5th Grade Math Quiz On Prime Factorization! Trivia Questions

1. Is 2442 divisible by 6?

Yes

No

IF the digit number is an even number and the last two digits is divisible by 6

Explanation

IF the digit number is an even number and the last two digits is divisible by 6

2. Is 2439 divisible by 9?

Yes

No

If digits of any number add to a number which is a multiple of 9, then it is divisible by 9

Explanation

If digits of any number add to a number which is a multiple of 9, then it is divisible by 9

3. Is 3 a factor of 138?

Yes

No

If digits of any number add to a number which is a multiple of 3, then it is divisible by 3

Explanation

If digits of any number add to a number which is a multiple of 3, then it is divisible by 3

4. What is the prime factorization of 48?

2 x 2 X 2 x 2 x 3

2 x 2 x 2 x 3

2 x 3 x 4

2 x 12 x 2

The prime factorization of a number involves breaking it down into its prime factors. In this case, the number is 48. The prime factorization of 48 is 2 x 2 x 2 x 2 x 3. This means that 48 can be expressed as the product of these prime numbers.

Explanation

The prime factorization of a number involves breaking it down into its prime factors. In this case, the number is 48. The prime factorization of 48 is 2 x 2 x 2 x 2 x 3. This means that 48 can be expressed as the product of these prime numbers.

5. Find the prime factors of 520?

2 x 3 x 4 x 5

2 x 2 x 2 X 5 x 13

2 x 5 x 52

The prime factors of 520 are 2, 2, 2, 5, and 13. This can be determined by breaking down 520 into its prime factors, which are the numbers that can only be divided evenly by 1 and themselves. In this case, 520 can be divided by 2, resulting in 260. 260 can then be divided by 2 again, resulting in 130. 130 can be divided by 2 once more, resulting in 65. Finally, 65 can be divided by 5 and 13. Therefore, the prime factors of 520 are 2, 2, 2, 5, and 13.

Explanation

The prime factors of 520 are 2, 2, 2, 5, and 13. This can be determined by breaking down 520 into its prime factors, which are the numbers that can only be divided evenly by 1 and themselves. In this case, 520 can be divided by 2, resulting in 260. 260 can then be divided by 2 again, resulting in 130. 130 can be divided by 2 once more, resulting in 65. Finally, 65 can be divided by 5 and 13. Therefore, the prime factors of 520 are 2, 2, 2, 5, and 13.

6. What is the prime factorization of 603

2 x 7 x 43

3 x 3 x 67

3 x 201

The prime factorization of a number involves finding the prime numbers that multiply together to give the original number. In this case, the prime factorization of 603 is 3 x 3 x 67. This means that 603 can be expressed as the product of these prime numbers, with each prime number appearing as many times as its exponent.

Explanation

The prime factorization of a number involves finding the prime numbers that multiply together to give the original number. In this case, the prime factorization of 603 is 3 x 3 x 67. This means that 603 can be expressed as the product of these prime numbers, with each prime number appearing as many times as its exponent.