Heron’s Formula: Geometry Quiz! Test

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| By Tanmay Shankar
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Tanmay Shankar
Community Contributor
Quizzes Created: 491 | Total Attempts: 1,846,919
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  • 1/15 Questions

    The area of a triangular signboard of sides 5 cm, 12 cm, and 13 cm is:

    • 60 cm2
    • 30 cm2
    • 12 cm2
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About This Quiz

Heron’s formula comes from geometry, and it gives the area of a triangle when the length of all three sides is known. It is not necessary to calculate angles of other distances in the triangle first. Heron’s formula was named after Hero of Alexandria. You must first calculate half of the triangle’s perimeter, and then you calculate the area. Give See morethis quiz a try, and make sure you collect your certificate when you are done.

Herons Formula: Geometry Quiz! Test - Quiz

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  • 2. 

    The sides of a triangle are 3 cm, 4 cm, and 5 cm. Its area is:

    • 15 cm2

    • 12 cm2

    • 9 cm2

    • 6 cm2

    Correct Answer
    A. 6 cm2
    Explanation
    The given triangle is a right-angled triangle with sides of lengths 3 cm, 4 cm, and 5 cm. The area of a right-angled triangle can be calculated using the formula: area = (1/2) * base * height. In this case, the base and height of the triangle are 3 cm and 4 cm respectively. Therefore, the area of the triangle is (1/2) * 3 cm * 4 cm = 6 cm2.

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  • 3. 

    The sides of a triangle are in a ratio of 25:14:12 and its perimeter is 510 m. The greatest side of the triangle is:

    • 270 m

    • 250 m

    • 170 m

    • 120 m

    Correct Answer
    A. 250 m
    Explanation
    The sides of a triangle are in a ratio of 25:14:12, which means that the lengths of the sides can be represented as 25x, 14x, and 12x, where x is a constant. The perimeter of the triangle is given as 510 m, so we can write the equation 25x + 14x + 12x = 510. Simplifying this equation gives us 51x = 510, which means x = 10. Therefore, the lengths of the sides are 250 m, 140 m, and 120 m. The greatest side of the triangle is 250 m.

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  • 4. 
    The area of ΔABC is: - ProProfs

    The area of ΔABC is:

    • 20 cm2

    • 10 cm2

    • Heron’s Formula: Geometry Quiz! Test - Quiz

    • Heron’s Formula: Geometry Quiz! Test - Quiz
    Correct Answer
    A.
  • 5. 

    The perimeter of a right triangle is 60 cm and its hypotenuse is 26 cm. The other two sides of the triangle are:

    • 26 cm, 8 cm

    • 25 cm, 9 cm

    • 24 cm, 10 cm

    • 20 cm, 14 cm

    Correct Answer
    A. 24 cm, 10 cm
    Explanation
    In a right triangle, the sum of the lengths of the two shorter sides (legs) is equal to the length of the hypotenuse. Therefore, if the hypotenuse is 26 cm, the sum of the lengths of the other two sides must be 26 cm. Among the given options, only 24 cm and 10 cm add up to 26 cm. Hence, the correct answer is 24 cm and 10 cm.

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  • 6. 

    When the sum of squares of two sides of a triangle is equal to the square of the length of the third side, then it is called a:

    • Scalene triangle

    • Right triangle

    • Isosceles triangle

    • Equilateral triangle

    Correct Answer
    A. Right triangle
    Explanation
    A right triangle is a triangle in which one of the angles is a right angle (90 degrees). In this case, the sum of the squares of the two shorter sides of the triangle is equal to the square of the longest side, which is the definition of a right triangle according to the Pythagorean theorem. Therefore, the given statement describes a right triangle.

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  • 7. 
    The area of the trapezium in the adjoining figure is: - ProProfs

    The area of the trapezium in the adjoining figure is:

    • 286 m2

    • 296 m2

    • 306 m2

    • 316 m2

    Correct Answer
    A. 306 m2
  • 8. 

    The perimeter of an equilateral triangle is 60 m. The area is:

    Correct Answer
    A.
    Explanation
    Perimeter of an equilateral triangle = 3 × side 60 m = 3 × side Side = 60 m / 3 = 20 m Area of an equilateral triangle = (√3 / 4) × side^2 Area = (√3 / 4) × 20^2 Area = (√3 / 4) × 400 Area = 100√3 sq m

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  • 9. 
    - ProProfs

    • 4 cm

    • 6 cm

    • 8 cm

    • 36 cm

    Correct Answer
    A. 6 cm
  • 10. 
    The area of the quadrilateral ABCD in the adjoining figure is: - ProProfs

    The area of the quadrilateral ABCD in the adjoining figure is:

    • 57 cm2

    • 95 cm2

    • 102 cm2

    • 114 cm2

    Correct Answer
    A. 114 cm2
  • 11. 

    The area of an isosceles triangle having a base 2 cm and the length of one of the equal sides 4 cm, is

    Correct Answer
    A.
    Explanation
    The area of an isosceles triangle can be found using the formula A = (1/2) * b * h, where b is the base and h is the height. In this case, the base is given as 2 cm and the length of one of the equal sides is 4 cm. Since the triangle is isosceles, we can divide the base into two equal parts, each measuring 1 cm. Now, we can use the Pythagorean theorem to find the height of the triangle. The height is the perpendicular distance from the midpoint of the base to the top vertex of the triangle. Using the Pythagorean theorem, we have h^2 = 4^2 - 1^2 = 15. Therefore, the height is sqrt(15) cm. Plugging these values into the formula, we get A = (1/2) * 2 * sqrt(15) = sqrt(15) cm^2.

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  • 12. 

    The edges of a triangular board are 6 cm, 8 cm and 10 cm. The cost of painting it at the rate of 9 paise per cm2 is:

    • Rs. 2.00

    • Rs. 2.16

    • Rs. 2.48

    • Rs. 3.00

    Correct Answer
    A. Rs. 2.16
    Explanation
    To find the cost of painting the triangular board, we need to calculate its area first. We can use Heron's formula to find the area of a triangle when the lengths of its sides are known. The semi-perimeter of the triangle is (6+8+10)/2 = 12 cm. Using this, we can calculate the area as √(12(12-6)(12-8)(12-10)) = √(12*6*4*2) = √(576) = 24 cm^2. Multiplying this by the painting rate of 9 paise per cm^2 gives us a cost of 24 * 9 = 216 paise. Converting this to rupees gives us Rs. 2.16.

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  • 13. 
    The area of the quadrilateral ABCD in the adjoining figure is: - ProProfs

    The area of the quadrilateral ABCD in the adjoining figure is:

    • 14.8 cm2

    • 15 cm2

    • 15.2 cm2

    • 16.4 cm2

    Correct Answer
    A. 15.2 cm2
    Explanation
    The area of a quadrilateral can be calculated by dividing it into triangles and finding the sum of their areas. In the given figure, we can divide the quadrilateral ABCD into two triangles, triangle ABC and triangle ACD. The area of triangle ABC can be calculated using the formula for the area of a triangle, which is 1/2 * base * height. The base of triangle ABC is 4 cm and the height is 3.8 cm, so the area of triangle ABC is 7.6 cm^2. Similarly, the area of triangle ACD can be calculated as 1/2 * base * height, which is 4 cm * 3.4 cm = 13.6 cm^2. Adding the areas of the two triangles gives us a total area of 7.6 cm^2 + 13.6 cm^2 = 21.2 cm^2. However, we need to subtract the area of triangle BCD, which is 1/2 * base * height = 4 cm * 1.2 cm = 4.8 cm^2. Therefore, the area of quadrilateral ABCD is 21.2 cm^2 - 4.8 cm^2 = 16.4 cm^2.

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  • 14. 
    - ProProfs

    • 5.196 cm2

    • 3.496 cm2

    • 1.732 cm2

    • 0.866 cm2

    Correct Answer
    A. 5.196 cm2
  • 15. 

    The sides of a triangle are 35 cm, 54 cm and 61 cm, respectively. The length of its longest altitude is:

    Correct Answer
    A.
    Explanation
    To find the length of the longest altitude of a triangle, we can use the formula for the area of a triangle. The formula is given as: Area = (1/2) * base * height. In this case, we know the lengths of the sides of the triangle, but we need to find the height of the triangle. We can use Heron's formula to find the area of the triangle, and then divide it by the corresponding base to find the height. Using Heron's formula, we find that the area of the triangle is approximately 924. Using the formula for the area of a triangle, we can find that the length of the longest altitude is approximately 30 cm.

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  • Current Version
  • Sep 30, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Jan 14, 2015
    Quiz Created by
    Tanmay Shankar

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