Electric Forces And Electric Fields (15)

1.

Near a long uniformly charge wire

Above a large uniformly charged plane

Inside a uniformly charged ball

Outside a uniformy charged sphere

Gauss law can be readily applied to find the electric field in all contexts

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Explanation

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2.

Repel

Attract

Attract or repel

Exert no electrostatic force

Charge insulator always spontaneously discharges

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Explanation

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3.

1.0 N/C

-1.0 N/C

0

0.25 N/C

It varies

The given answer is 0 because it is the only option that represents a constant electric field. All the other options either have a positive or negative value, or they vary, which means they are not constant.

Explanation

The given answer is 0 because it is the only option that represents a constant electric field. All the other options either have a positive or negative value, or they vary, which means they are not constant.

4. The magnitude of the electric force between two protons is 2.3e-26 N. how far apart are they?

0.10m

0.022m

3.1m

0.0057m

0.48m

The magnitude of the electric force between two protons is given as 2.3e-26 N. According to Coulomb's law, the magnitude of the electric force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Since the force is given and the charges of protons are constant, the only variable left is the distance between them. By rearranging Coulomb's law equation, we can solve for the distance. Therefore, the distance between the two protons is 0.10m.

Explanation

The magnitude of the electric force between two protons is given as 2.3e-26 N. According to Coulomb's law, the magnitude of the electric force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Since the force is given and the charges of protons are constant, the only variable left is the distance between them. By rearranging Coulomb's law equation, we can solve for the distance. Therefore, the distance between the two protons is 0.10m.

5.

F/12

F/3

F/6

3F/4

3F/2

The given options represent different fractions. The correct answer is F/12 because it is the smallest fraction among all the options.

Explanation

The given options represent different fractions. The correct answer is F/12 because it is the smallest fraction among all the options.

6.

It becomes larger

It becomes smaller

It stays the same

It changes unpredictably

It is zero

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Explanation

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7.

2.56 cm

5.12 cm

11.2 cm

3.34 m

4.24 m

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Explanation

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8.

The density matter is too great

The positive nuclei of your body repel the positive nuclei of the atoms of the ground

The density of the ground is greater than the density of your body

Atoms are bound together by chemical bonds

Electrons on the ground's surface of your feet repel one another

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Explanation

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9.

0

-560

-340

260

170

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Explanation

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10. A very small ball has a mass of 5.0e-3 Kg and a charge of 4 uC. What magnitude electric field directed upward will balance the weight of the ball?

1.2e4 N/C

8.2e2 N/C

2.0e-2 N/C

5.1e6 N/C

3.7e3 N/C

The weight of the ball can be balanced by the electric force acting on it. The electric force is given by F = qE, where F is the force, q is the charge, and E is the electric field. The weight of the ball is given by W = mg, where W is the weight, m is the mass, and g is the acceleration due to gravity. To balance the weight, the electric force must be equal to the weight. Therefore, qE = mg. Rearranging the equation, we get E = mg/q. Substituting the given values, we have E = (5.0e-3 kg)(9.8 m/s^2)/(4e-6 C) = 1.2e4 N/C.

Explanation

The weight of the ball can be balanced by the electric force acting on it. The electric force is given by F = qE, where F is the force, q is the charge, and E is the electric field. The weight of the ball is given by W = mg, where W is the weight, m is the mass, and g is the acceleration due to gravity. To balance the weight, the electric force must be equal to the weight. Therefore, qE = mg. Rearranging the equation, we get E = mg/q. Substituting the given values, we have E = (5.0e-3 kg)(9.8 m/s^2)/(4e-6 C) = 1.2e4 N/C.

11.

Upward and to the right

To the right

Downward

Downward and to the left

Field is zero at that point

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Explanation

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12.

1.15

-2.24

3.91

-1.15

0.863

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Explanation

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13. Estimate the magnitude of electric field strenght due to the proton of hydrogen atom at a distance of 5.39e-11m. The expected position of the electron in the atom.

10^-11 n/c

10^8 n/c

10^14 n/c

10^6 n/c

10^12 n/c

The magnitude of the electric field strength due to the proton of a hydrogen atom can be estimated using Coulomb's law. Coulomb's law states that the electric field strength is directly proportional to the charge and inversely proportional to the distance squared. Since the proton has a fixed charge, the only factor affecting the electric field strength is the distance. As the distance is given as 5.39e-11m, which is relatively small, the electric field strength is expected to be large. Among the given options, the closest magnitude is 10^12 n/c, which is the estimated magnitude of the electric field strength due to the proton of the hydrogen atom at that distance.

Explanation

The magnitude of the electric field strength due to the proton of a hydrogen atom can be estimated using Coulomb's law. Coulomb's law states that the electric field strength is directly proportional to the charge and inversely proportional to the distance squared. Since the proton has a fixed charge, the only factor affecting the electric field strength is the distance. As the distance is given as 5.39e-11m, which is relatively small, the electric field strength is expected to be large. Among the given options, the closest magnitude is 10^12 n/c, which is the estimated magnitude of the electric field strength due to the proton of the hydrogen atom at that distance.

14.

Increase masurably

Increase by an amount to small to measure directly

Stay unchanged

Decrease by an amount to small to measure directly

Decrease masurably

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Explanation

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