# GED Math - Get Your GED Now Study Series Test

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This practice test will determine you ability to pass the GED Math Test. You must gain a score of 80% or better to pass this practice test.

• 1.

### Jeff drive 3 1/2 miles to a jobsite and then back home on Monday, 6 1/4 miles to a jobsite and then back home on Tuesday and 8 1/3 miles to a jobsite and then back home on Friday.  If Jeff received .50/ per mile mileage reimbursement for his travel from home to work and back home, how much mileage reimbursement money would he receive?

• A.

\$15.25

• B.

\$18.09

• C.

\$36.16

• D.

\$12.25

• E.

\$41.50

B. \$18.09
Explanation
This results in a total mileage reimbursement of approximately \$18.09 for the week. ​​

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• 2.

### Chris bought a pair of Nikes and received a 30% discount and saved \$27 dollars on his purchase.  How much did the Nikes originally cost?

• A.

\$30

• B.

\$57

• C.

\$90

• D.

\$60

• E.

\$27

C. \$90
Explanation
If Chris received a 30% discount and saved \$27, this means that \$27 is equal to 30% of the original price of the Nikes. To find the original price, we can set up the equation: 30% of X = \$27. Solving this equation, we can find that X (the original price) is equal to \$90. Therefore, the Nikes originally cost \$90.

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• 3.

### The sales tax in Milwaukee, WI is 7.5%.  Linda bought a dress for \$150.  How much did Linda pay in sales tax?

\$11.25
Explanation
Linda paid \$11.25 in sales tax because 7.5% of \$150 is \$11.25.

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• 4.

### In the recent election, Jim Nixon ran for mayor and received 17,250 votes out of the 38,225 votes cast in the election.  What percent of the electorate voted for Jim Nixon?

• A.

45%

• B.

38%

• C.

17%

• D.

50%

• E.

57%

A. 45%
Explanation
Jim Nixon received 17,250 votes out of the total 38,225 votes cast in the election. To find the percentage of the electorate that voted for Jim Nixon, we divide his votes by the total votes and multiply by 100.

(17,250 / 38,225) * 100 = 0.45 * 100 = 45%

Therefore, 45% of the electorate voted for Jim Nixon.

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• 5.

### 3.A ship sails 20 km due North and then 35 km due East.  How far is it from its starting point?

• A.

65 km

• B.

35 km

• C.

55 km

• D.

26.8 km

• E.

40.3 km

E. 40.3 km
Explanation
The ship initially sails 20 km due North and then 35 km due East. To find the distance from its starting point, we can use the Pythagorean theorem. The North and East distances form the two sides of a right triangle, with the distance from the starting point being the hypotenuse. Using the Pythagorean theorem, the distance from the starting point is √(20^2 + 35^2) = √(400 + 1225) = √1625 ≈ 40.3 km.

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• 6.

### 1.A 4 m ladder rests against a vertical wall  with its foot 2 m from the wall.  How far up the wall does the ladder reach?

• A.

12

• B.

3.5

• C.

16

• D.

4

• E.

8.5

B. 3.5
Explanation
The ladder forms a right triangle with the wall and the ground. The ladder is the hypotenuse, the distance up the wall is the opposite side, and the distance from the wall to the foot of the ladder is the adjacent side. Using the Pythagorean theorem (a^2 + b^2 = c^2), we can solve for the length of the ladder. In this case, a = 2, b = unknown, and c = 4. Plugging these values into the equation, 2^2 + b^2 = 4^2, we get 4 + b^2 = 16. Solving for b, we get b^2 = 12, which means b = √12. Simplifying, we get b ≈ 3.46, which is approximately equal to 3.5. Therefore, the ladder reaches approximately 3.5 meters up the wall.

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• Nov 05, 2009
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