G12 T2 Class Work 1

1. A snail moves along a ruler. It takes 20 s to move from Q to R.What is its average speed from Q to R?

12/20 cm/s

(12-2)/20 cm/s

20/12 cm/s

20/(12-2) cm/s

The snail takes 20 seconds to move from Q to R. The average speed is calculated by dividing the distance traveled by the time taken. Since the distance is not given, we cannot determine the average speed accurately. However, the answer (12-2)/20 cm/s suggests that the snail traveled a distance of 10 cm (12-2) in 20 seconds, resulting in an average speed of 0.5 cm/s.

Explanation

The snail takes 20 seconds to move from Q to R. The average speed is calculated by dividing the distance traveled by the time taken. Since the distance is not given, we cannot determine the average speed accurately. However, the answer (12-2)/20 cm/s suggests that the snail traveled a distance of 10 cm (12-2) in 20 seconds, resulting in an average speed of 0.5 cm/s.

2. From the graph provided:

When is the bus slowing down?

From 0 to A and from B to C

From A to B and from D to E

From 0 to A and from D to E

From B to C only

The graph provided shows the speed of the bus over time. From the graph, it can be observed that the bus is slowing down only from point B to point C. This is indicated by the decreasing slope of the graph during that interval. Therefore, the correct answer is "From B to C only".

Explanation

The graph provided shows the speed of the bus over time. From the graph, it can be observed that the bus is slowing down only from point B to point C. This is indicated by the decreasing slope of the graph during that interval. Therefore, the correct answer is "From B to C only".

3. Calculate the acceleration for the interval 10 to 15 s.

0.8 m/s2

- 2 m/s2

- 0.8 m/s2

2 m/s2

The negative sign in front of the acceleration value indicates that the object is experiencing deceleration or slowing down during the interval from 10 to 15 seconds. The magnitude of the acceleration is 2 m/s2, meaning that the object is slowing down at a rate of 2 meters per second squared.

Explanation

The negative sign in front of the acceleration value indicates that the object is experiencing deceleration or slowing down during the interval from 10 to 15 seconds. The magnitude of the acceleration is 2 m/s2, meaning that the object is slowing down at a rate of 2 meters per second squared.

4. Two distance/time graphs and two speed/time graphs are shown.Which graph represents an object that is at rest?

A

B

C

D

Graph B represents an object at rest because the distance/time graph is a straight horizontal line, indicating that the object is not changing its position over time. Additionally, the speed/time graph for graph B is a flat line at zero, indicating that the object has zero speed and is not moving.

Explanation

Graph B represents an object at rest because the distance/time graph is a straight horizontal line, indicating that the object is not changing its position over time. Additionally, the speed/time graph for graph B is a flat line at zero, indicating that the object has zero speed and is not moving.

5. From the graph provided:

When is the acceleration 0?

From 0 to A and from B to C

From A to B, from C to D and from E to F

The acceleration is never zero

From 0 to A, from C to D and from E to F

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Explanation

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6. From the graph provided:

When is the bus speeding up?

From 0 to A and from B to C

From A to B and from D to E

From 0 to A and from D to E

From B to C only

The correct answer is "From 0 to A and from D to E". This can be determined by observing the graph provided. The graph shows the speed of the bus over time. From 0 to A, the speed of the bus increases, indicating that it is speeding up. Similarly, from D to E, the speed of the bus also increases, indicating that it is speeding up again.

Explanation

The correct answer is "From 0 to A and from D to E". This can be determined by observing the graph provided. The graph shows the speed of the bus over time. From 0 to A, the speed of the bus increases, indicating that it is speeding up. Similarly, from D to E, the speed of the bus also increases, indicating that it is speeding up again.

7. The graph represents the movement of a body:

How far has the body moved after 5 s?

2 m

10 m

25 m

50 m

The graph represents the distance traveled by the body over time. After 5 seconds, the graph shows that the body has moved a distance of 25 meters.

Explanation

The graph represents the distance traveled by the body over time. After 5 seconds, the graph shows that the body has moved a distance of 25 meters.

8. Calculate the acceleration for the interval 5 to 10 s.

2.4 m/s2

1.2 m/s2

- 1.2 m/s2

-2.4 m/s2

The acceleration for the interval 5 to 10 seconds is calculated to be 1.2 m/s2. This means that the velocity of the object is increasing by 1.2 meters per second every second during this time interval.

Explanation

The acceleration for the interval 5 to 10 seconds is calculated to be 1.2 m/s2. This means that the velocity of the object is increasing by 1.2 meters per second every second during this time interval.

9. From the graph provided:

Calculate the acceleration between D and E.

1 m/s2

0.24 m/s2

21 m/s2

5 m/s2

The acceleration between two points on a graph can be calculated by finding the change in velocity and dividing it by the time taken. In this case, the change in velocity between points D and E is 1 m/s and the time taken is 1 second. Therefore, the acceleration is 1 m/s^2.

Explanation

The acceleration between two points on a graph can be calculated by finding the change in velocity and dividing it by the time taken. In this case, the change in velocity between points D and E is 1 m/s and the time taken is 1 second. Therefore, the acceleration is 1 m/s^2.

10. From the graph provided:

State in which interval the acceleration is the highest.

From 0 to A

From A to B

From B to C

From C to D

From D to E

From E to F

The correct answer is From B to C. This can be determined by observing the graph and identifying the steepest slope. The steepest slope represents the highest acceleration. In this case, the steepest slope occurs between points B and C, indicating that the acceleration is the highest in this interval.

Explanation

The correct answer is From B to C. This can be determined by observing the graph and identifying the steepest slope. The steepest slope represents the highest acceleration. In this case, the steepest slope occurs between points B and C, indicating that the acceleration is the highest in this interval.