the pressure. Therefore, the equilibrium will shift towards the side with fewer gas molecules to achieve a new equilibrium with a lower pressure.

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3.

For the following reaction, how will the reaction equilibrium be affected by an increase in temperature? H₂O_2(l) <--> H_2(g) + O_2(g) DH = +187 kJ

It will shift to the right
It will shift to the left
There will be no change

Correct Answer

A. It will shift to the right

Explanation

The reaction is endothermic. According to Le Chatelier's Principle, increasing the temperature of an endothermic reaction will favor the endothermic direction. Thus, the equilibrium will shift to the right. Therefore, the correct answer is: It will shift to the right.

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4.

For the following reaction, how will the reaction equilibrium be affected by an increase in volume?H₂O_2(l) <--> H_2(g) + O_2(g) DH = +187 kJ

It will shift in favor of the products
It will shift in favor of the reactants
There will be no change

Correct Answer

A. It will shift in favor of the products

Explanation

An increase in volume will cause the reaction equilibrium to shift in favor of the products. According to Le Chatelier's principle, when the volume of a system is increased, the equilibrium will shift in the direction that produces fewer moles of gas. In this reaction, the reactants have one mole of gas (H2), while the products have two moles of gas (H2 and O2). Therefore, an increase in volume will favor the side with fewer moles of gas, which is the products.

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3

5.

For the following reaction, how will the reaction equilibrium be affected by the removal of oxygen gas?H₂O_2(l) <--> H_2(g) + O_2(g) DH = +187 kJ

It will shift to the right
There will be no change
It will shift to the left

Correct Answer

A. It will shift to the right

Explanation

When oxygen gas is removed from the reaction, the equilibrium will shift to the right in order to replace the lost oxygen. This is because the reaction wants to maintain a balance of reactants and products. By shifting to the right, more H2 and O2 will be produced, which will increase the concentration of oxygen gas in the system. This shift to the right will help restore the equilibrium and compensate for the removal of oxygen gas.

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6.

If volume is decreased for the following reaction system at equilibrium, what color will you expect the mixture to become? N₂O_4(g) + heat <--> 2 NO_{2(g)colorless brown}

Colorless
Brown

Correct Answer

A. Colorless

Explanation

The reaction given is an example of a reversible reaction, where the reactants N2O4(g) and NO2(g) can interconvert. At equilibrium, the forward and backward reactions occur at equal rates. In this reaction system, N2O4 is colorless and NO2 is brown. When the volume is decreased, according to Le Chatelier's principle, the equilibrium will shift in the direction that reduces the number of gas molecules. Since the forward reaction produces two moles of gas (2 NO2), decreasing the volume will shift the equilibrium to the left, favoring the reverse reaction and causing the colorless N2O4 to dominate. Therefore, the mixture will become colorless.

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Lechatelier's Principle

When more reactant is added into a reaction system at equilibrium, how does the system react to compensate for the stress that is applied?

Quiz Preview

When the pressure on a gaseous reaction system at equilibrium is increased, the equilibrium will shift...

For the following reaction, how will the reaction equilibrium be affected by an increase in temperature? H₂O_2(l) <--> H_2(g) + O_2(g) DH = +187 kJ

For the following reaction, how will the reaction equilibrium be affected by an increase in volume?H₂O_2(l) <--> H_2(g) + O_2(g) DH = +187 kJ

For the following reaction, how will the reaction equilibrium be affected by the removal of oxygen gas?H₂O_2(l) <--> H_2(g) + O_2(g) DH = +187 kJ

If volume is decreased for the following reaction system at equilibrium, what color will you expect the mixture to become? N₂O_4(g) + heat <--> 2 NO_{2(g)colorless brown}

Lechatelier's Principle

When more reactant is added into a reaction system at equilibrium, how does the system react to compensate for the stress that is applied?

Quiz Preview

When the pressure on a gaseous reaction system at equilibrium is increased, the equilibrium will shift...

For the following reaction, how will the reaction equilibrium be affected by an increase in temperature? H2O2(l) <--> H2(g) + O2(g) DH = +187 kJ

For the following reaction, how will the reaction equilibrium be affected by an increase in volume?H2O2(l) <--> H2(g) + O2(g) DH = +187 kJ

For the following reaction, how will the reaction equilibrium be affected by the removal of oxygen gas?H2O2(l) <--> H2(g) + O2(g) DH = +187 kJ

If volume is decreased for the following reaction system at equilibrium, what color will you expect the mixture to become? N2O4(g) + heat <--> 2 NO2(g)colorless brown

For the following reaction, how will the reaction equilibrium be affected by an increase in temperature? H₂O_2(l) <--> H_2(g) + O_2(g) DH = +187 kJ

For the following reaction, how will the reaction equilibrium be affected by an increase in volume?H₂O_2(l) <--> H_2(g) + O_2(g) DH = +187 kJ

For the following reaction, how will the reaction equilibrium be affected by the removal of oxygen gas?H₂O_2(l) <--> H_2(g) + O_2(g) DH = +187 kJ

If volume is decreased for the following reaction system at equilibrium, what color will you expect the mixture to become? N₂O_4(g) + heat <--> 2 NO_{2(g)colorless brown}