# Himpunan (Kls.7)

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Quizzes Created: 2 | Total Attempts: 1,602
Questions: 20 | Attempts: 723

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• 1.

### Himpunan huruf pembentuk kata "BINATANG" adalah ... .

• A.

{b, i, n, a, t, g}

• B.

{b, i, n, t, a, n, g}

• C.

{b, i, n, a, t, a, n, g}

• D.

{b, i, n, a}

A. {b, i, n, a, t, g}
Explanation
The correct answer is {b, i, n, a, t, g}. This is because the word "BINATANG" is spelled using the letters b, i, n, a, t, and g. The other options either include additional letters that are not present in the word or exclude letters that are necessary to spell the word correctly.

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• 2.

### Anggota dari B = {x < 50, x anggota bilangan kuadrat} adalah ... .

• A.

{1, 4, 9, 16, 25, 36, 49}

• B.

{4, 9, 16, 25, 36, 49}

• C.

{64, 81, 100, 121, ...}

• D.

{1, 2, 3, 4, 5, 6, 7}

A. {1, 4, 9, 16, 25, 36, 49}
Explanation
The correct answer is {1, 4, 9, 16, 25, 36, 49}. This is because the set B consists of numbers that are less than 50 and are perfect squares. The numbers 1, 4, 9, 16, 25, 36, and 49 are all perfect squares and they are all less than 50. Therefore, they are the elements of set B.

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• 3.

### Diketahui : P = {Bilangan kelipatan 5 antara 11 dan 32}.  Banyaknya anggota P yang merupakan bilangan genap adalah ... .

• A.

4

• B.

3

• C.

2

• D.

1

C. 2
Explanation
The set P consists of the numbers that are multiples of 5 between 11 and 32. The numbers in P are 15, 20, 25, and 30. Out of these numbers, only 20 and 30 are even. Therefore, there are two members of P that are even numbers.

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• 4.

### Jika A = {Huruf pembentuk kata "PENDIDIKAN"}, maka n(A) adalah ... .

• A.

10

• B.

9

• C.

8

• D.

7

D. 7
Explanation
The question asks for the cardinality of set A, which is defined as the set of letters that form the word "PENDIDIKAN". By counting the letters in the word, we can determine that there are 7 distinct letters: P, E, N, D, I, K, and A. Therefore, the cardinality or the number of elements in set A is 7.

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• 5.

### Jika himpunan P mempunyai 32 himpunan bagian, maka n(P) adalah ... .

• A.

6

• B.

5

• C.

4

• D.

3

B. 5
Explanation
The question asks for the value of n(P), which represents the number of elements in set P. The statement says that set P has 32 subsets. In general, the number of subsets of a set with n elements is 2^n. Therefore, if P has 32 subsets, it means that P has 2^5 = 32 elements. So, the correct answer is 5.

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• 6.

### Diketahui S = {Bilangan genap yang kurang dari 20}, A = {Bilangan kelipatan 2 yang kurang dari 20}. Komplemen dari A adalah ... .

• A.

{2}

• B.

Himpunan kosong

• C.

{2, 3, 6, 8, 10, 12, 14, 16, 18}

• D.

{1, 3, 5, 7, 9, 11, 13, 15, 17, 19}

B. Himpunan kosong
Explanation
The complement of A is the set of elements that are not in A. In this case, A is the set of even numbers less than 20. Therefore, the complement of A would be the set of odd numbers less than 20, which is an empty set.

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• 7.

### Diketahui : (i)     Kumpulan hewan-hewan kecil. (ii)    Kumpulan hewan berkaki empat. (iii)   Kumpulan sungai-sungai yang panjang. (iv)   Kumpulan lukisan-lukisan yang bagus. Diantara kumpulan-kumpulan di atas, yang merupakan himpunan adalah ... .

• A.

(i)

• B.

(ii)

• C.

(iii)

• D.

(iv)

B. (ii)
Explanation
The given options consist of different groups or collections. Option (ii) "Kumpulan hewan berkaki empat" is the only option that represents a specific group or collection of animals with four legs. The other options do not represent a specific group or collection, but rather a general category or description. Therefore, option (ii) is the correct answer as it is the only one that represents a himpunan or a specific group.

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• 8.

### Himpunan di bawah ini yang bukan merupakan himpunan bagian dari L = {2, 3, 5} adalah ... .

• A.

{himpunan kosong}

• B.

HImpunan kosong

• C.

{2, 5}

• D.

{2, 3, 5}

A. {himpunan kosong}
Explanation
The correct answer is {himpunan kosong} because it is the only option that is not a subset of L = {2, 3, 5}. The empty set is not a subset of any set, including L. The other options {2, 5} and {2, 3, 5} are subsets of L because they contain elements that are also in L.

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• 9.

### Dari 42 siswa kelas VII SMP Katolik St.Yoseph Kepanjen, terdapat 26 siswa gemar matematika, 15 siswa gemar IPA, dan 8 siswa gemar keduanya. Banyaknya siswa yang tidak gemar matematika dan IPA adalah ... .

• A.

9 siswa

• B.

8 siswa

• C.

7 siswa

• D.

6 siswa

A. 9 siswa
Explanation
From the given information, we know that there are 26 students who like mathematics and 15 students who like science. However, 8 students like both subjects. To find the number of students who do not like both subjects, we subtract the number of students who like both subjects from the total number of students who like mathematics and science. Therefore, the number of students who do not like both subjects is 26 + 15 - 8 = 33. However, the question asks for the number of students who do not like mathematics and science, so we subtract this number from the total number of students, which is 42. Therefore, the correct answer is 42 - 33 = 9 students.

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• 10.

### Pada suatu agen koran dan majalah terdapat 18 orang berlangganan koran dan majalah, 24 orang berlangganan majalah, dan 36 orang berlangganan koran. Banyaknya seluruh pelanggan agen tersebut adalah ... .

• A.

40 orang

• B.

42 orang

• C.

60 orang

• D.

78 orang

B. 42 orang
Explanation
The total number of customers of the newspaper and magazine agency can be calculated by adding the number of customers who subscribe to both the newspaper and magazine, the number of customers who only subscribe to the magazine, and the number of customers who only subscribe to the newspaper. In this case, there are 18 customers who subscribe to both, 24 customers who only subscribe to the magazine, and 36 customers who only subscribe to the newspaper. Adding these numbers together gives a total of 78 customers. Therefore, the correct answer is 78 customers.

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• 11.

### Dari pernyataan berikut, manakah yang bukan himpunan?

• A.

Kelompok bilangan ganjil

• B.

Kelompok makanan enak dan pedas

• C.

Kumpulan hewan menyusui

• D.

D. B himpunan bilangan prima

B. Kelompok makanan enak dan pedas
Explanation
The statement "kelompok makanan enak dan pedas" is not a set because it does not represent a well-defined collection of objects. It is a subjective description of food preferences rather than a clear and distinct grouping based on specific criteria. In contrast, the other options represent sets that can be defined and categorized based on their respective criteria.

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• 12.

### Dari pernyataan berikut, yang merupakan himpunan adalah ....

• A.

Kumpulan pemandangan yang indah

• B.

Kumpulan murid yang cantik

• C.

Kumpulan makanan enak

• D.

Kumpulan hewan berkaki empat

D. Kumpulan hewan berkaki empat
Explanation
The correct answer is "kumpulan hewan berkaki empat" because it is the only option that represents a set or a collection of things. The other options describe qualities or characteristics of a group of things, but they do not represent a set in themselves.

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• 13.

### Anggota dari himpunan B = { xI x 20, x  bilangan prima} adalah ....

• A.

{2, 3, 5, 7, 11, 13, 17}

• B.

{1, 2, 3, 5, 7, 11, 13, 17}

• C.

{2, 3, 5, 7, 9, 11, 13, 17}

• D.

{1, 2, 3, 5, 7, 9, 11, 13, 17}

A. {2, 3, 5, 7, 11, 13, 17}
Explanation
The correct answer is {2, 3, 5, 7, 11, 13, 17} because the question asks for the members of set B, which is defined as the set of prime numbers less than or equal to 20. The numbers 2, 3, 5, 7, 11, 13, and 17 are all prime numbers and they are all less than or equal to 20. Therefore, these numbers are the correct members of set B.

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• 14.

### Berikut ini yang merupakan himpunan kosong adalah ...

• A.

Himpunan bilangan prima yang ganjil

• B.

Himpunan bilangan prima yang genap

• C.

Himpunan bilangan prima antara 1 dan 3

• D.

Himpunan bilangan asli antara 3 dan 4

D. Himpunan bilangan asli antara 3 dan 4
Explanation
The given correct answer is "himpunan bilangan asli antara 3 dan 4" because a set is considered empty if it does not contain any elements. In this case, the set of natural numbers between 3 and 4 is empty because there are no natural numbers between these two values.

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• 15.

### Banyak anggota dari himpunan P = {1, 3, 5, 7, 9, 11} adalah ....

• A.

11

• B.

9

• C.

6

• D.

5

C. 6
Explanation
The correct answer is 6 because the set P contains 6 elements: 1, 3, 5, 7, 9, and 11.

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• 16.

• A.

N(P) = 6

• B.

P = 6

• C.

P = (6)

• D.

P = (1,2,3,4,5,6)

A. N(P) = 6
Explanation
The correct way to express the statement "Banyak anggota P adalah 6" (The number of members in P is 6) is by using the notation "n(P) = 6". This notation represents the cardinality or the number of elements in the set P.

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• 17.

### Misalkan A = {2, 3, 5, 7}, maka himpunan semesta yang mungkin dari himpunan A adalah ...

• A.

S = {bilangan prima}

• B.

S = {bilangan genap}

• C.

S = {bilangan ganjil}

• D.

A. S = {bilangan prima}
Explanation
The correct answer is S = {bilangan prima} because the set A = {2, 3, 5, 7} only contains prime numbers. The set S represents the universal set, which includes all possible elements that can be chosen from. Since A is a subset of the universal set, the only valid option for S is {bilangan prima}.

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• 18.

### Manakah himpunan-himpunan berikut yang ekuivalen ?

• A.

A = {1, 3, 5, 7}, B = {4, 6, 8, 10}

• B.

C = {bilangan ganjil}, D = {bilangan genap}

• C.

T = {huruf pembentuk kata “HISAP”}, K = {huruf pembentuk kata “PINTAR”}

• D.

A = {3, 4, 5, 6} , B = {bilangan asli antara 2 dan 7}

D. A = {3, 4, 5, 6} , B = {bilangan asli antara 2 dan 7}
Explanation
The sets A = {3, 4, 5, 6} and B = {bilangan asli antara 2 dan 7} are equivalent because they both contain the same elements. Set A contains the numbers 3, 4, 5, and 6, which are all natural numbers between 2 and 7. Set B also contains the same numbers, making them equivalent sets.

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• 19.

### Diketahui K = {p, q, r, s}. banyaknya himpunan bagian dari K adalah ....

• A.

16

• B.

8

• C.

4

• D.

2

A. 16
Explanation
The question asks for the number of subsets of set K, which contains four elements. The number of subsets can be calculated using the formula 2^n, where n is the number of elements in the set. In this case, since K contains four elements, there will be 2^4 = 16 subsets.

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• 20.

• A.

1

• B.

2

• C.

3

• D.

4