IQ Test-1 (Coding And Decoding)

The code for each letter in the word ANNJ is obtained by shifting the corresponding letter in the word BOOK one position to the right in the alphabet. Applying the same logic to the word LOOK, the letter L would be shifted to N, O to N, O to J, and K to J. Therefore, the code for LOOK would be KNNJ.

The code appears to be reversing the letters in the word and then rearranging them. In the word "SPIDER," the letters are reversed to spell "REDIPS," and then rearranged to form "PSDIRE." Applying the same pattern to the word "COMMON," the letters are reversed to spell "NOMMOC," and then rearranged to form "OCMMNO."

The given code rearranges the letters in the word by taking the first letter and placing it at the end, while keeping the remaining letters in the same order. Applying this code to the word "TEACHER" would result in "TAECEHR", which matches the first option.

The given code rearranges the letters in the word by taking the first letter, then the second and third letters in reverse order, followed by the fourth and fifth letters in reverse order, and so on. Applying this pattern to the word "CIRCULAR", we get "CRIUCALR".

The given question follows a pattern where each letter in the word BAT is replaced by the corresponding letter that is three positions ahead in the alphabet. Applying this pattern to the word PEN, we get the letters QHK. Therefore, the correct answer is QHK.

The given code follows a pattern where each letter in the word is shifted forward by one position in the alphabet. For example, P is coded as Q, A is coded as B, etc. Applying the same pattern to the word "COVER", each letter will be shifted forward by one position, resulting in the code "FQZGW".

To solve this type of encoding puzzle, let's analyze how LCMHN is transformed into MANGO.

Let's break it down letter by letter:

L -> M

C -> A

M -> N

H -> G

N -> O

By comparing the positions of the letters in the alphabet:

L is the 12th letter, and M is the 13th letter (L + 1 = M)

C is the 3rd letter, and A is the 1st letter (C - 2 = A)

M is the 13th letter, and N is the 14th letter (M + 1 = N)

H is the 8th letter, and G is the 7th letter (H - 1 = G)

N is the 14th letter, and O is the 15th letter (N + 1 = O)

The transformation pattern seems to be:

+1, -2, +1, -1, +1

Now, applying the same pattern to BOUTS:

B -> C (B + 1)

O -> M (O - 2)

U -> V (U + 1)

T -> S (T - 1)

S -> T (S + 1)

Therefore, BOUTS would be represented as CMVST.

The given question follows a pattern where each alternate letter in the word "NATURE" is shifted one position back in the alphabet. Applying the same pattern to the word "FAMINE", each alternate letter should be shifted one position backward, resulting in "EALIME". Therefore, the correct answer is "EALIME".

The code for each letter in the word "GAMBLE" is obtained by shifting it one position to the left in the alphabet. Applying the same logic to the word "FLOWER", each letter should be shifted one position to the left. Therefore, the correct code for "FLOWER" is "EMNXDS".

The given question involves encoding a word using a specific code. The code for "purify" is given as "RTTHHX". To find the code for "BLANCH", we need to find a pattern in the given code. Upon observation, it can be seen that each letter in the code is shifted forward by one position in the alphabet. Applying the same pattern to "BLANCH", we get "DKCMEG" as the code.

To determine how GLAMOUR would be coded, we need to identify the pattern used to encode SHELNXR as TEDIOUS. Let's analyze the pattern by comparing each corresponding letter:

S → T H → E E → D L → I N → O X → U R → S

Now let's break down the shifts:

S to T: +1

H to E: -3

E to D: -1

L to I: -3

N to O: +1

X to U: -3

R to S: +1

The pattern alternates between adding 1 and subtracting 3:

+1

-3

-1

-3

+1

-3

+1

Now, let's apply this pattern to GLAMOUR:

G (+1) → H

L (-3) → I

A (-1) → Z

M (-3) → J

O (+1) → P

U (-3) → R

R (+1) → S

So, the code for GLAMOUR would be HIZJPRS.

This is a letter-shifting code where each letter in the original word is replaced with the letter that comes before it in the alphabet.

NUST: N -> M, U -> T, S -> R, T -> S, resulting in MWPS

Applying the same pattern to GIKI:

GIKI: G -> F, I -> H, K -> J, I -> L, resulting in FHJL

To solve the problem of coding "SIMPLE" in the same way "HUMBLE" is coded as "IVNAKD," we need to understand the pattern or rule used in the coding.

Let's compare each letter in "HUMBLE" with "IVNAKD":

H -> I (H+1 = I)

U -> V (U+1 = V)

M -> N (M+1 = N)

B -> A (B-1 = A)

L -> K (L-1 = K)

E -> D (E-1 = D)

From this, we can see a pattern:

For the first three letters, each letter is shifted forward by 1 in the alphabet.

For the last three letters, each letter is shifted backward by 1 in the alphabet.

Using this pattern, let's code "SIMPLE":

S -> T (S+1 = T)

I -> J (I+1 = J)

M -> N (M+1 = N)

P -> O (P-1 = O)

L -> K (L-1 = K)

E -> D (E-1 = D)

So, "SIMPLE" will be coded as "TJNKOD".

In the given language, each letter of the word is shifted by a certain number of positions to obtain the coded word. By observing the given examples, it can be deduced that the first letter is shifted by 1 position, the second letter by 2 positions, the third letter by 3 positions, and so on. Applying the same pattern, the word "LKUMB" would be coded as "MMXCG" because L is shifted by 1 position to become M, K is shifted by 2 positions to become M, U is shifted by 3 positions to become X, M is shifted by 4 positions to become C, and B is shifted by 5 positions to become G.