Kimia Inti
Kerjakan soal berikut dalam waktu 30 menit, kesempatan hanya diberikan 2 kali. Manfaatkan sebaik-baiknya. Oc!
- 1.
Urutan daya tembus sinar-sinar radioaktif dimulai dari yang paling kuat adalah.......
- A.
Alfa, beta, gama
- B.
Gama, alfa, beta
- C.
Beta, alfa, gama
- D.
Alfa, gama, beta
- E.
Gama, beta, alfa
Correct Answer
E. Gama, beta, alfaExplanation
The correct answer is gama, beta, alfa. This is because gamma rays have the highest penetrating power among the three types of radioactive rays. They can easily pass through most materials and are the most dangerous to human health. Beta particles have a lower penetrating power and can be stopped by a sheet of aluminum or a few centimeters of air. Alpha particles have the lowest penetrating power and can be stopped by a sheet of paper or a few centimeters of air.Rate this question:
-
- 2.
Diantara sinar/partikel yang dipancarkan oleh peluruhan unsur radioaktif berikut yang tidak bermasa dan tidak bermuatan adalah ....
- A.
Alfa
- B.
Beta
- C.
Gamma
- D.
Positron
- E.
Elektron
Correct Answer
C. GammaExplanation
Gamma rays are a type of electromagnetic radiation that is emitted during radioactive decay. Unlike alpha and beta particles, gamma rays do not have mass or charge. Gamma rays are high-energy photons that can penetrate through materials and are often used in medical imaging and radiation therapy. Therefore, the correct answer is gamma.Rate this question:
-
- 3.
Suatu unsur radioaktif meluruh menjadi unsur baru dengan nomor ato berkurang satu, sedangkan masanya tetap. Partikel yang dipancarkan pada peluruhan tersebut adalah....
- A.
Proton
- B.
Elektron
- C.
Positron
- D.
Neutron
- E.
Alfa
Correct Answer
B. ElektronExplanation
When a radioactive element undergoes decay, it transforms into a new element with a decreased atomic number. This indicates that a proton is lost during the decay process. The particle that is emitted during this decay is an electron, which has a negative charge. Therefore, the correct answer is "elektron".Rate this question:
-
- 4.
Radioisotop 11 23Na meluruh membentuk isotop 10 22Ne dengan memancarkan partikel .....
- A.
Proton
- B.
Positron
- C.
Neutron
- D.
Elektron
- E.
Deutron
Correct Answer
B. PositronExplanation
When a radioisotope of 11 23Na decays, it forms an isotope of 10 22Ne by emitting a particle called a positron. A positron is a positively charged electron.Rate this question:
-
- 5.
Perubahan proton menjadi neutron di dalam inti disertai pemancaran .....
- A.
Elektron
- B.
Positron
- C.
Sinar gamma
- D.
Sinar X
- E.
Sinar beta
Correct Answer
A. ElektronExplanation
Perubahan proton menjadi neutron di dalam inti disertai pemancaran elektron. This is known as beta decay. In beta decay, a proton in the nucleus is converted into a neutron, and an electron (also known as a beta particle) is emitted from the nucleus.Rate this question:
-
- 6.
Pada reaksi inti berikut ini 5 10B + 2 4He 7 13N + X ; X adalah .......
- A.
Proton
- B.
Neutron
- C.
Positron
- D.
Elektron
- E.
Gamma
Correct Answer
B. NeutronExplanation
In the given nuclear reaction, 5 10B + 2 4He → 7 13N + X, the reactants are boron-10 (10B) and helium-4 (4He), and the product is nitrogen-13 (13N). The X represents an unknown particle that is produced in the reaction. Based on the conservation of mass and charge, the X particle must have no charge (neutron) because the total number of protons and neutrons on both sides of the reaction should be equal. Therefore, the correct answer is neutron.Rate this question:
-
- 7.
Mula-mula disimpan radioisotop yang mempunyai waktu paruh 10 hari, setelah disimpan selama 30 hari, maka tersisa radioisotop X sebanyak ......
- A.
50%
- B.
25%
- C.
12,5%
- D.
6,25%
- E.
3,12%
Correct Answer
C. 12,5%Explanation
The given question is asking for the percentage of radioisotope X that remains after it has been stored for 30 days. The radioisotope has a half-life of 10 days, which means that after 10 days, half of the radioisotope will decay. After another 10 days (20 days total), half of the remaining radioisotope will decay, leaving 25% of the original amount. After another 10 days (30 days total), half of the remaining radioisotope will decay again, leaving 12.5% of the original amount. Therefore, the correct answer is 12.5%.Rate this question:
-
- 8.
Waktu paruh 210 Bi adalah 5, jika mula-mula disimpan sebanyak 8 gram dan kemudian ternyata sisanya tinggal 1 gram, maka unsur tersebut telah disimpan selama .....
- A.
10 hari
- B.
15 hari
- C.
20 hari
- D.
25 hari
- E.
30 hari
Correct Answer
B. 15 hariExplanation
The half-life of 210 Bi is 5 days. If initially there were 8 grams of the element and now only 1 gram remains, it means that half of the element has decayed. Since the half-life is 5 days, it took 5 days for half of the element to decay from 8 grams to 4 grams. Therefore, it would take another 5 days for the remaining 4 grams to decay to 2 grams, and another 5 days for the remaining 2 grams to decay to 1 gram. So, in total, it would take 15 days for the element to decay from 8 grams to 1 gram.Rate this question:
-
- 9.
Bila waktu paruh suatu radioaktif = T detik, maka setelah 4T detik unsur radioaktif tinggal ....
- A.
½ bagian
- B.
¼ bagian
- C.
1/8 bagian
- D.
1/16 bagian
- E.
Tetap ( 1 bagian )
Correct Answer
D. 1/16 bagianExplanation
The correct answer is 1/16 bagian. This is because the question states that the half-life of a radioactive element is T seconds. This means that after T seconds, half of the radioactive element will remain. Therefore, after 4T seconds, the radioactive element will go through two half-lives, resulting in 1/2 * 1/2 = 1/4 of the element remaining. After 4T seconds, the element will go through another two half-lives, resulting in 1/4 * 1/2 = 1/8 of the element remaining. Finally, after 4T seconds, the element will go through another two half-lives, resulting in 1/8 * 1/2 = 1/16 of the element remaining.Rate this question:
-
- 10.
Dewasa ini radioisotop telah dipergunakan dalam berbagai bidang, baik sebagai sumber radiasi maupun sebagai perunut, misalnya (1). Membasmi hama gudang (2). Memeriksa kebocoran waduk (3). Memeriksa mutu pengelasan (4). Menentukan kecepatan aliran sungai (5). Sterilisasi alal-alat kedokteran (6). Terapi tumor dan kanker (7 ). Untuk Rontgent (8). Pengawetan bahan makanan Diantar kegiatan di atas, yang menggunakan radioisotop sebagai perunut adalah ......
- A.
(1), (3),(5), (6), dan (8)
- B.
(2), (4), dan (8)
- C.
(1), (2), (3), dan (4)
- D.
(5), (6), (7), dan (8)
- E.
(2), dan (4)
Correct Answer
E. (2), dan (4)Explanation
The activities that use radioisotopes as tracers are (2) checking for dam leaks and (4) determining the speed of river flow. The other activities listed do not involve the use of radioisotopes as tracers.Rate this question:
-
- 11.
Isotop radioaktif yang dipakai untuk mempelajari mekanisme reaksi esterifikasi adalah ....
- A.
P-32
- B.
C-14
- C.
Na-24
- D.
O-18
- E.
I-131
Correct Answer
D. O-18Explanation
O-18 is the correct answer because it is an isotope that can be used to study the mechanism of esterification reactions. Isotopes are atoms of the same element with different numbers of neutrons, and O-18 is an isotope of oxygen. By using O-18 labeled compounds in esterification reactions, researchers can track the movement of the oxygen atoms and gain insights into the reaction mechanism. This is because O-18 is a stable isotope that can be easily detected and distinguished from other isotopes of oxygen.Rate this question:
-
- 12.
Penggunaan radioisotop Co-60 dalam pengobatan kanker adalah karena zat ini memancarkan.....
- A.
Sinar beta
- B.
Sinar infra merah
- C.
Sinar gamma
- D.
Sinar ultraviolet
- E.
Sinar alpha
Correct Answer
C. Sinar gammaExplanation
The use of Co-60 radioisotope in cancer treatment is because it emits gamma rays. Gamma rays are highly penetrating and can effectively target and destroy cancer cells.Rate this question:
-
- 13.
Radioisotop dapat digunakan sebagai sumber radiasi atau perunut. Radioisotop yang dapat digunakan sebagai perunut adalah....
- A.
Mempelajari mekanisme reaksi
- B.
Terapi tumor/kanker
- C.
Mensterilisasi alat-alat kedokteran
- D.
Menghambat pertumbuhan
- E.
Memerikasa mutu pengelasan
Correct Answer
A. Mempelajari mekanisme reaksiExplanation
Radioisotop dapat digunakan sebagai perunut untuk mempelajari mekanisme reaksi. Radioisotop ini dapat digunakan dalam penelitian kimia untuk melabeli atau melacak molekul-molekul tertentu dalam suatu reaksi kimia. Dengan menggunakan radioisotop, ilmuwan dapat melihat bagaimana molekul-molekul tersebut berinteraksi dan berubah selama reaksi berlangsung. Hal ini membantu dalam memahami mekanisme reaksi dan proses kimia secara lebih mendalam.Rate this question:
-
- 14.
Radioisotop yang digunakan dalam reaksi fotosintesis adalah ....
- A.
Co-60
- B.
N-15
- C.
C-14
- D.
Na-24
- E.
Cl-37
Correct Answer
C. C-14Explanation
C-14 is the correct answer because it is a radioisotope that is commonly used in radiocarbon dating. Radiocarbon dating is a method used to determine the age of organic materials by measuring the amount of C-14 remaining in the sample. Since photosynthesis involves the uptake of carbon dioxide by plants, the C-14 isotope can be used to trace the carbon cycle and study the process of photosynthesis.Rate this question:
-
- 15.
Radioisotop berikut yang tidak diproduksi oleh BATAN adalah ....
- A.
P-32
- B.
Na-24
- C.
Na-22
- D.
Fe-58
- E.
I-131
Correct Answer
D. Fe-58Explanation
Fe-58 is the correct answer because it is not produced by BATAN. The other radioisotopes mentioned (P-32, Na-24, Na-22, and I-131) are commonly produced and used by BATAN for various purposes such as medical imaging, research, and industrial applications. However, Fe-58 is not typically produced by BATAN and has limited applications in nuclear medicine.Rate this question:
-
Quiz Review Timeline +
Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.
-
Current Version
-
Jul 22, 2024Quiz Edited by
ProProfs Editorial Team -
Jan 16, 2013Quiz Created by
Ernaumunurlaela
Back to top