Chemistry 1st Paper(Chapter Two)

1. Select the ones you like

I & iii

I & ii

Ii & iii

I , ii & iii

The correct answer is "i & iii" because it indicates that the options selected are i and iii. The other options are either missing or do not include the correct combination of choices.

Explanation

The correct answer is "i & iii" because it indicates that the options selected are i and iii. The other options are either missing or do not include the correct combination of choices.

2. 3rd(3য়) soktistorar(শক্তিস্তরের) jonno mvr ar man nichar konti?

Nh/2π

Nh/6π

3h/2π

4h/2π

The correct answer is 3h/2π.

Explanation

The correct answer is 3h/2π.

3. Select the ones you like

I & ii

I & iii

Ii & iii

I , ii & iii

The correct answer is i & iii. This means that the options i and iii are the ones that should be selected.

Explanation

The correct answer is i & iii. This means that the options i and iii are the ones that should be selected.

4. Nirdisto tapmattray(তাপমাত্রায়) 750 mL sompriktto(সম্পৃক্ত) drobona 200 g NaCl drobivuto(দ্রবীভূত) asa. gram akoka NaCl ar drabbota koto?

266.67 gL-1

240.30 gL-1

300.67 gL-1

150.22 gL-1

The concentration of NaCl in the solution can be calculated using the formula:

Concentration (g/L) = Mass of NaCl (g) / Volume of solution (L)

Given that the mass of NaCl is 200 g and the volume of the solution is 750 mL (which is equivalent to 0.75 L), we can substitute these values into the formula:

Concentration (g/L) = 200 g / 0.75 L = 266.67 g/L

Therefore, the correct answer is 266.67 gL-1.

Explanation

The concentration of NaCl in the solution can be calculated using the formula:

Concentration (g/L) = Mass of NaCl (g) / Volume of solution (L)

Given that the mass of NaCl is 200 g and the volume of the solution is 750 mL (which is equivalent to 0.75 L), we can substitute these values into the formula:

Concentration (g/L) = 200 g / 0.75 L = 266.67 g/L

Therefore, the correct answer is 266.67 gL-1.

5. NH₄⁺ ayon sonakkto(শনাক্ত) korone baborito bikarok(বিকারক) holo____

AgNO3 drobon

BaCl2 drobon

Neslar drobon

NH4OH drobon

not-available-via-ai

Explanation

not-available-via-ai

6. Nichar kon orbitalar sokti sorbo nonmo hoba?

3d

4s

4p

3s

not-available-via-ai

Explanation

not-available-via-ai

7. A₂B₃ ar drabbota(দ্রাব্যতা) S hola drabbota gunfol koto?

108 S3

27 S3

16 S4

8 S3

The given question is asking for the product of two numbers, A2B3 and S hola drabbota. The correct answer is 108 S3. However, without further information or context, it is difficult to provide a specific explanation for this answer. It is possible that the answer is derived from a specific mathematical calculation or formula that is not provided. Without more information, it is not possible to provide a comprehensive explanation.

Explanation

The given question is asking for the product of two numbers, A2B3 and S hola drabbota. The correct answer is 108 S3. However, without further information or context, it is difficult to provide a specific explanation for this answer. It is possible that the answer is derived from a specific mathematical calculation or formula that is not provided. Without more information, it is not possible to provide a comprehensive explanation.

8. Select the ones you like

I & ii

Ii & iii

I & iii

I , ii & iii

The correct answer is "i, ii & iii" because it includes all the options listed, i, ii, and iii.

Explanation

The correct answer is "i, ii & iii" because it includes all the options listed, i, ii, and iii.

9. Select the ones you like

I & ii

Ii & iii

I & iii

I , ii & iii

The correct answer is "i, ii & iii". This means that all of the options i, ii, and iii are correct and should be selected.

Explanation

The correct answer is "i, ii & iii". This means that all of the options i, ii, and iii are correct and should be selected.

10. N=2 , l=1 , m= 1 hola oi orbitalar(অরবিটালের) protik konti?

2Px

2Py

2Pz

2S

The quantum numbers given in the question indicate that the electron is in the 2nd energy level (n=2), in the p subshell (l=1), and the m value of 1 indicates that it is in the 2Py orbital. The 2Py orbital is one of the three p orbitals (Px, Py, Pz) in the second energy level.

Explanation

The quantum numbers given in the question indicate that the electron is in the 2nd energy level (n=2), in the p subshell (l=1), and the m value of 1 indicates that it is in the 2Py orbital. The 2Py orbital is one of the three p orbitals (Px, Py, Pz) in the second energy level.

11. Shikha(শিখা) porikkhay sonali-holud shikha sristy kora konti ?

Na

K

Ca

Cu

not-available-via-ai

Explanation

not-available-via-ai

12. Select the ones you like

Option 1

Option 2

Option 3

Option 4

The correct answer is Option 1 because it suggests that there are multiple options to choose from and the person is required to select the ones they like. The other options do not provide any indication of selecting preferences or choices.

Explanation

The correct answer is Option 1 because it suggests that there are multiple options to choose from and the person is required to select the ones they like. The other options do not provide any indication of selecting preferences or choices.

13. Alfa kona bicchuron(বিচ্ছুরন) porikkhay porday(পর্দায়) prolapon(প্রলেপন) thaka konti?

CuS

ZnS

FeS

NiS

The correct answer is NiS. The question is asking which compound contains the element "prolapon". "Prolapon" is the Bengali word for nickel, so the compound that contains nickel is NiS. CuS, ZnS, and FeS do not contain nickel.

Explanation

The correct answer is NiS. The question is asking which compound contains the element "prolapon". "Prolapon" is the Bengali word for nickel, so the compound that contains nickel is NiS. CuS, ZnS, and FeS do not contain nickel.

14. Kon alor frequency basi hoba?

X-ray

UV ray

IR

Radio waves

X-rays have a higher frequency compared to UV rays, IR, and radio waves. X-rays have wavelengths between 0.01 to 10 nanometers, which corresponds to frequencies between 30 petahertz to 30 exahertz. This high frequency allows X-rays to penetrate through the human body and other materials, making them useful in medical imaging and industrial applications.

Explanation

X-rays have a higher frequency compared to UV rays, IR, and radio waves. X-rays have wavelengths between 0.01 to 10 nanometers, which corresponds to frequencies between 30 petahertz to 30 exahertz. This high frequency allows X-rays to penetrate through the human body and other materials, making them useful in medical imaging and industrial applications.